Title: Queueing Theory-1
1Queueing Theory
2Basic Queueing Process
?
- Arrivals
- Arrival time distribution
- Calling population (infinite or finite)
- Service
- Number of servers(one or more)
- Service time distribution
- Queue
- Capacity(infinite or finite)
- Queueing discipline
Queueing System
3Examples and Applications
- Call centers (help desks, ordering goods)
- Manufacturing
- Banks
- Telecommunication networks
- Internet service
- Intelligence gathering
- Restaurants
- Other examples.
4Labeling Convention (Kendall-Lee)
/ / / / /
Interarrival timedistribution
Number of servers
Queueing discipline
System capacity
Calling population size
Service timedistribution
Notes
FCFS first come, first served LCFS last come,
first served SIRO service in random
order GD general discipline
M Markovian (exponential interarrival times,
Poisson number of arrivals) D Deterministic Ek Er
lang with shape parameter k G General
5Labeling Convention (Kendall-Lee)
- ExamplesM/M/1M/M/5M/G/1M/M/3/LCFSEk/G/2//10
M/M/1///100
6Terminology and Notation
- State of the system Number of customers in the
queueing system (includes customers in service) - Queue length Number of customers waiting for
service - State of the system - number of customers
being served - N(t) State of the system at time t, t 0
- Pn(t) Probability that exactly n customers are
in the queueing system at time t
7Terminology and Notation
- ?n Mean arrival rate (expected arrivals per
unit time) of new customers when n customers
are in the system - s Number of servers (parallel service
channels) - ?n Mean service rate for overall system
(expected customers completing service per
unit time) when n customers are in the system - Note ?n represents the combined rate at which
all busy servers (those serving customers)
achieve service completion.
8Terminology and Notation
- When arrival and service rates are constant for
all n, - ? mean arrival rate (expected arrivals
per unit time) - ? mean service rate for a busy server
- 1/? expected interarrival time
- 1/? expected service time
- ? ?/s? utilization factor for the service
facility expected fraction of time the
systems service capacity (s?) is being utilized
by arriving customers (?)
9Terminology and NotationSteady State
- When the system is in steady state, then
- Pn probability that exactly n customers are
in the queueing system - L expected number of customers in queueing
system -
- Lq expected queue length (excludes customers
being served) -
10Terminology and NotationSteady State
- When the system is in steady state, then
- ? waiting time in system (includes service
time) for each individual customer - W E?
- ?q waiting time in queue (excludes service
time) for each individual customer - Wq E?q
11Littles Formula
Demonstrates the relationships between L, W, Lq,
and Wq
- Assume ?n? and ?n? (arrival and service rates
constant for all n) - In a steady-state queue,
Intuitive Explanation
12Littles Formula (continued)
- This relationship also holds true for ? (expected
arrival rate) when ?n are not equal.
Recall, Pn is the steady state probability of
having n customers in the system
13Heading toward M/M/s
- The most widely studied queueing models are of
the form M/M/s (s1,2,) - What kind of arrival and service distributions
does this model assume? - Reviewing the exponential distribution.
- If T exponential(a), then
- A picture of the distribution
14Exponential Distribution Reviewed
- If T exponential(?), then
Var(T) ______
ET ______
15Property 1Strictly Decreasing
- The pdf of exponential, fT(t), is a strictly
decreasing function - A picture of the pdf
fT(t)
?
t
16Property 2Memoryless
- The exponential distribution has lack of memory
- i.e. P(T gt ts T gt s) P(T gt t) for all
s, t 0. - Example
- P(T gt 15 min T gt 5 min) P(T gt 10 min)
- The probability distribution has no memory of
what has alreadyoccurred.
17Property 2Memoryless
- Prove the memoryless property
- Is this assumption reasonable?
- For interarrival times
- For service times
18Property 3Minimum of Exponentials
- The minimum of several independent exponential
random variables has an exponential distribution - If T1, T2, , Tn are independent r.v.s, Ti
expon(?i) and - U min(T1, T2, , Tn),
- U expon( )
- Example
- If there are n servers, each with exponential
service times with mean ?, then U time until
next service completion expon(____)
19Property 4Poisson and Exponential
- If the time between events, Xn expon(?),
thenthe number of events occurring by time t,
N(t) Poisson(?t) - Note
- EX(t) at, thus the expected number of events
per unit time is a
20Property 5Proportionality
- For all positive values of t, and for small ?t,
- P(T t?t T gt t) ??t
- i.e. the probability of an event in interval ?t
is proportional to the length of that interval
21Property 6Aggregation and Disaggregation
- The process is unaffected by aggregation and
disaggregation
Aggregation
Disaggregation
N1 Poisson(?1)
N1 Poisson(?p1)
p1
N2 Poisson(?2)
N2 Poisson(?p2)
N Poisson(?)
