Title: Hypothesis Testing: Deciding between Reality and Coincidence
1LESSON 3
- Hypothesis Testing Deciding between Reality and
Coincidence
2Hypothesis Testing
- Developing Null and Alternative Hypotheses
- Type I and Type II Errors
- One-Tailed Tests About a Population Mean
- Two-Tailed Tests About a Population Mean
- Tests About a Population Proportion
- Hypothesis Testing and Decision Making
- Tests About a Population Proportion
-
3Developing Null and Alternative Hypotheses
- Hypothesis testing can be used to determine
whether a statement about the value of a
population parameter should or should not be
rejected. - The null hypothesis, denoted by H0 , is a
tentative assumption about a population
parameter. - The alternative hypothesis, denoted by Ha, is the
opposite of what is stated in the null
hypothesis. It is what we want to prove. - Hypothesis testing is similar to a criminal
trial. The hypotheses are - H0 The defendant is innocent
- Ha The defendant is guilty
4Developing Null and Alternative Hypotheses
- Testing Research Hypotheses
- The research hypothesis should be expressed as
the alternative hypothesis. - The conclusion that the research hypothesis is
true comes from sample data that contradict the
null hypothesis. - Alternative What you want to prove
- Null Status Quo
5Developing Null and Alternative Hypotheses
- Testing the Validity of a Claim
- Manufacturers claims are usually given the
benefit - of the doubt and stated as the null
hypothesis.
- The conclusion that the claim is false comes
from - sample data that contradict the null
hypothesis.
6Type I and Type II Errors
- Since hypothesis tests are based on sample data,
we must allow for the possibility of errors. - A Type I error is rejecting H0 when it is true.
- A Type II error is accepting H0 when it is false.
- The person conducting the hypothesis test
specifies the maximum allowable probability of
making a - Type I error, denoted by ? and called the level
of significance. - It is difficult to control for the probability
of making - a Type II error.
- Type I error Sending an innocent to jail
- Type II error freeing a guilty defendant.
7Summary of Forms for Null and Alternative
Hypotheses about a Population Mean
- The equality part of the hypotheses always
appears - in the null hypothesis.
- In general, a hypothesis test about the value
of a - population mean ?? must take one of the
following - three forms (where ?0 is the hypothesized
value of - the population mean).
One-tailed (lower-tail)
One-tailed (upper-tail)
Two-tailed
8Example Metro EMS
- Null and Alternative Hypotheses
- A major west coast city provides one of the
most comprehensive emergency medical services in
the world. Operating in a multiple hospital
system with approximately 20 mobile medical
units, the service goal is to respond to medical
emergencies with a mean time of 12 minutes or
less. - The director of medical services wants to
formulate a hypothesis test that could use a
sample of emergency response times to determine
whether or not the service goal of 12 minutes or
less is being achieved.
9Example Metro EMS
- Null and Alternative Hypotheses
- Hypotheses Conclusion and Action
- H0 ?????? The emergency service is
meeting - the response goal no follow-up
- action is necessary.
- Ha???????? The emergency service is
not - meeting the response goal
- appropriate follow-up action is
- necessary.
- Where ? mean response time for the
population - of medical emergency
requests.
10Example Metro EMS
- Type I and Type II Errors
- Population Condition
- H0 True Ha True
- Conclusion (?????? ) (?????? )
- Accept H0 Correct Type II
- (Conclude ???????
Conclusion Error -
- Reject H0 Type
I Correct - (Conclude ??????? ???? ??rror
Conclusion
11Level Of Significance VS Level Of Confidence
- The level of confidence indicates the probability
that the alternative hypothesis is correct if the
null hypothesis is rejected. A 90 level of
confidence can also be stated as a 10 level of
significance, and results can be summarized by
saying that a coefficient has been shown to be
statistically significant at the 10 level of
significance or the 90 level of confidence. - 1 -? is the confidence coefficient
- ? is the level of significance
12The Steps of Hypothesis Testing
- 1. Determine the appropriate hypotheses.
- 2. Select the test statistic for deciding
whether or not to reject the null hypothesis. - 3. Specify the level of significance ? for the
test or the level of confidence 1- ?. - 4. Use ? or 1- ? to develop the rule for
rejecting H0. - 5. Collect the sample data and compute the value
of the test statistic.
13Three methods to test the Null
- a) Compare the test statistic to the critical
value(s) in the rejection rule, or - b) Compute the p-value based on the test
statistic and compare it to ???to determine
whether or not to reject H0, or - c) Build a Confidence Interval If the confidence
interval contains the hypothesized value ?0, do
not reject H0. Otherwise, reject H0.
14First Method One-Tailed Tests about a Population
Mean s Known
- Hypotheses
- H0 ?????? ? or H0 ??????
- Ha???????? ?Ha????????
- Test Statistic ?? Known
-
-
15Continued
H0 ?????? Reject H0 if z gt
z? H0 ?????? Reject H0 if z lt -z?
16Upper-Tailed Test About a Population Mean
Reject H0
???????
