Title: Simple Harmonic Motion - 3
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2Session
Simple Harmonic Motion - 3
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4Session Objective
Problems
5Class Exercise - 1
6Solution
Total time from A back to A is
20.67 0.47
2.28 s
7Class Exercise - 2
8Solution
In the figure, d and r are density of ball and
liquid respectively.
9Solution contd..
Compare this by equation a w2x
Also d 3r
T 1.1 s
10Class Exercise - 3
A block is resting on a piston which is moving
vertically with an SHM of period 1 s. At what
amplitude of motion will the block and piston
separate?
11Solution
For the block, mg R ma or R m(g a)
In order to separate the block, R 0 or a g
Now a w2x
Þ g w2x
0.248 m
12Class Exercise - 4
A plank with a body of mass m placed on it starts
moving straight up according to the law X a(1
coswt), where X is the displacement from the
initial position, w 11 s1. Find the time
dependence of the force that the body exerts on
the plank. If a 4.0 cm plot this dependence.
13Solution
Plot is shown in the figure.
14Class Exercise - 5
15Solution
Restoring force on the bob mg sin(q b)
Force on the bob mgsin(q b)
If q is small, b is also small.
16Solution contd..
17Class Exercise - 6
18Solution
19Solution contd..
Tension is also increased as shown below.
20Solution contd..
21Class Exercise - 7
22Solution
A displaced position of the rod through an angle
q is shown in the given figure. The displacement
of spring is x. Let K1 and K2 be the stiffness of
the springs respectively.
Considering the torques actingon the rod, we have
23Solution contd..
When q is small, cos q 1 and sin q q
Hence, the motion is SHM.
24Class Exercise - 8
25Solution
We will analyse the problem relative to the
rotating bar AB. As the acceleration of bar will
be centripetal, a pseudo force will act on the
sleeve away from centre and will be of magnitude
m w2x.
26Solution contd..
27Class Exercise - 9
28Solution
29Solution contd..
The force is provided by friction of thelower
block.
30Class Exercise - 10
A liquid of density d is kept in a vertical
U-tube of uniform cross section A. If the liquid
column is slightly depressed and left, show that
the resulting motion of the liquid is SHM and
find the period.
31Solution
Let the liquid be depressed by a height x in the
right side of the U-tube. Then the liquid rises
above on the left-side by a height x.
? Restoring force Pressure Area
(2xdg) A
or K 2dgA
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