Title: Ch. 6
1Ch. 6 8.8 lecture notes
2Video Exploding Gummy Bear!
Im a wimp, so youre not getting the live
version! ? Please dont try this at home! ?
3Terms to know
- System
- Surroundings
- Heat
- Work
- Energy
4Rvw Endothermic vs. Exothermic Reactions
51st Law of Thermodynamics
- Nrg of universe is constant
- Nrg is conserved cannot be created nor destroyed
- Internal nrg (E) total nrg of the system.
- can be changed by flow of work (w), heat (q), or
both ?E q w - q gt 0
- q lt 0
- W gt 0
- W lt 0
6State functions
- Internal nrg (E) is a state function
- State functions depend only on initial and final
state of the system - Independent of path taken to get from start to
finish. - Example
7P-V work
8P-V work
- Work in terms of PV
- For expanding gas
- For compressed gas
9Enthalpy (H)
- Relates nrg P-V work H E PV
- At constant pressure (where only P-V work is
allowed), ?H nrg flow as heat qp - How is this so??? Derive the equation!
10Enthalpy of rxns (?H )
- ?H qp Hfinal Hinitial Hprods Hrxts
- Characteristics of enthalpy changes (?H )
- Enthalpy is an extensive property
- ?Hforward -?H reverse
- ?H depends on state of rxts and prods
- In terms of potential nrg, .
- Assume everything is at standard conditions (25
oC, 1 atm) unless stated otherwise
11Practice problem 1
- 2H2O2 (l) ? 2H2O (g) O2 (g)
- ?Hrxn -196 kJ
- What is ?H if 5.00 g of H2O2 is decomposed?
12Calorimetry
- Measures heat flow by measuring . . .
- Uses a calorimeter (see picture)
- Constant-pressure calorimetry
- Patm remains constant
- Used to determine changes in enthalpy (heats of
rxn) for rxns occuring in solution - ? ?H qp
- ?
13Coffee Cup Calorimeter
14Constant-volume calorimetry A bomb calorimeter
- No work is done. Why?
- Weighed rxts placed inside rigid steel container
(the bomb) and ignited - ??H q w qV
15Heat capacity
- Heat capacity (C) nrg needed to raise temp of a
body by.. Units ???? - C heat absorbed
- increase in temp
- Molar heat capacity heat capacity of one
of substance Units ???? - Specific heat capacity (c) heat capacity of one
of substance Units ????
16Some specific heats
Substance Specific Heat at 25oC
(J/goC) Lead 0.128
Gold 0.129
Silver 0.235
Copper 0.387
Iron 0.4498 Carbon
(graphite) 0.711 Granite
0.803 Olive Oil
2.0 Ethyl alcohol 2.45
Water, (liquid) 4.1796
Notice anything about the first 5 substances?
17Heat transfer
18Heat transfer
- Q mc?T ?H if at constant P
- If a hot object touches a cooler object
- Tf Ti for hot object
- Tf Ti for cooler object
- And Tf of hot object Tf of cooler object
- All heat lost by one object is gained by the
other, so - Q1
- Tip to avoid dealing with negative
-
19Practice problem 2
- A 150.0 g sample of a metal at 75.0 oC is added
to 150.0 g of water at 15.0 oC. The temperature
of the water rises to 18.3 oC. Calculate the
specific heat of the metal, assuming that all of
the heat lost by the metal is gained by the
water. (specific heat of water 4.18 J/g oC)
20Phase changes enthalpy
21Phase changes enthalpy
- How do you calculate enthalpy for segments BC and
DE? - How do you calculate enthalpy for segments AB, CD
and EF?
22Phase change constants for water
- Specific heat (c) for ice 2.09 J/goC
- Specific heat (c) for water 4.18 J/goC
- Specific heat (c) for vapor 1.84 J/goC
- ?Hfus Heat of fusion 6.01 kJ/mol
- ?Hvap Heat of vaporization 40.67 kJ/mol
23Phase change calorimetry
24Practice Problems
- Do problems on Calorimetry wkhst
25Pre-assessment Lewis Structures
- On your white board, draw the Lewis structures
for the following molecules - H2O
- CO2
- HCN
26Bond nrg enthalpy of rxns
- Reactants break bonds and new bonds form to make
products - Breaking bonds is.
- Forming bonds is.
- Bond enthalpy (D)
- As bond strength increases, bond enthalpy.
- Use bond enthalpies to calculate ?H without
having to know ?Hfs for all species
27More on bond enthalpies
- Need to know Lewis structures for compounds.
Just seeing N2H4 doesnt help us calculate the
bond enthalpy for it. We need to know HOW it
bonds
So, there are N-H bonds and N-N bond
28- ?Hrxn S (D of bonds broken) - S (D of bonds
formed) - NOTE Sum of RXTS Sum of PRODUCTS!!!
- Multiply bond enthalpy by number of bonds
- If ?Hrxn gt 0, nrg to break bonds is
nrg released when new bonds form - Vice-versa if ?Hrxn lt 0.
29Bond enthalpy, bond length and bond strength
CC CC C ? C
Bond length (Å) 1.54 1.34 1.20
Bond enthalpy (kJ/mol) 348 614 839
30Interpreting the chart
- As bond length ?, bond enthalpy
- As bond length ?, of bonds
- As of bonds ?, bond enthalpy
- As bond strength ?, bond enthalpy
- Therefore
- As bond length ?, bond strength
- As of bonds ?, bond strength
31Bond enthalpies for practice probs
- Bond Bond enthalpy (kJ/mol)
- CC 347
- CC 614
- C ? C 839
- HH 432
- N N 160
- N H 391
32- Bond Bond enthalpy (kJ/mol)
- N ? N 941
- Cl Cl 239
- C H 413
- H Cl 427
- C Cl 339
33Practice problem 3
- Calculate ?Hrxn for each of the following
- Cl2 CH4 ? CH3Cl HCl
- N2H4 ? N2 2 H2
- C2H4 HCl ? C2H3Cl H2
34Practice Problem 4
- The standard enthalpy of formation of NH3 is -46
kJ/mol. Use this information as well as the
balanced equation below to estimate the N-H bond
energy. Compare your result with the value in
previous table. - N2 (g) 3H2 (g) ? 2NH3 (g)