Tuesday, Sept. 24th: - PowerPoint PPT Presentation

1 / 23
About This Presentation
Title:

Tuesday, Sept. 24th:

Description:

Slide 1 – PowerPoint PPT presentation

Number of Views:62
Avg rating:3.0/5.0
Slides: 24
Provided by: ShariDE
Category:

less

Transcript and Presenter's Notes

Title: Tuesday, Sept. 24th:


1
(No Transcript)
2
(No Transcript)
3
Tuesday, Sept. 24th A DayWednesday, Sept.
25th B DayAgenda
  • Ch. 8 Tests
  • Begin Ch. 9 Stoichiometry
  • Start Sec 9.1 Calculating Quantities in
    Reactions
  • Stoichiometry, mole ratios
  • Moles Moles
  • Moles Mass
  • In-Class
  • Worksheet pg. 14-15 (moles moles)
  • Mass to Mass Stoichiometry worksheet
  • You MUST show work for credit!

4
Ch. 8 TestChemical Equations and Reactions
Class Average Score (out of 60) Average Percentage
3A 53.09 88.48
4B 51.23 85.38
5
Balanced Equations Show Proportions
  • The proportions of the ingredients in a muffin
    recipe let you adjust the amounts to make enough
    muffins even if you dont have balanced amounts
    initially.
  • A balanced chemical equation is very similar to a
    recipe in that the coefficients in the balanced
    equation show the proportions of the reactants
    and products.
  • Consider the reaction for the synthesis of water

6
Balanced Equations Show Proportions
  • 2 H2 O2 2 H2O
  • The coefficients show that two molecules of
    hydrogen react with one molecule of oxygen and
    form two molecules of water.
  • Calculations that involve chemical reactions use
    the proportions from balanced chemical equations
    to find the quantity of each reactant and product
    involved.

7
Relative Amounts in Equations can be Expressed in
Moles
  • The coefficients in a balanced equation also
    represent the moles of each substance.
  • For example, the equation below shows that
  • 2 mol C8H18 react with 25 mol O2 to form
  • 16 mol CO2 and 18 mol H2O.
  • 2 C8H18 25 O2 ? 16 CO2 18 H2O

8
Relative Amounts in Equations can be Expressed in
Moles
  • You can determine how much of a reactant is
    needed to produce a given quantity of product, or
    how much of a product is formed from a given
    quantity of reactant.
  • The branch of chemistry that deals with
    quantities of substances in chemical reactions is
    known as stoichiometry.
  • Stoichiometry the proportional relationship
    between two or more substances during
  • a chemical reaction.

9
The Mole Ratio is the Key
  • The coefficients in a balanced chemical equation
    show the relative numbers of moles of the
    substances in the reaction.
  • As a result, you can use the coefficients in
    conversion factors called mole ratios.
  • Mole ratios bridge the gap and can convert from
    moles of one substance to
  • moles of another.

10
The Mole Ratio is the Key!
  • The mole ratio is..
  • THE SECRET MAGIC STEP!!
  • when solving stoichiometry problems.

11
All stoichiometry problems can be solved by
following these 3 steps
  • Change the units of what you know into moles.
  • Use the mole ratio (secret magic step) to convert
    moles of the substance you were given into moles
    of the substance you want.
  • Change out of moles into the unit that you need
    for your final answer.
  • Thats all there is to it!

12
Sample Problem A, pg. 304
  • Consider the Haber process for the commercial
    preparation of ammonia, NH3
  • N2 3 H2 2 NH3
  • Question How many moles of hydrogen, H2, are
    needed to prepare 312 moles of ammonia, NH3?
  • Start with what you know 312 moles NH3
  • Use the secret magic step to convert moles of
    NH3 into moles of what you want, H2.
  • 312 mol NH3 X 3 mol H2
  • 2 mol NH3
  • 468 mol H2

13
Practice 1, pg. 304
  • Calculate the amounts requested if 1.34 mol H2O2
    completely react according to the following
    equation 2 H2O2 2 H2O O2
  • Moles of oxygen formed
  • 1.34 mol H2O2 X 1 mol O2 0.670 mol O2
  • 2 mole H2O2
  • b. Moles of water formed
  • 1.34 mol H2O2 X 2 mol H2O 1.34 mol H2O
  • 2 mol H2O2

14
Practice 2, pg. 304
  • Calculate the amounts requested if 3.30 mol Fe2O3
    completely react according to the following
    equation
  • Fe2O3 2 Al 2 Fe Al2O3
  • a) Moles of aluminum needed
  • 6.60 mol Al
  • b) Moles of iron formed
  • 6.60 mol Fe
  • c) Mole of aluminum oxide formed
  • 3.30 mol Al2O3

15
Problems Involving Mass, Volume, or Particles
  • Substances are usually measured by mass or
    volume. (Can you go to the balance and measure
    out 5 moles of NaCl?)
  • As a result, before using the mole ratio
  • (Secret Magic Step) you will need to convert
    units for mass and volume into moles.

16
Mass Moles
  • The conversion factor for converting between mass
    and moles is simply the molar mass of the
    substance.
  • You do remember molar mass, dont you?.....

17
Molar Mass Review
  • What is the molar mass of table salt, NaCl?
  • Na 22.99 g/mol
  • Cl 35.45 g/mol
  • 58.44 g/mol
  • What is the molar mass of sulfuric acid, H2SO4?
  • H 2 (1.01 g/mol) 2.02 g/mol
  • S 32.07 g/mol
  • O 4 (16.00 g/mol) 64.00 g/mol
  • 98.09 g/mol
  • OK, I feel better now that you guys remember this
    stuff. Lets try a sample problem

18
Remember the 3 steps
  • Change the units of what you know into moles.
  • Use the mole ratio (secret magic step) to convert
    moles of the substance you were given into moles
    of the substance you want.
  • Change out of moles into the unit that you need
    for your final answer.

19
Sample Problem B, pg. 307
  • What mass of NH3 can be made from 1,221 g H2 and
    excess N2? N2 3 H2 2 NH3
  • Remember, hydrogen is a diatomic element
  • Start with what you know 1,221 g H2
  • Convert to moles using molar mass
  • 1,221 g H2 X 1 mol H2 604.5 mol H2
  • 2.02 g H2
  • 3. Use mole ratio to convert moles H2
    moles NH3
  • 604.5 mol H2 X 2 mol NH3 403.0 mol NH3
  • 3 mol H2

20
Sample Problem B cont
  • Finally, use the molar mass to change moles of
    NH3 into grams of NH3
  • 403.0 mol NH3 X 17.04 g NH3 6,867 g NH3
  • 1 mol NH3
  • Thats ityou did it!

21
Practice 1, pg. 307
  • Use the equation below to answer the questions
    that follow
  • Fe2O3 2Al 2Fe Al2O3
  • How many grams of Al are needed to completely
    react with 135 g Fe2O3?
  • How many grams of Al2O3 can form when 23.6 g Al
    react with excess Fe2O3?
  • How many grams of Fe2O3 react with excess Al to
    make 475 g Fe?
  • How many grams of Fe will form when 97.6 g Al2O3
    form?

22
Update your graphic organizer
  • What do you use to change from
  • Moles Moles
  • Mole Ratio
  • Secret Magic Step
  • What do you use to change from
  • Moles Mass
  • Molar Mass
  • (g/mol)

23
In-Class/Homework Assignment
  • Worksheet pg. 14-15 (moles moles)
  • Mass to Mass Stoichiometry worksheet
  • We will finish section 9.1 next time.
  • You must SHOW ALL WORK on these worksheets for
    credit
Write a Comment
User Comments (0)
About PowerShow.com