Title: Chapter 23 Electrochemistry
1Chapter 23Electrochemistry
2Sections 23.1-23.2Electrochemical Cells
- OBJECTIVES
- Describe how RedOx rxns produce useful
electricity - Explain the structure and function of Voltaic
(Galvanic) Cells i.e. batteries
3The Nature of Voltaic (Galvanic) Cells
- You have already seen that when a strip of metal
is placed in a solution containing a less active
metal, a single replacement rxn will occur - This is a classic example of a RedOx rxn. Whether
the process is spontaneous or not can easily be
predicted by using Table J in your Reference
Tables for Physical Setting / CHEMISTRY
4Voltaic/Galvanic Cells
- If the half-rxns which define a RedOx rxn are
allowed to occur in separate beakers, the
electrons can be made to flow through an external
wire and used to perform work - The problem is that as the RedOx rxn tries to
proceed there is an imbalance of ions in the
beakers. Nature will not allow this, so we must
supply ions from an external source to keep each
solution electrically neutral. - The external source of ions is called a Salt
Bridge. It is composed of a salt- saturated gel
contained by a glass U-tube.
5The Daniell Cell
The Daniell Cell was the first wet cell
battery. It is composed of a copper electrode in
a copper (II) sulfate solution, a zinc electrode
in a zinc sulfate solution, a salt bridge
(usually containing sodium chloride), an external
wire, and a voltmeter. The electrons
spontaneously flow from the Zn electrode to the
Cu electrode. How the cell works is described in
the next slide.
6Daniell Cell Half-Rxns
- Oxidation Half-Rxn
- Zn(s) ? Zn2(aq) 2e-1 ANODE (-)
- Reduction Half-Rxn
- Cu2(aq) 2e-1 ? Cu(s) CATHODE ()
- An Ox, Red Cat
7So What Else Happens in the Daniell Cell?
- The electrons flow from the Zn electrode to the
Cu electrode - The two RedOx rxns happen simultaneously
- The cation in the salt bridge moves toward the
cathode (Cu Electrode) - The anion in the salt bridge moves toward the
anode (Zn Electrode) - The Zn electrode gets lighter in mass
- The Cu electrode gets heavier in mass
- The rxn stops (the battery is dead) when the salt
in the salt bridge runs out, or the Zn electrode
is used up, or the Cu2 ions run out
8Cell Voltages
- Standard cell conditions are defined as
- 1 Molar Solute, 25? C, 1 Atm
- A Standard Hydrogen Electrode under standard
conditions has a back voltage applied so the
observed cell voltage appears to be zero (see
diagrams in the next slides) - If a stated voltage (E) has a zero superscript
(E?), the experiment was done under standard
conditions
9(a) The Standard Hydrogen Cell and (b) Close up
of the Hydrogen Standard Electrode.
10Cell Voltages
- You text book has a table of Reduction Potentials
(voltages) on pg. 688 - Find the two half reactions for your cell in
this case we have - Cu2(aq) 2e-1 ? Cu(s) E? 0.34 V
- Zn2 (aq) 2e-1 ? Zn (s) E? -0.76 V
- Since you must have both a Red and an Ox rxn,
turn the half rxn with the smaller voltage around
and change the sign of the voltage (next slide)
11Cell Voltages (continued)
- In the present case we have
- Cu2(aq) 2e-1 ? Cu(s) E? 0.34 V
- Zn(s) ? Zn2 (aq) 2e-1 E? 0.76
V - If the number of electrons on each side is the
same simply add the half rxns together and
simplify the voltages are also added together in
a similar fashion - Cu2(aq) Zn(s) ? Zn2 (aq) Cu(s) Overall
Rxn - 0.34 (0.76) 1.10 Volts E?cell
12The Daniell Cell under Standard
Conditions(notice the cell voltage!)
