Title: CHEM 1211 PRINCIPLES OF CHEMISTRY I
1CHEM 1211 PRINCIPLES OF CHEMISTRY I
2Chapter 1. Fundamental Concepts
- Objectives
- Describe the forms, composition properties of
matter - Perform calculations on measurement results
following the rules of significant figures and
dimensional analysis. - Case Study burning wood
3Analysis of the contents of the solids
- 1. Composition
- Before burning
- Carbon, Hydrogen, Oxygen
- After burning
- Carbon
- Other substances detected water (gas)
- 2. Comparison of identities of substances same
or changed?
41.1. Chemistry Overview
- Definition
- Chemistry Study of
- composition, structure, and properties of
substances (matter) - transformations of substances from one to
another.
5b. Substance (matter)
- Any entity that has volume and weight.
- Examples
- Charcoal. Basic component one particle,
carbon - Water. Basic component an assembly of 3
particles one oxygen, two hydrogens. - http//images.google.com/images?hlenrlsGWYG,GWY
G2006-30,GWYGenqwatermoleculeum1ieUTF-8 - You?
- Light? See RQ2-1
6Running Quiz Question 1
- Is light a substance?
- a. Yes, because light has energy (sunlight can
burn you) - b. No, because light has no mass (sunlight can
burn you) - c. Yes, because light has a volume (sunlight can
burn you)
7Types of substances
- 1. Elements made of identical atoms
- Atom the smallest particle that can form a
substance. - Charcoal made of carbon atoms
- Aluminum foil made of aluminum atoms.
- Your own examples?
-
82. CompoundsSubstances made of molecules
- Molecule an assembly of atoms that is used to
build a substance - Water an assembly of two hydrogens and one
oxygen atoms - Salt an assembly of one sodium and one chlorine
atoms - Your own examples? See RQ2-2
9RQ2-2
- Is a mixture of iron and charcoal powders an
example of a compound? - a. No, because it is an element.
- b. Yes, because it is a mixture of two elements
that can be separated - c. No, because it is a mixture of two elements
that can be separated
10c. Composition and Structure
- Composition building blocks of a substance
- http//en.wikipedia.org/wiki/ImageBrick_likn_indi
a.JPG - Structure arrangements of building blocks inside
a substance - http//en.wikipedia.org/wiki/ImageFlemish_Bond.jp
g
11d. Transformations.
- Criterion comparison of substance identity
before after transformation. - 1 Chemical change Chemical reaction
- Substance identity after the transformation
different from identity before the transformation
- Ex
- Iron rusting
- Your own example?
122. Physical Transformation
- Substance identity stays the same
- Ice melting
- Chemical formula
- Ice H2O
- Water H2O
- Drying clothes
- Gas burning?
- RQ2-3
13RQ2-3
- Which part of burning a candle is a chemical,
which one is a physical change? - a. Candle wax melting and wick burning are both
physical changes. - b. Candle wax melting is a physical change and
candle wick burning is a chemical change. - c. Candle wax melting is a chemical change and
candle wick burning is a physical change.
14FYIBranches of Chemistry
- Analytical studies composition structure of
substances - Organic studies composition structure and
transformations of carbon based substances - Inorganic studies composition structure and
transformations of non-carbon based substances - Physical Studies microscopic properties of
substances
151.2. Classification of Substances
- Thought teasers Compare and tell the difference
between - Orange juice (O. J.) apple juice (A. J.) by
simple eye exam - Apple juice water by evaporation
- Water aluminum foil by breaking them down to
components
16Classification of Substances
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19RQ2-4
- Examine the previous graphic and identify which
picture shows which one of the following the
types of substances an element, a compound, a
homogeneous or a heterogeneous mixture? - a. Element d, Compound a, homogenous mixture
c, heterogeneous mixture b - b. Element a, Compound b, homogenous mixture
c, heterogeneous mixture d - c. Element b, Compound a, homogenous mixture
c, heterogeneous mixture d
201.3. Measurement Calculations
- Thought teasers what questions come to your mind
if you are told - You have 176
- You can drive this baby home for less than
20,000
21a. Overview
- 1. Measure
- Definition The quantitative evaluation of a
property - Example
- 176 cm. Measured property length
- other examples?
