Title: Dislocations
1Dislocations Plastic Deformation
- Phenomenon
- For ductile materials, plastic deformation will
result when the applied stress is greater than
its yield strength - in tension, specimen becomes longer and thinner
with deformation - Tensile stress vs strain curves
- Quantitative description
- yield strength
- tensile strength
- elongation
- equation
- sT K eTn
- What is the mechanism?
- dislocation movement
- Structure of this topic
- revisit concepts of crystals and dislocations
- how dislocation movement causes plastic
deformation - slip systems in crystalline materials
- shear vs tensile stresses
Reading 4.5, 7.1-7.6 (6th ed)
2Dislocations Plastic deformation
- Line defects - dislocations
- edge
- extra half plane
- displaced atoms along disln line
- Associated elastic energy
- screw
- displaced atoms along disln line
- Associated elastic energy
- mixed
- Dislocation (revisit)
- Crystalline materials
- Perfect crystals
- Defects in crystals
IMSE Dislocation-Edge
3Dislocations Plastic deformation
- Movement of dislocations
- edge dislocations
- dislocation moving on slip plane from position A
to B to C to D, creating a step on the surface of
b (burgurs vector)
IMSE Motion-Edge
4Dislocations Plastic deformation
Atomic view of edge dislocation motion from left
to right as a crystal is sheared.
Simulation of dislocation motion from left to
right as a crystal is sheared.
(Courtesy P.M. Anderson)
(Courtesy P.M. Anderson)
5Dislocations Plastic deformation
- Plastic deformation (micro)
- millions of dislocations moving in this way cause
plastic deformation
- process slip
- plane on which dislocation moves slip plane
- dislocation density
- 105-106 cm/cm3 in annealed state
- 109-1010 cm/cm3 when heavily deformed
- the magnitude and direction of deformation is
determined by b - dislocations can move in any way they like on the
slip plane - dislocations can be of any type
- Stress field self reading 7.3
Edge
IMSE Motion-Screw/Mixed
Screw
6Dislocations Plastic deformation
- Slip systems
- Can slip take place on any plane and in any
direction in a crystalline material? - Not really. Often, slip takes place on the close
packed planes and along the close packed
directions since these are easier (i.e. smallest
stress required to cause the slip)
- FCC crystals
- slip planes 111
- slip directions lt110gt
- one slip plane plus one slip direction a slip
system - 12 slip systems in a FCC structure 4 x 111
planes 3 lt110gt directions on each plane
7Dislocations Plastic deformation
- Plastic deformation (macro)
- How can macro-plastic deformation be realised by
micro-dislocation movement (slip) in a single
crystal?
- assuming there is only one slip system in
operation one slip plane and one slip direction
only - many parallel planes slip slip lines can be seen
on the surface - crystal is elongated under a tensile stress
- Question about the illustration?
- crystal rotation has to happen to keep the
loading forces in line - where is the shear stress needed to cause slip?
Zn single crystal
8Dislocations Plastic deformation
- Slip in single crystals
- Where is the shear stress?
- at a plane (the slip plane) whose normal is at f
to the tensile force F - if the slip direction on the slip plane is at l
to F, the resolved shear stress in this direction
is - tR Fs/As s cos f cos l
- cos f cos l is called the Schmid factor
- the maximum resolved shear stress on the slip
plane is when l p/2 - f (i.e. when the normal,
the slip direction and the loading direction are
on the same plan) - tR (max) s cos f sin f
s F/A
Fs (max) F sin f
Fs F cos l
As A /cos f
Note that the maximum tR direction may not be a
slip direction, i.e. slip may not be allowed in
this direction
9Dislocations Plastic deformation
- when f 45 and l 45
- cos f cos l 0.5
- which is the maximum, and thus the minimum yield
stress is - sy 2 tcrss
- sy changes with f and l (in single crystals)
- tcrss is the fundamental resistance force to
slip/plastic deformation, i.e. it is a materials
property.
- Slip in single crystals (2)
- Yielding tR reaches a critical value tcrss (the
critical resolved shear stress) to cause slip - tR tcrss
- or
- s cos f cos l tcrss
- that is
- s tcrss / (cos f cos l)
sy
10Dislocations Plastic deformation
- Solution
- to find out the Schmid factor
- f 45, tan l a (2)0.5/a
- cos f cos l cos 45 cos 54.7 0.409
- (a) tR s cos f cos l 52 x 0.409 21.3 MPa
- (b) sy tcrss/cos f cos l 30/0.409 73.3 MPa
- Slip in single crystals - Example 7.1
- BCC slip plane (110), slip direction 111
- stress direction 010
- (a) tR ? when s 52 MPa
- (b) sy ? when tcrss 30 MPa
11Dislocations Plastic deformation
- millions of small crystals (grains) form upon
solidification, separated by grain boundaries - each grain has its own (normally random)
orientation - Schmid factor?
- varies from grain to grain
- those with the greatest Schmid factors deform
first - when the grains are randomly oriented, there is
no dependence of sy on orientation - Yield strength is grain size dependent
- Plastic deformation of polycrystalline materials
- Revisit
- polycrystalline material
grain
12Dislocations Plastic deformation
- Slip lines on different grains
- Plastic deformation of polycrystalline materials
(2) - Grains are elongated
before deformation
after deformation
300 mm