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Chapter 5: Gases

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Title: Chapter 5: Gases


1
Chapter 5 Gases
  • 5.1 Measurements on Gases
  • 5.2 The Ideal Gas Law
  • 5.3 Gas Law Calculation
  • 5.4 Stoichiometry of Gaseous Reactions
  • 5.5 Gas Mixtures Partial Pressures and Mole
    Fractions
  • 5.6 Kinetic Theory of Gases
  • 5.7 Real Gases

2
Measurements On Gases
  • A gas is completely described by its volume,
    amount, temperature, and pressure.
  • A gas expands uniformly to fill any container in
    which it is placed. The volume of a gas is the
    volume of its container. Volume can be expressed
    in liters, cubic centimeters or cubic meters.
  • 1 L 103 cm3 10-3 m3

3
Properties of a Gases
  • The amount of matter in a gaseous sample is
    expressed in moles.
  • The temperature of a gas is measured in degrees
    Celsius. In any calculation involving the
    physical behavior of gases, temperature must be
    expressed on the Kelvin scale.

4
Properties (Contd)
  • Pressure is defined as force per unit area (psi
    pound per square inch). Pressure is measured
    using a manometer.
  • In a laboratory setting, pressure is expressed in
    millimeters of mercury (mm Hg) or atmospheres
    (atm).
  • 1 atm 760mm Hg

5
Pressure (Contd)
  • In the International System, the standard unit of
    pressure is the pascal (Pa). A related unit is
    the bar (105 Pa).
  • 1.013bar 1 atm 760mm Hg

6
Example 1
  • A balloon with a volume (V) of 2.36 x 104 m3
    contains 4.68 x 106g of He at 18ºC and 1.20bar.
    Express the volume of the balloon in liters, the
    amount in moles (n), the temperature (T) in K and
    the pressure (P) in both atmospheres and
    millimeters of mercury.
  • (a) V 2.36 x 104m3 x 1L/10-3m3 2.36 x 107L
  • (b) nHe 4.68 x 106g He x 1mole He/4.003g He
    1.17 x 106mol He

7
Example (Contd)
  • (c) T 18 273 291K
  • (d) P 1.20bar x 1atm/1.013bar 1.18atm
  • (e) P 1.20bar x 760mmHg/1.013bar 9.00 x 102
    mmHg

8
Ideal Gas Law
  • All gases are similar in their dependence of the
    volume on amount, temperature, and pressure.
  • I. Volume is directly proportional to amount.
  • V k1n
  • Where k1 is a constant, independent of the values
    V or n.

9
Ideal Gas Law (Contd)
  • II. Volume is directly proportional to absolute
    temperature.
  • V k2T
  • Where k2 is a constant (Charles Law).
  • III. Volume is inversely proportional to
    pressure.
  • V k3/P
  • Like k1 and k2, k3 is also a constant (Boyles
    Law).

10
Ideal Gas Law
  • Ideal Gas law as states is
  • V constant x (n x T)/P
  • The constants k1k2k3 are evaluated using
    Avogadros Law (Equal volumes of gases at the
    same T and P, contain the same number of moles).
    The new value is the constant R.
  • PV nRT

11
The Ideal Gas Constant
  • The ideal gas constant, R, can be calculated from
    experimental values.
  • Consider a gas at 0ºC and 1 atm (standard
    temperature and pressure, STP). At STP, 1 mole
    of a gas occupies a volume of 22.4L.
  • Solving for R, we get 0.0821 L atm/(mol K).
  • See Table 5.1 for R expressed in different units.

12
Gas Law Calculations
  • Can solve for
  • (i) the final state of a gas, knowing its
    initial state and the changes in P, V, n, or T
    that occur.
  • (ii) one of the four variables, P, V, n, or T,
    given the values of the other three.
  • (iii) the molar mass or density of a gas.

13
Final and Initial State Problems
  • Determine the effect on the V, P, n, or T of a
    change on one or more of these variables.
  • This involves a gas changing from an initial
    state to a final state.
  • Ex. A sample of gas at 25ºC and 1 atm is heated
    to 95ºC. What is the new P?

14
Example (Contd)
  • Initial state P1V nRT1
  • Final State P2V nRT2
  • Dividing, the second equation by the first,
    cancels V, n, and R. Therefore
  • P2/P1 T2/T1 (constant n, V)
  • Solve for P2 P2 T2/T1 x P1
  • P2 1atm x 368K/298K 1.23atm

15
Calculation of P, V, n or T
  • The ozone-friendly compound now used as a
    refrigerant in car air conditioners has the
    molecular formula C2F4H2. If 2.50g of this
    compound is introduced into an evacuated 500.0ml
    container at 10ºC, what pressure in atms is
    developed?

16
Problem (Contd)
  • First, convert V, n, and T into the proper units.
  • V 500.0ml x 1L/1000ml 0.5000ml
  • n 2.50g C2F4H2 x 1mole C2F4H2/102.04 C2F4H2
    0.0245mol
  • P nRT/V
  • 0.0245mol x 0.0821 x 283K/0.5000L
  • 1.14atm

17
Molar Mass and Density
  • Ideal gas law can be used to determine
    experimentally the molar mass of a gas.
  • Ex. Acetone is widely used as a solvent. A
    sample of acetone is placed in a 3.00L flask and
    vaporized by heating to 95ºC at 1.02atm. The
    vapor filling the flask at this temp. and
    pressure weighed 5.87g. Calculate the molar mass
    of acetone.

