Title: Cryptography
1Cryptography
- Lecture 2Stefan Dziembowskiwww.dziembowski.net
- stefan_at_dziembowski.net
2Plan
- Information-theoretic cryptography
- Introduction to cryptography based on the
computational assumptions - Provable security
- Pseudorandom generators
3The scenario from the previous lecture
Alice
Bob
Eve
Shannons theorem ? perfect secrecy is
possible only if the key is as long as the
plaintext
In real-life it is completely impractical
4What to do?
- Idea limit the power of the adversary.
- How?
- Classical (computationally-secure) cryptography
- bound his computational power.
- Alternative options exists
- (but are not very practical)
5Quantum cryptography
- Stephen Wiesner (1970s), Charles H. Bennett and
Gilles Brassard (1984)
quantum link
Alice
Bob
Quantum indeterminacy quantum states cannot be
measured without disturbing the original state.
Hence Eve cannot read the bits in an
unnoticeable way.
Eve
6Quantum cryptography
- Advantage
- security is based on the laws of quantum physics
- Disadvantage
- needs a dedicated equipment.
- Practicality?
- Currently successful transmissions for distances
of length around 150 km. - Commercial products are available.
7A satellite scenario
A third party (a satellite) is broadcasting
random bits.
000110100111010010011010111001110111 1110100111010
10101010010010100111100 00100111111110001010100100
0101010010 001010010100101011010101001010010101
Alice
Bob
Eve
8Ueli Maurer (1993) noisy channel.
1 0 1 0 1 0 0 1 1 0 1 0 0 1 0
1 0 1 0 1 0 0 1 1 0 1 0 0 1 0
1 0 1 0 1 0 0 1 1 0 1 0 0 1 0
0 0 1 0 0 0 0 1 1 0 0 0 0 1 1
1 0 1 1 1 0 0 1 1 0 1 0 0 0 1
some bits get flipped (because of the noise)
1 0 1 0 1 0 0 1 1 0 1 0 0 1 0
1 0 1 1 1 0 0 1 1 0 1 0 0 0 0
Assumption the data that the adversary receives
is noisy. (The data that Alice and Bob receive
may be even more noisy.)
9Bounded-Storage Model
- Another idea bound the size of adversarys memory
000110100111010010011010111001110111 1110100111010
10101010010010100111100 00100111111110001010100100
0101010010 001010010100101011010101001010010101
too large to fit in Eves memory
10Real (computationally-secure) cryptography starts
here
Eve is computationally-bounded
- But what does it mean?
- Ideas
- She has can use at most 1000 Intel Core 2
Extreme X6800 Dual Core Processors for at most
100 years... - She can buy equipment worth 1 million euro and
use it for 30 years...
its hard to reasonformally about it
11A better idea
- The adversary has access to a Turing Machine
that can make at most 1030 steps. - More generally, we could have definitions of a
type - a system X is (t,e)-secure if every Turing
Machine - that operates in time t
- can break it with probability at most e.
- This would be quite precise, but...
- We would need to specify exactly what we mean by
a Turing Machine - how many tapes it has?
- how does it access these tapes (maybe a random
access memory is a more realistic model..) - ...
- Moreover, this approach often leads to ugly
formulas...
12What to do?
(t,e)-security
- Idea
- t steps of a Turing Machine efficient
computation - e a value very close to zero.
How to formalize it? Use the asymptotics!
13Efficiently computable?
polynomial-time computable on a Turing Machine
efficiently computable
that is running in time O(nc) (for some c)
Here we assume that the Turing Machines are the
right model for the real-life computation. Not
true if a quantum computer is built...
14Very small?
very small negligible approaches 0
faster than the inverse of any polynomial Formal
ly
15Negligible or not?
no
yes
yes
yes
yes
no
16Security parameter
Typically, we will say that a scheme X is secure
if
A
P (M breaks the scheme X) is negligible
polynomial-time Turing Machine M
- The terms negligible and polynomial make
sense only if X (and the adversary) take an
additional input n called - a security parameter.
- In other words we consider an infinite sequence
- X(1),X(2),...
- of schemes.
17Example
- Consider the authentication scheme from the last
week
18Nice properties of these notions
- A sum of two polynomials is a polynomial
- poly poly poly
- A product of two polynomials is a polynomial
- poly poly poly
- A sum of two negligible functions is a negligible
function - negl negl negl
- Moreover
- A negligible function multiplied by a polynomial
is negligible - negl poly negl
19A new definition of an encryption scheme
20Is this the right approach?
- Advantages
- All types of Turing Machines are equivalent up
to a polynomial reduction.Therefore we do
need to specify the details of the model. - The formulas get much simpler.
- Disadvantage
- Asymptotic results dont tell us anything about
security of the concrete systems. - However
- Usually one can prove formally an asymptotic
result and then argue informally that the
constants are reasonable - (and can be calculated if one really wants).
21Provable security
- We want to construct schemes that are
- provably secure.
- But...
- why do we want to do it?
- how to define it?
- and is it possible to achieve it?
22Provable security the motivation
- In many areas of computer science formal proofs
are not essential. - For example, instead of proving that an algorithm
is efficient, we can just simulate it on a - typical input.
- In cryptography its not true, because
- there cannot exist an experimental proof that a
scheme is secure. - Why?
- Because a notion of a
- typical adversary
- does not make sense.
23How did we define the perfect secrecy?