Do Not Reject H0
z
za 1.645
0
17Lower-Tailed Test About a Population Mean
Reject H0
a ???1?
Do Not Reject H0
z
-za -1.28
0
18Second Method The Use of p-Values
- The p-value is the probability of obtaining a
sample result that is at least as unlikely as
what is observed. - The p-value can be used to make the decision in a
hypothesis test by noting that - if the p-value is less than the level of
significance ?, the value of the test statistic
is in the rejection region. - if the p-value is greater than or equal to ?, the
value of the test statistic is not in the
rejection region. - Reject H0 if the p-value lt ?.
19Lower-Tailed Test About a Population Mean
p-Value lt a , so reject H0.
a .10
p-value ????72
z
0
-za -1.28
z -1.46
20Upper-Tailed Test About a Population Mean
p-Value lt a , so reject H0.
a .04
p-Value ????11
z
za 1.75
z 2.29
0
21Third Method One-Tailed Confidence Interval
- We are sure that the population mean is at
least as large as (-) - Or We are sure that the population mean is not
larger than () - If CI does not include ? Reject Null
22Example Metro EMS
- One-Tailed Test about a Population Mean Large n
- Let ? P(Type I Error) .05
Sampling distribution of (assuming H0 is
true and ? 12)
Reject H0
Do Not Reject H0
???????
1.645?
c
12
(Critical value)
23Example Metro EMS
- One-Tailed Test about a Population Mean ? Known
- Let n 40, 13.25 minutes, ?
3.2 minutes -
- Since 2.47 gt 1.645, we reject H0.
- Conclusion We are 95 confident that Metro
EMS - is not meeting the response goal of 12
minutes - appropriate action should be taken to improve
- service.
24Example Metro EMS
- Using the p-value to Test the Hypothesis
- Recall that z 2.47 for 13.25. Then
p-value .0068. - Since p-value lt ?, that is .0068 lt .05, we
reject H0.
Reject H0
Do Not Reject H0
p-value???????
z
0
1.645
2.47
25Example Metro EMS
- 95 one-sided confidence interval calculation
- We are 95 confident that the mean is at least as
large as 12.417 - We are 95 confident that Metro EMS is not
meeting the response goal of 12 minutes.
Therefore Reject The Null Hypothesis
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27Two-Tailed Tests about a Population Mean s
Known
- Hypotheses
- H0 ????? ?
- Ha? ???????
- Test Statistic ? ?Known
-
- Rejection Rule Reject H0 if z gt z???
28Example Glow Toothpaste
- Two-Tailed Tests about a Population Mean The
production line for Glow toothpaste is designed
to fill tubes of toothpaste with a mean weight of
6 ounces. - Periodically, a sample of 30 tubes will be
selected in order to check the filling process.
Quality assurance procedures call for the
continuation of the filling process if the sample
results are consistent with the assumption that
the mean filling weight for the population of
toothpaste tubes is 6 ounces otherwise the
filling process will be stopped and adjusted. -
29Example Glow Toothpaste
- Two-Tailed Tests about a Population Mean Large
n - A hypothesis test about the population mean can
be used to help determine when the filling
process should continue operating and when it
should be stopped and corrected. - Hypotheses
- H0 ????? ?
- ??????Ha? ??????
- Rejection Rule
- ???????ssuming a .05 level of significance,
- Reject H0 if z lt -1.96 or if z gt 1.96
30Example Glow Toothpaste
- Two-Tailed Test about a Population Mean Large n
Sampling distribution of (assuming H0 is
true and ? 6)
Reject H0
Do Not Reject H0
Reject H0
??????????
??????????
z
0
1.96
-1.96
31First Method Glow Toothpaste
- Two-Tailed Test about a Population Mean Large n
- Assume that a sample of 30 toothpaste tubes
- provides a sample mean of 6.1 ounces. Standard
deviation (population) of 0.2 ounces. - Let n 30, 6.1 ounces, ? .2 ounces
-
- Since 2.74 gt 1.96, we reject H0.
- Conclusion We are 95 confident that the mean
filling weight of the toothpaste tubes is not 6
ounces. The filling process should be stopped
and the filling mechanism adjusted.
32Second Method Glow Toothpaste
- Using the p-Value for a Two-Tailed Hypothesis
Test - Suppose we define the p-value for a two-tailed
test as double the area found in the tail of the
distribution. - With z 2.74, the standard normal probability
- table shows there is a .5000 - .4969 .0031
probability - of a difference larger than .1 in the upper tail
of the - distribution.
- Considering the same probability of a larger
difference in the lower tail of the distribution,
we have - p-value 2(.0031) .0062
- The p-value .0062 is less than ? .05, so H0 is
rejected.
33Two-Tailed Tests About a Population Mean
1/2 p -value .0031
1/2 p -value .0031
a/2 .025
a/2 .025
z
0
z 2.74
z -2.74
za/2 1.96
-za/2 -1.96
34Third MethodConfidence Interval Approach to
aTwo-Tailed Test about a Population Mean
- Select a simple random sample from the population
and use the value of the sample mean to
develop the confidence interval for the
population mean ?. - If the confidence interval contains the
hypothesized value ?0, do not reject H0.
