Title: Linear Kinematics Chapter 3
1Linear KinematicsChapter 3
2Chapter Objectives
- Introduce the concept of inertia.
- Discuss the natural state of motion of objects.
- Introduce the study of kinematics.
- Describe motion.
- Lay the foundation for the study of kinetics.
3Newtons Laws
- Every body perseveres in its state of being at
rest or of moving uniformly straight forward,
except insofar as it is compelled to change its
state by force impressed - The rate of change of momentum of a body is
proportional to the resultant force acting on the
body and is in the same direction - All forces occur in pairs, and these two forces
are equal in magnitude and opposite in direction
4Aristotelian Physics are intuitive!
- Aristotle
- objects at rest remain at rest unless a force
acts on them - objects in motion did not remain in motion unless
a force acted constantly on them
5Aristotelian Physics are wrong!
- Galileo observed hidden forces that oppose motion
- Friction on a box sliding down an inclined plane
- Newton, who was born the year Galileo died,
quantified this concept of motion
6Law of Inertia
- Objects at rest tend to stay at rest.
- and
- Objects in uniform motion on a straight line
tend to stay in motion. - These are true unless the objects are disturbed
by outside forces.
7Question
- What are the units of inertia?
8Law of Inertia contd
- Force that which causes acceleration
- Uniform motion constant velocity
- Also known as Newtons first law
9Measuring Speed and Velocity
- Can measure speed and velocity in many ways.
- Usually measured with respect to the ground.
10Five Ways
- Observe the object passing a series of fixed
marks time it - Attach a long paper tape to the object, make
marks on the tape at a fixed frequency - Record reflected sound pulses (Doppler)
- Use a camera
- Use infra-red light gates
11Measure Walking Velocity
- Tools
- Tape
- Tape measure
- Stopwatch
12Deriving Velocity from Graphs
- Displacement vs. time graph
- Independent variable plotted on the x axis (time)
- Dependent variable plotted on the y axis
(displacement)
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14Generate displacement vs. time graph
- Tools
- Tape
- Tape measure
- Stopwatch
15Deriving Velocity from Graphs contd
- For a straight line
- m slope
- b y intercept
y mx b
16Deriving Velocity from Graphs contd
- Zero out displacement at time t0
- s displacement
- t time
- v velocity
- Then
s vt v ?s ?t
17Split Times
Generate plot in Excel. Does velocity change?
18Velocity and Acceleration
- Average vs. Instantaneous Velocity
- Note graphically, its all average, just over a
smaller time span
19Measuring Acceleration
- Average
- (final velocity initial velocity) / time
- Instantaneous?
- Slope of velocity-time curve
20Measuring velocity and acceleration
21Uniform Acceleration
- Acceleration rate of change of velocity
- Uniform acceleration equal changes in velocity
over equal time intervals
22Uniform Acceleration contd
- a acceleration
- u initial velocity
- v final velocity
- t time
-
v u at
23Uniform Acceleration contd
sut ½ at2
s½(u v)t
24Uniform acceleration contd
- To find v
- Note Previous equations apply to translation
with uniform acceleration only.
v2 u2 2as
25Uniform acceleration equations
sut ½ at2
v u at
s½(u v)t
v2 u2 2as
- Note These equations apply to translation with
uniform acceleration only.
26Example 3.2
- A skier begins his descent of a downhill section.
He gives himself a flying start by using his legs
to propel himself from his starting position. As
a result, his initial velocity is not 0 but is
2.5 m/s as he goes past the first marker on the
downhill section. The clock is started when he
goes past the first marker. Given that his
acceleration is 3 m/s2, calculate his velocity
when he goes past the second distance marker,
which is 10 m away from the first. How long (in
seconds) will it take him to get up to a velocity
of 25 m/s, assuming he maintains the acceleration
of 3 m/s2 as long as necessary?
27- A skier begins his descent of a downhill section.
He gives himself a flying start by using his legs
to propel himself from his starting position. As
a result, his initial velocity is not 0 but is
2.5 m/s as he goes past the first marker on the
downhill section. The clock is started when he
goes past the first marker. Given that his
acceleration is 3 m/s2, calculate his velocity
when he goes past the second distance marker,
which is 10 m away from the first. How long (in
seconds) will it take him to get up to a velocity
of 25 m/s, assuming he maintains the acceleration
of 3 m/s2 as long as necessary?
sut ½ at2
v u at
v2 u2 2as
s½(u v)t
28Example 3.2 solution
- A skier begins his descent of a downhill section.
