Title: Energy, Work and Power
1Energy, Work and Power
2HOMEWORK QUESTION
- Please do this question and hand it by Tuesday
after the reading week, in class - A 50kg child slides down a 45o frictionless hill
for 60m, starting with an initial velocity of
2m/s. The child then slides for 10m over a flat
surface that has a coefficient of kinetic
friction of 0.15, and finally back up another
frictionless hill with a slope of 30o. - Draw a pictures of the problem and determine how
far on the 2nd hill the child ends up (not the
height).
3For every conservative force, we can define a
potential energy function U so that WAB -DU
UA -UB
Note the negative
Examples Gravity (uniform g) Ug mgy,
where y is height Gravity (exact, for two
particles, a distance r apart)
Ug - GMm/r, where M and m are the masses
Ideal spring Us ½ kx2, where x is the
stretch Electrostatic forces (Fkq1q2/r),
where q are the charges
4Conservation of mechanical energy
If only conservative forces do work, potential
energy is converted into kinetic energy or vice
versa, leaving the total constant. Define the
mechanical energy E as the sum of kinetic and
potential energy
E ? K U K Ug Us ...
Conservative forces only W -DU Work-energy
theorem W DK So, DKDU 0 which
means that E does not change with time.
5Example Pendulum
L
- The pendulum is released from rest with the
string horizontal. - Find the speed at the lowest point (in terms of
the length L of the string).
vf
6Example Pendulum
?
- The pendulum is released from rest at an angle ?
to the vertical. - Find the speed at the lowest point (in terms of
the length L of the string).
vf
7Example
- You slide 20m down a frictionless hill with a
slope of 30o starting from rest. At the bottom
you collide and stick to another person (at rest)
that has 90 of your mass.a) Determine the
final velocity of the system.b) How would the
calculation and final velocity change if the
slope had a coefficient of kinetic friction of
0.1 ?
8Power
- The time rate of doing work is called power.If
an external force is applied to an object, and if
work is done by this force in a time interval ?t,
the average power is defined as
PW/?t (unit J/s Watt, W) For
instantaneous power, we would use the
derivative
PdW/dtAnd since WF.s, dW/dtFds/dtF.v, so
sometimes it is useful to write
PF . v
9Example
- An elevator motor delivers a constant force of
2x105N over a period of 10s as the elevator moves
20m. What is the power ?PW/t Fs/t
(2x105N)(20m)/(10s) 4x105 W - The same elevator is moving with an average
velocity of - The power is