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Bishop: Chapter 10 Key Management

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Title: Bishop: Chapter 10 Key Management


1
Bishop Chapter 10Key Management
2
Topics
  • Key exchange
  • Session vs interchange keys
  • Classical vs public key methods
  • Key generation
  • Cryptographic key infrastructure
  • Certificates
  • Key storage
  • Key escrow
  • Key revocation
  • Digital signatures

3
Notation
  • X ? Y Z W kX,Y
  • X sends Y the message produced by concatenating Z
    and W enciphered by key kX,Y, which is shared by
    users X and Y
  • A ? T Z kA W kA,T
  • A sends T a message consisting of the
    concatenation of Z enciphered using kA, As key,
    and W enciphered using kA,T, the key shared by A
    and T
  • r1, r2 nonces (nonrepeating random numbers)

4
Session, Interchange Keys
  • Alice wants to send a message m to Bob
  • Assume public key encryption
  • Alice generates a random cryptographic key ks and
    uses it to encipher m
  • To be used for this message only
  • Called a session key
  • She enciphers ks with Bobs public key kB
  • kB enciphers all session keys Alice uses to
    communicate with Bob
  • Called an interchange key
  • Alice sends m ks ks kB

5
Benefits
  • Limits amount of traffic enciphered with single
    key
  • Standard practice, to decrease the amount of
    traffic an attacker can obtain
  • Possible attacks
  • Example Alice will send Bob a message that is
    either BUY or SELL. Eve computes possible
    ciphertexts BUY kB and SELL kB. Eve
    intercepts enciphered message, compares, and gets
    plaintext at once.

6
Key Exchange Algorithms
  • Goal Alice, Bob get shared key
  • Key cannot be sent in clear
  • Attacker can listen in
  • Key can be sent enciphered, or derived from
    exchanged data plus data not known to an
    eavesdropper
  • Alice, Bob may trust third party
  • All cryptosystems, protocols publicly known
  • Only secret data is the keys, ancillary
    information known only to Alice and Bob needed to
    derive keys
  • Anything transmitted is assumed known to attacker

7
Classical Key Exchange
  • Bootstrap problem how do Alice, Bob begin?
  • Alice cant send it to Bob in the clear!
  • Assume trusted third party, Cathy
  • Alice and Cathy share secret key kA
  • Bob and Cathy share secret key kB
  • Use this to exchange shared key ks

8
Simple Protocol
request for session key to Bob kA
1. Alice
Cathy
ks kA ks kB
2. Alice
Cathy
ks kB
3. Alice
Bob
  • Then ks can be used as the secret key between
    Alice and Bob.
  • e.g., 4. Alice ? Bob M ks

9
Problems ?
  • How does Bob know he is talking to Alice?
  • Replay attack Eve records message from Alice to
    Bob (esp. messages 3 and 4), later replays it
    Bob may think hes talking to Alice, but he
    isnt.
  • e.g., Session key reuse Eve replays message from
    Alice to Bob, so Bob re-uses session key.
  • e.g., Eve replays the message Deposit 500 to
    Jacks account , originally sent from Alice to
    Bob.
  • Protocols must provide authentication and defense
    against replay.

10
Needham-Schroeder
Alice Bob r1
1. Alice
Cathy
Alice Bob r1 ks Alice ks kB
kA
2. Alice
Cathy
Alice ks kB
3. Alice
Bob
r2 ks
4. Alice
Bob
r2 1 ks
5. Alice
Bob
11
Argument Alice talking to Bob
  • Second message
  • Enciphered using key only she and Cathy know
  • So Cathy must have enciphered it
  • Response to first message
  • As r1 in it matches r1 in first message
  • Third message
  • Alice knows only Bob can read it
  • As only Bob can derive session key from that
    message
  • Any messages enciphered with that key are from Bob

12
Argument Bob talking to Alice
  • Third message
  • Enciphered using key only he and Cathy know
  • So Cathy must have enciphered it
  • Names Alice, session key
  • Cathy provided session key, says Alice is the
    other party //identity associated with the
    session key
  • Fourth message
  • Uses session key to determine if it is replay
    from Eve
  • If not, Alice will respond correctly in fifth
    message
  • If so, Eve cant decipher r2 and so cant
    respond, or responds incorrectly

13
Denning-Sacco Modification
  • Assumption of Needham-Schroeder All keys are
    secret.
  • Question Suppose Eve can obtain the session key.
    How does that affect the protocol?
  • In what follows, Eve knows ks .

