Eric The Sheep

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Eric The Sheep

• Heath, Rainer, Nathan and Tom

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How We Figured It Out

• First off, we made a table of the answers up to
  20, figuring the answers out by drawing them out.
  
• We saw a pattern emerge, for every three sheep in
  front of Eric, the number would increase

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FOR EVERY 1 SHEEP SHORN, ERIC WILL JUMP 2 SHEEP
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Formula for 1 sheerer

• X
• 3 1
• (except if the value of x is a multiple of 3, ie.
  3, 6, 9, 12)
• You must only take the integer and leave out the
  decimal numbers.
• Example. 5/31 2
• Example. 12/3 4

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A second formula

• A second formula we found to work was if the
  number of sheep in front of Eric is a multiple of
  3, simply divide by 3. If not, round the number
  up to the closet multiple of 3, ie. Round 19 up
  to 21 and divide by 3 to find 7, the answer.

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Questions

• 2. Yes, You can predict it using the formula. All
  you have to do is round up to the next multiple
  of 3 and then divide by 3.

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• 3. If Eric was to jump 4 round up to to the next
  multiple of 4 and divide by 4. Same with method
  used with 5, just sub in 5 instead of 4

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FOR EVERY 3 SHEEP SHORN, ERIC WILL JUMP 2 SHEEP
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Pattern for 3 shearers

• A pattern emerged, No. shorn before Eric, goes
  up by 1 , up by 1 again, then up by 1 and stay
  the same for the next 3, then repeats I.e.
  1,2,3,3,3,4,5,6,6,6
• The number at the end of the three same numbers
  created a ratio with the No. in front of Eric,
  of 53 I.e. 2012, 159, 106
• To figure out, round the number in front of
  Eric up to the next multiple of 5, then use the
  pattern to figure it out and count back

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Tried method

• 472 sheep in front of Eric, round up to 475, sub
  into ratio 53
• 475285, divide down 53
• Count 285 back 3 places (475-4723) answer is 282

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Thank You