Title: Background knowledge Magnetic field
1Background knowledge Magnetic field
- Magnetic field can be produced by a magnet or a
current-carrying conductor.
2Magnetic field lines
- Magnetic field lines are used to show the
strength and direction of a magnetic field.
Note 1. Field lines run from the N-pole round to
the S-pole. 2. When field lines are
closely-spaced, field is strong and vice-versa.
3Example 1 (a)
- In each of the following cases, draw the magnetic
field lines between the magnets and mark the
positions of the neutral points (if any).
4Example 1 (b)
- In each of the following cases, draw the magnetic
field lines between the magnets and mark the
positions of the neutral points (if any).
5Example 1 (c)
- In each of the following cases, draw the magnetic
field lines between the magnets and mark the
positions of the neutral points (if any).
6Example 1 (d)
- In each of the following cases, draw the magnetic
field lines between the magnets and mark the
positions of the neutral points (if any).
7Earths magnetic field
- The Earth has a weak magnetic field. It is so
weak that it does not affect much the field
patterns of permanent magnet. - It is rather like the field around a huge bar
magnet. - The south pole of the earth magnet is actually
in the north.
8Earths magnetic field
- It is convenient to resolve the earths field
strength B into horizontal and vertical
component, BH and BV respectively.
We have BH Bcos a and BV Bsin a. Compass
needles, whose motion is confined to a horizontal
plane, are affected by BH only.
9Flemings left-hand rule
- F force
- B magnetic field
- I current
10Factors affecting magnetic force
- B magnetic field
- I current
- l length of conductor in B-field
11Current balance
- magnetic force F acting upwards
- weight of the rider is equal to the magnetic
force when the frame PQRS is balanced.
12magnetic force and current
- Record the currents required to balance different
number of identical riders on PQ. - Results magnetic force (number of riders) ?
current - i.e. F ? I
13magnetic force and length
- Keep the current through PQ constant.
- Record the number of riders required to balance
the metal frame when one, two and three pairs of
equally strong magnadur magnets are used as
shown. - Results
- The magnetic force (number of riders) ? length
of conductor (number of pairs of magnadur
magnets) - i.e. F ? l
14magnetic force and magnetic field
- Replace the magnadur magnets by a coil of many
turns (for example 1100 turns) as shown below. - Hence, the magnetic field is provided from the
coil and the magnetic field can be increased by
increasing the coil current. - Keep the current through PQ constant.
- Record the coil currents required to balance
different number of identical riders on PQ.
- Results
- The magnetic force (number of riders) ? magnetic
field (coil current) - i.e. F ? B
15Conclusion
- The magnetic force is increased if
- the current is increased, (F ? I)
- the magnetic field is increased, (F ? B)
- there is a greater length of wire inside the
magnetic field. (F ? l)
16Precautions of using current balance
- Make sure the direction of the magnetic field is
perpendicular to the current-carrying arm. - Minimize the effect of the earths magnetic field
by aligning the current-carrying arm along the
N-S direction. - The set-up should be far from any
current-carrying conductors so as to avoid the
effect of stray magnetic fields. - To avoid overheating, the current should be
switched off as soon as measurements have been
taken. - Shield the set-up from the disturbance of wind.
17Magnetic flux density B
- Definition
- Electric field E force per unit charge
- (E F / Q)
- Gravitational field g force per unit mass.
- (g F / m)
- Magnetic flux density B (magnetic field) force
acting per unit current length. - (B F / Il )
- In words The magnetic flux density B is equal to
the force acting on a conductor of unit length
and carrying a unit current at right angles to
the field. - Unit of B Tesla (T) or N A-1 m-1
18Typical Values of the magnetic flux density
Source Magnetic field / T
Smallest value in a magnetically shielded room 10-14
Interstellar space 10-10
Earth's magnetic field 5 x 10-5
Small bar magnet 0.01
Big electromagnet 1.5
Strong lab magnet 10
Surface of a nucleus 106
19Magnetic force on a current-carrying conductor
- From definition B F/Il
- F BIl
- If the conductor and field are not at right
angles, but make an angle q with one another, the
expression becomes - F BIl sin q.