He gives himself a flying start by using his legs
to propel himself from his starting position. As
a result, his initial velocity is not 0 but is
2.5 m/s as he goes past the first marker on the
downhill section. The clock is started when he
goes past the first marker. Given that his
acceleration is 3 m/s2, calculate his velocity
when he goes past the second distance marker,
which is 10 m away from the first. How long (in
seconds) will it take him to get up to a velocity
of 25 m/s, assuming he maintains the acceleration
of 3 m/s2 as long as necessary?
Known u, s, a Unknown v
u2.5 m/s
s 10m
a 3 m/s2
v ?
29Pick an equation
Known u, s, a Unknown v
u2.5 m/s
s 10m
a 3 m/s2
v ?
sut ½ at2
v u at
v2 u2 2as
s½(u v)t
30Solve
v2 u2 2as
u2.5 m/s
s 10m
a 3 m/s2
v ?
31Example 3.2 solution part 2
- A skier begins his descent of a downhill section.
He gives himself a flying start by using his legs
to propel himself from his starting position. As
a result, his initial velocity is not 0 but is
2.5 m/s as he goes past the first marker on the
downhill section. The clock is started when he
goes past the first marker. Given that his
acceleration is 3 m/s2, calculate his velocity
when he goes past the second distance marker,
which is 10 m away from the first. How long (in
seconds) will it take him to get up to a velocity
of 25 m/s, assuming he maintains the acceleration
of 3 m/s2 as long as necessary?
Known u, v, a Unknown t
u2.5 m/s
t ?
a 3 m/s2
v 25 m/s
32Pick an equation
Known u, v, a Unknown t
u2.5 m/s
t ?
a 3 m/s2
v 25 m/s
sut ½ at2
v u at
v2 u2 2as
s½(u v)t
33Solve
v u at
u2.5 m/s
t ?
a 3 m/s2
v 25 m/s
34Acceleration due to gravity
- 9.81 m/s2
- Do you believe it?
35Velocity vs Time Graph
- Free fall is uniform acceleration attributable to
gravity. - Slope of the v-vs-t graph gives acceleration.
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38Positive, Negative, or Zero!
- Americas Favorite Game Show
39Velocity Positive, Negative, or Zero?
40Velocity Positive, Negative, or Zero?
41Velocity Positive, Negative, or Zero?
42Velocity Positive, Negative, or Zero?
43Acceleration Positive, Negative, or Zero?
44Acceleration Positive, Negative, or Zero?
45Acceleration Positive, Negative, or Zero?
46Acceleration Positive, Negative, or Zero?
Note acceleration is the second derivative of
displacement
47Frames of Reference
- Usually fixed with respect to surfaces of the
Earth - Can also be moving with respect to the Earth
- Relative Velocity
- Velocity WRT
48- Man WRT train
- Woman WRT man
- Describe velocity of
- Train
- Man on train
- Woman on platform
49- Describe velocity of
- Ball WRT woman
- Ball WRT man
50- Consider relative velocities in throwing events
- Javelin thrower is not standing still at release
- Add velocities to get javelin WRT ground
51Projectiles
- Ignoring friction, projectiles move with uniform
acceleration - Examples of projectiles
- Shot putt
- High jumper
- Long jumper
- Soccer ball
- Tennis ball
52Projectiles contd
- Horizontal and vertical components of velocity in
projectiles - Horizontal component is constant in the absence
of friction
Vx Vcos? X Vxt
53Projectiles contd
- Vertical component
- At top of projectile
- max height h, time to max height tup
Vy Vsin?
Vy 0 at t tup v u at 0 vsin? - g tup
tup vsin? / g
54Projectiles contd
- Define positive and negative direction.
- Up
- Down -
- Keep values constant
55Horizontal Range
See pg. 67-68 for flight time calculation
- Horizontal range of projectile
- If Landing height Release height,
56Optimum projection angle
57Release Height Not at Landing Height
dxh
- d is Descent distance
- h is maximum height
- x is projection height minus landing height
- x is positive if the projection level is higher
than the landing level. - x is negative if the projection level is lower
than the landing level.
58Parabolic Path
- A projectiles path in two dimensions forms a
parabola.
Solve for t
59Parabolic Path contd
- Equation of parabola in the xy plane
60Proof
61- Ball projected at 45º angle
- Path of ball illuminated stroboscopically at a
frequency of 28 Hz - Projection velocity approx. 4 m/s
62Note
- Horizontal velocity is constant once released
- 0.1 m across each flash
63Note
- Vertical velocity varies at a constant rate
- Trajectory is symmetric
64Summary
- The natural motion of a body is constant
velocity in a straight line - However, we more often see objects that are
stationary or moving with a constant acceleration - Do you actually believe Aristotle or Galileo and
Newton?