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DIGITAL SPREAD SPECTRUM SYSTEMS

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5-STAGE SIMPLE SHIFT REGISTER GENERATOR (Cont) OCTAL REPRESENTATION CONVERSION ... (b) Equivalent Modular Shift Register Generator (MSRG) Configuration of x5 x3 1 ... – PowerPoint PPT presentation

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Title: DIGITAL SPREAD SPECTRUM SYSTEMS


1
DIGITAL SPREAD SPECTRUM SYSTEMS
ENG-737
  • Wright State University
  • James P. Stephens

2
DIRECT SEQUENCE IMPLEMENTATION
(A)
x(t)
BPSK modulator
BPSK modulator
Data
s(t) A x(t) g(t) cos wt
sx(t) A x(t) cos wt
A cos wt
g(t)
Carrier
(B)
(C)
r(t) AA x(t - td) g(t - td) cos w(t td)
f
BPSK demod
Filter

s(t) AA x(t - td)
Output of correlator

g(t - td)
Correlator
3
SPREADING / DESPREADING
Locally generated PN bit stream B
Code Inversion
Locally generated PN bit stream D same as B
above
Embedded Ref.
4
SPREADING CODES
IMPORTANT CODE PROPERTIES
  • Must be easily generated at the transmitter and
    receiver (i.e. deterministic)
  • Behave as much as possible like a random sequence
  • Be difficult to exploit
  • Support multiple access
  • Provide ease of synchronization

5
SIMPLE SHIFT REGISTER GENERATOR (SSRG)
  • Data at first stage is shifted once toward the
    right each time clock pulse occurs
  • Clock input are normally not shown

6
SIMPLE SHIFT REGISTER GENERATOR (SSRG)
N 2n - 1
Where, N length of sequence n number of
stages
Repeats
7
M-SEQUENCES
  • If sequence goes through all possible states
    except all zeros, it is maximal

If not maximal, the output sequence will be
dependent on the initial fill
State Diagram
8
GENERAL FORM OF A LINEAR SSRG
  • Let
  • Be the output sequence
  • The general form for a linear SSRG is

The fundamental recursion relationship describing
the sequence element ck and the contents of the
register is
9
GENERAL FORM OF A LINEAR SSRG (Cont)
  • Where,
  • The sum is modulo-2 addition
  • ai is either 0 or 1
  • i 1, 2, 3, . . . . n-1 and an 1
  • The values are called
  • initial conditions or initial fill

10
5-STAGE SIMPLE SHIFT REGISTER GENERATOR
x0
x1
x2
x3
x4
x5
Clock
  • n 5 number of register stages
  • N length of sequence generated (maximal only if
    correct taps are chose)
  • Generator described by a polynomial over a field
    of two symbols, called Galois Field of 2 (GF2)
  • Generator g(x) is written

11
5-STAGE SIMPLE SHIFT REGISTER GENERATOR (Cont)
  • ai are the tap coefficients, for the example
    shown
  • a0 a1 a3 a4 a5 1
  • a2 0
  • Therefore, the generator polynomial is written
  • g(x) x5 x4 x3 x 1
  • This is called the generators characteristic
    polynomial

12
OCTAL REPRESENTATION CONVERSION
  • Example Convert 103o to generator polynomial
  • Solution
  • 1 0 3
  • 0 0 1 0 0
    0 0 1 1
  • X8 X7 X6 X5 X4
    X3 X2 X1 X0 X6 X 1


3
6
1
2
4
5
13
MAXIMAL LENGTH SEQUENCES
  • When the sequence goes through all 2n 1
    possible states, it is called an m-sequence
  • The periodic cycles of a linear SSRG sequence
    depend on
  • Register length, n
  • Feedback taps
  • Initial conditions
  • Only if feedback taps are chosen properly will
    the sequence be an m-sequence
  • A non-maximal sequence is one in which the
    register does not go through all possible states,
    i.e. the sequence will be initial fill dependent

14
EXAMPLE OF A NON-MAXIMAL SEQUENCE
24 1 15
Null Seq Seq A Seq B
0 0 0 0 - 0 0 0 0 0 - R
1 0 0 0 - 8 1 1 0 0 -12 0 1 1 0 - 6 0 0 1 1 - 3 0
0 0 1 -1 1 0 0 0 - R
1 1 1 1 - 15 0 1 1 1 - 7 1 0 1 1 - 11 1 1 0 1 -
13 1 1 1 0 - 14 1 1 1 1 - R
State Diagrams
15
PRIMITIVE POLYNOMIALS
16
NUMBER OF M-SEQUENCESfrom register length 3
through 16
Register Length n
Number of sequences
  • gt 2
  • 4 gt 4
  • 5 gt 6
  • 6 gt 4
  • 7 gt 18
  • 8 gt 16
  • 9 gt 48
  • 10 gt 60
  • 11 gt 176
  • 12 gt 96
  • 13 gt 630
  • 14 gt 756
  • 15 gt 1800
  • 16 gt 2048

