Title: Strings and Languages Operations
1Strings and Languages Operations
- Concatenation
- Exponentiation
- Kleene Star
- Regular Expressions
2Strings and Language Operations
- Concatenation
- Exponentiation
- Kleene star
- Pages 27-30 of the text
- Regular expressions
- Pages 71-75 of the text
3String Concatenation
- If x and y are strings over alphabet S, the
concatenation of x and y is the string xy formed
by writing the symbols of x and the symbols of y
consecutively. - Suppose x abb and y ba
- xy abbba
- yx baabb
4Properties of String Concatenation
- Suppose x, y, and z are strings.
- Concatenation is not commutative.
- xy is not guaranteed to be equal to yx
- Concatenation is associative
- (xy)z x(yz) xyz
- The empty string is the identity for
concatenation - x/\ /\x x
5Language Concatenation
- Suppose L1 and L2 are languages (sets of
strings). - The concatenation of L1 and L2, denoted L1L2,is
defined as - L1L2 xy x ? L1 and y ? L2
- Example,
- Let L1 ab, bba and L2 aa, b, ba
- What is L1L2?
- Solution
- Let x1 ab, x2 bba, y1 aa, y2 b, y3 ba
- L1L2 x1y1, x1y2, x1y3, x2y1, x2y2, x2y3
abaa, abb, abba, bbaaa, bbab, bbaba
6Language Concatenation is not commutative
- Let L1 aa, bb, ba and L2 /\, aba
- Let x1 aa, x2 bb, x3ba, y1 /\, y2 aba
- L1L2 x1y1, x1y2, x2y1, x2y2, x3y1, x3y2
aa, aaaba, bb, bbaba, ba, baaba - L2L1 y1x1, y1x2, y1x3, y2x1, y2x2, y2x3
aa, bb, ba, abaaa, ababb, ababa - L2L2 y1y1, y1y2, y2y1, y2y2 /\,
aba, aba, abaaba /\, aba, abaaba
(dropped extra aba)
7Associativity of Language Concatenation
- (L1L2)L3 L1(L2L3) L1L2L3
- Example
- Let L1a,b, L2c,d, and L3e,f
- L1L2L3(a,bc,d)e,f ac, ad,
bc, bde,f ace,acf,ade,aef,bce,bc
f,bde,bdf - L1L2L3a,b(c,de,f) a,bce,
df, ce, df ace,acf,ade,aef,bce,bc
f,bde,bdf
8Special Cases
- What language is the identity for language
concatenation? - The set containing only the empty string /\ /\
- Example
- aab,ba,abc/\ /\aab,ba,abc
aab,ba,abc - What about ?
- For any language L, L L
- Thus for concatenation is like 0 for
multiplication - Example
- aab,ba,abc aab,ba,abc
- The intuitive reason is that we must choose a
string from both sets that are being
concatenated, but there is nothing to choose from
.
9Exponentiation
- We use exponentiation to indicate the number of
items being concatenated - Symbols
- Strings
- Set of symbols (S for example)
- Set of strings (languages)
- a3 aaa
- x3 xxx
- S3 SSS x ? S x3
- L3 LLL
10Examples of Exponentiation
- Let xabb, Sa,b, Lab,b
- a4 aaaa
- x3 (abb)(abb)(abb) abbabbabb
- S3 SSS a,ba,ba,b aaa,aab,aba,abb,b
aa,bab,bba,bbb - L3 LLL ab,bab,bab,b
ababab,ababb,abbab,abbb,
babab,babb,bbab,bbb
11Results of Exponentiation
- Exponentiation of a symbol or a string results in
a string. - Exponentiation of a set of symbols or a set of
strings results in a set of strings - a symbol ? a string
- a string ? a string
- a set of symbols ? a set of strings
- a set of strings ? a set of strings
12Special Cases of Exponentiation
- a0 /\
- x0 /\
- S0 /\
- L0 /\ for any language L
- aa,bb0 /\
- a, aa, aaa, aaaa, 0 /\
- /\ 0 /\
- ?0 0 /\
13Kleene Star
- Kleene is a unary operation on languages.
- Kleene is not an operation on strings
- However, see the pages on regular expressions.
- L represents any finite number of concatenations
of L. - L Ukgt0 Lk L0 U L1 U L2 U
- For any L, /\ is always an element of L
- because L0 /\
- Thus, for any L, L ! ?
14Example of Kleene Star
- Let Laa
- L0 /\
- L1Laa
- L2 aaaa
- L3
- L L0 ? L1 ? L2 ? L3
- /\, aa, aaaa, aaaaaa,
- set of all strings that can be obtained by
concatenating 0 or more copies of aa
15Example of Kleene Star
- Let Laa, b
- L0 /\
- L1Laa,b
- L2 LL aaaa, aab, baa, bb
- L3
- L L0 ? L1 ? L2 ? L3
- set of all strings that can be obtained by
concatenating 0 or more copies of aa and b
16Regular Languages
- Regular languages are languages that can be
obtained from the very simple languages over S,
using only - Union
- Concatenation
- Kleene Star
- See lecture 14 and pages 71-75 of the text
17Examples of Regular Languages
- aab (i.e. aab )
- aa,b (i.e. aa ? b )
- a,b language of strings that can be
obtained by concatenating any number of as and
bs - bba,b language of strings that begin with
bb (followed by any number of as and bs) - abb,/\ language of strings that begin
with any number of as and end with an optional
bb. - a?b language of strings that consist of
only as or only bs and /\.
