Sign-Magnitude Representation - PowerPoint PPT Presentation

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Sign-Magnitude Representation

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High order bit is sign: 0 = positive (or zero), 1 = negative. Low order bits represent the magnitude: 0 (0002) thru 7 (1112) Number range for n bits = (2n-1) ... – PowerPoint PPT presentation

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Title: Sign-Magnitude Representation


1
Sign-Magnitude Representation
High order bit is sign 0 positive (or zero), 1
negative Low order bits represent the
magnitude 0 (0002) thru 7 (1112) Number range
for n bits (2n-1) Two representations for 0
2
Sign-Magnitude Representations
Addition and Subtraction of Numbers
  • 1- Both operands have same sign
  • Result sign bit is the same as the
  • operands' sign

4 3 7
0100 0011 0111
-4 (-3) -7
1100 1011 1111
  • 2- Operands have different sign
  • Operation is subtraction.
  • Sign of result depends on sign of
  • number with the larger magnitude
  • R X-Y
  • if XgtY subtract Y from X,
  • sign(R) sign(X).
  • if XltY subtract X from Y,
  • sign(R) sign(Y).

4 - 3 1
0 100 1 011 0 001
- 4 3 -1
1 100 0 011 1 001
3
Ones Complement Representation
  • Disadvantages of Sign-Magnitude Representation
  • Cumbersome addition/subtraction
  • Must compare magnitudes to determine sign of
    result

Ones Complement Representation
n
N (2 - 1) - N
Example 1's complement of 7
-1 in 1's comp.
Shortcut method simply compute bit wise
complement 0111 --gt 1000
-7 in 1's comp.
4
Ones Complement Representation
  • Subtraction implemented by addition using 1's
    complement
  • Still two representations of 0! This causes some
    problems
  • Some complexities in addition

5
Two Complement Representations
N 2s comp of N N 2n - N
Similar to 1's complement except shifted by one
position clockwise
  • Only one representation for 0
  • One more negative number than positive number

6
Two Complement Representations
n
N 2 - N
4
2 10000 7 0111 1001
repr. of -7
sub
Example Twos complement of 7
4
2 10000 -7 1001 0111
repr. of 7
Example Twos complement of -7
sub
Shortcut method
Twos complement bitwise complement 1 0111 -gt
1000 1 -gt 1001 (representation of -7) 1001 -gt
0110 1 -gt 0111 (representation of 7)
7
Number Systems
Ones Complement Calculations
Add carry-out of sign-bit to LSB (assuming no
overflow)
4 3 7
0100 0011 0111
-4 (-3) -7
1011 1100 10111 1 1000
Method 1- Add two n-bit numbers starting
from LSB 2- If there is an end carry (into
position n1), then remove carry and add a 1
to the LSB (end-around carry).
End around carry
4 - 3 1
0100 1100 10000 1 0001
-4 3 -1
1011 0011 1110
End around carry
8
Number Systems
Ones Complement Calculations
Why does end-around carry work? Its
equivalent to subtracting 2n and adding 1
(i.e. performing -2n1)
Case 1 (M gt N) S M - N M N M (2n -
1 - N) (M - N) 2n - 1 After end-around
carry SUM S -2n1 (M - N) 2n - 1 - 2n 1
M - N
Case 2 (-M-N, where M N lt 2n-1) -M (-N)
M N (2n - M - 1) (2n - N - 1)
2n 2n - 1 - (M N) -
1
after end around carry
2n - 1 - (M N)
this is the correct form for representing -(M
N) in 1's complement
9
Number Systems
Twos Complement Calculations
4 3 7
0100 0011 0111
Method (If no overflow) 1- Add two n-bit numbers
starting from LSB 2- Discard the carry out
of the sign-bit.
Overflow condition for 2s complement if carry
into sign-bit differs from carry out of sign-bit
then the results is an overflow
-4 3 -1
1100 0011 1111
Simpler addition scheme makes twos complement the
most common choice for integer number systems
within digital systems
10
Number Systems
Twos Complement Calculations
Discarding End Carry is equivalent to
subtracting 2n
Case 1 (-MN, where N gt M) S -M N M N
(2n - M) N 2n - (N - M) After discarding
end carry SUM S -2n 2n - (N - M) - 2n N - M
Case 2 (-M (-N), where M N lt 2n-1) S -M
(-N) M N (2n - M) (2n - N)
2n - (MN)
2n After discarding end carry SUM S -2n 2n -
(MN) 2n - 2n 2n - (MN)
(MN)
11
Overflow Conditions (2s Complement)
Overflow occurs when the result of adding two
positive (or two negative) n-bit numbers requires
more than n bits to be expressed correctly.
Overflow indications Adding two positive
numbers results in a negative number Adding two
negative numbers results in a positive number
12
Overflow Examples
0 1 1 1 0 1 0 1 0 0 1 1 1 0 0 0
1 0 0 0 1 0 0 1 1 1 0 0 1 0 1 1 1
5 3 -8
-7 -2 7
Overflow
Overflow
0 0 0 0 0 1 0 1 0 0 1 0 0 1 1 1
1 1 1 1 1 1 0 1 1 0 1 1 1 1 0 0 0
5 2 7
-3 -5 -8
No overflow
No overflow
Simple Check Overflow occurs when carry into
sign-bit does not equal the carry out of the
sign-bit.
13
Logic Circuits for Binary Addition
With twos-complement numbers, adders can perform
both addition and subtraction.
Half Adder Circuit
Half-adder Schematic
14
Logic Circuits for Binary Addition
Full Adder
Cascaded Multi-bit Adder
usually interested in adding more than two bits
this motivates the need for the full adder
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