Title: Welcome to Physics I !!!
1Physics I95.141LECTURE 1711/8/10
2Outline/Administrative Notes
- Notes
- HW Review Session on 11/17 shifted to 11/18.
- Last day to withdraw with a W is 11/12 (Friday)
- Outline
- Ballistic Pendulums
- 2D, 3D Collisions
- Center of Mass and translational motion
3Ballistic Pendulum
- A device used to measure the speed of a
projectile.
m
h
M
Mm
vo
v1
4Ballistic Pendulum
m
Mm
M
vo
v1
5Ballistic Pendulum
Mm
h
Mm
v1
6Exam Prep Problem
- You construct a ballistic pendulum out of a
rubber block (M5kg) attached to a horizontal
spring (k300N/m). You wish to determine the
muzzle velocity of a gun shooting a mass (m30g).
After the bullet is shot into the block, the
spring is observed to have a maximum compression
of 12cm. Assume the spring slides on a
frictionless surface. - A) (10pts) What is the velocity of the block
bullet immediately after the bullet is embedded
in the block? - B) (10pts) What is the velocity of the bullet
right before it collides with the block? - C) (5pts) If you shoot a 15g mass with the same
gun (same velocity), how far do you expect the
spring to compress?
7Exam Prep Problem
- k300N/m, m30g, M5kg, ?xmax12cm
- A) (10pts) What is the velocity of the block
bullet immediately after the bullet is embedded
in the block?
8Exam Prep Problem
- k300N/m, m30g, M5kg, ?xmax12cm
- B) (10pts) What is the velocity of the bullet
right before it collides with the block?
9Exam Prep Problem
- k300N/m, m30g, M5kg, ?xmax12cm
- C) (5pts) If you shoot a 15g mass with the same
gun (same velocity), how far do you expect the
spring to compress?
10Collisions
- In the previous lecture we discussed collisions
in 1D, and the role of Energy in collisions. - Momentum always conserved!
- If Kinetic Energy is conserved in a collision,
then we call this an elastic collision, and we
can write - Which simplifies to
- If Kinetic Energy is not conserved, the collision
is referred to as an inelastic collision. - If the two objects travel together after a
collision, this is known as a perfectly inelastic
collision.
11Collision Review
- Imagine I shoot a 10g projectile at 450m/s
towards a 10kg target at rest. - If the target is stainless steel, and the
collision is elastic, what are the final speeds
of the projectile and target?
12Collision Review
- Imagine I shoot a 10g projectile at 450m/s
towards a 10kg target at rest. - If the target is wood, and projectile embeds
itself in the target, what are the final speeds
of the projectile and target?
13Additional Dimensions
- Up until this point, we have only considered
collisions in one dimension. - In the real world, objects tend to exist (and
move) in more than one dimension! - Conservation of momentum holds for collisions in
1, 2 and 3 dimensions!
142D Momentum Conservation
- Imagine a projectile (mA) incident, along the
x-axis, upon a target (mB) at rest. After the
collision, the two objects go off at different
angles - Momentum is a vector, in order for momentum to be
conserved, all components (x,y,z) must be
conserved.
152D Momentum Conservation
- Imagine a projectile (mA) incident, along the
x-axis, upon a target (mB) at rest. After the
collision, the two objects go off at different
angles
16Conservation of Momentum (2D)
- Solving for conservation of momentum gives us 2
equations (one for x-momentum, one for
y-momentum). - We can solve these if we have two unknowns
- If the collision is elastic, then we can add a
third equation (conservation of kinetic energy),
and solve for 3 unknowns.
17Example problem
- A cue ball travelling at 4m/s strikes a billiard
ball at rest (of equal mass). After the
collision the cue ball travels forward at an
angle of 45º, and the billiard ball forward at
-45º. What are the final speeds of the two balls?
18Example Problem II
- Now imagine a collision between two masses
(mA1kg and mB2kg) travelling at vA2m/s and vB
-2m/s along the x-axis. If mA bounces back at an
angle of -30º, what are the final velocities of
each ball?
