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The genetic code and transcription

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hydrogen bonding between the codon and anticodon at the ... is the only codon to encode for ... sequence to one of the stop codons and protein synthesis stops ... – PowerPoint PPT presentation

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Title: The genetic code and transcription


1
Chapter 14
  • The genetic code and transcription
  • Introduction of translation (continuation in
    chapter 15)
  • Skip experiments skip pages 353-359

2
(No Transcript)
3
Triplet code
  • 64 codons to specify the 20 amino acids
  • Code is degenerate
  • Stop and start codons
  • Mutations

4
Degenerate code 64 codons and 20 amino acids
5
Wobble hypothesis
  • hydrogen bonding between the codon and anticodon
    at the third position is subject to modified
    base-pairing rules
  • May not adhere specifically to the established
    base-pairing rules

6
Codons
  • First amino acid
  • Methionine or N-formyl methionine
  • N-formyl methionine in bacteria
  • Formyl group or the entire N-formyl methionine
    removed from the final protein
  • AUG is the only codon to encode for methionine.
  • When AUG appears internally in mRNA, an
    unformylated methionine is inserted into the
    protein.

7
Stop codons
  • UAG, UAA, and UGA
  • Do not specify any amino acid
  • Nonsense mutations
  • Change the normal sequence to one of the stop
    codons and protein synthesis stops
  • Frameshift may result in reaching a stop codon

8
Types of mutations
  • Point mutation
  • Missense mutation
  • Nonsense mutation
  • Silent mutations
  • Transition
  • Transversion
  • Frameshift mutations

9
Types of mutations
10
The genetic code is nearly universal
mitochondria is different
11
Different initiation points create overlapping
genes
  • Single mRNA may have multiple initiation points
    for translation produce different proteins

12
RNA polymerase is used in transcription
  • RNA polymerase binds to the promoter
  • Makes RNA from a DNA template
  • No primer is required
  • Uses ribonucleotides instead of
    deoxyribonucleotides

13
DNA is transcribed into RNA
14
RNA polymerase from E. coli
  • contains the subunits a2, ß, ß', and s
  • The s subunit is responsible for promoter
    recognition
  • s subunit dissociates after synthesis begins (8-9
    nucleotides)

15
E. coli promoters
  • have two consensus sequences important for RNA
    polymerase binding

TATAAT, positioned at 10 Pribnow box TTGACA,
positioned at -35 Closer the sequence is to
consensus, the stronger the promoter is

16
Promoter sequence
  • Two important consensus sequences
  • -10 TATAAT (similar to eukaryotic -25 TATAAAA)
  • -35 TTGACA
  • Sequences on either side of -10 and -35 or in
    between are relatively unimportant in promoter
    recognition
  • Where to start transcribing
  • 1 sequence (10 bases upstream from the -10)
  • Which strand will be read
  • Template strand (3 to 5 on the DNA)
  • Which direction the RNA polymerase will move
  • 5 to 3

17
Promoter sequence is on the nontemplate strand of
DNA
18
Problem
  • DNA
  • 5CCGTGGACCTACGTACTATTATAGCTAGCCCTAGATTGGCCTGTCAAC
    GCGG3
  • 3GGCACCTGGATGCATGATAATATCGATCGGGATCTAACCGACAGTTGC
    GCC5
  • Where is the promoter sequence located?
  • Which is the template strand?
  • Which direction will transcription occur?
  • Where is the start site for transcription?

19
Steps in transcription
  • Initiation?Elongation?
  • Termination
  • Initiation RNAP binds the promoter
  • Elongation
  • RNA nucleotides added at the 3 end of growing
    RNA strand (5?3 direction)
  • Termination reach a specific sequence and new
    RNA molecule is released

20
Steps in transcription
21
Termination
  • Terminator where RNA polymerase disassociates
    from DNA
  • Sequence on DNA transcribed into RNA
  • Common sequence on the DNA is an inverted repeat
    (prokaryotes)
  • RNA creates a hairpin secondary structure
  • form a stem-loop structure followed by a string
    of Us
  • A-U base pairs needed to destabilize the DNA-RNA
    interaction and is needed to end transcription

22
RNA transcribes off the template strand
  • DNA
  • 5TGCTGGTCGACTG3 (1)
  • 3ACGCCCAGCTGAC5 (2)
  • RNA
  • 5UGCGGGUCGACUG3
  • DNA strand 1 nontemplate
  • DNA strand 2 template

23
Can you write a sequence in the DNA or RNA that
will form a stem loop structure?
24
Rho dependent termination
  • Protein that binds to RNA and moves down to RNA
    polymerase-DNA complex
  • A downstream portion of the newly synthesized RNA
    forms a stem loop
  • Causes RNA polymerase to disassociate from DNA
  • Rho breaks the H-bonds between the DNA-RNA hybrid
    and the RNA dissociates

(from Genomes 2)
25
Polycistronic mRNA
  • Unlike Eukaryotes, Prokaryotes have Polycistronic
    mRNA
  • Group of cotranscribed genes
  • One promoter and one terminator
  • Operon
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