- Experiment (m a message)
- the key k is chosen randomly
- message m is encrypted using k c
Enck(m) - c is given to the adversary
Idea 1The adversary should not be able to
compute k.
Idea 2The adversary should not be able to
compute m.
Idea 3The adversary should not be able to
compute any information about m.
Idea 4 The adversary should not be able to
compute any additional information about m.
makes more sense
24Idea The adversary should not be able to compute
any additional information about m.
25Towards the definition of computational secrecy...
A
A
P(C c) P(C c Mm)
m
c
A
A
P(C c M m0) P(C c M m1)
m0,m1
c
A
A
P(Enc(K,M) c M m0) P(Enc(K,M) c M
m1)
m0,m1
c
A
A
P(Enc(K,m0) c M m0) P(Enc(K,m1) c M
m1)
m0,m1
c
A
A
P(Enc(K,m0) c) P(Enc(K,m1) c)
m0,m1
c
26Indistinguishability
A
A
- P(Enc(K,m0) c) P(Enc(K,m1) c)
m0,m1
c
In other words the distributions of Enc(K,m0)
Enc(K,m1) are identical
IDEA change it to are indistinguishable by a
polynomial time adversary
27A game
(Gen,Enc,Dec) an encryption scheme
security parameter 1n
adversary (polynomial-time Turing machine)
oracle
chooses m0,m1 such that m0m1
- selects k G(1n)
- chooses a random b 0,1
- calculates c Enc(k,mb)
has to guess b
Alternative name semantially-secure (sometimes
we will say is computationally-secure, if the
context is clear)
Security definition We say that (Gen,Enc,Dec)
has indistinguishable encryptions if any
polynomial time adversary guesses b correctly
with probability at most 0.5 e(n), where e is
negligible.
28Testing the definition
- Suppose the adversary can compute k from some
Enc(k,m). Can he win the game? - Suppose the adversary can compute some bit of m
from Enc(k,m). Can he win the game?
YES!
YES!
29Is it possible to prove security?
- (Gen,Enc,Dec) -- an encryption scheme.
- For simplicity suppose that
- for a security parameter n the key is of length
n. - Enc is deterministic
- Consider the following language
Q What if L is polynomial-time decidable?
A Then the scheme is broken (exercise)
Is it really true?
On the other hand L is in NP.
(k is the NP-witness)
So, if P NP, then any semantically-secure
encryption is broken.
30If PNP, then the semantically-secure encryption
is broken
- Is it 100 true?
- Not really...
- This is because even if PNP we do not know what
are the constants. - Maybe PNP in a very inefficient way...
31- In any case, to prove security of a cryptographic
scheme we would need to show - a lower bound on the computational complexity of
some problem. - In the asymptotic setting that would mean that
- at least
- we show that P ? NP.
- Does the implication in the other direction hold?
- (that is does P ? NP imply anything for
cryptography?) - No! (at least as far as we know)
- Intuitively because NP is a notion from the
worst case complexity, and cryptography
concerns the average case complexity. - Therefore
- proving that an encryption scheme is secure is
probably much harder than proving that P ? NP.
32What can we prove?
- We can prove conditional results.
- That is, we can show theorems of a type
Suppose that some computational assumption A
holds
Suppose that some scheme Y is secure
then scheme X is secure.
then scheme X is secure.
33Research program in cryptography
- Base the security of cryptographic schemes on a
small number of well-specified computational
assumptions.
Examples of A decisional Diffie-Hellman
assumption strong RSA assumption
in this we have to believe
Some computational assumption A holds
the rest is provable
then scheme X is secure.
34Example
- We are now going to show an example of such
reasoning
Suppose that some computational assumption A
holds
Suppose that G is a cryptographic pseudorandom
generator
then scheme X is secure.
we G can construct a secure encryption scheme
35Pseudorandom generators
G(s)
s
36- If we use a normal PRG this idea doesnt work
(exercise). - It works only with the cryptographic PRGs.
37Looks random
- What does it mean?
- Non-cryptographic applications
- should pass some statistical tests.
- Cryptography
- should pass all polynomial-time tests.
38Cryptographic PRG
outputs
0 if he thinks its R
1 if he thinks its G(S)
a polynomial-timedistinguisher D
Should not be able to distinguish...
39Constructions
- There exists constructions of cryptographic
pseudorandom-generators, that are conjectured to
be secure. - Some of them are extremely efficient, and widely
used in practice. - They are called the stream ciphers (we will
discuss them later).
40Theorem
- If G is a cryptographic PRG then the encryption
scheme constructed before is semantically-secure
(i.e. it has indistinguishable encryptions).
cryptographic PRGs
computationally-secure encryption
41simulates
X
- If the adversary guessed b correctly then output
1 x is pseudorandom. - Otherwise output 0 x is random.
42x is a random string R
x G(S)
the adversary guesses b correctly with
probability 0.5
the adversary guesses b correctly with
probability 0.5 d(n)
prob. 0.5 d(n)
prob.0.5 - d(n)
prob. 0.5
prob. 0.5
outputs
1
0
1
0
QED
43Moral
cryptographic PRGs
semantically-secure encryption
- To construct secure encryption it suffices to
construct a secure PRG.
44Outlook
Cryptography
- one time pad,
- quantum cryptography,
- the satellite scenario
- often called
- information-theoretic,
- unconditional
- computationally-secure
- based on 2 assumptions
- some problems are computationally difficult
- our understanding of what computational
difficulty means is correct.