N Poisson(?)
p2
pk
? ?1?2?k
Nk Poisson(?k)
Nk Poisson(?pk)
Note p1p2pk1
22Back to Queueing
- Remember that N(t), t 0, describes the state of
the systemThe number of customers in the
queueing system at time t - We wish to analyze the distribution of N(t) in
steady state
23Birth-and-Death Processes
- If the queueing system is M/M////, N(t) is a
birth-and-death process - A birth-and-death process either increases by 1
(birth), or decreases by 1 (death) - General assumptions of birth-and-death processes
- 1. Given N(t) n, the probability distribution
of the time remaining until the next birth is
exponential with parameter ?n - 2. Given N(t) n, the probability distribution
of the time remaining until the next death is
exponential with parameter µn - 3. Only one birth or death can occur at a time
24Rate Diagrams
25Steady-State Balance Equations
26M/M/1 Queueing System
- Simplest queueing system based on birth-and-death
- We define ? mean arrival rate? mean service
rate ? ? / ? utilization ratio - We require ? lt ? , that is ? lt 1 in order to have
a steady state - Why?
Rate Diagram
?
?
?
?
?
1
2
3
4
0
?
?
?
?
?
27M/M/1 Queueing System Steady-State Probabilities
28M/M/1 Queueing System L, Lq, W, Wq
29M/M/1 Example ER
- Emergency cases arrive independently at random
- Assume arrivals follow a Poisson input process
(exponential interarrival times) and that the
time spent with the ER doctor is exponentially
distributed - Average arrival rate 1 patient every ½ hour
- ?
- Average service time 20 minutes to treat each
patient - ?
- Utilization
- ?
30M/M/1 Example ERQuestions
- What is the
- probability that the doctor is idle?
- probability that there are n patients?
- expected number of patients in the ER?
- expected number of patients waiting for the
doctor? - expected time in the ER?
- expected waiting time?
- probability that there are at least two patients
waiting? - probability that a patient waits more than 30
minutes?
31Car Wash Example
- Consider the following 3 car washes
- Suppose cars arrive according to a Poisson input
process and service follows an exponential
distribution - Fill in the following table
? ? L Lq W Wq P0
Car Wash A 0.1 car/min 0.5 car/min
Car Wash B 0.1 car/min 0.11 car/min
Car Wash C 0.1 car/min 0.1 car/min
What conclusions can you draw from your results?
32M/M/s Queueing System
- We define ? mean arrival rate? mean service
rate s number of servers (s gt 1)? ? / s?
utilization ratio - We require ? lt s? , that is ? lt 1 in order to
have a steady state
Rate Diagram
1
2
3
4
0
33M/M/s Queueing System Steady-State Probabilities
Pn CnP0
and
where
34M/M/s Queueing System L, Lq, W, Wq
How to find L? W? Wq?
35M/M/s Example A Better ER
- As before, we have
- Average arrival rate 1 patient every ½ hour?
2 patients per hour - Average service time 20 minutes to treat each
patient? 3 patients per hour - Now we have 2 doctorss
- Utilization
- ?
36M/M/s Example ERQuestions
- What is the
- probability that both doctors are idle?
- probability that exactly one doctor is idle?
- probability that there are n patients?
- expected number of patients in the ER?
- expected number of patients waiting for a doctor?
- expected time in the ER?
- expected waiting time?
- probability that there are at least two patients
waiting? - probability that a patient waits more than 30
minutes?
37Performance Measurements s 1 s 2
? 2/3 1/3
L 2 3/4
Lq 4/3 1/12
W 1 hr 3/8 hr
Wq 2/3 hr 1/24 hr
P(at least two patients waiting in queue) 0.296 0.0185
P(a patient waits more than 30 minutes) 0.404 0.022
38Travel Agency Example
- Suppose customers arrive at a travel agency
according to a Poisson input process and service
times have an exponential distribution - We are given
- ? .10/minute 1 customer every 10 minutes
- ? .08/minute 8 customers every 100 minutes
- If there were only one server, what would happen?
- How many servers would you recommend?
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42Single Queue vs. Multiple Queues
- Would you ever want to keep separate queues for
separate servers?
