Title: Vertical Curves Introduction
1Vertical Curves Introduction
2Vertical Curve Geometry
- Vertical curves use parabolas
- Field practice
3Geometry of Vertical Curves
- Notation
- BVC
- EVC
- V
- L
- g1
- g2
4Equal-Tangent Vertical Curves
EVC
Long chord
BVC
g2
g1
V
L/2
L/2
L
Datum
5Mathematics and Notation
- Rate of change of grade (r)
- Total change of grade g2 g1
- r total change/curve length
g1, g2 in L in stations
- Constant for each curve
- Sign of r shows sag curve () or crest curve
(-) - Length of curve (L)
- Same equation used
6Types of Curves
ve g2
-ve g1
ve g2
ve g1
-ve g1
ve g1
-ve g2
-ve g2
7Specification of Vertical Curves
- Given
- Specification depends on
- Design process involves
8Computation of BVC and EVC
- For equal-tangent parabolic curves
- Compute location and elevation of BVC and EVC
with
g1, g2 in L in stations
9Computing Elevation on Vertical Curves
- Two principal methods
- Offsets method
10Analytical Method
- Most common method
- Uses equation for parabolas
- For equal-tangent parabolas
- Know r, g1, BVC elevation, and x
- Compute elevation of any point on curve
11Analytical Method (contd)
- Computation of high or low point on curve
- Find first derivative and set equal to zero
- Plug x into original equation to compute elevation
12Example 1
- Given
- g1 3.00
- g2 - 1.00
- Station V 2000
- Elevation V 200.00'
- L 800.00'
- Find
- Equation of vertical curve
- Station and elevation of high point
V
EVC
BVC
13Example 1 Solution
- Curve parameters
- StaBVC StaV L/2 2000 400 1600
- ElevBVC ElevV L/2 ? g1 200.00' 4 ? 3.00
188.00' - r (g2 g1) / L (-1.00 3.00) / 8 -0.5
- Curve equation
14Example 1 Solution
- Station of high point
- Turning point (first derivative 0)
- Station of high point StaBVC 6.00 1600
600 2200
- Elevation of high point
- Consider curve equation where x 6.00
- y -0.25 x2 3x 188.00'
- y -0.25 (6)2 3(6) 188.00' 197.00'
15Example 2
- Given
- g1 -2.00
- g2 3.00
- Station V 1800
- Elevation V 100.00'
- L 600.00'
- Find
- Elevation of all stations
- Station and elevation of low point
EVC
q
BVC
m
p
n
o
V
16Example 2 Solution
- Curve parameters
- StaBVC StaV L/2 1800 300 1500
- ElevBVC ElevV L/2 ? g1 100.00' 3 ?
(-2.00) 106.00' - r (g2 g1) / L (3.00 -2.00) / 6 0.833
- Curve equation
- y 0.417 x2 2x 106.00'
- End point
- StaEVC StaV L/2 1800 300 2100
- ElevEVC ElevV L/2 ? g2 100.00' 3 ? (3.00)
109.00'
17Example 2 Solution
- Station of low point
- Turning point (first derivative 0)
- Station of low point StaBVC 2.40 1500
240 1740
- Elevation of low point
- Consider curve equation where x 2.40
- y 0.417 x2 2x 106.00'
- y 0.417 (2.4)2 2(2.4) 106.00' 103.60'
18Example 2 Solution
- Elevation of all stations
19Sight Distance on Vertical Curves
- Issue
- Two situations
- Stopping Sight Distance (SSD)
- Passing Sight Distance (PSD)
20Sight Distances Sag Curves
Sight obstructions
Headlight beam distance
21Sight Distances Crest Curves
22Estimating SSD
- Two equations might apply (feet)
- When sight distance is less than L
- When sight distance is greater than L
- Notes
- Equations assume
- Driver height 3.50 ft and obstruction height
0.50 ft - g1 and g2 in when L and s are in stations
- g1 and g2 in decimal form when L and s are in feet
23Estimating PSD (Crest Curves)
- Two equations might apply (feet)
- When sight distance is less than L
- When sight distance is greater than L
- Notes
- Equations assume
- Driver height 3.50 ft and obstruction height
4.25 ft - g1 and g2 in when L and s are in stations
- g1 and g2 in decimal form when L and s are in feet
24Example Sight Distance Analysis
- Given
- Design speed 70 mph
- SSD 600 feet
- PSD 2500 feet
- g1 3.00 and g2 -2.00
- Find
- Length of vertical curve for SSD
- Length of vertical curve for PSD
25Example Sight Distance Analysis
26Example Sight Distance Analysis
27Sight Distance on Vertical Curves
- Defining curve length
- Practical issues
28Readings
- Chapter 25 sections 25.1 25.4, 25.9, 25.11
25.13