19Example Problem II
- Now imagine a collision between two masses
(mA1kg and mB2kg) travelling at vA2m/s and vB
-2m/s on the x-axis. If mA bounces back at an
angle of -30º, what are the final velocities of
each ball, assuming the collision is elastic?
20Simplification of Elastic Collisions
- In 1D, we showed that the conservation of Kinetic
Energy can be written as - This does not hold for more than one dimension!!
21Problem Solving Collisions
- Choose your system. If complicated (ballistic
pendulum, for example), divide into parts - Consider external forces. Choose a time interval
where they are minimal! - Draw a diagram of pre- and post- collision
situations - Choose a coordinate system
- Apply momentum conservation (divide into
component form). - Consider energy. If elastic, write conservation
of energy equations. - Solve for unknowns.
- Check solutions.
22Center of Mass
- Conservation of momentum is powerful for
collisions and analyzing translational motion of
an object. - Up until this point in the course, we have chosen
objects which can be approximated as a point
particle of a certain mass undergoing
translational motion. - But we know that real objects dont just move
translationally, they can rotate or vibrate
(general motion) ? not all points on the object
follow the same path. - Point masses dont rotate or vibrate!
23Center of Mass
- We need to find an addition way to describe
motion of non-point mass objects. - It turns out that on every object, there is one
point which moves in the same path a particle
would move if subjected to the same net Force. - This point is known as the center of mass (CM).
- The net motion of an object can then be described
by the translational motion of the CM, plus the
rotational, vibrational, and other types of
motion around the CM.
24Example
F
F
F
F
25Center of Mass
- If you apply a force to an non-point object, its
center of mass will move as if the Force was
applied to a point mass at the center of mass!! - This doesnt tell us about the vibrational or
rotation motion of the rest of the object.
26Center of Mass (2 particles, 1D)
- How do we find the center of mass?
- First consider a system made up of two point
masses, both on the x-axis.
xB
mA
xA
x0
xB
x-axis
27Center of Mass (n particles, 1D)
- If, instead of two, we have n particles on the
x-axis, then we can apply a similar formula to
find the xCM.
28Center of Mass (2D, 2 particles)
- For two particles lying in the x-y plane, we can
find the center of mass (now a point in the xy
plane) by individually solving for the xCM and
yCM.
29Center of Mass (3D, n particles)
- We can extend the previous CM calculations to
n-particles lying anywhere in 3 dimensions.
30Example
- Suppose we have 3 point masses (mA1kg, mB3kg
and mC2kg), at three different points
A(0,0,0), B(2,4,-6) and C(3,-3,6).
31Solid Objects
- We can easily find the CM for a collection of
point masses, but most everyday items arent made
up of 2 or 3 point masses. What about solid
objects? - Imagine a solid object made out of an infinite
number of point masses. The easiest trick we can
use is that of symmetry!
32CM and Translational Motion
- The translational motion of the CM of an object
is directly related to the net Force acting on
the object. - The sum of all the Forces acting on the system is
equal to the total mass of the system times the
acceleration of its center of mass. - The center of mass of a system of particles (or
objects) with total mass M moves like a single
particle of mass M acted upon by the same net
external force.
33Example
- A 60kg person stands on the right most edge of a
uniform board of mass 30kg and length 6m, lying
on a frictionless surface. She then walks to the
other end of the board. How far does the board
move?
34Solid Objects (General)
- If symmetry doesnt work, we can solve for CM
mathematically. - Divide mass into smaller sections dm.
35Solid Objects (General)
- If symmetry doesnt work, we can solve for CM
mathematically. - Divide mass into smaller sections dm.
36Example Rod of varying density
- Imagine we have a circular rod (r0.1m) with a
mass density given by ?2x kg/m3.
x
L2m
37Example Rod of varying density
- Imagine we have a circular rod (r0.1m) with a
mass density given by ?2x kg/m3.
x
L2m