Title: Point Estimation of Parameters and Sampling Distributions
1Point Estimation of Parameters and Sampling
Distributions
- Outlines
- Sampling Distributions and the central limit
theorem - Point estimation
- Methods of point estimation
- Moments
- Maximum Likelihood
2Sampling Distributions and the central limit
theorem
- Random Sample
- Sampling distribution the probability
distribution of a statistic. - Ex. The probability distribution of is called
distribution of the mean.
3Sampling Distributions of sample mean
- Consider the sampling distribution of the sample
mean. - Xi is a normal and independent probability, then
4Central limit theorem
- n gt 30, sampling from an unknown population gt
the sampling distribution of will be
approximated as normal with mean µ and ?2/n.
5Central limit theorem
6Central limit theorem
- Ex. Suppose that a random variable X has a
continuous uniform distribution - Find the distribution of the sample mean of a
random sample of size n40 - Method 1.Calculate the value of mean and
variance of x - 2.
7Sampling Distribution of a Difference
- Two independent populations.
- Suppose that both populations are normally
distributed. - Then, the sampling distribution of is
normal with
µ1 ,?12
µ2 ,?22
8Sampling Distribution of a Difference
9Sampling Distribution of a Difference
- Ex. The effective life of a jet-turbine aircraft
engine is a random variable with mean 5000 hr.
and sd. 40 hr. The distribution of effective life
is fairly close to a normal distribution. The
engine manufacturer introduces an improvement
into the manufacturing process for the engine
that increases the mean life to 5050 hr. and
decrease sd. to 30 hr. - 16 components are sampling from the old process.
- 25 components are sampling from the improve
process. - What is the probability that the difference in
the two sample means is at least 25 hr?
10Point estimation
- Parameter Estimation calculation of a reasonable
number that can explains the characteristic of
population. - Ex. X is normally distributed with unknown mean
µ. - The Sample mean( ) is a point estimator of
population mean (µ) gt - After selecting the sample, is the point
estimate of µ.
11Point estimation
12Point estimation
- Ex. Suppose that X is a random variable with mean
µ and variance s2 . Let X1,X2 ,..., Xn be a
random sample of size n from the population. Show
that the sample mean and sample variance S2
are unbiased estimators of µ and s2 ,
respectively. - proof,
- proof,
13Point estimation
14Point estimation
- Sometimes, there are several unbiased estimators
of the sample population parameter. - Ex. Suppose we take a random sample of size n
from a normal population and obtain the data x1
12.8, x2 9.4, x3 8.7, x4 11.6, x5 13.1,
x6 9.8, x7 14.1,x8 8.5, x9 12.1, x10
10.3.
all of them are unbiased estimator of µ
15Point estimation
- Minimum Variance Unbiased Estimator (MVUE)
16Point estimation
17Method of Point Estimation
- Method of Moment
- Method of Maximum Likelihood
- Bayesian Estimation of Parameter
18Method of Moments
- The general idea of the method of moments is to
equate the population moments to the
corresponding sample moments. - The first population moment is E(X)µ........(1)
- The first sample moment is
........(2) - Equating (1) and (2),
- The sample mean is the moment estimator of the
population mean
19Method of Moments
- Moment Estimators
- Ex. Suppose that X1,X2 ,..., Xn be a random
sample from an exponential distribution with
parameter ?. Find the moment estimator of ? - There is one parameter to estimate, so we must
equate first population moment to first sample
moment. - first population moment E(X)1/?, first sample
moment
20Method of Moments
- Ex. Suppose that X1,X2 ,..., Xn be a random
sample from a normal distribution with parameter
µ and s2. Find the moment estimators of µ and s2. - For µ k1 The first population moment is E(X)µ
........(1) - The first sample moment is
........(2) - Equating (1) and (2),
- For s2 k2 The second population moment is
E(X2)µ2s2 ......(3) - The second sample moment is
......(4) - Equating (3) and (4),
-
21Method of Maximum Likelihood
- Concept the estimator will be the value of the
parameter that maximizes the likelihood function.
22Method of Maximum Likelihood
- Ex. Let X be a Bernoulli random variable. The
probability mass function is
23Method of Maximum Likelihood
- Ex. Let X be normally distributed with unknown µ
and known s2. Find the maximum likelihood
estimator of µ
24Method of Maximum Likelihood
- Ex. Let X be exponentially distributed with
parameter ?. Find the maximum likelihood
estimator of ?.
25Method of Maximum Likelihood
- Ex. Let X be normally distributed with unknown µ
and unknown s2. Find the maximum likelihood
estimator of µ, and s2. -
26Method of Maximum Likelihood
- The method of maximum likelihood is often the
estimation method that mathematical statisticians
prefer, because it is usually easy to use and
produces estimators with good statistical
properties.