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Construction Engineering 221

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Concrete cylinder test results (in psi) are 1000, 1200, 1150, 1100, and 1230. ... need to have three of six cylinders exceed 1200 psi before you can strip forms. ... – PowerPoint PPT presentation

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Title: Construction Engineering 221


1
Construction Engineering 221
  • Normal distribution part II

2
Normal distribution
  • Many measurements are normally distributed and
    can be converted to a standardized distribution
    in order to use z-tables
  • To calculate probabilities, it is typical to pick
    an acceptable level (say, .05) and calculate
    probability that z is greater than or less than
    that value (this will be important in hypothesis
    testing)

3
Normal distribution
  • Example
  • Concrete cylinder test results (in psi) are 1000,
    1200, 1150, 1100, and 1230. You need to have
    three of six cylinders exceed 1200 psi before you
    can strip forms. What is the probability that
    the sixth cylinder will exceed 1200 psi?
  • First calculate the mean and sd of the sample
  • Mean 1136, sd 90

4
Normal distribution
  • Z-statistic for the sixth cylinder is
  • 1200-1136/90 .711
  • Z .711, P .26115
  • Probability is (1 - .76115), or .2389, 24 chance
  • must add 50 area from left of the mean and
    subtract remaining area to find probability

5
Normal distribution
  • What if the specifications read that the average
    of six cylinders must be 1200?
  • 1200 X 6 7200
  • S (1-5) 5680
  • Cylinder 6 must test at 7200-5680 1520 for
    average to be 1200
  • Z 1520-1200/176.5 1.81
  • A(x) .46485
  • P 1-(.5 .46485) .0352, or 3 chance

6
Normal distribution
  • What if you asked to change the specification to
    read the average of the 5 highest of 6 tests
    (eliminate the outlier of 1000) must equal 1200?
  • 1200 1150 1100 1230 X/5 1200
  • X 1320 (sixth cylinder must test at 1320
  • Z 1320-1200/83.37 1.44
  • A(x) .42507
  • P 1-.92507, or 7.5

7
Normal Distribution
  • Is this important?
  • Assume an 18 million dollar job with a 12 month
    completion schedule
  • 1.5 million per month/ 22 workdays per 68,200
    per day
  • .03 X 68200 2046
  • .075 X 68200 5115
  • risk savings of over 3000 for a simple change
  • Consider you make (50,000 X1.4)/264 or 265/day

8
Normal distribution
  • Normal approximation of the Binomial distribution
    is used when the number of trials is large
  • Math gets cumbersome
  • Large sample sizes approach continuous
    distributions
  • Use normal approximations when values exceed
    those included in binomial tables
  • Use when np gt5 (or n (1-p)), or when ngt30

9
Normal distribution
  • Do 6 and 10 on page 82
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