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Public-Key Cryptography

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Title: Public-Key Cryptography


1
Chapter 3
  • Public-Key Cryptography
  • and Message Authentication

2
Recall
In chapter 3 Authentication includes all three
of these services
3
We need to defend against attacks such as
? bit flipping in stream cipher (my
time-of-attack example)
? cut and paste attack with ECB
4
3.1 Approaches to Message Authentication
Authentication Using Conventional (Symmetric)
Encryption Assuming that only sender and receiver
share a secret key, then successful decryption of
a message proves that it is from the sender.
But what about the Christmas bonus cut-and-paste
attack?
If the message also includes error-detection and
a sequence number, the receiver is assured that
no alteration has been made and that the
sequencing is proper.
Circular reasoning!
5
Message Authentication without Message
Encryption We may want to be able to authenticate
a message without encrypting it Examples
1. Public announcement, e.g. The system is going
down in 5 minutes!
2. Receiver to busy to decrypt incoming messages.
3. Checking integrity of a computer program
downloaded from a server.
Encryption and Authentication are
separate Either or both may be needed
6
Message Authentication Code A secret key is used
to generate a small block of data, the MAC, which
is appended to the message by the sender.
Knowing the secret key and the message, the
receiver re-calculates the MAC and compares it to
the appended value.
Sender calculates MAC
Secret
Recalculating the MAC is a forward calculation
fundamentally different from the reverse
calculation in decryption.
7
Message Authentication Code continued If the
appended code and the freshly-calculated code
agree, then
1. The receiver is assured that the message has
not been altered. (Chapter 1 data integrity
connectionless)
2. The receiver is assured that the message is
from the alleged sender, since nobody
else knows the secret key. (Chapter 1
participant authentication)
3. If the message includes a sequence number, the
receiver is assured that there are no
losses, duplications, or out-of-sequence
elements. (Chapter 1 data integrity
connection-oriented)
4. The sender cannot deny having sent the
message, since nobody else knows the
secret key. (Chapter 1 nonrepudiation)
Provided that suitable algorithms can be found to
generate the Message Authentication Code!
8
One-Way Hash Functions Given a message, M, of
arbitrary length a hash function produces a
short, fixed-length block that is unique to M
(fingerprint)
A hash function is a component of a MAC
system. It is not the complete system because a
hash itself does not involve any secret
information.
Figure 3.2 shows three ways to use hash functions
in producing a MAC.

9
Figure 3.2(a) is essentially the same as figure
3.1
Figure 3.2(b) is the same as 3.2(a), except using
public-key encryption (defer until later).


10
One-Way Hash Functions continued Figures 3.2
(a) and (b) involve encryption, which is slow and
expensive. Figure 3.2(c) is an alternative that
avoids encryption
Pre-Shared secret Not transmitted


This method is used in HMAC (see later) Sometimes
referred to as keyed hash
11
Recall from page 7 2. In developing a particular
security mechanism or algorithm, one must always
consider potential attacks on those security
features
3. Because of point 2, the procedures used to
provide particular services are often
counterintuitive It is not obvious from the
statement of a particular requirement that such
elaborate measures are needed. It is only when
the various counter-measures are considered that
the measures used make sense.
12
3.2 Secure Hash Functions Hash function
requirements
  1. H can be applied to a block of data of any size.
  2. H produces fixed-length output.
  3. H(x) is relatively easy to compute for any x,
    making both hardware and software implementation
    practical.

4. For any given value h it is computationally
infeasible to find x such that H(x)
h
Called one-way or preimage resistant
13
4. For any given value h it is computationally
infeasible to find x such that H(x)
h

Without the one-way property method (c) would
not work
Encryption functions must be reversible Hash
functions must not be reversible!
14
5. For any given block x, it is computationally
infeasible to find y ? x with H(y)
H(x)
Called second preimage resistant or weak
collision resistant


