Title: Daily Quiz
1Daily Quiz
2Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
3Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
1. Cr in a solution of Cr3 ions Cu in a
solution of Cu2 ions a. 0.5600 volts b. 0.7489
volts c. 0.8970 volts d. 1.0859 volts
4Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
2. zinc in a solution of Zn2 ions platinum in
a solution of Pt2 ions a. 0.4182
volts b. 0.7618 volts c. 1.1800
volts d. 1.9418 volts
5Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
3. HgCl2 and Hg2Cl2 lead in a solution of
Pb2 ions a. 0.031 volts b. 0.398
volts c. 1.000 volts d. 1.046 volts e. 1.977
volts
6Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
4. tin in a solution of Sn2 ions iodine in a
solution of I- ions a. 0.3845 volts b. 0.6730
volts c. 0.6865 volts d. 1.0050
volts e. 1.2935 volts
.
7Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
1. Cr in a solution of Cr3 ions Cu in a
solution of Cu2 ions a. 0.5600 volts b. 0.7489
volts c. 0.8970 volts d. 1.0859 volts
8Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
1. Cr in a solution of Cr3 ions Cu in a
solution of Cu2 ions Cr3 3e- ?
Cr -0.913 Cu2 2e- ? Cu 0.153
-(-0.913) 1.066 V
9Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
1. Cr in a solution of Cr3 ions Cu in a
solution of Cu2 ions Cr3 3e- ?
Cr -0.744 Cu2 2e- ? Cu 0.3419
-(-0.913) 1.066 V
10Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
1. Cr in a solution of Cr3 ions Cu in a
solution of Cu2 ions Cr3 3e- ?
Cr -0.744 Cu2 2e- ? Cu 0.3419
-(-0.744) 1.066 V
11Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
1. Cr in a solution of Cr3 ions Cu in a
solution of Cu2 ions Cr3 3e- ?
Cr -0.744 Cu2 2e- ? Cu 0.3419
-(-0.744) 1.0859 V
12Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
1. Cr in a solution of Cr3 ions Cu in a
solution of Cu2 ions a. 0.5600 volts b. 0.7489
volts c. 0.8970 volts d. 1.0859 volts
13Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
2. zinc in a solution of Zn2 ions platinum in
a solution of Pt2 ions a. 0.4182
volts b. 0.7618 volts c. 1.1800
volts d. 1.9418 volts
14Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
2. zinc in a solution of Zn2 ions platinum in
a solution of Pt2 ions Zn2 2e- ?
Zn -0.7618 Pt2 2e- ? Pt 1.18
-(-0.7618) 1.94 V
15Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
2. zinc in a solution of Zn2 ions platinum in
a solution of Pt2 ions Zn2 2e- ?
Zn -0.7618 Pt2 2e- ? Pt 1.18
-(-0.7618) 1.94 V
16Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
2. zinc in a solution of Zn2 ions platinum in
a solution of Pt2 ions Zn2 2e- ?
Zn -0.7618 Pt2 2e- ? Pt 1.18
-(-0.7618) 1.94 V
17Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
2. zinc in a solution of Zn2 ions platinum in
a solution of Pt2 ions Zn2 2e- ?
Zn -0.7618 Pt2 2e- ? Pt 1.18
-(-0.7618) 1.94 V
18Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
2. zinc in a solution of Zn2 ions platinum in
a solution of Pt2 ions a. 0.4182
volts b. 0.7618 volts c. 1.1800
volts d. 1.9418 volts
19Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
3. HgCl2 and Hg2Cl2 lead in a solution of
Pb2 ions a. 0.031 volts b. 0.398
volts c. 1.000 volts d. 1.046 volts e. 1.977
volts
20Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
3. HgCl2 and Hg2Cl2 lead in a solution of
Pb2 ions 2Hg2 2e- ? 2Hg22 0.920 Pb2 2e-
? Pb -(-0.1262) 1.046 V
21Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
3. HgCl2 and Hg2Cl2 lead in a solution of
Pb2 ions 2Hg2 2e- ? 2Hg22 0.920 Pb2 2e-
? Pb -(-0.1262) 1.046 V
22Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
3. HgCl2 and Hg2Cl2 lead in a solution of
Pb2 ions 2Hg2 2e- ? 2Hg22 0.920 Pb2 2e-
? Pb -(-0.1262) 1.046 V
23Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
3. HgCl2 and Hg2Cl2 lead in a solution of
Pb2 ions 2Hg2 2e- ? 2Hg22 0.920 Pb2 2e-
? Pb -(-0.1262) 1.046 V
24Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
3. HgCl2 and Hg2Cl2 lead in a solution of
Pb2 ions a. 0.031 volts b. 0.398
volts c. 1.000 volts d. 1.046 volts e. 1.977
volts
25Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
4. tin in a solution of Sn2 ions iodine in a
solution of I- ions a. 0.3845 volts b. 0.6730
volts c. 0.6865 volts d. 1.0050
volts e. 1.2935 volts
26Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
4. tin in a solution of Sn2 ions iodine in
a solution of I- ions Sn2 2e- ?
Sn -0.1375 I2 2e- ? 2I- 0.5355
-(-0.1375) 0.6730 V
27Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
4. tin in a solution of Sn2 ions iodine in
a solution of I- ions Sn2 2e- ?
Sn -0.1375 I2 2e- ? 2I- 0.5355
-(-0.1375) 0.6730 V
28Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
4. tin in a solution of Sn2 ions iodine in
a solution of I- ions Sn2 2e- ?
Sn -0.1375 I2 2e- ? 2I- 0.5355
-(-0.1375) 0.6730 V
29Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
4. tin in a solution of Sn2 ions iodine in
a solution of I- ions Sn2 2e- ?
Sn -0.1375 I2 2e- ? 2I- 0.5355
-(-0.1375) 0.6730 V
30Calculate the cell potential of voltaic cells
that contain the following pairs of half-cells
4. tin in a solution of Sn2 ions iodine in a
solution of I- ions a. 0.3845 volts b. 0.6730
volts c. 0.6865 volts d. 1.0050
volts e. 1.2935 volts
.