18Regular Expressions
- We can simplify the formula for regular languages
slightly by - leaving out the set brackets and
- replacing ? with
- The results are called regular expressions.
19Examples of Regular Expressions
Set notation Regular Expressions
aab aab
aa,b aa?b aab
a,b (a?b) (ab)
bba,b bb(a?b) bb(ab)
abb,/\ a(bb?/\) a(bb/\)
a?b ab
20String or Language?
- Consider the regular expression a(bb/\)
- a(bb/\) is a string over alphabet a, b, , ,
/\, (, ), ? - a(bb/\) represents a language over alphabet a,
b - It represents the language of strings over a,b
that begin with any number of as and end with an
optional bb. - Some regular expressions look just like strings
over alphabet a,b - Regular expression aaba represents the language
aaba - Regular expression /\ represents the language
/\ - It should be clear from the context whether a
sequence of symbols is a regular expression or
just a string.
21Module 1 Course Overview
- Course CSE 460
- Instructor Dr. Eric Torng
- TA To be determined
22What is this course?
- Philosophy of computing course
- We take a step back to think about computing in
broader terms - Science of computing course
- We study fundamental ideas/results that shape the
field of computer science - Applied computing course
- We learn study a broad range of material with
relevance to computing today
23Philosophy
- Phil. of life
- What is the purpose of life?
- What are we capable of accomplishing in life?
- Are there limits to what we can do in life?
- Why do we drive on parkways and park on
driveways?
- Phil. of computing
- What is the purpose of programming?
- What can we achieve through programming?
- Are there limits to what we can do with programs?
- Why dont debuggers actually debug programs?
24Science
- Physics
- Study of fundamental physical laws and phenomenon
like gravity and electricity - Engineering
- Governed by physical laws
- Our material
- Study of fundamental computational laws and
phenomenon like undecidability and universal
computers - Programming
- Governed by computational laws
25Applied computing
- Applications are not immediately obvious
- In some cases, seeing the applicability of this
material requires advanced abstraction skills - Every year, there are people who leave this
course unable to see the applicability of the
material - Others require more material in order to
completely understand their application - for example, to understand how regular
expressions and context-free grammars are applied
to the design of compilers, you need to take a
compilers course
26Some applications
- Important programming languages
- regular expressions (perl)
- finite state automata (used in hardware design)
- context-free grammars
- Proofs of program correctness
- Subroutines
- Using them to prove problems are unsolvable
- String searching/Pattern matching
- Algorithm design concepts such as recursion
27Fundamental Theme
- What are the capabilities and limitations of
computers and computer programs? - What can we do with computers/programs?
- Are there things we cannot do with
computers/programs?
28Module 2 Fundamental Concepts
- Problems
- Programs
- Programming languages
29Problems
- We view solving problems as the main application
for computer programs
30Definition
- A problem is a mapping or function between a set
of inputs and a set of outputs - Example Problem Sorting
(4,2,3,1)
(1,2,3,4)
(3,1,2,4)
(1,5,7)
(7,5,1)
(1,2,3)
(1,2,3)
31How to specify a problem
- Input
- Describe what an input instance looks like
- Output
- Describe what task should be performed on the
input - In particular, describe what output should be
produced
32Example Problem Specifications
- Sorting problem
- Input
- Integers n1, n2, ..., nk
- Output
- n1, n2, ..., nk in nondecreasing order
- Find element problem
- Input
- Integers n1, n2, , nk
- Search key S
- Output
- yes if S is in n1, n2, , nk, no otherwise
33Programs
34Purpose
- Why do we write programs?
- One answer
- To solve problems
- What does it mean to solve a problem?
- Informal answer For every legal input, a correct
output is produced. - Formal answer To be given later
35Programming Language
- Definition
- A programming language defines what constitutes a
legal program - Example a pseudocode program may not be a legal
C program which may not be a legal C program - A programming language is typically referred to
as a computational model in a course like this.
36C
- Our programming language will be C with minor
modifications - Main procedure will use input parameters in a
fashion similar to other procedures - no argc/argv
- Output will be returned
- type specified by main function type
37Maximum Element Problem
- Input
- integer n gt 1
- List of n integers
- Output
- The largest of the n integers
38C Program which solves the Maximum Element
Problem
- int main(int A, int n)
- int i, max
- if (n lt 1)
- return (Illegal Input)
- max A0
- for (i 1 i lt n i)
- if (Ai gt max)
- max Ai
- return (max)
39Fundamental Theme
- Exploring capabilities and limitations of C
programs
40Restating the Fundamental Theme
- We will study the capabilities and limits of C
programs - Specifically, we will try and identify
- What problems can be solved by C programs
- What problems cannot be solved by C programs
41Question
- Is C general enough?