Where ?(2n 1) is a Euler number i.e. the number
of positive integers including 1 that are
relatively prime to and less than 2n 1
17
COMPARISON OF SSRG WITH MSRG
(a) Simple Shift Register Generator (SSRG)
Configuration of x5 x2 1
(b) Equivalent Modular Shift Register Generator
(MSRG) Configuration of x5 x3 1
18
RECIPROCAL CODES
Time reversed replicas
19
CODE SEQUENCE PERIODS FOR M-SEQUENCES
Code Sequence Periods for Various m-sequence
Lengths at 1 Mcps
  • 127 1.27 x 10-4 sec
  • 255 2.55 x 10-4 sec
  • 511 5.11 x 10-4 sec
  • 1,023 1.023 x 10-3 sec
  • 2,047 2.047 x 10-3 sec
  • 4,095 4.095 x 10-3 sec
  • 8,191 9.191 x 10-3 sec
  • 131,071 1.31 x 10-1 sec
  • 524,287 5.24 x 10-1 sec
  • 8,388,607 8.388 sec
  • 27 134,217,727 13.421 sec
  • 2,147,483,647 35.8 min
  • 879,609,302,207 101.7 days
  • 2,305,843,009,213,693,951 7.3 x 104 years
  • 89 618,970,019,642,690,137,449,562,111 1.95 x
    109 years

Source Spread Spectrum Systems R.C. Dixon
20
GENERATING PN SEQUENCES IN MATLAB
  • Requires
  • pnf.m
  • oct2bin.m
  • x pnf(8,435,1,500,1,1)
  • of stages
  • Octal polynomial
  • Initial Fill in Octal
  • Length of sequence
  • Sampling Frequency
  • Bit rate

21
GENERATING PN SEQUENCES IN MATLAB (Cont.)
22
PROPERTIES OF M-SEQUENCES
  • M-sequences must have an even number of taps
  • Reciprocal codes can be generated by reversing
    the order of the taps
  • Exhibit the shift and add property
  • If an m-sequence is added to a phase shifted
    version of itself, then the resulting sequence is
    another shift of the original sequence
  • Example
  • 1 1 1 0 1 0
    0 ? Original sequence
  • 1 0 1 0 0 1
    1 ? Shifted by 2
  • 0 1 0 0 1 1
    1 ? Same sequence shifted by 4
  • Balance Property
  • In one period of an m-sequence, there is one more
    1 than 0 (result of not having an all zeros state)

23
RUN PROPERTIES OF M-SEQUENCES (Cont.)
  • 5. In one period there a 2(n-1) runs of
    consecutive 1s or 0s.
  • ½ are of length 1
  • ¼ are of length 2
  • 1/2l are of length l (Ex 1/8 of length 3,
    1/16 of length 4, . . .)
  • Or equivalently
  • 1 run of 1s of length n
  • 1 run of 0s of length n-1
  • 1 run of 1s and 1 run of 0s of length n-2
  • 2 runs of 1s and 2 runs of 0s of length n-3
  • 4 runs of 1s and 4 runs of 0s of length n-4
  • 2n-3 runs of 1s and 2n-3 runs of 0s of length. 1

24
BALANCE PROPERTYExample
  • M-sequence where n5, therefore l4
  • N 25 1 31

Total runs 2n-1 25-1 24 16 Total number
of bits 5 4 3 3 4 4 4 4 31
25
BALANCE PROPERTYExample
  • Generating polynomial 67o (n 5 and N 31)
  • The m-sequence is given as
  • 1 1 1 1 1 0 1 0 0 0 1 0 0 1 0 1 0 1 1 0
    0 0 0 1 1 1 0 0 1 1 0

1 2 3 4 5 6 7 8 9 10 11 12 13 14
15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31
Runs Present Number of Each Computation
0 4 ½(2n-1) ½(16) 8
1 4 Included in above
00 2 ¼(16) 4
11 2 Included in above
000 1 1/8(16) 2
111 1 Included in above
0000 1 1/16(16) 1
11111 1 1/16(16) 1
Total 16
26
PROPERTIES OF M-SEQUENCES (Cont.)
  • Number of maximal sequences possible
  • Number of sequences 1/n ?(2n 1)
  • Where
  • n the number of SSRG stages
  • ?(k) is Eulers number
  • ?(k) equals the number of positive integers less
    than k and relatively prime to k
  • If k is not prime, use
  • Where pfi s are the prime factors of k

27
NUMBER OF M-SEQUENCES Example
  • Let n 5, N 25 -1 31
  • 31 is a prime number, therefore
  • of sequences 1/n?(2n 1) 1/530 6
  • Note 30 is the number of positive integers
    less than k
  • This number does not include reciprocal codes
    since they are time-reversed replicas of the same
    sequence
  • Let n 4, N 24 -1 15
  • 15 is not a prime number, therefore prime factors
    are 3 and 5
  • of sequences
  • (1/4)(24 1)(1 1/3)(1 1/5)
    (1/4)(15)(2/3)(4/5) 2
  • The table 3.3 on page 72 of the Dixon text is
    incorrect for n4 and is verified from
    Error-Correcting Codes by Peterson and Weldon
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