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Mendelian Genetics, Punnett Squares, and Meiosis Jeopardy

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Mendelian Genetics 200. Mendel's 3 Conclusions about heredity are: ... Mendelian Genetics 400 ... Mendelian Genetics 1000. A brown fur squirrel is mated with a ... – PowerPoint PPT presentation

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Title: Mendelian Genetics, Punnett Squares, and Meiosis Jeopardy


1
Mendelian Genetics, Punnett Squares, and Meiosis
Jeopardy
  • Test 1.20
  • TOMORROW!!!

2
Mendelian Genetics 200
  • Mendels 3 Conclusions about heredity are
  • A) Law of Dominance, Law of Segregation, Law of
    DNA
  • B) Law of Dominance, Law of DNA, Law of
    Independent Assortment
  • C) Law of Dominance, Law of Segregation and Law
    of Independent Assortment
  • D) Law of Genes, Law of DNA, Law of the Pea Plant
  • Correct Answer C

3
Mendelian Genetics 400
  • Mendel took two true breeding pea plants (P1)
    with contrasting phenotypes and bred them. The
    F1 phenotype showed
  • A) DNA of P1
  • B) The dominant trait
  • C) The recessive trait
  • D) Mutations
  • Correct Answer B

4
Mendelian Genetics 600
  • The Law of Segregation States that each parent in
    the P1 generation can give
  • A) Only one allele to the offspring
  • B) Only recessive alleles to the offspring
  • C) Both alleles to the offspring
  • D) Mutated alleles to the offspring
  • Answer A

5
Mendelian Genetics 800
  • Mendel took two pea plants one with a recessive
    phenotype for flowers (white) the other with a
    dominant phenotype for flowers (purple), genotype
    unknown and bred them. The F1 outcome was all
    dominant phenotypes. What were the genotypes of
    the P1 generation? The offspring?
  • A) Pp x Pp..PP
  • B) PP x Pp..PP
  • C) Pp x pp..pp
  • D) PP x pp. Pp
  • Answer D

6
Mendelian Genetics 1000
  • A brown fur squirrel is mated with a grey furred
    squirrel. All offspring (F1) show patches of both
    grey and brown fur. Two F1 squirrels are bred
    and the F2 phenotypic ratio is 1 brown squirrel,
    2 patchy squirrels, 1 grey squirrel. This is a
    case of ________.
  • A) Complete Dominance
  • B) Incomplete Dominance
  • C) Co-Dominance
  • D) Mutation
  • Answer C

7
Mendelian Genetics 1200
  • A pink flower is bred with a white flower (P1).
    The F1 shows 2 pink flowers and 2 white flowers.
    The two pink flowers from the F1 are bred. The F2
    shows 1 red flower, 2 pink flowers and 1 white
    flower. This is a case of ___. What were the
    genotypes of the P1 generation?
  • A) Co- dominanceRr x rr
  • B) Incomplete dominanceRR x rr
  • C) Complete dominanceRr x rr
  • D) Incomplete dominanceRr x rr
  • Answer D

8
Punnett Squares 200
  • A Punnett Square uses the possible alleles from
    the P1 gametes to determine
  • A) Phenotype probability only of F1
  • B) Genotype and phenotype probability of F1
  • C) DNA of F1
  • D) Genotypic probability only of F1
  • Answer B

9
Punnett Squares 400
  • Assume the tall trait in pea plants to be
    dominant and the short trait to be recessive. A
    Tt plant mates with a Tt plant. What will be the
    genotypic and phenotypic ratio of the F1?
  • A) 121.31
  • B) 121.22
  • C) 040.40
  • D) 220.40
  • Answer A