- Or is it possible that there exists some problem
P such that - P can be solved by some program P in some other
reasonable programming language - but P cannot be solved by any C program?
42Churchs Thesis (modified)
- We have no proof of an answer, but it is commonly
accepted that the answer is no. - Churchs Thesis (three identical statements)
- C is a general model of computation
- Any algorithm can be expressed as a C program
- If some algorithm cannot be expressed by a C
program, it cannot be expressed in any reasonable
programming language
43Summary
- Problems
- When we talk about what programs can or cannot
DO, we mean what PROBLEMS can or cannot be
solved
44Module 3 Classifying Problems
- One of the main themes of this course will be to
classify problems in various ways - By solvability
- Solvable, half-solvable, unsolvable
- We will focus our study on decision problems
- function (one correct answer for every input)
- finite range (yes or no is the correct output)
45Classification Process
- Take some set of problems and partition it into
two or more subsets of problems where membership
in a subset is based on some shared problem
characteristic
46Classify by Solvability
- Criteria used is whether or not the problem is
solvable - that is, does there exist a C program which
solves the problem?
47Function Problems
- We will focus on problems where the mapping from
input to output is a function
48General (Relation) Problem
- the mapping is a relation
- that is, more than one output is possible for a
given input
49Criteria for Function Problems
- mapping is a function
- unique output for each input
50 Example Non-Function Problem
- Divisor Problem
- Input Positive integer n
- Output A positive integral divisor of n
9
51 Example Function Problems
- Sorting
- Multiplication Problem
- Input 2 integers x and y
- Output xy
2,5
52 Another Example
- Maximum divisor problem
- Input Positive integer n
- Output size of maximum divisor of n smaller than
n
9
53Decision Problems
- We will focus on function problems where the
correct answer is always yes or no
54Criteria for Decision Problems
- Output is yes or no
- range Yes, No
- Note, problem must be a function problem
- only one of Yes/No is correct
55 Example
- Decision sorting
- Input list of integers
- Yes/No question Is the list in nondecreasing
order?
56 Another Example
- Decision multiplication
- Input Three integers x, y, z
- Yes/No question Is xy z?
57 A Third Example
- Decision Divisor Problem
- Input Two integers x and y
- Yes/No question Is y a divisor of x?
58Focus on Decision Problems
- When studying solvability, we are going to focus
specifically on decision problems - There is no loss of generality, but we will not
explore that here
59Finite Domain Problems
- These problems have only a finite number of inputs
60Lack of Generality
- All finite domain problems can be solved using
table lookup idea
61Table Lookup Program
- int main(string x)
- switch x
- case Bill return(3)
- case Judy return(25)
- case Tom return(30)
- default cerr ltlt Illegal input\n
62Key Concepts
- Classification Theme
- Decision Problems
- Important subset of problems
- We can focus our attention on decision problems
without loss of generality - Same is not true for finite domain problems
- Table lookup
63Module 4 Formal Definition of Solvability
- Analysis of decision problems
- Two types of inputsyes inputs and no inputs
- Language recognition problem
- Analysis of programs which solve decision
problems - Four types of inputs yes, no, crash, loop inputs
- Solving and not solving decision problems
- Classifying Decision Problems
- Formal definition of solvable and unsolvable
decision problems
64Analyzing Decision Problems
- Can be defined by two sets
65Decision Problems and Sets
- Decision problems consist of 3 sets
- The set of legal input instances (or universe of
input instances) - The set of yes input instances
- The set of no input instances
66Redundancy
- Only two of these sets are needed the third is
redundant - Given
- The set of legal input instances (or universe of
input instances) - This is given by the description of a typical
input instance - The set of yes input instances
- This is given by the yes/no question
- We can compute
- The set of no input instances
67Typical Input Universes
- S The set of all finite length strings over
finite alphabet S - Examples
- a /\, a, aa, aaa, aaaa, aaaaa,
- a,b /\, a, b, aa, ab, ba, bb, aaa, aab, aba,
abb, - 0,1 /\, 0, 1, 00, 01, 10, 11, 000, 001, 010,
011, - The set of all integers
- If the input universe is understood, a decision
problem can be specified by just giving the set
of yes input instances
68Language Recognition Problem
- Input Universe
- S for some finite alphabet S
- Yes input instances
- Some set L subset of S
- No input instances
- S - L
- When S is understood, a language recognition
problem can be specified by just stating what L
is.
69Language Recognition Problem
- Traditional Formulation
- Input
- A string x over some finite alphabet S
- Task
- Is x in some language L subset of S?