- Note that
- 1. when q 90o (conductor ? field), F BIl.
- 2. when q 0o (conductor // field), F 0.
20Magnetic force on moving charge in a magnetic
field
21Magnetic force on moving charge in a magnetic
field
- Magnetic force acting on each moving charge
- If the conductor makes an angle q with the
magnetic field, -
- F Bqv sin q
22Motion of a charged particle in a magnetic field
- 1 Moving parallel to the field
- When a charged particle moves parallel to the
magnetic field, i.e. q 0o, there is no force
acting on it. Its velocity remains unchanged and
its path is a straight line.
232 Moving perpendicular to the field
242 Moving perpendicular to the field
- Period of circular motion
252 Moving perpendicular to the field
- Notes
- The magnetic force is always perpendicular to the
motion of the charged particle no work is done
by the magnetic field. - Kinetic energy of the charged particle remains
constant.
26Example 2
- The path of an electron in a uniform magnetic
field of flux density 0.01 T in a vacuum is a
circle of radius 0.05 m. Given that the charge
and mass of an electron are -1.6 x 10-19 C and
9.1 x 10-31 kg respectively. Find - (a) the speed and
- (b) the period of its orbit.
- Solution
27Current balance
- To measure steady magnetic field by using
principle of moment. - Clockwise moment anti-clockwise moment
- mgd2 BIld1
28Example 3 Current balanceA rider of mass 0.084 g
is required to balance the frame when an arm PQ,
of length 25 cm and carrying a current of 1.2 A,
is inside and in series with a flat, wide
solenoid as shown below.Find the magnetic flux
density inside the solenoid.
29Search coil and CRO
- A search coil is only used in measuring a varying
magnetic field. - A typical search coil consists of 5000 turns of
wire and an external diameter d 1.5 cm so that
it samples the field over a small area. - The search coil is placed with its plane
perpendicular to a varying magnetic field.
30Search coil and CRO
- Due to the change of magnetic flux, an e.m.f.,
which is induced in the search coil, can be
measured by a CRO. - The induced e.m.f. E is proportional to the flux
density B and the frequency f of the varying
magnetic field. i.e. E ? Bf - The earths magnetic field can be ignored because
it is a steady field.
31Cathode-ray oscilloscope (CRO)
- The CRO is a perfect voltmeter as its resistance
is very high. It can measure both d.c. and a.c.
voltages and show how they vary with time.
simulation
32Measuring d.c. voltages
- To measure a d.c. voltage, the time base is
usually switched off. Thus, it is the light spot
which is deflected. - Or the time base may be switched on to any high
value so that the horizontal trace is deflected.
From the deflection on the screen and the gain
control setting, the d.c. voltage is then
calculated.
Y-gain control 2 V cm-1
Vd.c. amount of deflection (cm) x Y-gain
control setting (V cm-1) 3 x 2 6 V
33Measuring a.c. voltages
- To measure an a.c. voltage, the time base is
usually switched off. The waveform displayed
becomes a vertical trace so that the amplitude
can be easily read on the screen. The maximum
voltage or peak voltage is then calculated from
the gain control setting. Note that the peak
voltage refers to half the length of the
vertical trace.
Y-gain control 5 V cm-1 Time base setting 10 ms
cm-1
Peak voltage Period Frequency
34Example 4 CRO waveformThe figure below shows a
waveform on a screen.(a) If the controls on the
CRO are set at 0.5 V cm-1 and 2 ms cm-1,
(i) the peak voltage, and (ii) the frequency
of the input signal.Solution
35Example 4 CRO waveformThe figure below shows a
waveform on a screen.(b) If the gain control is
changed to 1 V cm-1, sketch the trace on the
figure.Solution
36Example 4 CRO waveformThe figure below shows a
waveform on a screen. (c) If the time base
control is changed to 5 ms cm-1, sketch the
trace on the figure.Solution
37Time base
- When Vx increases linearly with time from A to B,
the spot of light on the screen moves at a
constant speed from the left to right of the
screen. - Then the spot of light flies back to the left
quickly when Vx suddenly drops from B to C. - The saw-tooth voltage Vx causes no vertical
movement of the spot of light..
