Title: Compound
1Compound
Inequalities
2You already know inequalities.
Often they are used to place
limits on variables.
That just means x can be any number equal to 9 or
less than 9.
3Sometimes we put more than one limit on the
variable
Now x is still less than or equal to 9, but it
must also be
greater than or equal to 7.
4Lets look at the graph
The upper limit is 9. Because x can be
equal to 9, we mark it with a filled-in
circle.
5The lower limit is -7. We also need to mark it
with a filled-in circle.
6There are other numbers that satisfy both
conditions.
Where are they found on the
graph?
What about 15?
It is less than or equal to 9?
Yes!
7Where are they found on the
graph?
What about 15?
It is also greater than or
equal to -7?
No!
8Because the word and is used, a number
on the graph needs to satisfy both parts of the
inequality.
9So lets try 20. Does 20 satisfy both conditions?
Yes!
10So lets try 20. Does 20 satisfy both conditions?
No!
11Since 20 does not satisfy both
conditions, it cant belong to the
solution set.
12There is one region we have not checked.
13We need to choose a number from
that region.
You want to choose 0?
Good choice! 0 is usually the
easiest number to work with.
14Does 0 satisfy both conditions?
Yes!
15Does 0 satisfy both conditions?
Yes!
16If one number in a region completely satisfies an
inequality,
you can know that every number in
that region satisfies the inequality.
17Lets graph another inequality
18First we mark the boundary points
The first sign
tells us we want an open circle,
19and the 12 tells us where
the circle goes.
20and the 12 tells us where
the circle goes.
21The second sign
tells us we want a closed circle,
22and the -1 tells us where the
circle goes.
23The boundary points divide the line into
three regions
1
2
3
24We need to test one point
from each region.
No!
Yes!
25Notice that the word used is or,
instead of and.
No!
Yes!
26Or means that a number
only needs to meet one condition.
No!
Yes!
27Because 10 meets one condition,
the region to which it belongs . . .
. . . belongs to the graph.
Yes!
28Lets check the next region
No!
No!
29Because 1 meets neither condition,
the numbers in that region
will not satisfy the inequality.
30Now the final region
Yes!
No!
31Again, 15 meets one condition
so we need to shade that region.
Yes!
32A quick review
To graph a compound inequality
1. Find and mark the boundary
points.
2. Test points from each region.
3. Shade the regions that satisfy
the inequality.
?
?
?
33A quick review
1. Find and mark the boundary
points.
2. Test points from each region.
3. Shade the regions that satisfy
the inequality.
or
34Given the graph below, write the
inequality.
First, write the boundary points.
35Then look at the marks on the graph,
and write the correct symbol.
36Since x is between the boundary points on
the graph,
it will be between the boundary points in
the inequality.
37Since x is between the boundary points on
the graph,
it will be between the boundary points in
the inequality.
38Try this one
Again, begin by writing the boundary points
39And again, you need to choose the correct symbols
40Because the x-values are not between the
boundary points on the graph,
we wont write x between the boundary points in
the equation.
41Because the x-values are not between the
boundary points on the graph,
we wont write them between the boundary points
in the equation.
42We will use the word, or, instead
Remember that or means a
number has to satisfy only one of the
conditions.
43We will use the word, or, instead
Remember that or means a
number has to satisfy only one of the
conditions.
44Is there any one number that belongs
to both shaded sections in the
graph?
NO!
Say NO!
45So it would be incorrect to use and. And implies
that a number meets both conditions.
46Solving compound inequalities is easy if . . .
. . . you remember that a compound inequality is
just two inequalities put together.
47You can solve them both at the same time
48Write the inequality from the graph
1 Write boundaries
2 Write signs
3 Write variable
49Solve the inequality
Is this what you did?
50You did remember to reverse the signs . . .
. . . didnt you?
Good job!