- 3 set formulation
- Input Universe
- S for a finite alphabet S
- Yes input instances
- Some set L subset of S
- No input instances
- S - L
- When S is understood, a language recognition
problem can be specified by just stating what L
is.
70Equivalence of Decision Problems and Languages
- All decision problems can be formulated as
language recognition problems - Simply develop an encoding scheme for
representing all inputs of the decision problem
as strings over some fixed alphabet S - The corresponding language is just the set of
strings encoding yes input instances - In what follows, we will often use decision
problems and languages interchangeably
71Visualization
72Analyzing Programs which Solve Decision Problems
73Program Declaration
- Suppose a program P is designed to solve some
decision problem P. What does Ps declaration
look like? - What should P return on a yes input instance?
- What should P return on a no input instance?
74Program Declaration II
- Suppose a program P is designed to solve a
language recognition problem P. What does Ps
declaration look like? - bool main(string x)
- We will assume that the string declaration is
correctly defined for the input alphabet S - If S a,b, then string will define variables
consisting of only as and bs - If S a, b, , z, A, , Z, then string will
define variables consisting of any string of
alphabet characters
75Programs and Inputs
- Notation
- P denotes a program
- x denotes an input for program P
- 4 possible outcomes of running P on x
- P halts and says yes P accepts input x
- P halts and says no P rejects input x
- P halts without saying yes or no P crashes on
input x - We typically ignore this case as it can be
combined with rejects - P never halts P infinite loops on input x
76Programs and the Set of Legal Inputs
- Based on the 4 possible outcomes of running P on
x, P partitions the set of legal inputs into 4
groups - Y(P) The set of inputs P accepts
- When the problem is a language recognition
problem, Y(P) is often represented as L(P) - N(P) The set of inputs P rejects
- C(P) The set of inputs P crashes on
- I(P) The set of inputs P infinite loops on
- Because L(P) is often used in place of Y(P) as
described above, we use notation I(P) to
represent this set
77Illustration
All Inputs
I(P)
78Analyzing Programs and Decision Problems
- Distinguish the two carefully
79Program solving a decision problem
- Formal Definition
- A program P solves decision problem P if and only
if - The set of legal inputs for P is identical to the
set of input instances of P - Y(P) is the same as the set of yes input
instances for P - N(P) is the same as the set of no input instances
for P - Otherwise, program P does not solve problem P
- Note C(P) and I(P) must be empty in order for P
to solve problem P
80Solvable Problem
- A decision problem P is solvable if and only if
there exists some C program P which solves P - When the decision problem is a language
recognition problem for language L, we often say
that L is solvable or L is decidable - A decision problem P is unsolvable if and only if
all C programs P do not solve P - Similar comment as above
81Illustration of Solvability
Inputs of Program P
Y(P)
N(P)
82Program half-solving a problem
- Formal Definition
- A program P half-solves problem P if and only if
- The set of legal inputs for P is identical to the
set of input instances of P - Y(P) is the same as the set of yes input
instances for P - N(P) union C(P) union I(P) is the same as the set
of no input instances for P - Otherwise, program P does not half-solve problem
P - Note C(P) and I(P) need not be empty
83Half-solvable Problem
- A decision problem P is half-solvable if and only
if there exists some C program P which
half-solves P - When the decision problem is a language
recognition problem for language L, we often say
that L is half-solvable - A decision problem P is not half-solvable if and
only if all C programs P do not half-solve P
84Illustration of Half-Solvability
Inputs of Program P
Y(P)
N(P)
85Hierarchy of Decision Problems
All decision problems
The set of half-solvable decision problems is a
proper subset of the set of all decision
problems The set of solvable decision problems is
a proper subset of the set of half-solvable
decision problems.
86Why study half-solvable problems?
- A correct program must halt on all inputs
- Why then do we define and study half-solvable
problems? - One Answer the set of half-solvable problems is
the natural class of problems associated with
general computational models like C - Every program half-solves some decision problem
- Some programs do not solve any decision problem
- In particular, programs which do not halt do not
solve their corresponding decision problems
87Key Concepts
- Four possible outcomes of running a program on an
input - The four subsets every program divides its set of
legal inputs into - Formal definition of
- a program solving (half-solving) a decision
problem - a problem being solvable (half-solvable)
- Be precise with the above two statements!