Single queue
Multiple queues
43Bank Example
- Suppose we have two tellers at a bank
- Compare the single server and multiple server
models - Assume ? 2, ? 3
L Lq W Wq P0
44Bank ExampleContinued
- Suppose we now have 3 tellers
- Again, compare the two models
45M/M/s//K Queueing Model(Finite Queue Variation
of M/M/s)
- Now suppose the system has a maximum capacity, K
- We will still consider s servers
- Assuming s K, the maximum queue capacity is K
s - List some applications for this model
- Draw the rate diagram for this problem
46M/M/s//K Queueing Model(Finite Queue Variation
of M/M/s)
Rate Diagram
1
2
3
4
0
- Balance equations Rate In Rate Out
47M/M/s//K Queueing Model(Finite Queue Variation
of M/M/s)
- Solving the balance equations, we get the
following steady state probabilities
Verify that these equations match those given in
the text for the single server case (M/M/1//K)
48M/M/s//K Queueing Model(Finite Queue Variation
of M/M/s)
To find W and Wq Although L ? lW and Lq ? lWq
because ln is not equal for all n,
and
where
49M/M/s///N Queueing Model(Finite Calling
Population Variation of M/M/s)
- Now suppose the calling population is finite
- We will still consider s servers
- Assuming s K, the maximum queue capacity is K
s - List some applications for this model
- Draw the rate diagram for this problem
50M/M/s///N Queueing Model(Finite Calling
Population Variation of M/M/s)
Rate Diagram
1
2
3
4
0
- Balance equations Rate In Rate Out
51M/M/s///N Results
52Queueing Models with Nonexponential Distributions
- M/G/1 Model
- Poisson input process, general service time
distribution with mean 1/? and variance ?2 - Assume ? ?/? lt 1
- Results
53Queueing Models with Nonexponential Distributions
- M/Ek/1 Model
- Erlang Sum of exponentials
- Think it would be useful?
- Can readily apply the formulae on previous slide
where - Other models
- M/D/1
- Ek/M/1
- etc
54Application of Queueing Theory
- We can use the results for the queueing models
when making decisions on design and/or operations - Some decisions that we can address
- Number of servers
- Efficiency of the servers
- Number of queues
- Amount of waiting space in the queue
- Queueing disciplines
55Number of Servers
- Suppose we want to find the number of servers
that minimizes the expected total cost, ETC - Expected Total Cost Expected Service Cost
Expected Waiting Cost(ETC ESC EWC) - How do these costs change as the number of
servers change?
Expected cost
Number of servers
56Repair Person Example
- SimInc has 10 machines that break down frequently
and 8 operators - The time between breakdowns Exponential, mean
20 days - The time to repair a machine Exponential, mean
2 days - Currently SimInc employs 1 repair person and is
considering hiring a second - Costs
- Each repair person costs 280/day
- Lost profit due to less than 8 operating
machines400/day for each machine that is down - Objective Minimize total cost
- Should SimInc hire the additional repair person?
57Repair Person ExampleProblem Parameters
- What type of problem is this?
- M/M/1
- M/M/s
- M/M/s/K
- M/G/1
- M/M/s finite calling population
- M/Ek/1
- M/D/1
- What are the values of ? and ??
58Repair Person ExampleRate Diagrams
- Draw the rate diagram for the single-server and
two-server case
Single server
1
2
3
4
10
9
8
0
1
2
3
4
10
9
8
Two servers
0
- Expected service cost (per day) ESC
- Expected waiting cost (per day) EWC
59Repair Person ExampleSteady-State Probabilities
- Write the balance equations for each case
- How to find EWC for s1? s2?
60Repair Person ExampleEWC Calculations
Nn g(n) s1 s1 s2 s2
Nn g(n) Pn g(n) Pn Pn g(n) Pn
0 0 0.271 0 0.433 0
1 0 0.217 0 0.346 0
2 0 0.173 0 0.139 0
3 400 0.139 56 0.055 24
4 800 0.097 78 0.019 16
5 1200 0.058 70 0.006 8
6 1600 0.029 46 0.001 0
7 2000 0.012 24 0.0003 0
8 2400 0.003 7 0.00004 0
9 2800 0.0007 0 0.000004 0
10 3200 0.00007 0 0.0000002 0
EWC EWC 281/day 281/day 48/day 48/day
61Repair Person ExampleResults
- We get the following results
s ESC EWC ETC
1 280/day 281/day 561/day
2 560/day 48/day 608/day
3 840/day 0/day 840/day
62Supercomputer Example
- Emerald University has plans to lease a
supercomputer - They have two options
Supercomputer Mean number of jobs per day Cost per day
MBI 30 jobs/day 5,000/day
CRAB 25 jobs/day 3,750/day
- Students and faculty jobs are submitted on
average of 20 jobs/day, distributed
Poisson i.e. Time between submissions
__________ - Which computer should Emerald University lease?
63Supercomputer ExampleWaiting Cost Function
- Assume the waiting cost is not linear h(?)
500 ? 400 ? 2 (? waiting time in days) - What distribution do the waiting times follow?
- What is the expected waiting cost, EWC?
64Supercomputer ExampleResults
- Next incorporate the leasing cost to determine
the expected total cost, ETC - Which computer should the university lease?