Title: Rates of Reaction
1Rates of Reaction
2RATE CHANGE DURING A REACTION
Reactions are fastest at the start and get
slower as the reactants concentration drops. In
a reaction such as A 2B gt C the
concentrations might change as shown
- Reactants (A and B)
- Concentration decreases with time
- Product (C)
- Concentration increases with time
-
- the steeper the curve the faster the
- rate of the reaction
-
- reactions start off quickly because
- of the greater likelihood of collisions
-
- reactions slow down with time as
- there are fewer reactants to collide
3MEASURING THE RATE
RATE How much concentration changes with time. It
is the equivalent of velocity.
THE SLOPE OF THE GRADIENT OF THE CURVE GETS LESS
AS THE REACTION SLOWS DOWN WITH TIME
CONCENTRATION
y
x
TIME
- the rate of change of concentration is found
from the slope (gradient) of the curve - the slope at the start of the reaction will
give the INITIAL RATE - the slope gets less (showing the rate is
slowing down) as the reaction proceeds
4Rate of Reaction
- The rate of a reaction is defined as the change
in concentration per unit time in any one
reactant or product.
5Rate of Reaction
- The rate of a reaction is defined as the change
in concentration per unit time in any one
reactant or product. - The rate of reaction depends on 5 factors.
- Nature of reactants
- Particle size
- Concentration
- Temperature
- Catalysts.
6Nature of reactants
- The reaction between acidified sodium dichromate
and Ammonium Iron (11) sulphate is instantaneous.
(Ionic) - The reaction between acidified sodium dichromate
and ethanal occurs much more slowly. (Covalent)
7Particle Size.
- Large Marble chips
- Small marble chips CaCO3 2HCl ? CaCl2 CO2
H2O - Powdered Marble
- The Rate of the reaction increases as the
particle size decreases. - The smaller the particle size the greater the
surface area. - Therefore the greater the number of collisions,
the greater - the number of successful collisions.
8INCREASING SURFACE AREA
- Increasing surface area increases chances of a
collision - more particles are exposed - Powdered solids react quicker than larger lumps
- Catalysts (e.g. in catalytic converters) are in
a finely divided form for this reason -
- In many organic reactions there are two liquid
layers, one aqueous, the other non-aqueous.
Shaking the mixture improves the reaction rate as
an emulsion is often formed and the area of the
boundary layers is increased giving more
collisions.
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CUT THE SHAPE INTO SMALLER PIECES
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3
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SURFACE AREA 993333 30 sq units
SURFACE AREA 9 x (111111) 54 sq units
9Coal Dust Explosion
10Concentration
- The greater the concentration the greater the
rate of reaction - This reaction is studied using the reaction
between sodium - thiosulfate and Hydrochloric acid.
- Na2S2O3 2HCl -gt S 2NaCl SO2
H2O - If the concentration of the reactants is
increased, the number - of collisions will also be increased.
- If the number of collisions is increased then the
number of - effective collisions will be increased.
11INCREASING CONCENTRATION
Increasing concentration more frequent
collisions increased rate of reaction
Low concentration fewer collisions
Higher concentration more collisions
However, increasing the concentration of some
reactants can have a greater effect than
increasing others
12Temperature
- The greater the temperature the greater the rate
of reaction - This reaction is studied using the reaction
between sodium - thiosulfate and Hydrochloric acid.
- Na2S2O3 2HCl -gt S 2NaCl SO2
H2O - The rate of a reaction increases as the
temperature increases because more of the
colliding molecules have the minimum activation
energy needed to react.
13INCREASING TEMPERATURE
Effect increasing the temperature increases the
rate of a reaction particles get more energy so
they can overcome the energy barrier particle
speeds also increase so collisions are more
frequent
ENERGY CHANGES DURING A REACTION As a reaction
takes place the enthalpy of the system rises to a
maximum, then falls A minimum amount of energy
is required to overcome the ACTIVATION ENERGY
(Ea). Only those reactants with energy equal to,
or greater than, this value will react. If more
energy is given to the reactants then they are
more likely to react.
Typical energy profile diagram for an exothermic
reaction
14INCREASING TEMPERATURE
MAXWELL-BOLTZMANN DISTRIBUTION OF MOLECULAR ENERGY
NUMBER OF MOLECUES WITH A PARTICULAR ENERGY
MOLECULAR ENERGY
Because of the many collisions taking place
between molecules, there is a spread of molecular
energies and velocities. This has been
demonstrated by experiment. It indicated that
... no particles have zero energy/velocity
some have very low and some have very high
energies/velocities most have intermediate
velocities.
