More Functions and Sets - PowerPoint PPT Presentation

About This Presentation
Title:

More Functions and Sets

Description:

More Functions and Sets Rosen 1.8 Inverse Image Let f be an invertible function from set A to set B. Let S be a subset of B. We define the inverse image of S to be ... – PowerPoint PPT presentation

Number of Views:58
Avg rating:3.0/5.0
Slides: 15
Provided by: Larr1169
Category:
Tags: functions | more | sets

less

Transcript and Presenter's Notes

Title: More Functions and Sets


1
More Functions and Sets
  • Rosen 1.8

2
Inverse Image
  • Let f be an invertible function from set A to set
    B. Let S be a subset of B. We define the
    inverse image of S to be the subset of A
    containing all pre-images of all elements of S.
  • f-1(S) a?A f(a) ?S

3
Let f be an invertible function from A to B. Let
S be a subset of B. Show that f-1(S) f-1(S)
  • What do we know?
  • f must be 1-to-1 and onto

4
Let f be an invertible function from A to B. Let
S be a subset of B. Show that f-1(S) f-1(S)
  • Proof We must show that f-1(S) ? f-1(S) and
    that f-1(S) ? f-1(S) .
  • Let x ? f-1(S). Then x?A and f(x) ? S. Since
    f(x) ? S, x ? f-1(S). Therefore x ? f-1(S).
  • Now let x ? f-1(S). Then x ? f-1(S) which
    implies that f(x) ? S. Therefore f(x) ? S and x
    ? f-1(S)

5
Let f be an invertible function from A to B. Let
S be a subset of B. Show that f-1(S) f-1(S)
  • Proof
  • f-1(S) x?A f(x) ? S Set builder notation
  • x?A f(x) ? S Def of Complement
  • f-1(S) Def of Complement

6
Floor and Ceiling Functions
  • The floor function assigns to the real number x
    the largest integer that is less than or equal to
    x. ?x?
  • ?x? n iff n ? x lt n1, n?Z
  • ?x? n iff x-1 lt n ? x, n?Z
  • The ceiling function assigns to the real number x
    the smallest integer that is greater than or
    equal to x. ?x?
  • ?x? n iff n-1 lt x ? n, n?Z
  • ?x? n iff x ? n lt x1, n?Z

7
Examples
  • ?0.5? 1
  • ?0.5? 0
  • ?-0.3? 0
  • ?-0.3? -1
  • ?6? 6
  • ?6? 6
  • ?-3.4? -3
  • ?3.9? 3

8
Prove that ?xm? ?x? m when m is an integer.
  • Proof Assume that ?x? n, n?Z.
  • Therefore n ? x lt n1.
  • Next we add m to each term in the inequality to
    get nm ? xm lt nm1.
  • Therefore ?xm? nm ?x? m

?x? n iff n ? x lt n1, n?Z
9
Let x?R. Show that ?2x? ?x? ?x1/2?
  • Proof Let n?Z such that ?x? n. Therefore
  • n ? x lt n1. We will look at the two cases
  • x ? n 1/2 and x lt n 1/2.
  • Case 1 x ? n 1/2
  • Then 2n1 ? 2x lt 2n2, so ?2x? 2n1
  • Also n1 ? x 1/2 lt n2, so ?x 1/2 ? n1
  • ?2x? 2n1 n n1 ?x? ?x1/2?

10
Let x?R. Show that ?2x? ?x? ?x1/2?
  • Case 2 x lt n 1/2
  • Then 2n ? 2x lt 2n1, so ?2x? 2n
  • Also n ? x 1/2 lt n1, so ?x 1/2 ? n
  • ?2x? 2n n n ?x? ?x1/2?

11
Characteristic Function
  • Let S be a subset of a universal set U. The
    characteristic function fS of S is the function
    from U to 0,1such that fS(x) 1 if x?S and
    fS(x) 0 if x?S.
  • Example Let U Z and S 2,4,6,8.
  • fS(4) 1
  • fS(10) 0

12
Let A and B be sets. Show that for all x,
fA?B(x) fA(x)fB(x)
  • Proof fA?B(x) must equal either 0 or 1.
  • Suppose that fA?B(x) 1. Then x must be in the
    intersection of A and B. Since x? A?B, then x?A
    and x?B. Since x?A, fA(x)1 and since x?B fB(x)
    1. Therefore fA?B fA(x)fB(x) 1.
  • If fA?B(x) 0. Then x ? A?B. Since x is not in
    the intersection of A and B, either x?A or x?B or
    x is not in either A or B. If x?A, then fA(x)0.
    If x?B, then fB(x) 0. In either case fA?B
    fA(x)fB(x) 0.

13
Let A and B be sets. Show that for all x,
fA?B(x) fA(x) fB(x) - fA(x)fB(x)
  • Proof fA?B(x) must equal either 0 or 1.
  • Suppose that fA?B(x) 1. Then x?A or x?B or x is
    in both A and B. If x is in one set but not the
    other, then fA(x) fB(x) - fA(x)fB(x)
    10(1)(0) 1. If x is in both A and B, then
    fA(x) fB(x) - fA(x)fB(x) 11 (1)(1) 1.
  • If fA?B(x) 0. Then x?A and x?B. Then fA(x)
    fB(x) - fA(x)fB(x) 0 0 (0)(0) 0.

14
Let A and B be sets. Show that for all x,
fA?B(x) fA(x) fB(x) - fA(x)fB(x)
  • A B A?B fA?B(x) fA(x) fB(x) - fA(x)fB(x)
  • 1 1 1 1 11-(1)(1) 1
  • 1 0 1 1 10-(1)(0) 1
  • 0 1 1 1 01-(0)(1) 1
  • 0 0 0 0 0)-(0)(0) 0
Write a Comment
User Comments (0)
About PowerShow.com