88Module 5
- Topics
- Proof of the existence of unsolvable problems
- Proof Technique
- There are more problems/languages than there are
programs/algorithms - Countable and uncountable infinities
89Overview
- We will show that there are more problems than
programs - Actually more problems than programs in any
computational model (programming language) - Implication
- Some problems are not solvable
90Preliminaries
- Define set of problems
- Observation about programs
91Define set of problems
- We will restrict the set of problems to be the
set of language recognition problems over the
alphabet a. - That is
- Universe a
- Yes Inputs Some language L subset of a
- No Inputs a - L
92Set of Problems
- The number of distinct problems is given by the
number of languages L subset of a - 2a is our shorthand for this set of subset
languages - Examples of languages L subset of a
- 0 elements
- 1 element /\, a, aa, aaa, aaaa,
- 2 elements /\, a, /\, aa, a, aa,
- Infinite of elements an n is even, an n
is prime, an n is a perfect square
93Infinity and a
- All strings in a have finite length
- The number of strings in a is infinite
- The number of languages L in 2a is infinite
- The number of strings in a language L in 2a
may be finite or infinite
94Define set of programs
- The set of programs we will consider are the set
of legal C programs as defined in earlier
lectures - Key Observation
- Each C program can be thought of as a finite
length string over alphabet SP - SP a, , z, A, , Z, 0, , 9, white space,
punctuation
95Example
- int main(int A, int n) 26 characters
including newline - int i, max 13
characters including initial tab -
1 character newline - if (n lt 1) 12
characters - return (Illegal Input) 28 characters
including 2 tabs - max A0 13
characters - for (i 1 i lt n i) 25
characters - if (Ai gt max) 18
characters - max Ai 15
characters - return (max) 15
characters - 2
characters including newline
96Number of programs
- The set of legal C programs is clearly infinite
- It is also no more than SP
- SP a, , z, A, , Z, 0, , 9, white space,
punctuation
97Goal
- Show that the number of languages L in 2a is
greater than the number of strings in SP - SP a, , z, A, , Z, 0, , 9, white space,
punctuation - Problem
- Both are infinite
98How do we compare the relative sizes of infinite
sets?
- Bijection (yes)
- Proper subset (no)
99Bijections
- Two sets have EQUAL size if there exists a
bijection between them - bijection is a 1-1 and onto function between two
sets - Examples
- Set 1, 2, 3 and Set A, B, C
- Positive even numbers and positive integers
100Bijection Example
- Positive Integers Positive Even Integers
- 1 2
- 2 4
- 3 6
- ... ...
- i 2i
- ...
101Proper subset
- Finite sets
- S1 proper subset of S2 implies S2 is strictly
bigger than S1 - Example
- women proper subset of people
- number of women less than number of people
- Infinite sets
- Counterexample
- even numbers and integers
102Two sizes of infinity
103Countably infinite set S
- Definition 1
- S is equal in size (bijection) to N
- N is the set of natural numbers 1, 2, 3,
- Definition 2 (Key property)
- There exists a way to list all the elements of
set S (enumerate S) such that the following is
true - Every element appears at a finite position in the
infinite list
104Uncountable infinity
- Any set which is not countably infinite
- Examples
- Set of real numbers
- 2a, the set of all languages L which are a
subset of a - Further gradations within this set, but we ignore
them
105Proof
106(1) The set of all legal C programs is
countably infinite
- Every C program is a finite string
- Thus, the set of all legal C programs is a
language LC - This language LC is a subset of SP
107For any alphabet S, ? is countably infinite
- Enumeration ordering
- All length 0 strings
- S0 1 string l
- All length 1 strings
- S strings
- All length 2 strings
- S2 strings
-
- Thus, SP is countably infinite
108Example with alphabet a,b
- Length 0 strings
- 0 and l
- Length 1 strings
- 1 and a, 2 and b
- Length 2 strings
- 3 and aa, 4 and ab, 5 and ba, 6 and bb, ...
- Question
- write a program that takes a number as input and
computes the corresponding string as output
109(2) The set of languages in 2a is uncountably
infinite
- Diagonalization proof technique
- Algorithmic proof
- Typically presented as a proof by contradiction
110Algorithm Overview
- To prove this set is uncountably infinite, we
construct an algorithm D that behaves as follows - Input
- A countably infinite list of languages L subset
of a - Output
- A language D(L) which is a subset of a that
is not on list L
111Visualizing D
List L L0 L1 L2 L3 ...
Language D(L) not in list L
112Why existence of D implies result
- If the number of languages in 2a is countably
infinite, there exists a list L s.t. - L is complete
- it contains every language in 2a
- L is countably infinite
- The existence of algorithm D implies that no list
of languages in 2a is both complete and
countably infinite - Specifically, the existence of D shows that any
countably infinite list of languages is not
complete
113Visualizing One Possible L
l
a
aa
aaa
aaaa
...
- Rows is countably infinite
- Given
- Cols is countably infinite
- a is countably infinite
L0
L1
L2
L3
L4
...
- Consider each string to be a feature
- A set contains or does not contain each string
114Constructing D(L )
- We construct D(L) by using a unique feature
(string) to differentiate D(L) from Li - Typically use ith string for language Li
- Thus the name diagonalization
D(L)
l
a
aa
aaa
aaaa
...
OUT
L0
IN
IN
IN
IN
IN
L1
OUT
IN
IN
IN
OUT
IN
L2
OUT
OUT
OUT
OUT
OUT
IN
L3
IN
IN
OUT
OUT
OUT
IN
L4
IN
IN
OUT
OUT
OUT
OUT
...
115Questions
l
a
aa
aaa
aaaa
...
