X-Ray Diffraction - PowerPoint PPT Presentation

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X-Ray Diffraction

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X-Ray Diffraction Path Length Phase Difference For a new atom in a unit cell yb xa Diffraction angle: 2 d sin = sin = /2d Reflection from plane through new atom ... – PowerPoint PPT presentation

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Title: X-Ray Diffraction


1
X-Ray Diffraction
  • Path Length
  • Phase Difference
  • For a new atom in a unit cell

yb
xa
2
  • Diffraction angle
  • 2 d sin? ?
  • sin? ?/2d

?
Bright spot ?
d
(h,k,l)
3
  • Reflection from plane through new atom
  • Planes at same angle

?
??
4
  • New plane at spacing
  • ? (hx ky lz) d

?
?
??
5
  • Extra path length
  • ?x ? sin?
  • On each side

?
?
? sin?
?
??
? sin?
6
  • Extra path length
  • ?x 2 ? sin?
  • But sin? ?/2d Bragg spot
  • ?x ??/d

?
? sin?
?
?x
? sin?
7
  • phase difference
  • 2? radians in one ?
  • ?x 2?/? 2? ?/d

?
? sin?
?
??
? sin?
8
  • phase difference
  • ?? 2? (hx ky lz)

?
? sin?
?
??
? sin?
9
  • phase difference
  • ?? 2? (hx ky lz)

2?ix/?
?
e
? sin?
?
2?ix/???
e
? sin?
10
  • phase difference
  • ?? 2? (hx ky lz)

2?ix/?
?
e
? sin?
2?ix/?
e
e
2?i(hxkylz)
?
? sin?
11
Systematic Extinctions
yb
  • Body Centered Cubic
  • x ½ y ½ z ½
  • ?? 2? (hx ky lz) n? with n odd
  • ?? 2? (h/2 k/2 l/2) n?

xa
12
Systematic Extinctions
yb
xa
  • Body Centered Cubic
  • (1,1,1) ?? 2? (1/2 1/2 1/2)
  • (1,1,1) ?? 3? waves cancel
  • h k l even for reflection to appear
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