22Components of a Measure
- Example 176 cm
- Questions answered
- How much?
- What?
- Magnitude how large or small?
- Accuracy range of measuring instrument
- Units conventional quantitative reference used
to describe a property in measurement
23 2. Measurement Standard
- Definition Set of accepted units used in
measurement - SI (metric) system standard for scientific
measurement - Property Unit Abbreviation
- Length meter m
- Mass gram g
- Amount
- of substance mole mol
- Time second s
- Temperature Kelvin K
- More units Table 1.1, pg 16
24RQ2-5
- Are mass and amount of substance identical or
different properties? Explain. - a. Different. Mass tells how many building blocs
substance has. Amount of substance tells if a
substance is heavy or light. - b. Identical. Mass tells if a substance is heavy
or light. Amount of substance tells how many
building blocs a substance has. - c. Different. Mass tells if a substance is heavy
or light. Amount of substance tells how many
building blocs a substance has.
253. Prefixes
- Definition Prefix Multiple of the basic unit
- Originally designed to express very small and
very large measures using shorter numbers - Example 0.000000001 m 1nm
- n nano prefix, multiplies base unit (m) by
1/1000000000 or 10-9 or 1E-9
26Some Prefixes (Table 1.2, pg 19)
- Prefix multiplies Example
- (Abbrevn) base unit by
- Giga (G) 1E9 Gbyte
- Mega (M) 1E6 MHz
- Kilo (k) 1E3 Kg
- Deci (d) 1E-1 dm
- Centi (c) 1E-2 cm
- Milli (m) 1E-3 mg
- Micro (m) 1E-6 m m
- Nano (n) 1E-9 ns
27b. Uncertainty
- Part of a measure that is subject to
- Approximation
- Last digit in a number
- Measure Uncertainty
- 25 L 1L
- 274.9 lb 0.1 lb
28a. Expressions of UncertaintyPrecision and
Accuracy
- Precision
- Extent of agreement between
- different measures
- Accuracy
- Extent of agreement between
- different measures and the accepted
- value
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32Measure of Uncertainty Error
- Tools needed to determine the error
- Experimental Value EV
- Accepted Value AV
- Error 100 (AV EV) / AV
33Measure of Uncertainty Illustration
- Melting Point of Aspirin (AV 135 o C)
- Experimental Set 1 2
- 134 138
- 136 137
- 133 138
- 138 138
- Calculate average values and errors
- Indicate the set with highest precision, accuracy
34A student measures the mass of a penny 4 times
and records the following data. What can be said
about the data if the actual mass of the penny is
2.4987 g?
- a. The data is neither accurate nor precise.
- b. The data is accurate, but not precise.
- c. The data is not accurate, but it is precise.
35c. Significant Figures (SF)
- Definition Digits of a number that are related
to measurement - SFs show the level of uncertainty of a measure.
- Uncertainty is reflected in the last digit of a
number - SF Determination
- Count from left to right
- Start from 1st non-zero digit
36Significant Figures (Illustration)
- Example
- number SF's
- 530 3
- 00530 3
- 0.000530 3
37Numbers ending in 0's without decimal dot
- SFs depends on the range of the measuring
instrument - 1300 g
- Instrument Significant SFs
- range zeros
- Hundreds 0 2
- Tens 1 3
- Ones 2 4
38RQ2-6. When reading a graduated cylinder, read
the volume at the bottom of the meniscus.
- What volume of liquid is in the graduated
cylinder? - 4.5 mL
- 4.6 mL
- 4.56 mL
39d. Scientific (Exponential) Notation (SN)
- Definition Convention used to write very small
very large numbers more conveniently - Features of a number in SN N x 10n
- N digit factor number in the form a.bcd a
digit from 1 to 9 b, c, d digits from 0 to
9. - N shows the number of significant figures.