L0
IN
IN
IN
IN
IN
L1
OUT
IN
IN
IN
OUT
L2
OUT
OUT
OUT
OUT
OUT
L3
IN
IN
OUT
OUT
OUT
L4
IN
IN
OUT
OUT
OUT
...
- Do we need to use the diagonal?
- Every other column and every row?
- Every other row and every column?
- What properties are needed to construct D(L)?
116Visualization
All problems
The set of solvable problems is a proper subset
of the set of all problems.
117Summary
- Equal size infinite sets bijections
- Countable and uncountable infinities
- More languages than algorithms
- Number of algorithms countably infinite
- Number of languages uncountably infinite
- Diagonalization technique
- Construct D(L) using infinite set of features
- The set of solvable problems is a proper subset
of the set of all problems
118Module 6
- Topics
- Program behavior problems
- Input of problem is a program/algorithm
- Definition of type program
- Program correctness
- Testing versus Proving
119Number Theory Problems
- These are problems where we investigate
properties of numbers - Primality
- Input Positive integer n
- Yes/No Question Is n a prime number?
- Divisor
- Input Integers m,n
- Yes/No question Is m a divisor of n?
120Graph Theory Problems
- These are problems where we investigate
properties of graphs - Connected
- Input Graph G
- Yes/No Question Is G a connected graph?
- Subgraph
- Input Graphs G1 and G2
- Yes/No question Is G1 a subgraph of G2?
121Program Behavior Problems
- These are problems where we investigate
properties of programs and how they behave - Give an example problem with one input program P
- Give an example problem with two input programs
P1 and P2
122Program Representation
- Program variables
- Abstractly, we define the type program
- graph G, program P
- More concretely, we define type program to be a
string over the program alphabet SP a, , z,
A, , Z, 0, , 9, punctuation, white space - Note, many strings over SP are not legal programs
- We consider them to be programs that always crash
- Possible declaration of main procedure
- bool main(program P)
123Program correctness
- How do we determine whether or not a program P we
have written is correct? - What are some weaknesses of this approach?
- What might be a better approach?
124Testing versus Analyzing
Test Inputs x1 x2 x3 ...
Outputs P(x1) P(x2) P(x3) ...
Analysis of Program P
Program P
1252 Program Behavior Problems
- Correctness
- Input
- Program P
- Yes/No Question
- Does P correctly solve the primality problem?
- Functional Equivalence
- Input
- Programs P1, P2
- Yes/No Question
- Is program P1 functionally equivalent to program
P2
126Module 7
- Halting Problem
- Fundamental program behavior problem
- A specific unsolvable problem
- Diagonalization technique revisited
- Proof more complex
127Definition
- Input
- Program P
- Assume the input to program P is a single
unsigned int - This assumption is not necessary, but it
simplifies the following unsolvability proof - To see the full generality of the halting
problem, remove this assumption - Nonnegative integer x, an input for program P
- Yes/No Question
- Does P halt when run on x?
- Notation
- Use H as shorthand for halting problem when space
is a constraint
128Example Input
- Program with one input of type unsigned int
- bool main(unsigned int Q)
- int i2
- if ((Q 0) (Q 1)) return false
- while (iltQ)
- if (Qi 0) return (false)
- i
-
- return (true)
-
- Input x
- 4
129Three key definitions
130Definition of list L
- SP is countably infinite where SP
characters, digits, white space, punctuation - Type program will be type string with SP as the
alphabet - Define L to be the strings in SP listed in
enumeration order - length 0 strings first
- length 1 strings next
-
- Every program is a string in SP
- For simplicity, consider only programs that have
- one input
- the type of this input is an unsigned int
- Consider strings in SP that are not legal
programs to be programs that always crash (and
thus halt on all inputs)
131Definition of PH
- If H is solvable, some program must solve H
- Let PH be a procedure which solves H
- We declare it as a procedure because we will use
PH as a subroutine - Declaration of PH
- bool PH(program P, unsigned int x)
- In general, the type of x should be the type of
the input to P - Comments
- We do not know how PH works
- However, if H is solvable, we can build programs
which call PH as a subroutine
132Definition of program D
- bool main(unsigned int y) / main for program D
/ - program P generate(y)
- if (PH(P,y)) while (1gt0) else return (yes)
- / generate the yth string in SP in enumeration
order / - program generate(unsigned int y)
- / code for program of slide 21 from module 5
did this for a,b / - bool PH(program P, unsigned int x)
- / how PH solves H is unknown /
133Generating Py from y
- We wont go into this in detail here
- This was the basis of the question at the bottom
of slide 21 of lecture 5 (alphabet for that
problem was a,b instead of SP). - This is the main place where our assumption about
the input type for program P is important - for other input types, how to do this would vary
- Specification
- 0 maps to program l
- 1 maps to program a
- 2 maps to program b
- 3 maps to program c
-
- 26 maps to program z
- 27 maps to program A
-
134Proof that H is not solvable
135Argument Overview
H is solvable
D is NOT on list L
136Proving D is not on list L
- Use list L to specify a program behavior B that
is distinct from all real program behaviors (for
programs with one input of type unsigned int) - Diagonalization argument similar to the one for
proving the number of languages over a is
uncountably infinite - No program P exists that exhibits program
behavior B - Argue that D exhibits program behavior B
- Thus D cannot exist and thus is not on list L
137Non-existent program behavior B
138Visualizing List L
0
1
2
3
4
...