15INCREASING TEMPERATURE
MAXWELL-BOLTZMANN DISTRIBUTION OF MOLECULAR ENERGY
T1
NUMBER OF MOLECUES WITH A PARTICULAR ENERGY
T2
TEMPERATURE T2 gt T1
MOLECULAR ENERGY
- Increasing the temperature alters the
distribution - get a shift to higher energies/velocities
- curve gets broader and flatter due to the
greater spread of values - area under the curve stays constant - it
corresponds to the total number of particles
16INCREASING TEMPERATURE
MAXWELL-BOLTZMANN DISTRIBUTION OF MOLECULAR ENERGY
NUMBER OF MOLECUES WITH A PARTICULAR ENERGY
NUMBER OF MOLECULES WITH SUFFICIENT ENERGY TO
OVERCOME THE ENERGY BARRIER
Ea
MOLECULAR ENERGY
ACTIVATION ENERGY - Ea The Activation Energy is
the minimum energy required for a reaction to
take place The area under the curve beyond Ea
corresponds to the number of molecules with
sufficient energy to overcome the energy barrier
and react.
17INCREASING TEMPERATURE
TEMPERATURE T2 gt T1
MAXWELL-BOLTZMANN DISTRIBUTION OF MOLECULAR ENERGY
T1
T2
NUMBER OF MOLECUES WITH A PARTICULAR ENERGY
EXTRA MOLECULES WITH SUFFICIENT ENERGY TO
OVERCOME THE ENERGY BARRIER
Ea
MOLECULAR ENERGY
Explanation increasing the temperature gives more
particles an energy greater than Ea more
reactants are able to overcome the energy barrier
and form products a small rise in temperature can
lead to a large increase in rate
18Catalysts
19Types of Catalysis
- Homogeneous catalysis. This is catalysis in which
both the reactants and the catalyst are in the
same phase. (Iodine snake experiment) - Heterogeneous catalysis. This is catalysis in
which the reactants and catalyst are in different
phases. (Hydrogen peroxide (liquid) and Manganese
dioxide (solid)) - Auto catalysis.One of the products in the
reaction catalyses the reaction. (Permanganate
ions and Fe2 ions.)
20Mechanisms of catalysis
- Intermediate compound theory.
- A B ? AB SLOW
- A C ? AC FAST
- AC B? AB C FAST
- The decomposition of hydrogen peroxide catalysed
by the presence of I ions (iodine snake reaction)
illustrates the formation of an intermediate. - Overall Reaction
- 2H2O2 2H2O O2
- Step 1
- H2O2 I- H2O IO-
- Step 2
- H2O2 IO- H2O O2 I-
- Also
- Sodium Hydrogen tartrate Hydrogen peroxide
Co2 ions (pink) - Pink? Blue/Green ?Pink
- Cobalt Intermediate
Cobalt
21Surface Adsorption Theory
- Methanol Methanal
- CH3OH
HCHO - Platinum
- 2H2 O2 ? 2H2O
- A good example is the reaction of Hydrogen and
Oxygen to form - water using finely divided Platinum as the
catalyst. - The Hydrogen and oxygen molecules settle on the
surface of the - catalyst. The adsorbed atoms form weak bonds
with the metal - atoms. Transition metals can act as catalysts
because they have - vacant d orbitals.
- The hydrogen and oxygen molecules then react to
form water. - The products leave the surface of the catalyst.
(desorption)
22Catalytic converters.
- Exhaust fumes contain carbon monoxide (CO),
nitrogen - monoxide (NO), nitrogen dioxide (NO2) and unburnt
- hydrocarbons. a catalytic converter converts
these gases to - environmentally friendly gases.
- The catalytic converter consists of a thin
coating of platinum, - palladium, and rhodium on a ceramic or metal
honeycomb inside - a stainless steel case.
-
Pt/Pd/Rh (Temp 300 C) - 2CO 2NO ? 2CO2 N2
- The un-burnt hydrocarbons react with oxides of
nitrogen to form carbon dioxide nitrogen and
water.
23Catalytic converter
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25Collision Theory
- For a reaction to occur, the reacting particles
must collide with each other. - For the formation of product a certain minimum
energy is required in the collision. - Such a collision is called an effective
- collision.
26COLLISION THEORY
- Collision theory states that...