13Another Example (pg. 1 of 5)
- PROBLEM Suppose someone gave you Al(s), Zn(s),
Al(NO3)3(aq), Zn(NO3)2(aq), and NaC2H3O2 as a
paste construct a Voltaic cell and label or
explain all components - SOLUTION First, identify the electrodes (usually
solids), then immerse them in their appropriate
electrolytes, and let the paste be the salt
bridge so in this case we have - Al(s) in Al(NO3)3(aq)
- Zn(s), in Zn(NO3)2(aq)
- NaC2H3O2 as a paste is in the salt bridge
14Another Example (pg. 2 of 5)
- Now write the Reduction Half Rxns using pg. 688
- Al3(aq) 3e-1 ? Al(s) E?
-1.66 V - Zn2(aq) 2e-1 ? Zn(s) E?
-0.76 V - You must have the same number of electrons on
both sides of the arrow, so multiple the first
rxn by 2 and the second rxn by 3. The voltages,
however, are not changed - 2Al3(aq) 6e-1 ? 2Al(s) E?
-1.66 V - 3Zn2(aq) 6e-1 ? 3Zn(s) E?
-0.76 V
15Another Example (pg. 3 of 5)
- Turn the smaller voltage rxn around, change sign,
and add - 2Al(s) ? 2Al3(aq) 6e-1 (Ox) E?
1.66 V - 3Zn2(aq) 6e-1 ? 3Zn(s) (Red) E? -0.76
V - 2Al(s) 3Zn2(aq) ? 3Zn(s) 2Al3(aq)
- Over All Net Ionic Rxn (balanced by charge
mass!) - E?cell 0.90 V (1.66 V) (-0.76 V)
- Note that all cell voltages must be positive!
16Another Example (pg. 4 of 5)
- Thus, we know
- Electrons flow from Al(s) ? Zn(s)
- The cell voltage is 0.90 V
- Reduction occurs at the Zn electrode, and it is
the cathode () - Oxidation occurs at the Al electrode, and it is
the anode (-) - Na1(aq) from the salt bridge flows to the
cathode (Zn) - C2H3O2(aq)-1 from the salt bridge flows to the
anode (Al) - The Zn electrode gets heavier while the Al
electrode gets lighter
17Another Example (pg. 5 of 5)
18Other Batteries Lead Storage Cell
19Other Batteries Standard Dry Cell
20Other Batteries Alkaline Battery
21Section 23.3Electrolytic Cells More
- OBJECTIVES
- Describe how RedOx rxns can be used to
electroplate - Discuss some other practical applications of
electrochemistry
22Electrolytic Cell Basics
- Electrolytic Cells require an external D.C. power
supply - The power supply forces a RedOx rxn to take place
backwards (rxn normally has a positive DG? or a
negative E?) - Usually, there is only one beaker containing both
the electrolyte and electrode - AnOx RedCat still works .. but the cathode is
now (-) and the anode is now (). This is
backwards compared to a Voltaic Cell!
23Electroplating of Silver Metal
The oxidation of sliver metal has an E? value of
-0.80 V, so it is not a spontaneous reaction. The
external power source supplies this voltage to
drive the rxn as seen in the adjacent diagram.
The silver electrode is oxidized (loses weight)
and the spoon is plated by the reduction of
silver ions.
24The Formation of Rust
Water acts as the medium for the RedOx rxn
between solid Fe (oxidized) and molecular oxygen
(reduced) water. The rxn causes a pit to form
that will eventually go all the way though the
metal. Some metals, such as Al or Ag, form a
protective oxidized layer that prevents pitting.
25How to Prevent Rust
- Coat the metal with paint or lacquer to seal out
oxygen - Use a sacrifice metal
- This implies a metal that oxidizes (rusts) easier
than the metal you which to protect, is allowed
to rust such that the electrons it produces are
fed into the protected metal (see next slide) - Apply an external D.C. voltage
- This is essentially the same as the previous
method, but instead of a sacrifice metal a
battery is used
26One Type of Cathodic Protection
27Tarnishing
- Some metals, such as aluminum and silver, form a
thin layer of oxide (rust), which protects the
metal from corroding or pitting all the way
through - Other metals, such as iron, have no such
protection and rusts all the way through to the
other side - Sorry this is the last time we will use the
slide notes this year!!!
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