- Rows is countably infinite
- Sp is countably infinite
- Cols is countably infinite
- Set of nonnegative integers is countably infinite
P0
P1
P2
P3
P4
...
- Consider each number to be a feature
- A program halts or doesnt halt on each integer
- We have a fixed L this time
139Diagonalization to specify B
- We specify a non-existent program behavior B by
using a unique feature - (number) to differentiate B from Pi
0
1
2
3
4
...
B
P0
NH
H
H
H
H
H
P1
NH
H
H
H
NH
H
P2
NH
NH
NH
NH
NH
H
P3
H
H
NH
NH
NH
H
P4
NH
H
H
H
H
H
...
140Arguing D exhibits program behavior B
141Code for D
- bool main(unsigned int y) / main for program D
/ - program P generate(y)
- if (PH(P,y)) while (1gt0) else return (yes)
- / generate the yth string in SP in enumeration
order / - program generate(unsigned int y)
- / code for extra credit program of slide 21
from lecture 5 did this for a,b / - bool PH(program P, unsigned int x)
- / how PH solves H is unknown /
142Visualization of D in action on input y
- Program D with input y
- (type for y unsigned int)
- Given input y, generate the program (string) Py
- Run PH on Py and y
- Guaranteed to halt since PH solves H
- IF (PH(Py,y)) while (1gt0) else return (yes)
0
1
2
...
D
...
y
P0
H
H
H
P1
H
H
NH
P2
NH
NH
NH
...
Py
H
NH
...
143Alternate Proof
144Alternate Proof Overview
- For every program Py, there is a number y that we
associate with it - The number we use to distinguish program Py from
D is this number y - Using this idea, we can arrive at a contradiction
without explicitly using the table L - The diagonalization is hidden
145H is not solvable, proof II
- Assume H is solvable
- Let PH be the program which solves H
- Use PH to construct program D which cannot exist
- Contradiction
- This means program PH cannot exist.
- This implies H is not solvable
- D is the same as before
146Arguing D cannot exist
- If D is a program, it must have an associated
number y - What does D do on this number y?
- 2 cases
- D halts on y
- This means PH(D,y) NO
- Definition of D
- This means D does not halt on y
- PH solves H
- Contradiction
- This case is not possible
147Continued
- D does not halt on this number y
- This means PH(D,y) YES
- Definition of D
- This means D halts on y
- PH solves H
- Contradiction
- This case is not possible
- Both cases are not possible, but one must be for
D to exist - Thus D cannot exist
148Implications
- The Halting Problem is one of the simplest
problems we can formulate about program behavior - We can use the fact that it is unsolvable to show
that other problems about program behavior are
also unsolvable - This has important implications restricting what
we can do in the field of software engineering - In particular, perfect debuggers/testers do not
exist - We are forced to test programs for correctness
even though this approach has many flaws
149Summary
- Halting Problem definition
- Basic problem about program behavior
- Halting Problem is unsolvable
- We have identified a specific unsolvable problem
- Diagonalization technique
- Proof more complicated because we actually need
to construct D, not just give a specification B
150Module 8
- Closure Properties
- Definition
- Language class definition
- set of languages
- Closure properties and first-order logic
statements - For all, there exists
151Closure Properties
- A set is closed under an operation if applying
the operation to elements of the set produces
another element of the set - Example/Counterexample
- set of integers and addition
- set of integers and division
152Integers and Addition
7
Integers
153Integers and Division
.4
2
5
Integers
154Language Classes
- We will be interested in closure properties of
language classes - A language class is a set of languages
- Thus, the elements of a language class (set of
languages) are languages which are sets
themselves - Crucial Observation
- When we say that a language class is closed under
some set operation, we apply the set operation to
the languages (elements of the language classes)
rather than the language classes themselves
155Example Language Classes
- In all these examples, we do not explicitly state
what the underlying alphabet S is - Finite languages
- Languages with a finite number of strings
- CARD-3
- Languages with at most 3 strings
156Finite Sets and Set Union
0,1,00,11
Finite Sets
157CARD-3 and Set Union
0,1,00,11
CARD-3
CARD-3 sets with at most 3 elements
158Finite Sets and Set Complement
/\,00,10,11,000,...
0,1,01
Finite Sets
159Infinite Number of Facts
- A closure property often represents an infinite
number of facts - Example The set of finite languages is closed
under the set union operation - union is a finite language
- union l is a finite language
- union 0 is a finite language
- ...
- l union is a finite language
- ...