10
Punnett Squares 600
  • Assume the superpower of laser beams is a
    recessive trait (b). A laser beam hero mates with
    another superhero of unknown genotype or
    phenotype. The F1 offspring phenotypic ratio is
    2 no beams 2 beams. What was the genotype and
    phenotype of the unknown Parent? Offspring?
  • A) BB, no beams, 2 Bb bb
  • B) bb, beams, 2 BB 2 Bb
  • C) Bb, incomplete beams, 2 BB 2 bb
  • D) Bb, no beams, 2 Bb 2 bb
  • Answer D

11
Punnett Squares 800 honors
  • Assume the traits blue hair and pink eyes are
    dominant in an alien species. Orange eyes and
    green hair are recessive. What is the probability
    of having a child with pink eyes and green hair
    if the P1 generation genotypes are PPBb x Ppbb?
  • A) 25
  • B) 50
  • C) 75
  • D) 0
  • Answer B

12
Punnett Squares 1000
  • A chicken homozygous recessive for no feathers
    (ff) and heterozygous for big beak (Bb) mates
    with a chicken of unknown genotype and phenotype.
    The F1 has 2 birds with feathers and small beaks
    and 6 birds with feathers and big beaks. What is
    the genotype of the unknown chicken?
  • A) BbFf
  • B) Bbff
  • C) bbFF
  • D) BbFF
  • Answer D

13
Meiosis 200
  • The outcome of meiosis is
  • A) two haploid gamete cells with different DNA
    (alleles)
  • B) four haploid gamete cells with differing DNA
    (alleles)
  • C) four diploid gamete cells with differing DNA
    (alleles)
  • D) two diploid gamete cells with identical DNA
    (alleles)
  • Answer B

14
Meiosis 400
  • The two phases of meiosis are
  • A) Meiosis I and Mitosis
  • B) Meiosis I and cytokinesis
  • C) Meiosis I and Meiosis II
  • D) Prophase and Metaphase
  • Answer C

15
Meiosis 600
  • The outcome of Meiosis I is
  • A) The duplication of homologous chromosomes into
    tetrads which divide into two genetically
    identical diploid cells
  • B) The duplication of homologous chromosomes into
    tetrads which divide into two genetically
    differing diploid cells cells
  • C) The formation of 4 haploid gamete cells
  • D) The formation of 4 identical diploid
  • Answer B

16
Meiosis 800
  • The difference between Mitosis and Meiosis is
  • A) in Meiosis I two non identical genetically
    cells are form and in meiosis II 4 haploid cells
    are produce
  • B) in Meiosis I four identical genetic cells are
    produced and in meiosis II 2 identical haploid
    cells are produced
  • C) in Meiosis there is no interphase and no
    cytokinesis
  • D) in Meiosis there is no chromosome duplication
  • Answer A

17
Meiosis 1000
  • Meiosis can be described by the following
    acronym I-PMAT-C PMAT-C. In interphase
    _________ occurs. In cytokinesis ____________
    occurs. There are ________ round(s) of interphase
    and _______ round(s) of cytokinesis.
  • A) cell division, duplication of chromosomes, 1,
    2
  • B) cell division, cell fusion, 2, 1
  • C) duplication of chromosomes, cell division, 1,
    2
  • D) duplication of chromosomes, cell division, 2,
    1
  • Answer C

18
Final Jeopardy
  • 2 exotic species of fish have been detected in
    Lake Lanier 1 male, 1 female. They appear to be
    phenotypically similar to a saltwater species (S)
    from Australia which kills all competing fish in
    a freshwater ecosystem. The species can have a
    recessive trait which allows it to survive in
    freshwater (ss). It is only a predator if it
    acquires the dominant fang allele (F). If it
    does not, the organism will benefit the ecosystem
    by only eating garbage (ff). A pet store owner
    fesses up to letting the 2 exotic fish loose.
  • Both are related offspring of parents Ffss x
    ffSs. What are the possible genotypes of the
    offspring (F1)? What is the genotype of the
    offspring? If the offspring mated, what is the
    probability their offspring (F2) will damage the
    Lake Lanier ecosystem?
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