Title: Video systems continue
1Video systems (continue)
2Practice
Modify the program to get a string from a
keyboard to display the input string on the
middle of the screen with reverse video Hint
Using INT 10H function 13H (last weeks slide)
with 17H as attribute Review for midterm exam
3Review (Week 4 and 3)
- Determine the instruction address for the
following given values for CS and IP - (a) CS 26AE0, IP 0044
- Instruction address 26B24H
- (b) CS 25BD0, IP 003F
- Instruction address 25C0FH
- (c) CS 272D0, IP 029C.
- Instruction address 2756C.
4Review
- 2. The BIOS Data Area begins in low memory at
segment address_400H__________ - 4. A __directive__ enables you to control the way
in which a program assembles and lists. - 5. The first byte of an instruction is the
_operation__ the other bytes are _operand__,
which reference an immediate value, register, or
memory location.
5Review
- 3. The value 2505H is stored in locations 130 and
131, and 1C04H is stored in locations 132 and
133. What is the effect of the following related
instructions? - (a) MOV BX,0130
- 0525H in BX
- (b) ADD BX,0132
- 0941H in BX
- (c) MOV 0134,BX
- 4109H in locations 0134 and 0135.
6Review
- 6. The expression in an operand of a data item
may contain a _____?__ to indicate an
uninitialized item. - 7. The statement DW 10 DUP(25) defines 10 word__
initialized with the value _25__. - 8. A comment following an instruction on the same
line is preceded by what character? - (a) (b)
- (c) (d) a blank
7Review
- 6. The expression in an operand of a data item
may contain a _____?__ to indicate an
uninitialized item. - 7. The statement DW 10 DUP(25) defines 10 word__
initialized with the value _25__. - 8. A comment following an instruction on the same
line is preceded by what character? - (a) (b)
- (c) (d) a blank
8Using Graphic Mode
- Graphic mode uses pixels to generate color
patterns. - It represents a pixel from one to eights bits
- There are 10 common graphic modes. They are
different in terms of pages, colors,
resolution. - EMU8086 supports 1 graphic mode (INT 10H,
function 13H) - Page 1, Resolution 320 x 200, 256 colors
9Setting graphic mode
- INT 10H, function 00H
- Step 1 Set AL 13H
- Step 2 Set AH 0
- Step 3 Call INT 10H
-
10Direct Video Display
- Fastest way to display text or graphic characters
is to transfer them directly to video display
area - The address of page 0 for mode 3 is B8000H.
Each character require two bytes (one for
representing the character itself and one for its
attribute) - Moving a pair of characterattribute into video
area of the active page will cause the character
appear immediately on screen
11Example of direct video display
- MOV AX, 0B800h
- MOV ES, AX
- print message using ES
- as segment
- MOV ES00h, 48h H
- MOV ES02H, 45h E
- MOV ES04H, 4ch L
- MOV ES06H, 4ch L
- MOV ES08H, 4fh O
12Example of direct video display
13Example of direct video display
MOV AX, 0B800H MOV ES, AX MOV AX, 0003H Set
the current video mode to text mode INT 10H
INT 10H, function 00H (mode03H is standard
text) MOV AX, 0500H Set the active page
00 INT 10H CALL DISPLAY
14Example of direct video display
DISPLAY PROC NEAR mov cx,25 vertical line
mov di,0 again1 mov esdi,48h mov
esdi1,4eh add di,80 loop again1 DISPLAY
ENDP
15Direct Video Display
16Direct video display Practice
- Modify the previous program to draw horizontal
line on the screen using direct video display
17Review exercise (Week 1 and 2)
- 1. The smallest unit of data in a computer is a
_bit___. It may be off so that its value is
__0___, or on so that its value is __1__. - 2. In a byte, the parity bit always requires that
the number of bits on is a(n) ___odd___ number. - 3. The number 210 equals _1024_____, which is
represented by the letter _K_, for kilobyte. - 4. A negative binary number contains a __1___ in
its leftmost position. A negative value is
expressed in what is called __twos
complement__________ notation.
18Review exercise (Week 1 and 2)
- 5. The _hexadecimal_____ (base 16) numbering
system involves the digits 0 through F. - To indicate a base 16 number in a program, you
code the letter _H_ immediately after the number. - 6. A segment is an area that begins on a
_paragraph__________ boundary, that is, at any
location evenly divisible by decimal 16__, or hex
10__. A segment may be located almost anywhere in
memory and in real mode may be up to _64K___
bytes in size. - 7. Within a program, memory locations are
relative to the start of a __segment________ the
distance in bytes is expressed as a(n)
__offset______ from its start.
19Review exercise (Week 1 and 2)
- 8. To convert a binary number into its two's
complement form - (a) add 1,
- (b) reverse the bit values,
- (c) reverse the bit values and add 1,
- (d) reverse the bit values and subtract 1.
- 9. Reverse-byte sequence means that the processor
stores - (a) byte values upside down,
- (b) byte addresses backwards,
- (c) numeric values with bytes in reverse
sequence, - (d) all values with bytes in reverse sequence.
20Review exercise (Week 1 and 2)
- 10. The general purpose registers are
- (a) AX, BX, CX, DX (b) SP, BP, IP
- (c) DI, SI (d) CS, DS, ES, SS
- 11. The index registers are the
- (a) AX, BX, CX, DX (b) SP, BP, IP
- (c) DI, SI (d) CS, DS, ES, SS
- 12. What is the maximum size of a segment?
- (a) 4K (b) 64K
- (c) 256K (d) no limit
21Review exercise (Week 1 and 2)
- 13. Provide the two instructions to initialize
the address of the data segment in the DS
register, given the name DATSG. - MOV AX,DATSG
- MOV DS,AX
22Review exercise (Week 1 and 2)
23Practice
2B360H
PSP
DS2B360H
Stack Segment
SS2B360H100H 2B460H
Data Segment
ES2B360H SP0030H
CS2B360H100H 30H 70H
2B500H
Code Segment
Memory