Title: Ch. 15
1Ch. 15 16 Review
- Everything except Polyprotics Lewis
Acids/Bases!!
2Practice 1
- Write the equilibrium-constant expressions for
the following processes - H2(g) I2(g) ? 2HI(g)
- Cd4(aq) 4Br-(aq) ? CdBr4(aq)
- P4 (s) 5 O2 (g) ? P4O10 (s)
3Practice 2
- For the UNBALANCED reaction
- NH3 (aq) ? N2 (g) H2 (g)
- Write an equilibrium expression
- Calculate the value of K at 127C for
- NH3 3.1x10-2M
- N2 8.5x10-1 M
- H2 3.1x10-3 M
- Calculate the value of K with the above
concentrations for the following reaction - 1/2 N2 3/2 H2 ? NH3
4Practice 3
- A mixture of hydrogen and nitrogen in a reaction
vessel is allowed to attain equilibrium at 472C.
The equilibrium mixture of gases was analyzed and
found to contain 7.38 atm H2 , 2.46 atm N2 , and
0.166 atm NH3. From these data, calculate the
equilibrium constant Kp for the reaction
5Practice 4
- Sulfur trioxide decomposes at high temperature in
a sealed container - Initially, the vessel is charged at 1000 K with
SO3(g) at a partial pressure of 0.500 atm. At
equilibrium the SO3 partial pressure is 0.200
atm. Calculate the value of Kp at 1000 K.
6Practice 5
- At 448C the equilibrium constant Kc for the
reaction - is 50.5. Predict in which direction the reaction
will proceed to reach equilibrium at 448C if we
start with 2.0 ? 102 mol of HI, 1.0 ? 102 mol
of H2, and 3.0 ? 102 mol of I2 in a 2.00-L
container.
7Practice 6
- Consider the equilibrium
- In which direction will the equilibrium shift
when - N2O4 is added
- NO2 is removed
- the total pressure is increased by addition of
N2(g) - the volume is increased
- the temperature is decreased
87.) Determine if the following is acidic, basic,
or neutral.
9Answer
- Ions Cu2, NO3-
- Cu2 H2O ? Cu(OH)2 H
- weak base acidic (due to H)
- NO3- H2O ? HNO3 OH-
- strong acid neutral
- (will dissociate, so H and OH- will form
water) - Salt Acidic
108.) Determine if the following is acidic, basic,
or neutral.
11Answer
- Ions K, ClO4-
- K H2O ? KOH H
- strong base neutral
- (will dissociate, so H and OH- will form
water) - ClO4- H2O ? HClO4 OH-
- strong acid neutral
- (will dissociate, so H and OH- will form
water) - Salt neutral
129.) Determine if the following is acidic, basic,
or neutral.
13Answer
- Ions Na, H2PO4-
- Na H2O ? NaOH H
- strong base neutral
- (will dissociate, so H and OH- will form
water) - H2PO4- H2O ? H3PO4 OH-
- weak acid basic (due to OH-)
-
- Salt basic
1410.) Determine if the following is acidic, basic,
or neutral.
15Answer
- Ions Li, F-
- Li H2O ? LiOH H
- strong base neutral
- (will dissociate, so H and OH- will form
water) - F- H2O ? HF OH-
- weak acid basic (due to OH-)
-
- Salt basic
1611) Determine if the following is acidic, basic,
or neutral.
- (NH4)2CO3
- Extra info
- Kb (of NH3) 1.8x10-5
- ka (of HCO3-) 5.6x10-11
17Answer
- Ions NH4, CO3-2
- NH4 H2O ? NH3 H3O
- weak base acidic (due to H3O)
-
- CO3- H2O ? HCO3- OH-
- weak acid basic (due to OH-)
-
- must compare Kb vs. Ka to decide pH of salt
- Kb (of NH3) 1.8x10-5
- Ka of NH4 5.6x10-10
- ka (of HCO3-) 5.6x10-11
- kb of CO3-2 1.8x10-4
- Salt basic since Kb is greater than ka
1812.) Complete the following table
pH H pOH OH Acidic, basic, or neutral?
5.4 x 104
7.8 x 10-10
10.75
5.00
19Answers
- ROW1
- pH 3.27
- pOH 10.73
- OH 1.9 x 1011
- acidic (since pH lt 7)
- ROW 2
- pH 4.89
- H 1.3 x 105
- pOH 9.11
- acidic (since pH lt 7)
- ROW 3
- H 1.8 x 10-11
- pOH 3.25
- OH 5.6 x 104
- basic (since pH gt 7)
- ROW 4
- pH 9.00
- H 1.0 x 109
- OH 1.0 x 105
- basic (since pH gt 7)
20Practice 13
- Calculate the pH of a 0.0430 M HNO3 solution.
21Answer
- Since HNO3 is a strong acid, the nitric acid
solution will be 100 ionized. - Thus H NO3 0.0430 M.