Alice ks kB
a. Eve
Bob
r2 ks
b. Alice (intercepted by Eve)
Bob
r2 1 ks
c. Eve
Bob
14
Problem Solution
  • In the protocol above, Eve impersonates Alice.
  • Problem replay in the third step of
    Needham-Schroeder
  • i.e., Step a in the previous slide
  • Solution use time stamp T to detect replay

15
Needham-Schroeder with Denning-Sacco Modification
Alice Bob r1
1. Alice
Cathy
Alice Bob r1 ks Alice T ks
kB kA
2. Alice
Cathy
Alice T ks kB
3. Alice
Bob
  • Bob will reject the message if T is too old.

r2 ks
4. Alice
Bob
r2 1 ks
5. Alice
Bob
16
Needham-Schroeder with Denning-Sacco Modification
  • Weakness If clocks are not synchronized, Bob may
    either reject valid messages or accept replays.
  • Denning-Sacco Parties with slow clocks are
    vulnerable to replay.
  • Gong Parties with fast clocks are also
    vulnerable.
  • Resetting clock does not eliminate
    vulnerability.

17
Otway-Rees Protocol
  • Corrects the problem in the Needham-Schroeder
  • That is, Eve replaying the third message in the
    protocol
  • Does not use timestamps
  • Not vulnerable to the problems that Denning-Sacco
    modification has
  • Uses an integer n to associate all messages with
    particular exchange

18
The Protocol
n Alice Bob r1 n Alice Bob
kA
1. Alice
Bob
n Alice Bob r1 n Alice Bob
kA r2 n Alice Bob kB
2. Cathy
Bob
n r1 ks kA r2 ks kB
3. Cathy
Bob
n r1 ks kA
4. Alice
Bob
19
Argument Alice talking to Bob
  • Fourth message
  • If n matches the first message, Alice knows it is
    part of this exchange protocol.
  • Cathy generated ks because only she and Alice
    know kA .
  • Alice determines that the enciphered part belongs
    to the exchange as r1 matches r1 in encrypted
    part of the first message.

20
Argument Bob talking to Alice
  • Third message
  • If n matches the second message, Bob knows it is
    part of this exchange protocol.
  • Cathy generated ks because only she and Bob know
    kB .
  • Bob knows that the enciphered part belongs to the
    exchange as r2 matches r2 in encrypted part of
    the second message.

21
Replay Attack against the Otway-Rees Protocol ?
  • Eve acquires a ks and the message in the third
    step
  • n r1 ks kA r2 ks kB
  • Eve forwards appropriate part to Alice
  • Alice has no ongoing key exchange with Bob n
    matches nothing, so is rejected.
  • Alice has ongoing key exchange with Bob n does
    not match, so is again rejected.
  • If replay is for the current key exchange, and
    Eve sent the relevant part before Bob did, Eve
    could simply listen to traffic no replay is
    needed for Eve to get the information.

22
Kerberos
  • Authentication system
  • Based on Needham-Schroeder with Denning-Sacco
    modification
  • Central server plays role of trusted third party
    (Cathy)
  • Ticket
  • Issuer vouches for identity of requester of
    service
  • Authenticator
  • Identifies sender

23
Idea
  • User u authenticates to the Kerberos server
  • Obtains ticket Tu,TGS for ticket granting service
    (TGS)
  • User u wants to use service s
  • User u sends authenticator Au, ticket Tu,TGS to
    the TGS asking for ticket for service s.
  • TGS sends ticket Tu,s to user u.
  • User sends Au, Tu,s to the server as a request to
    use s.
  • Details follow

24
Ticket
  • Credential saying the ticket issuer (i.e., the
    authentication server) has identified the ticket
    requester (i.e., user u)
  • Example ticket issued to user u for service s
  • Tu,s s u us address valid time
    ku,s ks
  • where
  • ku,s is session key for user u and the ticket
    granting service s.
  • ks is the key shared between s and the
    authentication server
  • Valid time is interval for which the ticket is
    valid.
  • us address may be IP address or something else
  • Note more fields, but not relevant here

25
Authenticator
  • Credential containing identity of the sender of a
    ticket
  • Used to confirm the sender is the entity to which
    the ticket was issued.
  • Example an authenticator that user u generates
    for authenticating himself to service s
  • Au,s u generation time kt ku,s
  • where
  • kt is an alternate session key
  • Generation time is when authenticator generated
  • Note more fields, not relevant here

