Title: Physics 2211: Lecture 11 Todays Agenda
1Physics 2211 Lecture 11Todays Agenda
- Friction
- What is it?
- How do we characterize it?
- Model of friction
- Static Kinetic friction
- Some problems involving friction
2New Topic Friction
- What does it do?
- It opposes motion!
- How do we characterize this in terms we have
learned? - Friction results in a force in the direction
opposite to the direction of motion!
y
x
3Friction...
- Friction is caused by the microscopic
interactions between the two surfaces
- Friction force is the result of the
electromagnetic forces acting between the two
surfaces.
4Friction...
- Force of friction acts to oppose motion
- Parallel to surface.
- Perpendicular to Normal force.
y
x
5Model for Sliding Friction
- The direction of the frictional force vector is
perpendicular - to the normal force vector .
- The constant ?K is called the coefficient of
kinetic friction.
6Model...
- Dynamics
- SFX FA ? ?KN ma
- SFY N mg
- so FA ???Kmg ma
y
Assume forces are acting at center of mass of
block.
x
7Example Forces and Motion
- A box of mass m1 1.5 kg is being pulled by a
horizontal string having tension T 90 N. It
slides with friction (mk1 0.51) on top of a
second box having mass m2 3 kg, which in turn
slides with friction (mk2 0.068) on a floor. - What is the acceleration of the second box (m2) ?
slides with friction (mk10.51 )
T
m1
slides with friction
(mk20.068 )
a ?
m2
8Example Forces and Motion
- First draw FBD of the top box
N1
m1
fK1 - mK1N1
T
y
- m1g
x
9Example Forces and Motion
- Newtons 3rd law says the forces on box 1 exerted
by box 2 are equal and opposite to the forces on
box 2 exerts by box 1.
- As we just saw, these forces are due to friction
and the normal force.
N1 m1g
- mK1m1g
m1
fK1
m2
- fK1
- N1
10Example Forces and Motion
- Now consider the FBD of box 2
N2
fK1 mk1m1g
m2
fK2 mk2N2
-N1 -m1g
-m2g
11Inclined Plane with Friction
a
y
?
x
12Inclined plane...
- Resolve force due to gravity into components.
- Applied Newtons 2nd law in both dimensions.
y
x
13Static Friction...
- So far we have considered friction acting when
something moves. - We also know that it acts in un-moving static
systems - In these cases, the force provided by friction
will depend on the forces applied on the system.
y
x
14Static Friction...
- Just like in the sliding case except a 0.
- x FA ??fF 0
- y N mg
- While the block is static fF ??FA
y
x
15Static Friction...
- The maximum possible force that the friction
between two objects can provide is fMAX ?SN,
where ?s is the coefficient of static friction. - So fF ? ?S N.
- As one increases F, fF gets bigger until fF ?SN
and the object starts to move.
y
x
16Static Friction...
- ?S is discovered by increasing F until just
before the block starts to slide - x FMAX ?? fMAX 0 but fMAX ?SN
- y N mg
-
- ?S ??FMAX / mg
y
x
17Example Forces and Motion
- A box of mass m 10.21 kg is at rest on a floor.
The coefficient of static friction between the
floor and the box is ms 0.4. - A rope is attached to the box and pulled at an
angle of q 30o above horizontal with tension T
40 N. - Does the box move?
T
q
m
static friction (ms 0.4 )
18Example Forces and Motion
- Pick axes draw FBD of box.
y N T sin q - mg maY 0
N mg - T sin q
x T cos q - fF maX
m
The box will move if T cos q - fF gt 0
19Static Friction
- We can also consider ?S on an inclined plane.
- In this case, the force provided by friction will
depend on the angle ? of the plane.
?
20Static Friction...
- The force provided by friction, fF , depends on ?.
fF
N
a 0 (block is not moving)
mg sin ????fF ???
?
(Newtons 2nd Law along x-axis)
mg
?
21Static Friction...
- We can find ?s by increasing the ramp angle until
the block slides
mg sin ?M ???fF????
fF
N
In this case
?fF????SN ? ??Smg cos ?M
mg sin ?M????Smg cos ?M????
?M
mg
?
?S???tan ?M?
22Additional comments on Friction
- Since fF ?N , the force of friction does not
depend on the area of the surfaces in contact. - By definition, it must be true that ?S gt ?K
for any system (think about it...).
23Aside
- Graph of Frictional force vs Applied force
fF ?SN
fF ?KN
fF
fF FA
FA
24Problem Box on Truck
- A box with mass m sits in the back of a truck.
The coefficient of static friction between the
box and the truck is ?S. - What is the maximum acceleration a that the
truck can have without the box slipping?
?S
m
a
25Problem Box on Truck
- Draw Free Body Diagram for box
- Consider case where fF is max...(i.e. if the
acceleration were any larger, the box would
slip).
N
y
fF ?SN
x
mg
26Problem Box on Truck
- Use for both x and y
directions - x ?SN maMAX
- y N mg
-
- aMAX ?S g
N
y
aMAX
fF ?SN
x
mg
27Lecture 11, ActForces and Motion
- An inclined plane is accelerating with constant
acceleration a. A box resting on the plane is
held in place by static friction. What is the
direction of the static frictional force?
?S
a
fF
fF
fF
(a) (b) (c)
28Recap of todays lecture
- Friction
- What is it?
- How do we characterize it?
- Model of friction.
- Static Kinetic friction.
-
- Some problems involving friction.
- Read Sections 5.2 in Tipler.