Otherwise, reject H0.
35Example Glow Toothpaste
- Confidence Interval Approach to a Two-Tailed
Hypothesis Test - The 95 confidence interval for ? is
- or 6.0284 to 6.1716
- Since the hypothesized value for the population
mean, ?0 6, is not in this interval, the
hypothesis-testing conclusion is that the null
hypothesis, - H0 ? 6, can be rejected.
-
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38Tests about a Population Mean? Unknown
- Test Statistic ? ?Unknown
-
-
- This test statistic has a t distribution with n
- 1 degrees of freedom. - Rejection Rule
- One-Tailed Two-Tailed
- H0 ?????? Reject H0 if t gt t?
- H0 ?????? Reject H0 if t lt -t?
- H0 ?????? Reject H0 if t gt t??? U
39p -Values and the t Distribution
- The format of the t distribution table provided
in most statistics textbooks does not have
sufficient detail to determine the exact p-value
for a hypothesis test. - However, we can still use the t distribution
table to identify a range for the p-value. - An advantage of computer software packages is
that the computer output will provide the p-value
for the - t distribution.
40Example Highway Patrol
- One-Tailed Test about a Population Mean Small n
- A State Highway Patrol periodically samples
vehicle speeds at various locations on a
particular roadway. The sample of vehicle speeds
is used to test the hypothesis - H0 m lt 65.
- The locations where H0 is rejected are deemed
the best locations for radar traps. - At Location F, a sample of 16 vehicles shows a
mean speed of 68.2 mph with a standard deviation
of 3.8 mph. Use an a .05 to test the
hypothesis.
41Example Highway Patrol
- One-Tailed Test about a Population Mean Small n
- Let n 16, 68.2 mph, s 3.8 mph
- a .05, d.f. 16-1 15, ta 1.753
-
- Since 3.37 gt 1.753, we reject H0.
- Conclusion We are 95 confident that the mean
speed of vehicles at Location F is greater than
65 mph. Location F is a good candidate for a
radar trap.
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43Excel
- Give below is a sample of monthly rent values ()
for one-bedroom apartments. The data is a sample
of 70 apartments in a particular city. The data
are presented in ascending order. - Lets suppose we want to test
-
44Continued
- The first step is to find
- Variable Name
- Number of Observations
- Lowest Value
- Mean
- Median
- Standard Deviation
- Standard Error
- Maximum Value
- 1st Quartile
- 3rd Quartile.
45Continued
- Variable Name Rent
- Number of Observations 70
- Lowest Value 425
- Mean 490.8
- Median 475
- Standard Deviation 54.74
- Standard Error 6.54
- Maximum Value 615
- 1st Quartile 446.25
- 3rd Quartile 552.5
46Null Hypothesis ?500
47Null Hypothesis ??515
Null Hypothesis ?? 515
48Null Hypothesis ??480
Null Hypothesis ?? 480
49Summary of Test Statistics to be Used in
aHypothesis Test about a Population Mean
Yes
No
n gt 30 ?
No
Popul. approx. normal ?
? known ?
Yes
Yes
Use s to estimate s
No
? known ?
No
Use s to estimate s
Yes
Increase n to gt 30
50A Summary of Forms for Null and Alternative
Hypotheses About a Population Proportion
- The equality part of the hypotheses always
appears - in the null hypothesis.
- In general, a hypothesis test about the value
of a - population proportion p must take one of
the - following three forms (where p0 is the
hypothesized - value of the population proportion).
One-tailed (lower tail)
One-tailed (upper tail)
Two-tailed
51Tests About a Population Proportion
where
assuming np gt 5 and n(1 p) gt 5
52Tests About a Population Proportion
- Rejection Rule p Value Approach
Reject H0 if p value lt a
- Rejection Rule Critical Value Approach
H0 p???p?
Reject H0 if z gt z?
H0 p???p?
Reject H0 if z lt -z?
H0 p???p?
Reject H0 if z lt -z??? or z gt z???
53Example NSC
- Two-Tailed Test about a Population Proportion
Large n - For a Christmas and New Years week, the
National Safety Council estimated that 500 people
would be killed and 25,000 injured on the
nations roads. The NSC claimed that 50 of the
accidents would be caused by drunk driving. - A sample of 120 accidents showed that 67 were
caused by drunk driving. Use these data to test
the NSCs claim with a 0.05.
54Two-Tailed Test About a Population Proportion
- Critical Value Approaches
1. Determine the hypotheses.
2. Specify the level of significance.
a .05
3. Compute the value of the test statistic.
55Two-Tailed Test About a Population Proportion
4. Determine the criticals value and rejection
rule.
For a/2 .05/2 .025, z.025 1.96
Reject H0 if z lt -1.96 or z gt 1.96
5. Determine whether to reject H0.
Because 1.278 gt -1.96 and lt 1.96, we cannot
reject H0.
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57End Lesson 3