Without property 5 methods 3.2 (a) and (b) would
not work
15
3.2 Secure Hash Functions - continued
6. It is computationally infeasible to find any
pair (x, y) such that H(x)
H(y)
Called (strong) collision-resistant
This property is necessary to defend against the
birthday attack.
16
Birthday Attack
Probability that two specific people have same
birthday is 1/365
In a group of n people there are n(n-1)/2 pairs
Probability that any two people have same
birthday is n(n-1)/(2 365)
What does n have to be for probability to be 0.5?
Approximating n(n-1) as n2 we get n2 2
365 0.5 or n v365 about 19
With 128-bit hash function, probability that two
specific messages have same hash value is 2-128
But probability that two messages exist with same
hash value is 2-64
17
Security of Hash Functions Clearly, it is
desirable to use a hash function that has
property 6, strong collision resistance.
For a hash code of length n bits we expect the
level of effort required to break it by brute
force to be 2n BUT
Preimage-resistant (property 4) 2n/2
(yields to Birthday Attack) Second
preimage resistant (property 5) 2n/2
(yields to Birthday Attack)
Strong collision resistant (property 6) 2n
(resists Birthday Attack)
A 160-bit hash code is now regarded as suspect!
18
Simple Hash Functions
Ci bi1 XOR bi2 XOR bi3 . XOR bim
But XOR is commutative, so could permute blocks
without changing C
OK for accidental transmission errors, but
useless for defense against Darth.
19
SHA Secure Hash Function

Focus on SHA-512 - block size 1024 bits, hash
code size 512 bits.
Security 256 indicates that SHA does not have
property 6
20
Step 1 Append padding bits. Step 2 Append
original length


