Title: Case II: Testing Difference Between Means
1Case II Testing Difference Between Means
- Case II Do observations taken on two groups of
subjects differ from one another? Do the two sets
represent samples from identical or different
populations? - Case IIa Known population standard deviation
- Case IIb Population standard deviation not
known
2Case IIa Z test of Difference between Means
- Do observations take on two groups of subjects
differ from one another? Do the two sets
represent samples from identical or different
populations? - known population standard deviations
3Teacher Expectancy Study
- Sample 60 elementary children randomly selected
and randomly assigned to experimental (bloomers)
or control group. - Mean IQ of Bloomers 110.23
- Mean IQ of control group109.57
- Known population s.d.s (sigmas) experimental
group 10 and control group 10 - Is their a significant difference between
post-test IQ between Bloomers and Controls?
4Case IIa Design Requirements
- One independent variable with two levels
- Dependent variable is continuous (interval or
ratio) - A subject appears in one group only
- Population s.d. is known
5Case IIa Assumptions
- Scores in two groups are independent of one
another - Scores in the respective populations are normally
distributed - Variances of scores in two populations are equal
(homogeneity of variance)
6Teacher Expectancy Null and Alternative
Hypotheses
- Assume the null hypothesis is true until proven
guilty - State the Null Hypothesis
- H0 ?Bloomers ? Control
- H0 ? Bloomers- ? Control 0
- State the Alternative (Research) Hypothesis
- H1 ? Bloomers gt ? Control (directional,
one-tailed) - H1 ? Bloomers- ? Control gt 0 (directional,
one-tailed) - Or could have been
- H1 ? Bloomers not ? Control
(non-directional, two-tailed) - H1 ? Bloomers- ? Control not 0
(non-directional, two-tailed)
7Case II Same or Different Population
8Sampling Distribution of Differences between Means
68
95
99
-1se
-2se
1se
2se
-3se
3se
0
Null Hypothesis
9Sampling Distribution of Difference between Means
10Teacher Expectancy Testing Hypothesis (cont)
- Calculate the standard error of the difference of
means 2.57 - Calculate Zobserved by subtracting the sample
difference of means from the known
(hypothesized) population difference of means and
dividing by the standard error of the difference
of means - ((110.23-109.57)- (0)) /2.57
- .66/2.57.26 standard error points
- Evaluate against criteria (set level of
significance) - Significance level .05 one-tailed 1.65
(Zcritical) - Significance level .01 one-tailed 2.33
(Zcritical)
11Defining the Critical Area - Teacher Expectancy
Unlikely at .05
Unlikely at .01
1.65se
2.33se
0 population mean difference
12Teacher Expectancy (cont)
- Decision Rule
- If Zobserved falls outside of the chosen
Zcritical then reject the null hypothesis (H0) - If observed Z falls inside of the chosen
Zcritical then do not reject the null hypothesis
(H0) - Decision
- Having picked a significance levelof .05 our
Zobserved of .26 falls inside of the chosen
Zcritical of 1.65 so we would not reject the null
hypothesis - Conclusion
13Making Decision -Teacher Expectancy
Z Distribution Normal Curve
One tailed test
H0 ?E - ?c 0
.26
?diff 0
2se
-2se
1se
-1se
Critical Values
1..65se
2.33se
.01
.05
p
14Case IIb t-Test of Differences between
Independent Means
- Do the two samples belong to an identical
population or to a different population? - Population s.d. not known
15Case IIb Design Requirements for Use of t Test
- One independent variable with two levels
- Dependent variable is continuous (interval or
ratio) - A subject appears in one group only
- Population s.d.s not known
16Case IIb Assumptions
- Scores in two groups are independent of one
another - Scores in the respective populations are normally
distributed - Variances of scores in two populations are equal
(homogeneity of variance)
17Example T-test Two Sample Independent Means
Teacher Expectancy
18T-test for Two Sample (Independent Means) Designs
- Set Null Hypothesis ?e - ? c 0
- Set Alternative Hypothesis ? e - ? c gt 0
(one-tailed) - Examine Assumptions of t-test
- Independence and random sampling
- Normality within each population
- Homogeneity of variance (equal variance in two
pops) - Decide Significance Level alpha .01
- Compute standard error for difference between
means 6.44
19T-test for Two Sample (cont)
- Locate tcritical with N-2 df tcritical (.01/1,8)
2.896 - Compute tobserved
- ((116.4 -105.2)- 0)/6.44
- 11.2/6.44 1.74
- Decision Rule
- Reject H0 if tobserved gt tcritical
- Do Not Reject H0 if tobserved lt tcritical 1.74
lt 2.896 - Decision???
- Conclude although difference was in expected
direction, there is insufficient evidence to lead
us to believe that the observed difference in our
sample is due to anything other than chance
20Teacher Expectancy E.g.
t Distribution Sample Sizes 5 each df8 Alpha
.01
One tailed test
H0 ?E - ?c 0
1.74
0
2se
-2se
1se
-1se
Critical Values
1.860e
2..89se
.01
.05
P
21Teacher Expectancy 99 CI
- (Xe-Xc) - tcritical(.01/2,8) (sxe-xc)
- lt ue-uc lt
- (Xe-Xc) tcritical(.01/2,8) (sxe-xc)
- 11.2 - 2.306 (6.44) lt ue-uc lt 11.2 2.306
(6.44) - 11.2 - 14.85 lt ue-uc lt 11.2 14.85
- -3.65 lt ue-uc lt 26.05
- 95 CI tells us that over all random samples of
difference between means, the true value of ?e-
?c lies within this interval of IQ points with a
probability of ..95
22Assessing Practical Significance
- Significant findings may not be practically
significant - Three ways of assessing practical significance or
strength of association - Strength of Association
- Estimated Effect Size
- Statistical Power
23Practical Significance Strength of Association
- After making decision to reject H0
- The degree to which the sample data are found to
be incompatible with the H0 - Proportion of variance in dependent variable
accounted for, explained by, independent variable - Ranges from 0-1.00
24Practical Significance Effect Size (d)
- .20 - weak effect
- .33 - meaningful
- .50 - medium effect
- .80 - strong effect