Title: Topics to cover in 2nd part
1Topics to cover in 2nd part
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2Chapter 8 - Project ManagementChapter Topics
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3Project Management
- Questions
- Why do we need to study Project Management?
- How does a project management technique work?
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4Objective
- The main purpose is to govern the operations of a
project such that all activities involved are
well administrated and that we can also control
its completion time
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5Project management technique
- Steps to solve a project management
- problem
- to represent a project problem graphically
- to determine its completion time
- to carry out sensitivity analysis, if any
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61. Represent a project problem graphically
Event Processing Time Precedent constraints
A B C 20 30 10 -- A B
- Steps
- Gather all information and organize them in a
table format that consists of event, processing
time, and precedent constraints as follows - Draw a semantic network to represent them
- Special case!
-
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7Semantic network to represent them
- Here, we use three symbols
- node to represent stage
-
- line/branch to represent event
- arrow to represent precedent
- constraint
- Example
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8Example
Path Event Proc Time Pred Const
1-2 2-3 3-4 A B C 20 30 10 -- A B
C
A
B
1
2
3
4
30
10
20
Rule1 All nodes must starts from one Node and
ends with one node
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9Special case!
- When two or events taken places in the same time
interval - (known an concurrent events)
- Consider the following example!
- How to draw it?
Event Processing Time Precedent constraints
A B C 3 5 7 -- A A
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10Case 1
A
B
2
3
1
5
3
C
7
Wrong!
Rule2 no node can have two outcomes and end
with the same note
Solution
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11Solutions for Rule 2
A dummy activity shows a precedence
relationship Reflects no processing time
3
B
Dummy 10
A
1
2
5
C
Solution 1
4
Dummy 2 0
What one is better?
A
B
1
2
4
Solution 2
C
3
Dummy 0
3
Dummy 0
B
A
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1
2
4
Solution 3
C
122. Determine its completion time
- Consider the project network as shown in next
slide - Question Is it an easy way to find out the
- solution?
- Answer YES, it knows as
- Critical Path Method (CPM)
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13The Project Network All Possible Paths for
Obtaining a Solution
Figure 8.3 Expanded network for building a house
showing concurrent activities.
Table 8.1 Possible Paths to complete the
House-Building Network
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Then the completion time for paths A, B, C and D
can be computed as
14The Project Network
Completion time for path A 1?2 ? 3 ? 4
? 6 ? 7, 3 2 0 3 1 9 months (Critical
Path)
path B 1 ? 2 ? 3 ? 4 ? 5 ? 6 ? 7, 3 2 0
1 1 1 8 months
path C 1 ? 2 ? 4 ? 6 ? 7, 3 1 3 1
8 months path D 1 ? 2 ? 4 ? 5 ? 6 ? 7,
3 1 1 1 1 7 months The critical path is
the longest path through the network the minimum
time the network can be completed.
This is the Solution!
Figure 8.5 Alternative paths in the network
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15Critical Path Method (CPM)
- General concepts
- For each branch of the project network, we
firstly determine four values of ES, EF, LS and
LF - For each branch, we compute their slack time,
- Slack time (LS-ES) or (LF-EF)
- The critical path is located at branch that has
- slack time 0
- (Do you know the reason why?)
- How it works?
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16How CPM works?
- Steps
- Prepare the project network
- Construct a table as follows
- Compute ES and EF
- Compute LS and LF
- Compute LS-ES or LF-EF
-
Branch ES EF LS LF
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ESij max (EFi) EFij ESi tij with
EF10
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Critical path when LS-ES0
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17Compute ES and EF
- Note
- When computing these values, the pattern is like
moving zic-zac format by firstly computer ES12
and then adding it to EF12 and move to next
branch by copying the max values of the branch
1-2 to say, 2-3 - We compute them from top to bottom!
- Their relationship
- Example 1
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18The starting point of ES and EF
- Consider
- Then
- EF1 0
- ES12 max (EF1) EF12 ES12 t12
- 0 0 t12
t12
1
2
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19Branches ESij max(EFi) EFijESijtij
1-2 2-3 2-4 3-4 4-5 4-6 5-6 6-7 ES12 max(EF1) ES23max(EF2) ES24max(EF2) ES34max(EF3) ES45max(EF4) ES46max(EF4) ES56max(EF5) ES67max(EF6) EF12ES12t12 EF23ES23t23 EF24 EF34 EF45 EF46 EF56 EF67
The overall computation is shown in next slide
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20Complete solution
- ES is the earliest time an activity can
start. ESij Maximum (EFi) - EF is the earliest
start time plus the activity time. EFij ESij
tij
add all ti for note 2
Add all t to note 4 and take the longest time Max
(node 3t34, node2t24) max (50,
31) max(5,4)5
Max(node4t46,node5t56 max(53,51)8
(noteyou can compute these values and show in
the network diagram as well)
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21The Project Network Activity Scheduling-
Earliest Times
- ES is the earliest time an activity can
start. ESij Maximum (EFi) - EF is the earliest
start time plus the activity time. EFij ESij
tij
Figure 8.6 Earliest activity start and finish
times
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22Compute LS and LF
- Note We compute these values from the bottom to
top, with assigning - LSij LFi -tij LFij min LSj
- with
- the end of LFij EFij
- Example computing Figure 8.3
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23Branches LSij LFij-tij LFijmin(LSj)
1-2 2-3 2-4 3-4 4-5 4-6 5-6 6-7 LS12 Li12-t12 LS23 LF23-t23 LS24 LF24-t24 LS34 LF34-t34 LS45 LF45-t45 LS46 LF46-i46 LS56 LF56-t56 LS67 LF67-t67 LF12min(LS2) LF23min(LS3) LF24min(LS4) LF34min(LS4) LF45min(LS5) LF46min(LS6) LF56min(LS6) LF67min(LS7)
The overall computational is shown in next slide
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24- LS is the latest time an activity can start
without delaying critical path time. LSij LFij
- tij - LF is the latest finish time
LFij Minimum (LSj)
Min(node3-t23,node4-t24) Min(5-2,5-1)Min(3,4)3
Min(node 6-t46,node5-t45) Min(8-3,7-1) Min(5,6)
5
Min(node 7-t67) Min(9-1)8
Same as EF67 from the previous slide
Start with the end node first
Again, you can place these values onto the
branches
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25The Project Network Activity Scheduling - Latest
Times
- LS is the latest time an activity can start
without delaying critical path time. LSij LFij
- tij - LF is the latest finish time
LFij Minimum (LSj)
Figure 8.7 Latest activity start and finish times
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26Compute LS-ES or LF-EF
- Two ways you can achieve it
- by compiling slack, Sij
- by showing branches
-
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27The Project Network Calculating Activity Slack
Time
- Slack, Sij, computed as follows Sij LSij
- ESij or Sij LFij - EFij
Table 8.2 Activity
Slack Figure 8.9 Activity
Slack
What does it mean?