- particles must COLLIDE before a reaction can
take place - not all collisions lead to a reaction
- reactants must possess at least a minimum amount
of energy - ACTIVATION ENERGY - plus
- particles must approach each other in a certain
relative way - the STERIC EFFECT - According to collision theory, to increase the
rate of reaction you therefore need... - more frequent collisions increase particle
speed or - have more particles present
- more successful collisions give particles more
energy or - lower the activation energy
27The Activation energy
- The Activation energy is the minimum energy which
colliding particles must have for a reaction to
occur.
28Energy profile diagram
- A catalyst works by reducing the activation
energy.
29ADDING A CATALYST
- Catalysts provide an alternative reaction
pathway with a lower Activation Energy (Ea) - Decreasing the Activation Energy means that
more particles will have sufficient - energy to overcome the energy barrier and
react - Catalysts remain chemically unchanged at the
end of the reaction.
WITHOUT A CATALYST
WITH A CATALYST
30ADDING A CATALYST
- Catalysts provide an alternative reaction
pathway with a lower Activation Energy (Ea) - Decreasing the Activation Energy means that
more particles will have sufficient - energy to overcome the energy barrier and
react - Catalysts remain chemically unchanged at the
end of the reaction.
WITHOUT A CATALYST
WITH A CATALYST
31ADDING A CATALYST
MAXWELL-BOLTZMANN DISTRIBUTION OF MOLECULAR ENERGY
NUMBER OF MOLECUES WITH A PARTICULAR ENERGY
NUMBER OF MOLECULES WITH SUFFICIENT ENERGY TO
OVERCOME THE ENERGY BARRIER
Ea
MOLECULAR ENERGY
The area under the curve beyond Ea corresponds to
the number of molecules with sufficient energy to
overcome the energy barrier and react. If a
catalyst is added, the Activation Energy is
lowered - Ea will move to the left.
32ADDING A CATALYST
MAXWELL-BOLTZMANN DISTRIBUTION OF MOLECULAR ENERGY
NUMBER OF MOLECUES WITH A PARTICULAR ENERGY
EXTRA MOLECULES WITH SUFFICIENT ENERGY TO
OVERCOME THE ENERGY BARRIER
Ea
MOLECULAR ENERGY
The area under the curve beyond Ea corresponds to
the number of molecules with sufficient energy to
overcome the energy barrier and react. Lowering
the Activation Energy, Ea, results in a greater
area under the curve after Ea showing that more
molecules have energies in excess of the
Activation Energy
33CATALYSTS - A REVIEW
- work by providing an alternative reaction
pathway with a lower Activation Energy - using catalysts avoids the need to supply extra
heat - safer and cheaper - catalysts remain chemically unchanged at the
end of the reaction. - Types Homogeneous Catalysts
Heterogeneous Catalysts - same phase as reactants different phase to
reactants - e.g. CFCs and ozone e.g. Fe in
Haber process - Uses used in industry especially where an
increase in temperature results in - a lower yield due to a shift in equilibrium
(Haber and Contact Processes)
- CATALYSTS DO NOT AFFECT THE POSITION OF ANY
EQUILIBRIUM - but they do affect the rate at which
equilibrium is attained - a lot is spent on research into more effective
catalysts - the savings can be dramatic - catalysts need to be changed regularly as they
get poisoned by other chemicals - catalysts are used in a finely divided state to
increase the surface area
34Monitoring the rate of production of oxygen from
hydrogen peroxide using manganese dioxide as a
catalyst
- Hydrogen peroxide decomposes into water and
oxygen as follows - H2O2(l) ? H2O(l) 1/2 O2(g)
- This occurs much too slowly to be
- monitored. However, manganese
- dioxide acts as a suitable catalyst,
- and the reaction occurs at a
- measurable rate.
35Method 2
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38Questions
- 1. Why is the slope of the graph steepest in the
early stages of the reaction? - Since rate is proportional to concentration,
the greatest rate, indicated by the steepest
slope, is evident in the early stages when the
concentration of hydrogen peroxide is at a
maximum. - 2. At what stage is the reaction complete?
- When the graph becomes horizontal.
- 3. What would be the effect on the graph of
doubling the amount of - manganese(IV) oxide?
- The increased surface area of catalyst would
speed up the reaction, giving a steeper slope and
an earlier completion. The volume of oxygen
produced would be unchanged.
39- 4. Would doubling the manganese(IV) oxide create
a practical difficulty? Explain your answer. - Yes. The production of oxygen could become
too quick for accurate monitoring. - 5. What would be the effect on the graph of
doubling the concentration of - hydrogen peroxide?