- 10n exponential factor n exponent whole
number.
40SN Writing Procedure
- Write number in normal notation
- Place decimal dot after 1st digit in the number
- Count the number of places the decimal dot must
move to return to original position. - Exponent the number of places the dot must move
- Positive Exponent if dot is moved to the right
- Negative Exponent if dot is moved to the left
- Examples 0.000009473 2584963170 written with 3
SFs.
41RQ2-7
- If you measure 15000 g of sand with a balance
that weighs down to hundreds of grams, how should
you report it? - a. Report it as 15000 g because that is what the
instrument says. - b. Report it as 1.50E4 g because on that balance
the measure is between 14900 and 15100 g and has
3 SFs. - c. Report it as 1.5E4 g because on that balance
the measure is between 14000 and 16000 g and has
2 SFs.
42 e. Rounding off
- Writing a measure with less digits than the
original number - Read pg 25
43f. Significant Figures in Calculations
- 1. Multiplication Division
- Rule of SF's in final result same as in
measure with least SF's. - number SF's
- 12.34 4
- x 2.34 3
- 28.8756 6 in calculations
- 28.9 3 in reported results
442. Addition Subtraction
- of digits after the decimal dot in final
result same as in measure with the fewest
digits after decimal period. - Example
- number digits after period
- 9.874 3
- 9.8 1
- 19.674 3 in calculations
- 19.7 1 in reported results
45 g. Perfect (exact) numbers
- 's without uncertainty
- SFs potentially infinite, not counted in
calculations - counted whole items.
- eggs, people, cars,
- Defined Quantities
- ex 1 km 0.62137 mi. 1.5172938 km 1.517293 x
0.62137 mi 0.9428003 mi.
46Significant Figures in Calculations (Illustration)
- (1.7E6 2.63E5) 7.33 ?
- (944345 9.9) 5.3 ?
- Extra exercise 81, pg 41
47RQ2-8
- If you use 2.1, 2.1 and 2.3 mL of solution to run
a chemical reaction, what is the average volume
of solution used? - a. 6.5 mL / 3 2.166666666666666667 mL, because
that is the mathematical result. - b. 6.5 mL / 3 2.2 mL, because the original
measure has 2 SFs and 3 is an exact number. - c. 6.5 mL / 3 2 mL, because the number of SFs
of a division result is determined by the number
with the lowest number of SFs.
481.4. Conversion of Units Dimensional Analysis
- Any conversion requires a conversion factor
- Conversion Factor(CF) tool used to convert a
measure from original to target units - CF Numeric and dimensional relation between
original and target unit. - Relation
- Measure in Original unit x CF Measure in Target
Unit - CF Measure in Target Unit / Measure in Original
unit
49Conversion Factor (Illustration)
- 1 cm 1E-5 km
- CF for cm to km conversion
- 1E-5 km/cm
- CF for Km to cm conversion
- 1E5 cm/km
50 a. Metric system Conversions
- Prefix to Prefix conversion through the base
unit - Procedure
- Convert original to base unit. Result CF of
original to base unit. - Convert base to final unit. Result CF of base to
final unit. - Convert original to final unit through base unit.
Multiply the two CFs. Result CF of original to
final unit - Ex 115 mm ?km
51Metric system Conversions (Illustration)
- May average rainfall in Tifton 115 mm
- km ?
- CF of mm to m 1 mm 1E-3 m -gt
- CF1 1E-3 m / mm
- CF of m to km 1 km 1E3 m -gt
- CF2 1 km / 1E3 m 1E-3 km/m
- Overall CF CF1 x CF2 1E-3 m/mm x 1E-3 km/m
1E-6 km/mm - 115 mm 115 x 1 mm 115 x 1E-6 km
- 1.15E2 x 1E-6 km 1.15E-4 km
52Numeric Illustration (Shortcut)
- May average rainfall in Tifton 115 mm
- km ?
