Title: Principles of Reactivity: Chemical Equilibria
1Principles of ReactivityChemical Equilibria
2- Chemical reactions are reversible
- In a closed system, an equilibrium state will be
reached between reactants and products - Outside forces can affect the equilibrium
3Ca2(aq) 2HCO3- (aq) CaCO3(s) CO2(g)
H2O(l)
- Initially the product concentration is zero
- The reactants react at some rate
- As the reaction proceeds, the forward reaction
rate decreases - Products begin to react to reform reactants
- Reverse reaction rate increases as products are
being formed - Eventually the rate of the forward reaction
equals the rate of the reverse reaction - Dynamic equilibrium is
- established
4- Some links http//www.chm.davidson.edu/ChemistryAp
plets/equilibria/BasicConcepts.html - http//www.chm.davidson.edu/ronutt/che115/EquKin/E
quKin.htm
5Reaction Quotient and Equilibrium Constant
- At equilibrium, concentration of reactants and
products are related - At equilibrium, ratio of products to reactants is
constant - HI2 a constant
-
H2I2
H2(g) I2 (g) 2HI(2)
6Equilibrium Constant
- ICE table
- Equation H2(g) I2 (g)
2H2(g) - Initial conc (M) 0.0175
0.0175 0 - Change in conc (M) -0.0138
-0.0138 0.0276 - as rxn proceeds to
- equilibrium
- Equilibrium conc (M) 0.0037
0.0037 0.0276 - HI2 (0.0276)2 56
- H2I2
(0.0037)(0.0037)
7Reaction Quotient and Equilibrium Constant
- aA bB cC dD
- Under any reaction conditions
- Reaction quotient Q product
concentration CcDd -
reactant concentration AaBb - At equilibrium
- Reaction quotient equilibrium constant Keq
CcDd -
AaBb - When reaction has reached equilibrium, the
reaction quotient has a constant value, known as
the equilibrium constant, Keq - Law of Mass Action
- Expresses relative concentrations of reactants at
equilibrium in terms of an equilibrium constant
8Equilibrium Constant Expression
- aA bB cC dD
- Keq CcDd
- AaBb
- Product concentration in numerator
- Reactant concentration in denominator
- Concentration raised to power of its
stoichiometric coefficient in balanced equation - K depends on particular reaction and temperature
- K has no units
- Value of K is indicative of whether reaction is
product or reactant favored - Can calculate reactant or product concentration
at equilibrium
9- Homogeneous equilibria equilibrium conditions
where all reactants and products are in the same
state - Heterogeneous equilibria equilibrium conditions
where reactants and products are in more than one
state
10Writing Equilibrium Constant Expressions
- Concentrations of any solid or liquid reactants
and products are not included in the equilibrium
expression - S(s) O2(g) SO2(g) Keq SO2
- O2
- NH3(aq) H2O(l) NH4(g) OH-(aq)
KeqNH4OH - NH3
- Equilibrium constant expression written with
reactant and product concentration in moles/L - Keq sometimes written as Kc
11Graph pg 664 butane-isobutane equilibrium
- There are an infinite number of possible sets of
equilibrium concentrations of reactants to
products - A straight line produced
- Slope K
- Sets of concentrations of reactants and products
that do not lie along equilibrium line are not at
equilibrium.
12Reactions Involving Gases
- Equilibrium constant expression can be written in
terms of partial pressures of reactants and
products - H2(s) I2(g) 2HI(g) Kp P2 HI
- PH2PI2
- sometimes Kc and Kp are the same but not
usually
13Meaning of the Equilibrium Constant, K
- Kgtgt1 Reaction is product favored
- Kltlt 1Reaction is reactant favored
-
reactants products
14Meaning of the Reaction Quotient, Q
- Under any reaction conditions
- Reaction quotient Q product concentration
CcDd -
reactant concentration AaBb - Compare Q and K
- Q lt K, the system not at equilibrium and some
reactants will be converted to products - Q gt K, the system is not at equilibrium and some
products will be converted to reactants - Q K, the system is at equilibrium
- Example and exercise 16.3, 16.4 pg 665-666
15Determining an Equilibrium Constant
- Substitute concentrations of reactants and
products - at equilibrium in equilibrium expression
- But, we usually do not know all of the
concentrations of reactants and products at
equilibrium - Know equilibrium concentration of only one
reactant or product - Remaining ones need to be determined using
stoichiometry and the balanced equation - Set up an ICE table to help in organization of
data
16Determining an Equilibrium Constant
- Equation (_at_ 1000K) 2SO2(g)
O2 (g) 2SO3(g) - Initial conc (M) 1.00
1.00 0 - Change in conc (M) -0.925
-0.925/2 0.925 - Equilibrium conc (M) 1.00-0.925
1.00- 0.925/2 0.925 - Measured values 0.075
0.537 - Mol SO3 produced mol SO2 consumed
- 22 ratio from balanced equation
- Mol SO3 produced 0.5 mol O2 consumed
- 21 ratio from balanced equation
- K SO32 (0.925)2
2.8 x102 _at_ 1000K - SO22O2 (0.075)2(0.537)
- Example and exercises 16.3, 16.4, 16.5 pg 667-669
17Calculating equilibrium concentrations from Keq
- Look at example 16.5 pg 668
- Calculations involving the quadratic equation
(ax2 bx c 0) - x -b v b2 -4ac
- 2a
- Equation (K 1.20) PCl5(g)
PCl3 (g) Cl2(g) - Initial conc (M) 1.60
0 0 - Change in conc (M) 1.60 - x
x x - Equilibrium conc (M) 1.60 - x
x x
- K 1.20 PCl3Cl2 x2
x2 1.20x -1.92 0 - PCl5
1.60 x - solve for x x 0.91 and -2.11 Cant
have negative value, x 0.91 - PCl5 1.60 - 0.91 0.69M
- PCl3 Cl2 0.91M
18Calculating equilibrium concentrations from Keq
- Is there anything less complicated that still
gives us a reasonably accurate answer? - Need to understand meaning of Keq
- When Keq is large
- conc of products high, reactants mostly consumed
value of x large - When Keq is small
- conc of reactants high, products low value of x
small - A B C
- Keq BC x2
if Keq and A0 are known, need - A A0 x
to find C, B - When K is very small, x ltlt A0 , therefore A0
x A0 - Therefore Keq x2
- A0
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20Calculating equilibrium concentrations from Keq
- When can we use this approximation technique?