- The pH - log 0.0430 1.37
22Practice 14
- Calculate the pH of a 0.020 M Ba(OH)2 (aq)
solution.
23Answer
- Since Ba(OH)2 is a strong base it is 100
ionized. Note that ionization gives 2 OH ions
for each mole of Ba(OH)2. - Thus OH 2 x 0.020 M 0.040 M
- pOH -log0.040 1.40
- pH 14 1.40 12.60
24Practice 15
- Calculate the pH of a 0.250 M HC2H3O2 solution.
Ka(HC2H3O2) 1.8 x 10-5.
25 Answer
Balanced Equation HC2H3O2 H C2H3O2
Initial Concentration (M) 0.250 0 0
Change (M) - x x x
Equilibrium Concentration (M) 0.250 - x x x
Answer
(a)
Thus x2 4.5 x 10-6 x 2.12 x 10-3 H. pH
2.67.
26Practice 16
- Calculate the pH of a 0.600 M solution of
methylamine CH3NH2. Kb 4.4 x 104.
27 Answer
Answer Since CH3NH2 is a weak base, the balanced
equation for the reaction is CH3NH2 H2O
CH3NH3 OH.
Balanced Equation CH3NH2 H2O CH3NH3 OH
Initial Concentration (M) 0.600 ___ 0 0 0
Change (M) - x ___ x x x
Equilibrium Concentration (M) 0.600 - x ___ x x x
Thus x 1.62 x 10-2 OH, and pOH 1.79. The
pH 12.21.
28Practice 17
- The pH of a 0.10 M solution of a weak base is
9.67. What is the Kb of the base?
29 Answer
Answer The balanced equation for a weak base B
is given in Eq(10). The equilibrium table
required is given below.
Balanced Equation B H2O BH OH
Initial Concentration (M) 0.10 ___ 0 0 0
Change (M) - x ___ x x x
Equilibrium Concentration (M) 0.10 - x ___ x x x
At equilibrium, OH BH x. Use the pH to
calculate the OH at equilibrium (which is the
value of x). Here pOH 14.00 pH 14.00
9.67 4.33. Thus
30Practice 18
- Use the following acidity constants to help
answer the questions below - Ka(HC2H3O2) 1.8 x 10 5
- Ka(HCN) 4.9 x 1010
- Ka(HCOOH) 1.7 x 10-4
- Which of the three acids is the weakest?
- Which of the following bases is the strongest
C2H3O2-, CN- , or HCOO- ? - What is the pKa of HCN?
- What is the Kb for CN- ?
31Answer
- (1) smallest k value HCN
- (2) strong base weakest acid lowest k value
HCN (acid) CN- (base) - (3) pKa -log Ka -log (4.9x10-10) 9.31
- (4) Ka x Kb 1x10-14
- kb 1x10-14 2.0 x 10-5
- 4.9x10-10
3219.) Predict whether an aqueous solution would be
acidic, basic or neutral?
- 1.sodium nitrate
- 2.ammonium iodide
- 3.sodium bicarbonate
- 4.ammonium cyanide
- 5.sodium hypochlorite
- 6.potassium acetate
33Predict whether an aqueous solution would be
acidic, basic or neutral? ANSWERS
- 1.sodium nitrate NaNO3 neutral
- 2.ammonium iodide NH4I acidic
- 3.sodium bicarbonate NaHCO3 basic
- 4.ammonium cyanide NH4CN basic (Kb ?)
- kb (for NH3) vs. Ka (for HCN)
- 1.8x10-5 vs. 4.9x10-10
- 5.sodium hypochlorite NaClO basic
- 6.potassium acetate KC2H3O2 basic
34Practice 20 (from ch. 15 study questions)
- Suppose that 0.50 moles of hydrogen gas, 0.50
moles of iodine gas, and 0.75 moles of hydrogen
iodide gas are introduced into a 2.0 Liter vessel
and the system is allowed to reach equilibrium. - H2(g) I2(g) ? 2 HI(g)
- Calculate the concentrations of all three
substances at equilibrium. At the temperature of
the experiment, Kc equals 2.0 x 10-2.
35Practice 21 (from ch. 15 study questions)
- Nitrosyl chloride NOCl decomposes to nitric oxide
and chlorine when heated - 2 NOCl(g) ? 2 NO(g) Cl2(g)
- At 600K, the equilibrium constant Kp is 0.060.
In a vessel at 600K, there is a mixture of all
three gases. The partial pressure of NOCl is 675
torr, the partial pressure of NO is 43 torr and
the partial pressure of chlorine is 23 torr. - a. What is the value of the reaction quotient?
- b. Is the mixture at equilibrium?
- c. In which direction will the system move to
reach equilibrium? - d. When the system reaches equilibrium, what will
be the partial pressures of the components in
the system? (just set up the problem, do not
solve all the way!!)