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3.6 Polynomial and Rational Inequalities

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Procedure for Solving Polynomial Inequalities ... ( Use your calculator to check your results.) Text Example ... If struggling, do p 378#48 first.) Solution ... – PowerPoint PPT presentation

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Title: 3.6 Polynomial and Rational Inequalities


1
3.6 Polynomial and Rational Inequalities
Introduce infant mortality module.
2
Definition of a Polynomial Inequality
  • A polynomial inequality is any inequality that
    can be put in one of the forms
  • anxn an-1xn-1 a2x2 a1x a0 lt 0 anxn
    an-1xn-1 a2x2 a1x a0 gt 0
  • anxn an-1xn-1 a2x2 a1x a0 lt 0 anxn
    an-1xn-1 a2x2 a1x a0 gt 0
  • where the coefficients are real numbers and the
    degree is 2 or higher.

3
Procedure for Solving Polynomial Inequalities
  • Express the inequality in the standard form
    (leading coefficient positive set against zero.)
  • ex anxn an-1xn-1 a2x2 a1x a0 lt 0
  • Solve the equation anxn an-1xn-1 a2x2 a1x
    a00. The real solutions are the boundary
    points.
  • Locate these boundary points on a number line,
    thereby dividing the number line into test
    intervals.
  • Choose one representative number within each test
    interval. If substituting that value into the
    original inequality produces a true statement,
    then all real numbers in the test interval belong
    to the solution set. If substituting that value
    into the original inequality produces a false
    statement, then no real numbers in the test
    interval belong to the solution set.
  • Write the solution set the interval(s) that
    produced a true statement.

4
Example
Solve and graph the solution set on a real number
line 2x2 3x gt 2. (Dont look at notes, no
need to write.)
Solution
Step 1 Write the inequality in standard form. We
can write by subtracting 2 from both sides to get
zero on the right. 2x2 3x 2 gt 2 2
2x2 3x 2 gt 0
Step 2 Solve the related quadratic (polynomial)
equation. Replace the inequality sign with an
equal sign. Thus, we will solve. 2x2 3x
2 0 This is the related quadratic equation.
(2x 1)(x 2) 0 Factor.
2x 1 0 or x 2 0 Set each factor equal to
0.
x -1/2 or x 2 Solve for x.
The boundary points are 1/2 and 2. So far, we
have taken similar steps to solve quadratic
(polynomial) EQUATIONS.
5
Example cont.
Solve and graph the solution set on a real number
line 2x2 3x gt 2.
Solution
Step 3 Locate the boundary points on a number
line. The number line with the boundary points
is shown as follows
The boundary points divide the number line into
________ test intervals. Including the boundary
points (because of the given greater than or
equal to sign), the intervals are
6
Example cont.
Solve and graph the solution set on a real number
line 2x2 3x gt 2.
Solution
Step 4 Take one representative number within each
test interval and substitute that number into the
original inequality (belongs or not to the
solution set?).
7
Example cont.
Solve and graph the solution set on a real number
line 2x2 3x gt 2.
Solution
Step 5 The solution set are the intervals that
produced a true statement. Our analysis shows
that the solution set is (-ºº, -1/2 or 2,
ºº).
Find the graphing error(s). When you get tired of
this method, let me know, there is a more
conceptual method that is much quicker (using
signs.)
8
  • Ex Graph the solutions of

9
ExDo p 378 44. Ex Finally find the
equation of a graph that has no solutions. (Use
your calculator to check your results.)
10
Text Example(Dont look at notes, not necessary
to write. If struggling, do p 37848 first.)
Solution
Step 1 Express the inequality so that one side is
zero and the other side is a single quotient. We
subtract 2 from both sides to obtain zero on the
right.
IMPORTANT We MUST set 0 first!
11
Text Example cont.
-x-5 lt 0 x 3
Solution
Step 2 Find boundary points by setting the
numerator and the denominator equal to zero.
12
Text Example cont.
Step 3 Locate boundary points on a number line.
(In this case, -5 and 3. How many testing
intervals now? Name them.)
Step 4 Take one representative number within each
test interval and substitute that number into the
original equality. (Fill in your notes.)
13
Text Example cont.
Step 5 The solution set are the intervals that
produced a true statement. Our analysis shows
that the solution set is (-ºº, -5 or (-3, ºº)
14
The Position Formula for a Free-Falling Object
Near Earths Surface
  • An object that is falling or vertically projected
    into the air has its height in feet above the
    ground given by
  • s -16 t 2 v0 t s0
  • where s is the height in feet, v0 is the original
    velocity (initial velocity) of the object in feet
    per second, t is the time that the object is in
    motion in seconds, and s0 is the original height
    (initial height) of the object in feet.
  • Q What shape would this have if we were to
    graph it? What variables would go on each axis?
    What does this mean physically?

15
Examples -16 t 2 v0 t s0
An object is propelled straight up from ground
level with an initial velocity of 80 fps. Its
height at time t is described by
__________________ where the height, s, is
measured in feet and the time, t, is measured in
seconds. In which time interval will the object
be more than 64 feet above the ground? (What is
s0 ?) How does this graph look? Put it in your
calculator to check your guess.
Solution
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