26
(No Transcript)
27
Protocol
user TGS
1. user
Cathy
ku,TGS ku Tu,TGS
Cathy
2. user
service Au,TGS Tu,TGS
3. user
TGS
user ku,s ku,TGS Tu,s
4. user
TGS
Au,s Tu,s
5. user
service
t 1 ku,s
6. user
service
28
Exercises
  • In constructing Au,s (see steps 3 and 5), the
    user u needs to know his session key with s,
    i.e., ku,s. How does u get the session key?
    Hint Show details of Au,s and Tu,s .
  • How is the session key between u and the TGS,
    i.e., ku,TGS , used in the protocol?
  • How is the session key between u and the service
    provider s, i.e., ku,s , used in the protocol?
  • c.f., An alternative illustration of the Kerberos
    protocol http//sce.cl.uh.edu/yang/teaching/csci5
    233fall02/Kerberos_Authentication_Steps.html

29
Analysis
  • First two steps get user ticket to use TGS
  • User u can obtain session key, ku,TGS , only if u
    knows key shared with Cathy, Ku .
  • Next four steps show how u gets and uses ticket
    for service s
  • Service s validates request by checking sender
    (using Au,s) is the same as entity ticket issued
    to
  • Step 6 optional used when u requests confirmation

30
Problems
  • Relies on synchronized clocks
  • If not synchronized and old tickets,
    authenticators not cached, replay is possible.
  • Tickets have some fixed fields
  • Dictionary attacks possible
  • Kerberos 4 session keys weak (had much less than
    56 bits of randomness) researchers at Purdue
    found them from tickets in minutes
  • Solutions? A potential research or survey project

31
Key Exchange using Public Key
  • Here interchange keys known
  • eA, eB Alice and Bobs public keys known to all
  • dA, dB Alice and Bobs private keys known only
    to the owner
  • Simple protocol
  • ks is the desired session key

ks eB
Alice
Bob
32
Problem and Solution
  • Vulnerable to forgery or replay
  • Because eB known to anyone, Bob has no assurance
    that it was really Alice that sent the message
  • Simple fix uses Alices private key
  • ks is the desired session key

ks dA eB
Alice
Bob
33
Notes
  • Can include message enciphered with ks
  • Assumes Bob has Alices public key, and vice
    versa
  • If not, each must get it from a public server
  • If keys not bound to identity of the owner,
    attacker Eve can launch a man-in-the-middle
    attack (next slide Cathy is public server
    providing public keys)
  • Solution to this (binding identity to keys)
    discussed later as public key infrastructure (PKI)

34
Man-in-the-Middle Attack (in key exchange using
public keys)
send Bobs public key
Eve intercepts request
Alice
Cathy
send Bobs public key
Cathy
Eve
eB
Cathy
Eve
eE
Eve
Alice
ks eE
Eve intercepts message
Bob
Alice
ks eB
Bob
Eve
35
Key Generation
  • Goal generate difficult-to-guess keys
  • Problem statement given a set of K potential
    keys, choose one randomly
  • Equivalent to selecting a random number between 0
    and K1 inclusive
  • Why is this hard generating random numbers
  • Actually, numbers are usually pseudo-random, that
    is, generated by an algorithm

36
What is Random?
  • Sequence of cryptographically ransom numbers a
    sequence of numbers n1, n2, such that for any
    integer k gt 0, an observer cannot predict nk even
    if all of n1, , nk1 are known
  • Best physical source of randomness
  • Random pulses
  • Electromagnetic phenomena
  • Characteristics of computing environment such as
    disk latency
  • Ambient background noise

37
What is Pseudorandom?
  • Sequence of cryptographically pseudorandom
    numbers sequence of numbers intended to simulate
    a sequence of cryptographically random numbers
    but generated by an algorithm
  • Very difficult to do this well
  • Linear congruential generators nk (ank1 b)
    mod n broken
  • Polynomial congruential generators nk (ajnk1j
    a1nk1 a0) mod n broken too
  • Here, broken means next number in sequence can
    be determined

38
Best Pseudorandom Numbers
  • Strong mixing function function of 2 or more
    inputs with each bit of output depending on some
    nonlinear function of all input bits
  • Examples DES, MD5, SHA-1
  • Use on UNIX-based systems
  • (date ps gaux) md5
  • where ps gaux lists all information about all
    processes on system

39
Next
  • Continued (Bishop, Chapter 10)
  • Cryptographic key infrastructure
  • Certificates
  • Key storage
  • Key escrow
  • Key revocation
  • Digital signatures
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