Title: Cutting a Pie is Not a Piece of Cake
1Cutting a Pie is Not a Piece of Cake
- Walter Stromquist
- Swarthmore College
- mail_at_walterstromquist.com
- Third World Congress of the Game Theory Society
- Evanston, IL
- July 13, 2008
2Cutting a Pie is Not a Piece of CakeJulius B.
Barbanel, Steven J. Brams, Walter Stromquist
-
- Mathematicians enjoy cakes for their own
sake and as a metaphor for more general fair
division problems. - A cake is cut by parallel planes into n pieces,
one for each of n players whose preferences are
defined by separate measures. It is known that
there is always an envy-free division, and that
such a division is always Pareto optimal. So for
cakes, equity and efficiency are compatible. - A pie is cut along radii into wedges. We
show that envy-free divisions are not necessarily
Pareto optimal --- in fact, for some measures,
there may be no division that is both envy-free
and Pareto optimal. So for pies, we may have to
choose between equity and efficiency.
2
3 - This is joint work with
Julius B. Barbanel (Union
College) -
- Steven J. Brams (New York University)
4- 1. Introduction
- 2. Cakes
- 3. Pies
- 4. Summary
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6Some definitions
- Cakes are cut by parallel planes.
- The cake is an interval C 0, m .
- Points in interval possible cuts.
- Subsets of interval possible pieces.
- We want to partition the interval into S1, S2,
, Sn, where - Si i-th players piece.
- Players preferences are defined by measures
v1, v2, , vn - vi (Sj ) Player is valuation of piece
Sj. - These are probability measures.
- We always assume that they are non-atomic (single
points always have value zero).
6
7Absolutely continuous
- Sometimes we assume that the measures are
absolutely continuous with respect to each other. - In effect, this assumption means that pieces with
positive length also have positive value to every
player.
8- 1. Introduction
- 2. Cakes
- 3. Pies
- 4. Summary
9Two playersI cut, you choose
9
10n playersEverybody gets 1/n
- Referee slides knife from left to right
- Anyone who thinks the left piece has reached 1/n
says STOP and gets the left piece. - Proceed by induction. (Banach - Knaster ca.
1940)
10
11Envy-free divisions
- A division is envy-free if no player thinks any
other players piece is better than his own - vi (Si) ? vi (Sj) for every i and j.
- Can we always find an envy-free division?
- Theorem (1980) For n players, there is always
an envy-free division in which each player
receives a single interval. - Proofs
- (WRS) The division simplex
- (Francis Edward Su) Sperners Lemma
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12Two moving knives the squeeze
- A cuts the cake into thirds (by his measure).
- Suppose B and C both choose the center piece.
- A moves both knives in such a way as to keep end
pieces equal (according to A) - B or C says STOP when one of the ends becomes
tied with the middle. (Barbanel and Brams, 2004)
12
13Undominated allocations
- A division Si S1, S2, , Sn is dominated by
a division - Ti T1, T2, , Tn if
- vi(Ti) ? vi(Si) for every i
- with strict inequality in at least one case.
- That is T makes some player better off, and
doesnt make any player worse off. - Si is undominated if it isnt dominated by
any Ti . - undominated Pareto optimal efficient
-
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14Envy-free implies undominated
- Is there an envy-free allocation that is also
undominated? - Theorem (Gale, 1993) Every envy-free division
of a cake into n intervals for n players is
undominated (assuming absolute continuity). - So for cakes EQUITY ? EFFICIENCY.
14
15Gales proof
- Theorem (Gale, 1993) Every envy-free division
of a cake into n intervals for n players is
undominated. - Proof Let Si be an envy-free division.
- Let Ti be some other division that we think
might - dominate Si.
- S2 S3 S1
- T3 T1 T2
- v1(T1) lt v1(S3) ? v1(S1)
-
- so Ti doesnt dominate Si after all. //
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16Cakes without absolute continuity
- First players preference Uniform, EXCEPT on the
leftmost third of the cake. The first player
likes only the left half of the leftmost third. - All other players preferences are uniform.
- The only envy-free divisions involve cutting the
pie in thirds. - None of these divisions is undominated.
- Without absolute continuity We may have to
choose between envy-free and undominated.
17Summary for cakes
- With absolute continuity
- There is always an envy-free division.
- Every envy-free division is also undominated.
- There is always a division that is both
envy-free and undominated. - Without absolute continuity
- There is always an envy-free division.
- For some measures, there is NO division that is
both envy-free - and undominated. We may have to choose!
- Unless n 2, when there is always an envy-free,
undominated division, whatever the measures.
18- 1. Introduction
- 2. Cakes
- 3. Pies
- 4. Summary
19Pies
- Pies are cut along radii. It takes n cuts to
make pieces for n players. - A cake is an interval.
- A pie is an interval with its endpoints
identified.
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21Pies
- 1. Are there envy-free divisions for pies?
- YES
- 2. Does Gales proof work?
- NO
- Envy-free does NOT imply undominated
- 3. Are there pie divisions that are both
envy-free and undominated? (Gales
question, 1993) - YES for two players
- NO if we dont assume absolute continuity
- NO for the analogous problem with unequal
claims - (Brams, Jones, Klamler next talk!)
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22Pies
- For n ? 3, there are measures for which there
does NOT exist an envy-free, undominated
allocation. - These measures may be chosen to be absolutely
continuous. - So, Gales question is answered in the negative.
233
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2
24The example
- Partition the pie into 18 tiny sectors.
- Each players preference is uniform, except
- Each player dislikes certain sectors (grayed
out). - Each player perceives positive or negative
bonuses (C) - or mini-bonuses (?) in certain sectors.
- The measures for three players
C ? C C C ? C ? C C C ?
C
C
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25Pies for two players
- Of all envy-free allocations, pick the one most
preferred by Player 2. - That allocation is both envy-free and undominated.
26Summary for pies
- With or without absolute continuity
- There is always an envy-free division.
- For some measures, there is NO division that is
both envy-free - and undominated. We may have to choose!
- Unless n 2, when there is always an envy-free,
undominated division, whatever the measures.
27- 1. Introduction
- 2. Cakes
- 3. Pies
- 4. Summary
28SummaryWhen must there be an
envy-free,undominated allocation?
CAKE PIE
2 players YES YES
?3 players YES, assuming absolute continuity (otherwise NO) NO
29Cookies
- This cookie cutter has blades at fixed 120-degree
angles. - But the center can go anywhere. Is there always
an envy-free division of the cookie? Envy-free
and undominated?
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