21
Often referred to as the compression function
property of SHA-512 Every bit of hash code is a
function of every bit of the input
22
3.3 Message Authentication Codes
Hashed Message Authentication Code (HMAC) A hash
function such as SHA-512 involves no secret
information hash must be combined with secret
information to produce a message authentication
code.
Figure 3.2
23
HMAC Design Objectives
1. To use, without modification, available hash
functions.
2. To allow for easy replaceability of the
embedded hash function in case more
secure hash functions are found or required
(NIST competition for new hash function).
3. To preserve the original performance of the
hash function without incurring
significant degradation.
4. To use and handle keys in a simple way
5. To have a well-understood cryptographic
analysis of the strength of the authentication
mechanism based on reasonable assumptions
on the embedded hash function.
HMAC can be proven secure provided that the
embedded hash function has some reasonable
cryptographic strengths.
24
Repeat HMAC Design Objectives 2. To allow for
easy replaceability of the embedded hash function
in case more secure hash functions
are found or required
If the embedded hash function were ever
discovered to be insecure, a replacement (more
secure) hash function could be inserted into
HMAC. Use of the original hash function before
the discovery would not be invalidated.
This assumes that whoever discovered the
insecurity announced it and didnt exploit it
privately!
This contrasts with the situation with
encryption if an encryption algorithm were
broken, messages previously encrypted with the
algorithm could be decrypted.
25
The HMAC Algorithm
First part of key padded to b bits
Padded Message
SHA-512
Second part of key padded to b bits
Result of inner hash is message for outer hash
HMAC adds three executions of the basic hash
function should not add significant time for
long messages.
SHA-512
Final result
26
MACs Based on Block Ciphers Cipher-Based Message
Authentication Code We adopted the philosophy
that encryption and authentication have separate
objectives and techniques. Why merge them here?
Quote from NIST publication 800-38B CMAC may be
appropriate for information systems in which an
approved block cipher is more readily available
than an approved hash function. This does not
seem to be a compelling reason to study this.
On the other hand, Stallings (p77) states that
systems that simultaneously protect
confidentiality and authenticity (integrity) of
communications may have advantages (and may be
mandated in federal systems).
Because of the limited time we have available, we
will omit this section.
27
3.4 Public-Key Cryptography Principles Public-Key
Encryption Structure
? first publicly proposed by Diffie and Hellman
in 1976 (but known to British
cryptographers in WWII)
? first truly revolutionary advance in encryption
in literally thousands of years
? public-key algorithms based on mathematical
functions
? public-key cryptography is asymmetric,
involving use of two separate keys, one
made public and the other kept private.
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29
Common misconceptions about public-key
cryptography
? public-key cryptography more secure than
symmetric (conventional)
cryptography
For same key length public-key is less secure
1024-bit asymmetric keys are about as secure as
80-bit symmetric keys.
30
Common misconceptions about public-key
cryptography - continued
? public-key cryptography is a general-purpose
technique that has made symmetric
(conventional) cryptography obsolete
public-key is about 1,000 times slower than
symmetric, so will not replace symmetric for bulk
encryption
? key distribution is trivial when using
public-key encryption, compared to
cumbersome key distribution centers in symmetric
encryption
public-key distribution usually involves a
central agent
31
Recall from section 2.1 A symmetric encryption
scheme has five ingredients
Section 3.4 A public-key encryption scheme has
six ingredients
? plaintext
? encryption algorithm
? public and private key
? ciphertext
? decryption algorithm
32
? public and private key The public key of the
pair is made public for others to use The
private key is known only to its owner.
One key of the pair is used for encryption, the
other for decryption
Terminology although the private key is kept
secret, we refer to it as private so as not to
confuse with the secret key of symmetric
encryption.
33
Figure 3.9 (a)
Bob
Alice
Essential steps for confidentiality 1. Each
user generates a pair of keys
2. Each user places one of the keys in a public
register
or other accessible file
3. If Bob wishes to send a confidential message
to Alice, he obtains her public key and
encrypts the message with it.
4. Alice decrypts the message with her private
key.
34
Bob obtained these from public register or other
accessible file
Figure 3.9
No authentication of Bob! Everybody knows
Alices public key!
We do not send long messages this way!
35
Applications for Public-Key Cryptosystems
? encryption/decryption but not used for long
messages,
? digital signatures we will study in section
3.6
? key exchange we will study in section 4.3
36
Requirements for Encryption using Public-Key
Cryptography
1. It is computationally easy for party B to
generate a key pair PUB, PRB
2. It is computationally easy for a sender A,
knowing PUB to encrypt a (short)
message to send to B
3. It is computationally easy for B to decrypt
the message using his/her
private key
4. It is computationally infeasible for an
opponent, knowing PUB to
determine the private key PRB
5. It is computationally infeasible for an
opponent, knowing PUB and the
