Informal Geometry Period 1 - PowerPoint PPT Presentation

About This Presentation
Title:

Informal Geometry Period 1

Description:

The following table shows the number of people that like a particular fast food restaurant. What is the probability that a person likes Wendy s? – PowerPoint PPT presentation

Number of Views:43
Avg rating:3.0/5.0
Slides: 21
Provided by: CobbCoun308
Category:

less

Transcript and Presenter's Notes

Title: Informal Geometry Period 1


1
Warm-up
  • The following table shows the number of people
    that like a particular fast food restaurant.
  • What is the probability that a person likes
    Wendys?
  • What is the probability that a person likes
    McDonalds or Burger King?
  • 3. What is the probability that a randomly chosen
    person is female or likes McDonalds?

McDonalds Burger King Wendys
Male 20 15 10
Female 20 10 25
7/20
65/100 13/20
3/4
2
Math I
UNIT QUESTION How do you use probability to make
plans and predict for the future? Standard
MM1D1-3 Todays Question When do I add or
multiply when solving compound probabilities? Stan
dard MM1D2.a,b.
3
Probability
  • Conditional Probability and Independent vs.
    Dependent events

4
Conditional Probability
  • A conditional probability is the probability of
    an event occurring, given that another event has
    already occurred. The conditional probability of
    event B occurring, given that event A has
    occurred, is denoted by P(B/A) and is read as
    probability of B, given A.
  • This is an and question, and solved by
    multiplication

5
Conditional Probability
  • Two cards are selected in sequence from a
    standard deck. Find the probability that the
    second card is a queen, given that the first card
    is a king, and we did not replace the king.
  • Because the first card is a king and is not
    replaced, the remaining deck has 51 cards, 4 of
    which are queens, so P(B/A) 4/51 ? 0.0078

6
Conditional Probability
Gene Present Gene Not Present Total
High IQ 33 19 52
Normal IQ 39 11 50
Total 72 30 102
  • The above table shows the results of a study in
    which researchers examined a childs IQ and the
    presence of a specific gene in the child. Find
    the probability that a child has a high IQ, given
    that the child has the gene.

7
Conditional Probability
Gene Present Gene Not Present Total
High IQ 33 19 52
Normal IQ 39 11 50
Total 72 30 102
  • There are 72 children who have the gene so the
    sample space consists of these 72 children. Of
    these, 33 have a high IQ, so
  • P(B/A) 33/72 ? 0.458

8
Conditional Probability
Gene Present Gene Not Present Total
High IQ 33 19 52
Normal IQ 39 11 50
Total 72 30 102
  • Find the probability that a child does not have
    the gene.
  • P(child does not have the gene) 30/102
  • Find the probability that a child does not have
    the gene, given that the child has a normal IQ
  • P(B/A) 11/50

9
Blood Type Blood Type Blood Type Blood Type Blood Type
O A B AB Total
RH Factor Positive 156 139 37 12 344
RH Factor Negative 28 25 8 4 65
Total 184 164 45 16 409
  • What is the probability of the blood being type B
    given it is positive?
  • 37/344
  • What is the probability of the blood being type
    RH Positive, given it is B or AB?
  • (37 12)/(45 16) 49/61

10
Independent Events
  • Two events A and B, are independent if the fact
    that A occurs does not affect the probability of
    B occurring.
  • Then P(B/A) P(B)
  • Examples - Landing on heads from two different
    coins, rolling a 4 on a die, then rolling a 3 on
    a second roll of the die.
  • Probability of A and B occurring
  • P(A and B)P(A)P(B)

11
Probability
  • NOTE
  • You add something to get the probability of
    something OR something
  • You multiply something to get the probability of
    something AND something.

12
Experiment 1
  • A coin is tossed and a 6-sided die is rolled.
    Find the probability of landing on the head side
    of the coin and rolling a 3 on the die.
  • P (head)1/2
  • P(3)1/6
  • P (head and 3)P (head)P(3)
  • 1/2 1/6
  • 1/12

13
Experiment 2
  • A card is chosen at random from a deck of 52
    cards. It is then replaced and a second card is
    chosen. What is the probability of choosing a
    jack and an eight?
  • P (jack) 4/52
  • P (8) 4/52
  • P (jack and 8) 4/52 4/52
  • 1/169

14
Experiment 3
  • A jar contains three red, five green, two blue
    and six yellow marbles. A marble is chosen at
    random from the jar. After replacing it, a second
    marble is chosen. What is the probability of
    choosing a green and a yellow marble?
  • P (green) 5/16
  • P (yellow) 6/16
  • P (green and yellow) P (green) x P (yellow)
  • 15 / 128

15
Experiment 4
  • A school survey found that 9 out of 10 students
    like pizza. If three students are chosen at
    random with replacement, what is the probability
    that all three students like pizza?
  • P (student 1 likes pizza) 9/10
  • P (student 2 likes pizza) 9/10
  • P (student 3 likes pizza) 9/10
  • P (student 1 and student 2 and student 3 like
    pizza) 9/10 x 9/10 x 9/10 729/1000

16
Dependent Events
  • Two events A and B, are dependent if the fact
    that A occurs affects the probability of B
    occurring.
  • Examples- Picking a blue marble and then picking
    another blue marble if I dont replace the first
    one.
  • Probability of A and B occurring
  • P(A and B)P(A)P(B/A)

17
Experiment 1
  • A jar contains three red, five green, two blue
    and six yellow marbles. A marble is chosen at
    random from the jar. A second marble is chosen
    without replacing the first one. What is the
    probability of choosing a green and a yellow
    marble?
  • P (green) 5/16
  • P (yellow given green) 6/15
  • P (green and then yellow) P (green) x P
    (yellow)
  • 1/8

18
Experiment 2
  • An aquarium contains 6 male goldfish and 4 female
    goldfish. You randomly select a fish from the
    tank, do not replace it, and then randomly select
    a second fish. What is the probability that both
    fish are male?
  • P (male) 6/10
  • P (male given 1st male) 5/9
  • P (male and then, male) 1/3

19
Experiment 3
  • A random sample of parts coming off a machine is
    done by an inspector. He found that 5 out of 100
    parts are bad on average. If he were to do a new
    sample, what is the probability that he picks a
    bad part and then, picks another bad part if he
    doesnt replace the first?
  • P (bad) 5/100
  • P (bad given 1st bad) 4/99
  • P (bad and then, bad) 1/495

20
Class Work
  • Pg 353, 5 8 all and
  • Handout 5-40 and 5-73 through 5-88
Write a Comment
User Comments (0)
About PowerShow.com