- Increasing the concentration of a reactant
would speed up the rate, as indicated by a
steeper slope. Doubling the concentration would
produce double the final volume of oxygen. - 6. Would doubling the concentration of hydrogen
peroxide create a practical difficulty? Explain
your answer. - Yes. The capacity of the collection vessel
could be exceeded.
40Studying the effects on reaction rate of (i)
concentration and (ii) temperature
- The reaction used is that between a sodium
thiosulfate solution and hydrochloric acid - 2HCl(aq) Na2S2O3(aq) 2NaCl(aq)
SO2(aq) S(s)? H2O(l) - The precipitate of sulfur formed gradually
obscures a cross marked on paper and placed
beneath the reaction flask. The rate of reaction,
and consequently the time taken to obscure the
cross, depends on a number of variables such as
temperature, concentration and volume. By varying
one of these and keeping the others constant, the
effect on rate can be studied. - The inverse of the time taken to obscure the
cross is the measure of reaction rate used in
this experiment.
41Effect of concentration
- 1. Place 100 cm3 of the sodium thiosulfate
solution into a conical flask. - 2. Add 10 cm3 of 3 M hydrochloric acid to the
flask, while starting the stop clock at the same
time. - 3. Swirl the flask and place it on a piece of
white paper marked with a cross. - 4. Record the time taken for the cross to
disappear. - 5. Repeat the experiment using 80, 60, 40 and 20
cm3 of. sodium thiosulfate solution respectively.
In each case, add water to make the volume up to
100 cm3 and mix before adding HCl. - 6. If the initial sodium thiosulfate
concentration is 0.1 M, subsequent concentrations
will be 0.08 M, 0.06 M, 0.04 M and 0.02 M
respectively.
42- 7.Record the results in a table similar to the
following - Concentration of thiosulfate 0.l M 0.08 M 0.06
M 0.04 M 0.02 M -
- Reaction time (s)
- 1/time
-
- 8. Draw a graph of 1/time against concentration.
This is effectively a graph of - reaction rate against concentration.
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44Effect of temperature
- Procedure NB Wear your safety glasses.
- 1 . Place 100 cm3 of 0.05 M sodium thiosulfate
solution into a conical flask. - 2. Warm the flask gently until the temperature is
about 20 0C. - 3. Add 5 cm3 of 3 M HCl, starting a stop clock at
the same time, before proceeding. - 4. Without delay, swirl the flask, place it on a
piece of white paper marked with a cross, and
record the exact temperature of the contents of
the flask. - 5. Record the time taken for the cross to
disappear - 6. Repeat the experiment, heating the thiosulfate
to temperatures of approximately - 30 0C, 40 0C, 50 0C and 60 0C respectively
(before adding the HCl). - 7. Record the results in a table similar to the
following
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46Questions
- Suggested Answers to Student Questions
- 1. What is the effect of increasing the
concentration on the reaction time? - The reaction time is decreased.
- 2. What is the effect of increasing the
concentration on the reaction rate? - The rate is increased.
- 3. What is meant by saying that two quantities
are directly proportional? - If one of the quantities is
increased/decreased by a certain factor, the
other changes in exactly the same way. - 4. What is the effect of raising the temperature
on the reaction time? - The reaction time is decreased.
- 5. What is the effect of raising the temperature
on the reaction rate? - Suggest two factors responsible for the result
observed. - The rate is increased. The higher temperature
results in greater kinetic energy of the
particles present. This causes - (i) more collisions per unit time, and
- (ii) a greater proportion of the collisions to
have the activation energy needed for products
to form. - Both (i) and (ii) result in a rate increase.
47- 6. Suggest a reason why it is not recommended to
carry out the experiment at temperatures higher
than about 60 0C. - The reaction occurs so quickly that it is not
possible to measure the time - accurately.
- 7. Which is the limiting reactant in the
temperature experiment? - 100 cm3 of 0.05 M Na2S2O3 contains
- 100/1000 x 0.05 0.005 moles
Na2S2O3 - 5 cm3 of 3 M HCl
contains - 5/1000 x 3 0.015 moles HCl
- According to the balanced equation, the reacting
ratio is Na2S2O3 HCl 12 - The amounts used are in the ratio
- Na2S2O3 HCl 0.005 0.015 1 3
-
- Clearly Na2S2O3 is the limiting
reactant. -