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6.9

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... 1/3,x) will give us different answers than the following approach: ... (D) Homework. SL Math text, Chap 29B, p712, Q1-7. HL Math text, Chap 30B, p730, Q1-11 ... – PowerPoint PPT presentation

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Title: 6.9


1
6.9 Discrete Random Variables
  • IBHLY2 - Santowski

2
(A) Random Variables
  •  Now we wish to combine some basic statistics
    with some basic probability ? we are interested
    in the numbers that are associated with
    situations resulting from elements of chance i.e.
    in the values of random variables
  • We also wish to know the probabilities with which
    these random variables take in the range of their
    possible values ? i.e. their probability
    distributions

3
(A) Random Variables
  • So 2 definitions need to be clarified
  • (i) a discrete random variable is a variable
    quantity which occurs randomly in a given
    experiment and which can assume certain, well
    defined values, usually integral ? examples
    number of bicycles sold in a week, number of
    defective light bulbs in a shipment
  • discrete random variables involve a count
  •  
  • (ii) a continuous random variable is a variable
    quantity which occurs randomly in a given
    experiment and which can assume all possible
    values within a specified range ? examples the
    heights of men in a basketball league, the volume
    of rainwater in a water tank in a month
  • continuous random variables involve a measure

4
(B) CLASSWORK
  • CLASSWORK (to review the distinction between the
    2 types of random variables)
  • Math SL text, pg 710, Chap29A, Q1,2,3
  • Math HL Text, p 728, Chap 30A, Q1,2,3

5
(C) The Distributions of Random Variables
  • For any random variable, there is an associated
    probability distribution
  •  
  • the discrete probability distribution is
    associated with discrete random variables ? so
    this probability distribution describes a
    discrete random variable in terms of the
    probabilities associated with each individual
    value that the variable may take
  • the normal distribution is associated with
    continuous random variables
  • we will initially consider only discrete data and
    their associated probability distributions

6
(C) The Distributions of Random Variables
  • We will toss three coins. The random variable, X,
    will represent the number of heads obtained.
    Construct a table and a graph to represent the
    discrete probability distribution
  • the probability of exactly 1 head in three tosses
    will be written as P(X1) (which I can read as
    the probability that my random variable ( of
    heads) has the value 1 i.e. 1 head is tossed)
  • It can be determined in many different ways ? I
    will use binomial probability distribution ((p
    q)3) from our last section ? C(3,1) x (0.5)1 x
    (0.5)3-1 3 x 0.5 x 0.25 0.375
  • Or I could use a GDC and determine
    binompdf(3,0.5,1) 0.375
  • (Or I could use the Fundamental Counting
    Principle gt p(H) x p(T) x p(T) x
    C(3,1) ) 0.375
  • Likewise, I could do similar calculations to find
    the associated probabilities for 0,1,2,3 Heads
    gt I will write this as P(X x) and equate it
    to C(3,x) x (0.5)x x (0.5)3-x, x 0,1,2,3

7
(C) The Distributions of Random Variables
  • I get the following graph
  • I get the following table

x P(Xx)
0 0.125
1 0.375
2 0.375
3 0.125
8
(C) The Distributions of Random Variables
  • ex 2. Of the 15 light bulbs in a box, 5 are
    defective. Four bulbs are chosen at random from
    the box. Let the random variable, X, represent
    the number of defective bulbs selected. Construct
    a table and graph to represent this distribution.
  • (NOTE the events are NOT independent (as
    selecting a defective bulb first, now influences
    the probabilities of the selection of a second
    bulb ? therefore, binompdf(4,1/3,x) will give us
    different answers than the following approach
  • the number of ways of selecting x defective bulbs
    from the 5 is C(5,x)
  • the number of ways of selecting (4 - x)
    non-defective bulbs is C(10, 4-x)
  • the number of ways of selecting 4 bulbs from 15
    is C(15,4)
  • so our basic probability formula would be ( of
    specific events) ) (total of events) C(5,x)
    x C(10,4-x) ) C(15,4)

9
(C) The Distributions of Random Variables
  • I get the following table
  • I get the following graph

x P(X x)
0 0.154
1 0.440
2 0.330
3 0.073
4 0.004
10
(D) Homework
  • SL Math text, Chap 29B, p712, Q1-7
  • HL Math text, Chap 30B, p730, Q1-11
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