18
Example (Contd)
  • n PV/RT
  • (1.02atm)(3.00L)/(0.0821)(368K)
  • 0.101mol
  • m M x n
  • M m/n 5.87g/0.101mol 58.1g

19
Density
  • Density MP/RT
  • Density of a gas is dependent on
  • Pressure. Compressing a gas increases its
    density.
  • Temperature. As temperature increases, density
    decreases.
  • Molar Mass.

20
Stoichiometry of Gaseous Reactions
  • Law of Combining Volumes (Gay-Lussac) The volume
    ratio of any two gases in a reaction at constant
    temperature and pressure is the same as the
    reacting mole ratio.

21
Example
  • Octane, C8H18, is one of the hydrocarbons added
    to gasoline. On combustion, octane produces CO2
    and H2O. How many liters of oxygen, measured at
    0.974atm and 24ºC, are required to burn 1.00g of
    octane.

22
Example (Contd)
  • 2C8H18(l) 25O2(g) ? 16CO2(g) 18H2O(l)
  • noxygen 1.00g C8H18 x 1mol C8H18/114.22g C8H18
    x 25mol O2/2mol C8H18 0.109mol O2
  • Voxygen nRT/P
  • 0.109mol x 0.0821 x 297K/0.974atm
  • 2.73L

23
Gas Mixtures Partial Pressures and Mole Fraction
  • For a mixture of 2 gases A and B, the total
    pressure is given by the expression
  • Ptot ntot(RT/V) (nA nB)RT/V
  • Separating the terms on the right
  • Ptot nA RT/V nB RT/V
  • These two terms are, according to the ideal gas
    law, the pressures that A and B would exert if
    they were alone. These quantities are referred
    to as partial pressures.

24
Partial Pressures (Contd)
  • PA partial pressure A nART/V
  • PB partial pressure B nBRT/V
  • Ptot PA PB
  • This relation was first derived by John Dalton in
    1801 and is referred to as Daltons Law of
    Partial Pressures.

25
Partial Pressures (Contd)
  • The total pressure of a gas mixture is the sum of
    the partial pressures of the components of the
    mixture.
  • Consider a gaseous mixture of hydrogen and
    helium
  • Phydrogen 2.46atm Phelium 3.69atm
  • Ptot 2.46atm 3.69atm 6.15 atm

26
Wet Gases Partial Pressures of Water
  • When a gas such as hydrogen is collected by
    bubbling through water, it picks up water vapor.
    Therefore
  • Ptot Pwater Phydrogen
  • The partial pressure of water is equal to the
    vapor pressure of liquid water. It has a fixed
    value at a given temperature. The partial
    pressure of hydrogen can then be calculated by
    subtraction.

27
Vapor Pressure (Contd)
  • Vapor pressure, like density and solubility, is
    an intensive physical property that is
    characteristic of a particular substance.
  • Water at 25ºC is 23.76 mm Hg
  • 40ºC is 55.3 mm Hg
  • 70ºC is 233.7 mm Hg
  • 100ºC is 760.0 mm Hg

28
Partial Pressure and Mole Fraction
  • A mixture of containing gases A and B
  • PA nART/V Ptot ntotRT/V
  • PA/Ptot nA/ntot
  • The fraction nA/ntot is referred to as the mole
    fraction of A in the mixture. It is the fraction
    of the total number of moles that is accounted
    for gas A. Using XA to represent the mole
    fraction,
  • PA XAPtot
  • The partial pressure of a gas in a mixture is
    equal to its mole fraction multiplied by the
    total pressure.

29
Kinetic Theory of Gases
  • Molecular Model
  • I. Gases are mostly empty space total volume is
    negligible compared with that of the container.
  • II. Gas molecules are in constant, chaotic
    motion collide frequently velocities constantly
    changing.
  • III. Collisions are elastic no attractive
    forces to make molecules stick together.
  • IV. Gas pressure is caused by collisions of
    millions of molecules with the walls of the
    container.

30
Expression for Pressure, P
  • According to laws of physics
  • P Nmu2/3V
  • Where V volume, N is the number of molecules, m
    is the mass, and u is the average speed.

31
Average Kinetic Energy of Translational Motion
(Et)
  • The kinetic energy, Et, of a gas molecule m
    moving at speed u is
  • Et mu2/2
  • From the previous equation for P, we see that mu2
    3PV/N, therefore
  • Et 3PV/2N
  • The ideal gas law states that PV nRT,
    therefore
  • Et 3nRT/2N

32
Kinetic Theory (Contd)
  • At a given temperature, molecules of different
    gases must have the same average kinetic energy
    of translational motion.
  • The average translational kinetic energy of a gas
    molecule is directly proportional to the Kelvin
    temperature.

33
Real Gases
  • The deviations from the ideal gas law become
    larger at high pressures and low temperatures.
  • In general, the closer a gas is to the liquid
    state, the more it will deviate from the ideal
    gas law.
  • Deviations from the ideal gas law occur because
    it neglects two forces
  • 1. Attractive forces between gas particles.
  • 2. The finite volume of gas particles.
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