160First-order logic and closure properties
- A way to formally write (not prove) a closure
property - For all L1, ...,Lk in LC, op (L1, ... Lk) in LC
- Only one expression is needed because of the for
all quantifier - Number of languages k is determined by arity of
the operation op
161Example F-O logic statements
- For all L1,L2 in FINITE, L1 union L2 in FINITE
- For all L1,L2 in CARD-3, L1 union L2 in CARD-3
- For all L in FINITE, Lc in FINITE
- For all L in CARD-3, Lc in CARD-3
162Stating a closure property is false
- What is true if a set is not closed under some
k-ary operator? - There exist k elements of that set which, when
combined together under the given operator,
produce an element not in the set - There exists L1, ...,Lk in LC, op (L1, , Lk) not
in LC - Example
- Finite sets and set complement
163Complementing a F-O logic statement
- Complement For all L1,L2 in CARD-3, L1 union L2
in CARD-3 - not (For all L1,L2 in CARD-3, L1 union L2 in
CARD-3) - There exists L1,L2 in CARD-3, not (L1 union L2 in
CARD-3) - There exists L1,L2 in CARD-3, L1 union L2 not in
CARD-3
164Proving/Disproving
- Which is easier and why?
- Proving a closure property is true
- Proving a closure property is false
165Module 9
- Recursive and r.e. language classes
- representing solvable and half-solvable problems
- Proofs of closure properties
- for the set of recursive (solvable) languages
- for the set of r.e. (half-solvable) languages
- Generic element/template proof technique
- Relationship between RE and REC
- pseudoclosure property
166RE and REC language classes
- REC
- A solvable language is commonly referred to as a
recursive language for historical reasons - REC is defined to be the set of solvable or
recursive languages - RE
- A half-solvable language is commonly referred to
as a recursively enumerable or r.e. language - RE is defined to be the set of r.e. or
half-solvable languages
167Why study closure properties of RE and REC?
- It tests how well we really understand the
concepts we encounter - language classes, REC, solvability,
half-solvability - It highlights the concept of subroutines and how
we can build on previous algorithms to construct
new algorithms - we dont have to build our algorithms from
scratch every time
168Example Application
- Setting
- I have two programs which can solve the language
recognition problems for L1 and L2 - I want a program which solves the language
recognition problem for L1 intersect L2 - Question
- Do I need to develop a new program from scratch
or can I use the existing programs to help? - Does this depend on which languages L1 and L2 I
am working with?
169Closure Properties of REC
- We now prove REC is closed under two set
operations - Set Complement
- Set Intersection
- In these proofs, we try to highlight intuition
and common sense
170Set Complement Example
- Even the set of even length strings over 0,1
- Complement of Even?
- Odd the set of odd length strings over 0,1
- Is Odd recursive (solvable)?
- How is the program P that solves Odd related to
the program P that solves Even?
171Set Complement Lemma
- If L is a solvable language, then L complement is
a solvable language - Proof
- Let L be an arbitrary solvable language
- First line comes from For all L in REC
- Let P be the C program which solves L
- P exists by definition of REC
172proof continued
- Modify P to form P as follows
- Identical except at very end
- Complement answer
- Yes -gt No
- No -gt Yes
- Program P solves L complement
- Halts on all inputs
- Answers correctly
- Thus L complement is solvable
- Definition of solvable
173P Illustration
YES
P
Input x
No
174Code for P
- bool main(string y)
-
- if (P (y)) return no else return yes
-
- bool P (string y)
- / details deleted key fact is P is guaranteed
to halt on all inputs /
175Set Intersection Example
- Even the set of even length strings over 0,1
- Mod-5 the set of strings of length a multiple of
5 over 0,1 - What is Even intersection Mod-5?
- Mod-10 the set of strings of length a multiple
of 10 over 0,1 - How is the program P3 (Mod-10) related to
programs P1 (Even) and P2 (Mod-5)
176Set Intersection Lemma
- If L1 and L2 are solvable languages, then L1
intersection L2 is a solvable language - Proof
- Let L1 and L2 be arbitrary solvable languages
- Let P1 and P2 be programs which solve L1 and L2,
respectively
177proof continued
- Construct program P3 from P1 and P2 as follows
- P3 runs both P1 and P2 on the input string
- If both say yes, P3 says yes
- Otherwise, P3 says no
- P3 solves L1 intersection L2
- Halts on all inputs
- Answers correctly
- L1 intersection L2 is a solvable language
178P3 Illustration
Yes/No
P1
Yes/No
P2
179Code for P3
- bool main(string y)
-
- if (P1(y) P2(y)) return yes
- else return no
-
- bool P1(string y) / details deleted key fact
is P1 always halts. / - bool P2(string y) / details deleted key fact is
P2 always halts. /
180Other Closure Properties
- Unary Operations
- Language Reversal
- Kleene Star
- Binary Operations
- Set Union
- Set Difference
- Symmetric Difference
- Concatena