- If 100Keq lt A0 you can use this
technique - See example 16.6 pg 670
- Do exercise 16.7 pg 671
21More about Keq and balanced equations
- When the stoichiometric coefficients of a
balanced equation are multipled by some factor,
the equilibrium constant for the new equation is
the old equilibrium constant raised to the power
of the multiplication factor - C(s) ½ O2(g) CO(g) Keq1
CO/O2 ½ 4.6x 1023 - 2C(s) O2(g) 2CO(g) Keq2
CO2/O2 2.1x 1047 - Keq2 CO2/O2 CO/O2 ½ 2 Keq12
- Keq2 (Keq1)2
22More about Keq and balanced equations
- The equilibrium constants for a reaction and its
reverse are the reciprocals of each other - HCO2H(aq) H2O (l) HCO2-(aq)
H3O(aq) -
- Keqf HCO2-H3O Keqr HCO2H
- HCO2H
HCO2-H3O - 1.8x 10-4 5.6x 103
-
- Keqr 1/Keqf
23More about Keq and balanced equations
- When two or more chemical equations are added to
produce a net equation, the equilibrium constant
for the net equation is the product of the
equilibrium constants for the added equations - AgCl(s) Ag(aq)
Cl-(aq) Keq1 1.8 x
10-10 - Ag(aq) 2NH3 (aq) Ag(NH3) (aq)
Keq2 1.6 x 107 - AgCl(s) 2NH3 (aq) Ag(NH3)
(aq) Cl-(aq) - Keqnet Keq1 Keq2 AgCl- Ag(NH3)
Ag(NH3) Cl- -
AgNH32 NH32 - Keqnet Keq1 Keq2 2.9 x 10-3
- Examples and exercises 16.7,16.8, 16.9 pg.
673-674
24Disturbing a Chemical EquilibriumLe Chateliers
Principle
- Le Chateliers Principle
- If a stress (disturbance) is applied to a system
at equilibrium, the system will tend to adjust so
that the stress is reduced - (the equilibrium will shift to right or left)
Change in temperature - What stresses (disturbances)
- Change in concentration of one of the reactants
or products - Change in volume, pressure for a system of gases
- Change in temperature
- Be familiar with table 16.2 pg 675
25Disturbing a Chemical EquilibriumLe Chateliers
Principle
- Change in temperature
- endothermic
- N2(g) O2(g) 2NO(g) ?Hrxn
180.5kJ - Keq T
- 4.5 x 10-31 298
- 6.7 x 10-10 900
- 1.7 x 10-3 2300
- exothermic
- 2NO2(g) N2O4(g)
?Hrxn -57.2kJ - Keq T
- 1300 273
- 170 298
-
26Effect of Temperature Change
- Think of heat as a reactant or a product
- endothermic
- equilibrium shifts to the right
- exothermic
- equilibrium shifts to the left
- New equilibrium will be established with new
equilibrium concentrations of rectants and
products and a new Keq
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28Effect of addition or removal of a reactant or
product
- If conc. of reactant or product is changed at a
given T, equilibrium will eventually be
re-established - New equilibrium concentrations of reactants and
products will be different - But ratio of products to reactants (Keq) will be
the same - CH3CH2 CH2 CH3 (g)
CH3CH(CH3)CH3 (g) -
- If add more butane reaction will
proceed more in the forward - direction than the reverse direction
until equilibrium has been re- - established
-
- Example 16.8, exercise 16.10 pg 678
29CH4(g) H2O(g) CO(g) 3H2(g)
- In what direction will the equilibrium shift if
- Add water
- Add CO
- Remove hydrogen
- Add methane
- Remove methane
- Remove CO
- Remove water
- Add hydrogen
30Effect of Volume Change for a gas phase equilibria
- What happens to concentration or pressure of a
gas as volume changes? - If pressure is increased (decrease in volume) the
system will shift in direction that produces
fewer particles - If pressure is decreased (increase in volume) the
system will shift in direction that produces the
greater number of particles - 2NO2(g) N2O4(g)
- Exercise 16.12
31In what direction will the equilibrium shift if
- PCl5(g) heat PCl3 (g) Cl2(g)
- Add chlorine
- Increase pressure
- Remove heat
- Remove PCl3
- 2NH3(g) CO2(g) CO(NH2)2 (g) H2O(g)
- Add CO2
- Remove CO(NH2)2
- Increase T
- Decrease P
- Add water