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A.P. Physics B

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A.P. Physics B 6.5 # s 2-4 By: Anna Findley 6.5 # 2 2. [CJ5 6.P.036.] A 47.0 g golf ball is driven from the tee with an initial speed of 52.0 m/s and rises to a ... – PowerPoint PPT presentation

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Title: A.P. Physics B


1
A.P. Physics B
  • 6.5 s 2-4
  • By Anna Findley

2
6.5 2
  • 2. CJ5 6.P.036. A 47.0 g golf ball is driven
    from the tee with an initial speed of 52.0 m/s
    and rises to a height of 24.6 m.
  • (a) Neglect air resistance and determine the
    kinetic energy of the ball at its highest point.
  • (b) What is its speed when it is 8.0 m below its
    highest point?

3
Solution Part A
  • (a) Neglect air resistance and determine the
    kinetic energy of the ball at its highest point.
  • KE mgh½ mv2
  • KE (.047kg) (9.8) (24.6m) ½ (.047kg)
    (52.0m/s) 2
  • KE 52.2 J

4
Solution Part B
  • (b) What is its speed when it is 8.0 m below its
    highest point?
  • KE mgh ½mv2 mg (h-8.0)
  • (52.2J) (.047kg) (9.8) (24.6m) ½(.047kg) v 2
    (.047kg) (9.8) (16.6m)
  • V 48.77m/s

5
6.5 3
  • 3. CJ5 6.P.037. A cyclist approaches the bottom
    of a gradual hill at a speed of 11 m/s. The hill
    is 5.0 m high, and the cyclist estimates that she
    is going fast enough to coast up and over it
    without peddling. Ignoring air resistance and
    friction, find the speed at which the cyclist
    crests the hill.

6
Solution 3
  • KE PE KE PE
  • ½ mv2 mgh ½ mv2 mg
  • (½)(112) 0 (½)(v2) (9.8)(5)
  • V 4.8 m/s
  • Remember mass cancels out...

7
6.5 4
  • 4. CJ5 6.P.041. A water slide is constructed
    so that swimmers, starting from rest at the top
    of the slide, leave the end of the slide
    traveling horizontally. As the drawing shows, one
    person hits the water 5.00 m from the end of the
    slide in a time of 0.500 s after leaving the
    slide. Ignoring friction and air resistance, find
    the height H in the drawing.

8
Solution 4
  • Vx d/t
  • Vx (5.00m) / (0.500s)
  • Vx 10.0 m/s
  • Vfy Viy at
  • Vfy 0 (9.8) (0.500s)
  • Vfy (4.9m/s)

9
Solution 4 Continued
  • Use the Pythagorean Theorem to find Vf
  • Vx2 Vfy2 vf2
  • Vf 11.14
  • Vf2 2ad
  • 11.142 2 (9.8) d
  • D 6.33
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