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28The Project Network Activity Slack
- Slack is the amount of time an activity can be
delayed without delaying the project. - Slack time exists for those activities not on
the critical path for which the earliest and
latest start times are not equal. - Shared slack is slack available for a sequence
of activities.
Figure 8.8 Earliest activity start and finish
times
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29Sensitivity Analysis
- Today, we only consider one case
- Probabilistic Activity Times
- Refer to activity time estimates usually can not
be made with certainty - PERT is known as the solution method
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30PERT
- In PERT, three different time estimations are
applied - most likely time (m),
- the optimistic time (a) , and
- the pessimistic time (b).
- How do we make use of these three values?
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31Probabilistic Activity Times
- We used these values to estimate the mean and
variance of a beta distribution -
- mean (expected time)
- variance
- How to use these values to solve a project
network problem?
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32PERT
- We simply apply t values in CPM and determine the
values of - ES
- EF
- LS
- LF
- S
- and branches with slack 0 still consider as
critical paths - Example.
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33Procedures for PERT
- Step 1 based on the values of a, b and m,
determine the t and v values for each path - Step 2 determine the critical path by using t
values in the CPM - Step 3 compute its corresponding means and
standard deviations according. - Example
- Result implication
- Applications
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34PERT Example
- Step 1 computer t and v values
- Step 2 determine the CPM
- Step 3 determine v value
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35Step 1 computer t and v values
Figure 8.11 Network with mean activity times and
variances
Table 8.3 Activity Time Estimates for Figure
8.10
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36Step 2 determine the CPM
Figure 8.12 Earliest and latest activity times
Table 8.4 Activity Earliest and Latest Times and
Slack
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37Step 3 determine v value
- The expected project time is the sum of the
expected times of the critical path activities. - The project variance is the sum of the variances
of the critical path activities. - The expected project time is assumed to be
normally distributed (based on central limit
theorum). - In example, expected project time (tp) and
variance (vp) interpreted as the mean (?) and
variance (?2) of a normal distribution - ? 25 weeks
- ?2 6.9 weeks
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38Probability Analysis of the Project Network
- Using normal distribution, probabilities are
determined by computing number of standard
deviations (Z) a value is from the mean. - Value
is used to find corresponding probability in
Table A.1, App. A.
Figure 8.13 Normal distribution of network
duration
Critical value
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39- Consider when
- x 30
- x 22
- Tutorial Assignment
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40Probability Analysis of the Project
NetworkExample 1
- ?2 6.9 ? 2.63
- Z (x-?)/ ? (30 -25)/2.63 1.90
- Z value of 1.90 corresponds to probability of
.4713 in Appendix A of p715. Probability of
completing project in 30 weeks or less (.5000
.4713) .9713, - or 97.13 (Why so high a probability
rate?)
Figure 8.14 Probability the network will be
completed in 30 weeks or less
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41Probability Analysis of the Project
NetworkExample 2
Z (22 - 25)/2.63 -1.14 Z value of 1.14
(ignore negative) corresponds to probability of
.3729 in Table A.1, appendix A. Probability that
customer will be retained is .1271 ( 0.5-
0.3729) , or 12.71 (Again, why so low
probability rate?)
Figure 8.15 Probability the network will be
completed in 22 weeks or less
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42Tutorial Assignment
- Try to use QM to solve CPM/PERT problems (see
slide 19) - Exercises (Chapter 8)
- Old 8, 10, 17
- New 4, 6, 11
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43Probability Analysis of the Project
NetworkCPM/PERT Analysis with QM for Windows
Exhibit 8.1
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44The Project Network Activity Slack
- Slack is the amount of time an activity can be
delayed without delaying the project. - Slack time exists for those activities not on
the critical path for which the earliest and
latest start times are not equal. - Shared slack is slack available for a sequence
of activities.
Figure 8.8 Earliest activity start and finish
times
45The Project Network Calculating Activity Slack
Time
- Slack, Sij, computed as follows Sij LSij
- ESij or Sij LFij - EFij
Table 8.2 Activity
Slack Figure 8.9 Activity
Slack