Title: Physics 2211: Lecture 25 Todays Agenda
1Physics 2211 Lecture 25Todays Agenda
- Collisions in two dimensions
2Two blocks that initially move as shown undergo a
1-D collision. After the collision, the 2.0 kg
block recoils to the left with a speed of 9.0
m/s. What is the velocity of the 4.0 kg
block after the collision? (1) 0 m/s (2)
1.0 m/s left (3) 2.0 m/s left (4) 3.0 m/s
left (5) 4.0 m/s left (6) 5.0 m/s left
4.0 kg
2.0 kg
3.0 m/s
6.0 m/s
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3PART 2 For the collision we just discussed,
compute the change in kinetic energy and describe
the type of collision. (1) 30 J
lost---inelastic collision (2) 48 J
lost---inelastic collision (3) 0 J
lost---elastic collision (4) 54 J
lost---totally inelastic collision (5) 81 J
lost---totally inelastic collision
4.0 kg
2.0 kg
3.0 m/s
6.0 m/s
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4Momentum Conservation
- The concept of momentum conservation is one of
the most fundamental principles in physics. - This is a component (vector) equation.
- We can apply it to any direction in which there
is no external force applied. - You will see that we often have momentum
conservation even when energy is not conserved.
5Inelastic collision in 2-D
- Consider a collision in 2-D (cars crashing at a
slippery intersection...no friction).
V
v1
m1 m2
m1
m2
v2
before
after
6Inelastic collision in 2-D...
- There are no net external forces acting.
- Use momentum conservation for both components.
v1
V (Vx,Vy)
m1 m2
m1
m2
v2
7Inelastic collision in 2-D...
- So we know all about the motion after the
collision!
V (Vx,Vy)
Vy
?
Vx
82-D Elastic Collision of 2 objects
- Suppose we know what the pre-collision
velocities are. - We want to find out about the motion of both
objects after the collision. - We want v1x,f , v1y,f , v2x,f , v2y,f
- What else do we know
- In an elastic collision, kinetic energy is
conserved as well as momentum. This leads to 3
equations - Ef Ei
- Px,f Px,i (where Px p1x p2x m1v1x
m2v2x etc) - Py,f Py,i
- We have 3 equations and 4 unknowns
- We need more information (scattering angle,
masses).
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