- 1 mm 1E-3 m (1)
- 1 km 1E3 m -gt 1 m 1E-3 km (2)
- Replace m in relation (1) by its value from
- relation (2)
- 1 mm 1E-3 x 1E-3 km 1E-6 km
- 115 mm 115 x 1 mm 115 x 1E-6 km
- 1.15E2 x 1E-6 km 1.15E-4 km
- Extra exercise 57, pg 40
53b. Metric-English System conversion
- Find conversion factor used to express one
original unit into target units - Multiply the number in original units by
conversion factor to find the number in target
units - Unit Conversion tables see Inner back cover of
textbook - Ex 11.5 cm ? In
54Numeric Illustration
- May average rainfall in Tifton 11.5 cm
- in ?
- From tables 1 in 2.54 cm -gt 1 cm 0.394 in
- 11.5 x 1 cm 11.5 x 0.394 in 4.54 in
- Extra ex 83, pg 41 (b kg ot lb)
55Numeric Illustration (2)
- A jogger runs at an average speed of 5.9 mi/h.
How fast does she run in m/s? - From tables
- 1 mi 5280 ft
- 1 m 3.281 ft -gt 1 ft 0.3048 m
- 1 mi 5280 x 0.3048 m ? m
- 1 h 3600 s
- 5.9 mi/h 5.9 x ? m / 3600 s ? m/s
- Extra Exercise 87, pg 41
56Extra Exercise
- The non-SI unit, the hand (used by equestrians),
is 4 inches. What is the height in meters, of a
horse that stands 15 hands high? - Convert hands to ins to cms to ms
57RQ2-9
- If you convert a measure from a large to small
unit, what happens to the magnitude of the
measure? - a. It decreases, because it takes a larger number
of smaller units to match a larger unit. - b. It increases, because it takes a larger number
of smaller units to match a larger unit. - c. It increases, because it takes a smaller
number of smaller units to match a larger unit.
58 c. Fahrenheit - Celsius Temperature Conversions
- Read pg 17
- Problem The average May temperature in Tifton is
83.8 oF. What is the temperature in Kelvins? - Challenge Calculate the temperature that is the
same both in Celsius and Fahrenheit scales.
591.5 Physical Properties (Read Section 1.4, pg 11)
- a. Length, Area and Volume
- Standard of length meter
- Area (length)2
- Standard m2
- Volume (length)3
- Standard m3
- liter most commonly used SI unit of volume for
- liquids
- 1 L 1 dm3
- 1 mL 1 cm3
60b. Mass Weight
61c. Density
- The mass of a unit volume of substance
- d m / V wt / V -gt wt V x d V wt / d
62Numeric Illustration
- Copper has a density of 8.96 g/cc. An Ingot of
Copper with a mass of 57 kg is drawn into wire
with a diameter of 9.50 mm. What length of wire
can be produced? Note the volume of a cylinder
is found using the relation V p x radius2 x
length
63Problem Solving Strategy
- Information provided
- Density of copper 8.96 g/cc
- Weight of ingot 57 kg 57000 g
- Diameter of wire 9.50 mm 0.950 cm
- Information Requested
- Length of the copper wire
64Problem Solving Technique
- From Known to Next Unknown
- 1. Set up the expression of the final answer to
the problem. - 2. Use the known parameters in the expression to
figure out the unknown parameters , one by one. - Length V / (p x radius2)
- What parameter is unknown, how can it be found?
- See RQ2-10
65RQ2-10
- Examine the relation Length V / (p x radius2).
What parameter is unknown, how can it be found? - a. r is unknown and can be found using the
relation (r (V/(length x p))1/2 - b. V is unknown and can be found using the
relation V (p x radius2) x length - c. V is unknown and can be found using the
relation V wt/d
66Problem Solving (Continued)
- Unknown volume, to be determined next.
- Volume wt / d 57000 g / 8.96 (g/cc) ? cc
- Length ? E3 cc / (3.14 x (1/2 x 0.950)2) ? Cm
- Extra ex 65, pg 40