Title: Tuesday, Sept. 24th:
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3Tuesday, Sept. 24th A DayWednesday, Sept.
25th B DayAgenda
- Ch. 8 Tests
- Begin Ch. 9 Stoichiometry
- Start Sec 9.1 Calculating Quantities in
Reactions - Stoichiometry, mole ratios
- Moles Moles
- Moles Mass
- In-Class
- Worksheet pg. 14-15 (moles moles)
- Mass to Mass Stoichiometry worksheet
- You MUST show work for credit!
4Ch. 8 TestChemical Equations and Reactions
Class Average Score (out of 60) Average Percentage
3A 53.09 88.48
4B 51.23 85.38
5Balanced Equations Show Proportions
- The proportions of the ingredients in a muffin
recipe let you adjust the amounts to make enough
muffins even if you dont have balanced amounts
initially. - A balanced chemical equation is very similar to a
recipe in that the coefficients in the balanced
equation show the proportions of the reactants
and products. - Consider the reaction for the synthesis of water
6Balanced Equations Show Proportions
- 2 H2 O2 2 H2O
- The coefficients show that two molecules of
hydrogen react with one molecule of oxygen and
form two molecules of water. - Calculations that involve chemical reactions use
the proportions from balanced chemical equations
to find the quantity of each reactant and product
involved.
7Relative Amounts in Equations can be Expressed in
Moles
- The coefficients in a balanced equation also
represent the moles of each substance. - For example, the equation below shows that
- 2 mol C8H18 react with 25 mol O2 to form
- 16 mol CO2 and 18 mol H2O.
- 2 C8H18 25 O2 ? 16 CO2 18 H2O
8Relative Amounts in Equations can be Expressed in
Moles
- You can determine how much of a reactant is
needed to produce a given quantity of product, or
how much of a product is formed from a given
quantity of reactant. - The branch of chemistry that deals with
quantities of substances in chemical reactions is
known as stoichiometry. - Stoichiometry the proportional relationship
between two or more substances during - a chemical reaction.
9The Mole Ratio is the Key
- The coefficients in a balanced chemical equation
show the relative numbers of moles of the
substances in the reaction. - As a result, you can use the coefficients in
conversion factors called mole ratios. - Mole ratios bridge the gap and can convert from
moles of one substance to - moles of another.
10The Mole Ratio is the Key!
- The mole ratio is..
- THE SECRET MAGIC STEP!!
- when solving stoichiometry problems.
11All stoichiometry problems can be solved by
following these 3 steps
- Change the units of what you know into moles.
- Use the mole ratio (secret magic step) to convert
moles of the substance you were given into moles
of the substance you want. - Change out of moles into the unit that you need
for your final answer. - Thats all there is to it!
12Sample Problem A, pg. 304
- Consider the Haber process for the commercial
preparation of ammonia, NH3 - N2 3 H2 2 NH3
- Question How many moles of hydrogen, H2, are
needed to prepare 312 moles of ammonia, NH3? - Start with what you know 312 moles NH3
- Use the secret magic step to convert moles of
NH3 into moles of what you want, H2. - 312 mol NH3 X 3 mol H2
- 2 mol NH3
- 468 mol H2
13Practice 1, pg. 304
- Calculate the amounts requested if 1.34 mol H2O2
completely react according to the following
equation 2 H2O2 2 H2O O2 - Moles of oxygen formed
- 1.34 mol H2O2 X 1 mol O2 0.670 mol O2
- 2 mole H2O2
- b. Moles of water formed
- 1.34 mol H2O2 X 2 mol H2O 1.34 mol H2O
- 2 mol H2O2
14Practice 2, pg. 304
- Calculate the amounts requested if 3.30 mol Fe2O3
completely react according to the following
equation - Fe2O3 2 Al 2 Fe Al2O3
- a) Moles of aluminum needed
- 6.60 mol Al
- b) Moles of iron formed
- 6.60 mol Fe
- c) Mole of aluminum oxide formed
- 3.30 mol Al2O3
15Problems Involving Mass, Volume, or Particles
- Substances are usually measured by mass or
volume. (Can you go to the balance and measure
out 5 moles of NaCl?) - As a result, before using the mole ratio
- (Secret Magic Step) you will need to convert
units for mass and volume into moles.
16Mass Moles
- The conversion factor for converting between mass
and moles is simply the molar mass of the
substance. - You do remember molar mass, dont you?.....
17Molar Mass Review
- What is the molar mass of table salt, NaCl?
- Na 22.99 g/mol
- Cl 35.45 g/mol
- 58.44 g/mol
- What is the molar mass of sulfuric acid, H2SO4?
- H 2 (1.01 g/mol) 2.02 g/mol
- S 32.07 g/mol
- O 4 (16.00 g/mol) 64.00 g/mol
- 98.09 g/mol
- OK, I feel better now that you guys remember this
stuff. Lets try a sample problem
18Remember the 3 steps
- Change the units of what you know into moles.
- Use the mole ratio (secret magic step) to convert
moles of the substance you were given into moles
of the substance you want. - Change out of moles into the unit that you need
for your final answer. -
19Sample Problem B, pg. 307
- What mass of NH3 can be made from 1,221 g H2 and
excess N2? N2 3 H2 2 NH3 - Remember, hydrogen is a diatomic element
- Start with what you know 1,221 g H2
- Convert to moles using molar mass
- 1,221 g H2 X 1 mol H2 604.5 mol H2
- 2.02 g H2
- 3. Use mole ratio to convert moles H2
moles NH3 - 604.5 mol H2 X 2 mol NH3 403.0 mol NH3
- 3 mol H2
20Sample Problem B cont
- Finally, use the molar mass to change moles of
NH3 into grams of NH3 - 403.0 mol NH3 X 17.04 g NH3 6,867 g NH3
- 1 mol NH3
- Thats ityou did it!
21Practice 1, pg. 307
- Use the equation below to answer the questions
that follow - Fe2O3 2Al 2Fe Al2O3
- How many grams of Al are needed to completely
react with 135 g Fe2O3? - How many grams of Al2O3 can form when 23.6 g Al
react with excess Fe2O3? - How many grams of Fe2O3 react with excess Al to
make 475 g Fe? - How many grams of Fe will form when 97.6 g Al2O3
form?
22Update your graphic organizer
- What do you use to change from
- Moles Moles
- Mole Ratio
- Secret Magic Step
- What do you use to change from
- Moles Mass
- Molar Mass
- (g/mol)
23In-Class/Homework Assignment
- Worksheet pg. 14-15 (moles moles)
- Mass to Mass Stoichiometry worksheet
- We will finish section 9.1 next time.
- You must SHOW ALL WORK on these worksheets for
credit