ciphertext, to recover the plaintext
6. (useful, not required) Either of the two
related keys can be used for
encryption, the other for decryption
37
3.5 Public-Key Cryptography Algorithms The RSA
Algorithm Developed in 1977 by Rivest, Shamir,
and Adleman at MIT.
RSA is a block cipher in which the plaintext and
ciphertext are represented by integers between 0
and n 1 for some n (modulus)
For plaintext block M, the ciphertext block C is
obtained by C Me mod n
e could be called the encryption exponent
The plaintext is recovered by M Cd mod n
If both sender and receiver know n and e but only
the receiver knows d, the receivers public key
is e, n and private key is d, n
38
3.4 Public-Key Cryptography Algorithms -
continued From previous slide
For plaintext block M, the ciphertext block C is
obtained by C Me mod n
The plaintext is recovered by M Cd mod n
M Cd mod n (Me mod n)d mod n Med
mod n
1. For this to work, it must be possible to find
n, e, and d such that Med mod n M for all M lt
n
2. It must be relatively easy to calculate Me and
Cd for all M lt n
3. It must be infeasible to compute d, given e
and n
39
1 3. Select p 17, q 11 so n 187 and
f(n) 160
4. Choose e such that it is relatively prime to
160 and less than 160
Divisors of 160? yes 1, 2, 4, 5, 8,
10 no 3 6, 7 9
11, 12, 13 .
Choose e 7
40
1 3. Select p 17, q 11 so n 187 and
f(n) 160 4. e 7
5. Determine d such that de mod 160 1
7d 1, 161, 321, 481 ..
7 23 161
Public key is 7, 187 Private key is 23,
187
41
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42
Encryption evaluate 887 mod 187
Decryption evaluate 1123 mod 187
1123 is a big number and hard to handle by simple
programming!
Factorize the big number and use properties of
modular arithmetic (page 402)
43
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45
An actual RSA key (from lab session 2)
leftrsasigkey0sAQOc8zSaKhfo46XdLSBzFLDOadFDitIU
XfL3bP9v7aWH5seCtYrDV7bfAnzHmYqJ6yClH8cJEEYUvdVtO3
/2H2dGLeigTD1XuKQzxrFeFbV66W6s06WdVEZfu7k0gWVF
HTjAUkXDZV8cVU94m7KHVjAyx45GPN4/YOoMgN3t1QCdSGyt
lulyc42oosrWow8dv3oxVgwHUsHRF1aUoT7RcOZ9m9V6UsI
ZXK5coXOJAN6f2T690dUBMcZvCYiBmi6RJAZ1DZncrQFxOtFft
75qC0VJvUufcMtLYQ6dMhcQFkO58efN2tXAtCEuzGUSVh2ftm
/hf7S0qsjWaZXQWiCy9NH3V7HhZVF2KzTH The
exponent of the RSA public key is forced to the
value 3
This modulus is 2238 bits long
46
Two possible approaches to defeating the RSA
algorithm
? brute force (try all possible keys) for
key-length (say) 1024 bits, this is infeasible
? try to factor n into p x q - most efforts do
this, but with n (say) 300 decimal digits, its
hard!
47
RSA Challenges
48
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49
RSA 640 If modulus, n, is the 193-digit
number 310 7418240490 0437213507 5003588856
7930037346 0228427275 4572016194 8823206440
5180815045 5634682967 1723286782 4379162728
3803341547 1073108501 9195485290 0733772482
2783525742 3864540146 9173660247 7652346609 What
are p and q?
The factoring research team of F. Bahr, M. Boehm,
J. Franke, T. Kleinjung continued its
productivity with a successful factorization of
the challenge number RSA-640, reported on
November 2, 2005. The factors are 16347336458092
5384844313388386509085984178367003309231218111085
2389333100104508151212118167511579 and 1900871
281664822113126851573935413975471896789968
515493666638539088027103802104498957191261465571
The effort took approximately 30
2.2GHz-Opteron-CPU years according to the
submitters, over five months of calendar time.
They earned a prize of 20,000.
50
Diffie-Hellman Key Exchange The purpose of the
algorithm is to enable two users to exchange a
secret key securely that can then be used for
subsequent symmetric encryption of messages.
The algorithm itself is limited to the exchange
of the keys.
(however, an extension of D-H, known as El Gamal
can be used for encryption)
The Diffie-Hellman algorithm depends for its
effectiveness on the difficulty of computing
discrete logarithms.
51
modulus
generator
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53
Global public parameters q and a established in
advance
Figure 3.13
54
Required to prove the two computations of K give
the same value
55
Required to prove the two computations of K give
the same value
56
Trivial example of Diffie-Hellman problem 3.21
57
Problem 3.21(a) If A has public key YA 9.
what is As private key XA? Recall YA aXA mod
q Want 9 2XA mod 11
From previous slide 64 mod 11 9 so XA 6
Because of the difficulty of computing discrete
logarithms, an attacker knowing a, q, YA and YB
cannot easily compute K
Problem 3.21(b) If B has public key YB 3,
what is shared key K ? Recall K (YB)XA mod q
36 mod 11 729 mod 11 3
58
3192-bit Diffie-Hellman public key (from lab
session 4)
59
Key Exchange Protocols ways of using
Diffie-Hellman
? simple protocol figure 3.13
? using a central repository of public D-H keys
(next slide).
60
In this implementation, both private and public
DH keys are semi-permanent
61
Man-in-the-Middle Attack
Alice
Bob
Problem the simple protocol does not
authenticate the participants.
Well return to this problem in chapter 8
62
Other Public-Key Cryptography Algorithms ?
Digital Signature Standard - use in lab session
1 ? Elliptic-Curve Cryptography know it
exists (increasing importance)
63
3.6 Digital Signatures Bob wants to send a
message to Alice its not confidential, but he
wants her to be sure that it is from him
(authentication).
Fig 3.9(b)
Bob
Alice
Here, the entire message serves as a digital
signature Bob would normally encrypt just a hash
of the message and append it (next slide).
64
Figure 3.2(b) was a better representation of
digital signatures
Caution! Alice and Bob swapped from previous
slide!
Alice
Bob
Figure 3.2

