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How to solve word problem in Physics

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This equation asks for v2. It is the final velocity, which the problem states is. v2 = -1m/ s ... What is it? It is final stopwatch reading. The problem states ... – PowerPoint PPT presentation

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Title: How to solve word problem in Physics


1
How to solve word problemin Physics
  • Average Acceleration Problem

By Nerima Pasic
2
  • At t 5 s an object is traveling at 5m/s.
  • At t 8s its velocity is 1m/s.
  • Find the average acceleration for this interval.

3
Strategy
  • What does problem ask for?
  • The problem asks for average acceleration under
    certain conditions.

4
What is given?
  • Time t15 s
  • Velocity v15m/s
  • Time t2 8 s
  • Velocity v2 -1m/ s

5
What is equation for average acceleration?
  • aave (v2-v1) / (t2 t1 )

6
Lets work from left to right!
aave (v2-v1) / (t2 t1 )
This equation asks for v2
7
What is v2 ?
It is the final velocity, which the problem
states is v2 -1m/ s
8
Working left to right equation now asks for v1
aave (v2-v1) / (t2 t1 )
What is v1?
Its initial velocity which the problem states is
V15m/s.
9
Working top down, the equation next asks for
t2.
What is it?
aave (v2-v1) / (t2 t1 )
It is final stopwatch reading.
The problem states that this is t2 8 s
10
Continuing left-right the equation next asks for
t1 .
aave (v2-v1) / (t2 t1 )
Again, What is it?
It is initial stopwatch reading, which the
problem states is t1 5s.
11
Lets go back and see now what was given?
  • Time t15 s ..initial time
  • Velocity v15m/s..initial velocity
  • Time t2 8 sfinal time
  • Velocity v2 -1m/ s..final velocity

12
Substituting these results in the starting
equation gives
  • aave (-1m/s)-(5m/s)/(8s-5s)
  • Factoring units gives aave (-1-5)m/(8-5) s/s
  • aave (-6m)/(3s/s)
  • aave 2m/s/s or aave 2m/s2
  • (s2 means s x s second squared)
  • Average acceleration is
  • 2 meter per second-every second.
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