38Example 5 displaying a.c. waveforms
39Example 5 displaying a.c. waveforms
40Measuring of phase relationships
- The phase difference f of two p.ds (Vx and Vy)
can be observed on phase difference f - a double-beam CRO.
41- If a double-beam CRO is not available, the phase
difference can be found by applying the two p.ds
of the same frequency and amplitude to the X- and
Y-plates (time base off) simultaneously. - The phase difference can be determined from the
trace on the screen of the CRO as follows. - In general, the trace is an ellipse except when
the f is 0o, 90o, 180o, 270o or 360o.
42Comparing of frequencies
- When two p.ds of different frequencies fx and fy
are applied to the X- and Y-plates (time base
off), more complex figures are obtained, know as
Lissajous figures.
simulation
43In any particular case, the frequency ratio can
be found by
44In any particular case, the frequency ratio can
be found by
45Magnetic field around a long straight wire
- 1. The field lines are circles around the wire.
- 2. The magnetic field is the strongest close to
the wire. - 3. Increasing the current makes the magnetic
field stronger. - 4. Reversing the current also reverses the
direction of field lines, but the field pattern
remains unchanged.
46Right hand grip rule
If the right hand grips the wire so that the
thumb points the same way as the current, the
fingers curls the same way as the field lines.
47Experiment to show that B ? I and B ? 1 / r
48- B ? I and B ? 1 / r
- B ? I/r
- B m0I/(2pr) where I is the current and is the
permeability of free space (m0 4p x 10-7 T m
A-1)
49B m0I/(2pr) (m0 4p x 10-7 T m A-1)
- Example 7
- Two long wires X and Y each carries a current of
20 A in the directions as shown in the figure. If
the distance between the wires is 10 mm, find the
magnitude and direction of the magnetic flux
density at - (a) P
50B m0I/(2pr) (m0 4p x 10-7 T m A-1)
- Example 7
- Two long wires X and Y each carries a current of
20 A in the directions as shown in the figure. If
the distance between the wires is 10 mm, find the
magnitude and direction of the magnetic flux
density at - (b) Q.
51Magnetic field around a flat coil
- At the centre of the coil
- The field lines are straight and at right angles
to the plane of the coil - Outside the coil,
- The field lines run in loops.
52Experimental set-up
- By using the experimental-setup shown, it is
found that the magnetic field is - 1. directly proportional to the current and
the number of turns, and - 2. inversely proportional to the radius of the
coil. - Note The magnetic field is greatest at the
centre.
53Magnetic field due to a long solenoid
- From the field pattern of the solenoid, it can be
found that - 1. inside the solenoid, the field lines are
straight and evenly-spaced. This indicates that
the field is of uniform strength. - 2. outside the solenoid, the pattern is similar
to that around a bar magnet, with one end of the
solenoid behaving like a N-pole and the other
end like a S-pole.
54Right hand grip rule
If the right hand grips the solenoid so that the
fingers curls the same way as the current, the
thumbs points to the north pole of the solenoid.
55Magnetic field due to a long solenoid
- The magnetic field of the solenoid can be
increased by - 1. increasing the current,
- 2. increasing the number of turns on the coil.
56Magnetic field due to a long solenoid
- The magnetic field of the solenoid can be
increased by - 1. increasing the current,
- 2. increasing the number of turns on the coil.
- In vacuum, the magnitude of the magnetic flux
density B at a point O on the axis near the
centre of the solenoid of length l, having N
turns and carrying a current I is given by - B m0NI/l or B m0nI where n is the number of
turns per unit length (n N/l)
57Experiment to show that B ? N, B ? I and B ? 1 / l
58Magnetic field due to a long solenoid
- Note The magnetic field within a solenoid is
independent of the shape and the cross section
area of the solenoid.
59Magnetic field due to a long solenoid
- At the ends of solenoid
- The magnetic field at the ends of the solenoid is
weaker. It is half that in the central region
within the solenoid.