65
Benefits of the Digital Signature
? Since only Alice knows her private key, if Bob
can decode and verify the signature with
her public key, the message must have come
from Alice
(giving
authentication and non-repudiation).
? Without Alices private key, Darth cannot
substitute a different message and produce
a correctly-encrypted hash
(giving message integrity).
66
Benefits of the Digital Signature
But this does not provide message confidentiality!
? The signature (encrypted hash of the message)
can be detached from the message itself.
Because the hash refers uniquely to the
particular message, Darth cannot claim that
the detached signature belongs to a different
message (useful when several people in
different countries must sign).
67
End of Chapter 3
At this point in the course we have covered all
the basic techniques needed to provide
confidentiality and authentication services. In
the rest of the course we examine specific
implementations for use in various situations.
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69
Part TwoNetwork Security Applications
  • Chapter 4
  • Key Distribution and User Authentication

70
4.1 Symmetric Key Distribution Using Symmetric
Encryption Possible methods of key sharing
between A and B
1. A selects key, physically delivers to B
2. Third party C selects key, physically
delivers to A and B
3. If A and B have previously shared a key, a
new key could be chosen by one of them
and sent to the other encrypted with the old
key
Problem If an attacker ever succeeds in gaining
access to one key, then all subsequent keys are
revealed.
4. If A and B each have an encrypted connection
to a trusted third party C, C could generate
the key and transmit it to A and B
over the encrypted connections
C is called the Key Distribution Center (KDC)
71
Key Distribution Center (KDC) uses two types of
key
? Session Key used to protect messages between
two users
? Master key used to protect messages between a
user and the KDC
Master key B ? C
Master key A ? C
Session key A ? B
72
Oppliger Unfortunately, KDCs have many
disadvantages.
The most important disadvantage is that each
entity must unconditionally trust the KDC and
share a secret master key with it. There are
situations in which this level of trust is
neither justified nor can be accepted by the
communicating entities.
Consequently, the use of key establishment
protocols (that typically make used of public key
cryptography in some way or another) provide a
viable alternative in many situations.
73
4.3 Key Distribution Using Asymmetric Encryption
Two aspects ? distribution of public keys
? use of public-key encryption to share secret
keys for symmetric cryptography.
At first thought there is no problem
just put your public key on a bulletin board!
Problem somebody else posts a key, stating it to
be yours.
Need a trusted third party to certify that the
public key is yours, and distribute it.
The trusted third party is called a Certificate
Authority, which issues Public Key Certificates
(next section).
74
Fig 4.3 Public-Key Certificate Generation
75
This uses a digital signature to authenticate the
certificate.
The certificate can then be used to authenticate
the holders digital signatures.
Bob
Alice
Figure 3.2
76
Public-Key Distribution of Secret (symmetric
cryptography) Keys Bob and Alice may be
geographically distant how to exchange key?
? Diffie-Hellman (but no authentication)
? use public-key encryption 1. Bob prepares
a message
2. He encrypts it using symmetric algorithm,
using one-time session key
3. He encrypts the session key with Alices
public key
4. He attaches the encrypted session key to the
encrypted message
5. Alice uses her private key to decrypt the
session key
6. Alice reverses the symmetric encryption of
the message
76
77
4.4 X.509 Certificates
We used public-key certificates in the previous
section Here we give details of the generation
and standard form of a public-key certificate,
X.509
X.509 defines a framework for the provision of
authentication services by the X.500 directory to
its users
78
hash
Figure 4.4 X.509 Formats
79
little, if any, utility
Certificate binds these two together
The only encryption in the certificate
hash
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81
Characteristics of the X.509 Certificate User
certificates generated by a CA have the following
characteristics
? Any user with access to the public key of the
CA can verify the user public
key that was certified.
? No party other than the certification
authority can modify the certificate
without this being detected.
How do you get the CAs public key?
82
Tools gt Options gt Advanced gt View
Certificates
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86
Revocation of Certificate Although the
certificate includes an expiration date, it may
be necessary to revoke a certificate before then
(eg. private key revealed). CA needs to publish
periodic revocation lists.
Must be signed by CA!
hash
87
Reasons for Revocation of Certificates
? Confidentiality of the users private key has
been compromised.
? The user is no longer certified by this CA
? The CAs certificate is assumed to be
compromised (CAs private key has been
released)
From Peterson and Davie .. If all certificates
had unlimited life spans, the Certificate
Revocation List would always be getting longer,
since you could never take a certificate off the
CRL for fear that some copy of the revoked
certificate might be used. However, by attaching
an expiration date to a certificate when it is
issued, we can limit the length of time that a
revoked certificate has to stay on the CRL.
88
Omit 4.2 Kerberos
Omit 4.5 Public-Key Infrastructure
Omit 4.6 Federated Identity Management
End Chapter 4
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