60Current-carrying conductor Position of magnetic field Magnetic flux density (B) Symbol
1. Long straight wire Around the wire r perpendicular distance from wire
2. Circular coil At the centre N number of turns r radius of coil
3. Solenoid Inside
3. Solenoid At the ends
N number of turns l length of solenoid
61Force between currents
- Magnetic field due to current through P
- Magnetic force acting on Q
Applying Flemings left hand rule, force acting
on wire Q is towards wire P.
62- Similarly, the force acting on wire P is towards
wire Q. Hence, the two wires attract each other. - By Newtons third law, the magnetic force acting
on P magnetic force acting on Q. - ?
63Summary Unlike current repel, like current
attract
- Parallel wires with current flowing in the same
direction, attract each other. - Parallel wires with current flowing in the
opposite direction, repel each other.
64Summary Unlike current repel, like current
attract
- The force per unit length on each conductor
- When the current I1 I2 1 A, and the
separation between the wires r 1 m, - the force per unit length on the conductor
N m-1
65Summary Unlike current repel, like current
attract
- Definition of the ampere
- The ampere is constant current which, flowing in
two infinitely long, straight, parallel
conductors of negligible cross-section and placed
in a vacuum 1 metre apart, produces between them
a force equal to 2 x 10-7 Newton per metre of
their length.
66Example 8
- The figure below shows two horizontal wires, P
and Q, 0.2 m apart, carrying currents of 1.5 A
and 3 A respectively. - (a) Calculate the force per metre on wire Q.
- (b) State the direction of the force.
- (c) State the direction and magnitude of the
force per metre on wire P due to the current in
wire Q
.
67Moment and couple
- Couple - consists of 2 equal and opposite
parallel forces whose lines of action do not
coincide (??).
F
d
F
torque of couple F x d/2 F x d/2 Fd
68Torque on a rectangular current-carrying coil in
a uniform B-field
- Torque F(b sin q)
- NBIlb sin q
- NBAI sin q
69Maximum and minimum torque on a coil
- The maximum torque is NBAI when the plane of coil
is parallel to the field (q 90o). - The torque on the coil is zero when the plane of
coil is perpendicular to the field (q 0o).
70Example 9
- Example 9
- A square coil has sides of length 5 cm. The coil
consist of 20 turns of insulated wire carrying a
current of 0.2 A. The plane of the coil is at an
angle 40o to a uniform magnetic field of flux
density of 25 mT. Calculate the torque acting on
the coil. - Solution
71Moving-coil galvanometer
- The moving-coil meter contains a coil wound on an
aluminium former around a soft-iron cylinder. - The coil is pivoted on bearings between the poles
of a cylindrical magnet. - Current flows through the coil via a pair of
spiral springs called hair springs.
72Theory
- When a current is passed through a coil in a
magnetic field, the coil experiences a torque.
The coil rotates, moving the pointer across the
scale. - The normal of plane of the coil is always
perpendicular to the magnetic field, the torque
on the coil is given by - T NBAI sin 90o NBAI
73Theory
- The movement of the coil is opposed by the hair
springs. - The restoring torque (t) exerted by the hair
springs to oppose the rotation is given by - t kq
- where k is the torsion constant of the
hairsprings
74Linear scale
- The coil comes to rest when the magnetic turning
effect (torque) on the coil is balanced by the
turning effect (restoring torque) from the hair
springs. - BANI kq
- Hence, I ? q the galvanometer scale is linear
75Sensitivity
- The current sensitivity of a galvanometer is
defined as the deflection per unit current - i.e. current sensitivity q/I BAN/k.
- The voltage sensitivity of a galvanometer is
defined as the deflection per unit voltage - i.e. voltage sensitivity q/V q/(IR)
BAN/(kR) - where R is the resistance of the coil.
- The sensitivity can be increased, i.e. the coil
deflects more for a certain current or voltage,
by - 1. using a stronger magnet (larger B),
- 2. using weaker hair springs (smaller k).
- 3. using a coil with larger area (larger A),
and - 4. increasing the number of turns of the coil
(larger N).