Title: Statistics 221
1Statistics 221
- Chapter 4 Part A
- Probability
24.1 Experiments and Events
- In statistics, the word experiment means an
event that generates an well-defined outcome. - Examples of events flipping a coin (outcomes
heads or tails) or drawing a card from a deck
(outcomes face card or not), taking a test
(outcomes pass or not), selecting one item from
a batch of items (outcomes defective or not). - Well use the word event rather than
experiment when we refer to this phenomenon.
3Events
- Events can be single-outcome events or
collective-outcome events. - For example, if your event is flipping a coin,
there is one single outcome that is heads or
tails. - But if your event is flipping 10 coins there
are 10 outcomes which are collected into a
single outcome such as the number of those 10
flips that resulted in heads. - Example this outcome HHHHTTHHTH would be
considered an outcome of 7 for 7 heads.
4Sample space
- The sample space for an event is the set of all
possible outcomes. - A sample point is a member of the sample space,
any one particular outcome. - For example, if the event is flipping a coin,
the sample space is heads, tails a sample
point one particular outcome is heads. - If your event is rolling two die, the sample
space is 1-1, 1-2, 1-3, 1-4, 1-5, 1-6, 2-1, 2-2,
etc.. To express the outcome as a single value,
the sum of the face values on the two die could
be used.
5Defining sample space
- When you want to define an events sample space,
you determine how many possible outcomes there
are and you (may be able to) list them all. - For example, if your event involves tossing a
coin one time, then the sample space is H, T -
(heads or tails) and there are two possible
outcomes.
6Defining sample space
- Sometimes, you can just list all the possible
outcomes and count them. But some events have
many, many possible outcomes too many to count
one-by-one. If that is the case, there are
short-cut formulas that can be used to calculate
the number of possible outcomes. - Combination events may have many possible
outcomes and require the formula method to
determine sample space.
7Counting the number of possible outcomes for
combination events
- If your event is a combination event such as
flipping a coin two times, then the sample space
is H, H, H, T, T, H, T, T (four possible
outcomes). - If your event is flipping a coin three times,
then the sample space is H, H, H, H, H, T,
H, T, H, H, T, T, T, H, H, T, H, T, T,
T, H, T, T, T (eight possible outcomes).
8Counting possible outcomes for combination events
- So how many outcomes are possible if you toss a
coin 4 times? 5? - Recall that some events have many, many possible
outcomes as with some combination events and
there may be too many to list. - Fortunately, there is a short-cut formula that
can be used (if certain conditions are met) to
calculate the number of outcomes in the sample
space.
9The formula for counting the number of possible
outcomes
- If an experiment/event has (t) steps/phases,
multiply the number of possible outcomes (n) at
step 1 by the number of possible outcomes (n) at
step 2 by the number of possible outcomes at
step t. - Example if the step is tossing a coin and
there are two possible outcomes (n 2) and your
event is tossing a coin 5 times (t5), then the
number of possible outcomes is 2 2 2 2 2
or 32. - H, H, H, H, H would be one of those possible
outcomes or in other words, one sample point.
10Applying the counting formula to define sample
space
- If you roll a die once (t1), the number of
possible outcomes each time you roll is 6 (n6),
so total number of possible outcomes is 6. - The sample space is 1, 2, 3, 4, 5, 6.
- If you roll it twice (t2), the number of
possible outcomes is 6 (n6) each time, then the
total number of possible outcomes is 6 6 or
36. - The sample space is 1-1, 1-2, 1-3 .
- If you roll it three times (t3), the number of
possible outcomes is 6 6 6 or 216.
11Example ofApplying the counting formula to
define sample space
- A telephone number has a three-digit area code.
- How many three digit area codes can there be?
- Each digit can be any digit from 0 to 9 (10
possible outcomes). - So if n10, t3, then there can be 10 10 10
or 1,000 possible area codes.
12What if the number of possible outcomes are not
the same for each step?
- What if I said that the middle digit must be a 0
or 1? Now, how many area codes can there be? - Wed have to use this formula 10 2 10 200.
- (10 possibilities for the first digit, 2
possibilities for the 2nd digit, 10 possibilities
for the 3rd digit.)
13Another example
- The Kentucky Power and Light Company is about to
start a large construction project. The project
has two phases (1) design and (2) construction. - The design phase could take 2, 3, or 4 months
the construction phase could take 6, 7, or 8
months. - Define the sample space. In other words,
determine how many possible outcomes there are
there for completion times and list them.
14Example of defining sample space Kentucky Power
and Light Co.
- How many possible outcomes?
- 3 (for phase 1) 3 (for phase 2) 9
15What are the possible outcomes?
Possibilities for the number of months to complete
- Design Construction
- Phase 1 Phase 2 Total
- 2 6 8
- 2 7 9
- 2 8 10
- 3 6 9
- 3 7 10
- 3 8 11
- 4 6 10
- 4 7 11
- 4 8 12
16Example of defining sample space Bradley
Investments
- Bradley has invested in two stocks, Markley Oil
and Collins Mining. Bradley has determined that
the possible outcomes of these investments three
months from now are as indicated in the table
below. Define the sample space. In other words,
how many possible outcomes are there and what are
they?
Possible Profit in 3 Months (in 000)
- Markley Oil Collins Mining
- 10 8
- 5 -2
- 0
- -20
17How many possible outcomes are there?
- Markley n1
- Collins n2
- n1 n2 (4) (2) 8
18What are the outcomes?A tree diagram is
sometimes used to express the outcomes
Markley Oil Collins Mining
Gain 8
(10, 8) Gain 18,000 (10, -2) Gain
8,000 (5, 8) Gain 13,000 (5, -2)
Gain 3,000 (0, 8) Gain 8,000 (0,
-2) Lose 2,000 (-20, 8) Lose
12,000 (-20, -2) Lose 22,000
Lose 2
Gain 10
Gain 8
Lose 2
Gain 5
Gain 8
Even
Lose 2
Lose 20
Gain 8
Lose 2
19Defining sample space using the permutation
formula
- In the previous examples, when we defined sample
space, we were actually asking the question How
many permutations are possible? - The permutations formula is written like this
N!
P
N
n
(N n)!
- where N is the number of outcomes for one step
and n is the number of steps/times.
20Permutations
- The permutations formula can be simplified. For
example, what is the number of possible 3-digit
area codes that are possible?
10 10 10 1,000
10P3
N is 10 n is 3
(multiply 10 by itself 3 times.)
21Permutations with replacement
- The previous question was about defining the
sample space when we were sampling with
replacement. - When you sample with replacement, each time you
select a digit, there is still the same number of
digits to select from the next time. - For example, you have a choice of 10 possible
values for the first digit, after you select the
first digit, there are still 10 possible values
for the 2nd and 3rd digits, etc.
22Permutations without replacement
- What if I said, the same digit cannot be used
more than once? How many area codes are possible?
Now the formula is
10P3
10 9 8 720
- This is called sampling without replacement.
Each time you select a digit, there is one less
digit to select from next time. The sample space
will be reduced when you sample without
replacement.
23Combinations
- Combination questions are similar to permutation
questions but all different orders count as one
possible outcome/sample point. - For example, if we had to select three letters
from the alphabet, the outcome of ABC is not a
distinct outcome from CBA. - The combinations formula is
N!
C
N
n
(N n)! n!
- where N is the number of outcomes for one step
and n is the number of steps/times.
24A combinations example
- If you had to select three letters from the
alphabet, how many different combinations of
three letters are possible? - The combinations formula can be simplified to
26 25 24 3 2 1
26C3
2600
Combination questions are usually considered as
without replacement situations.
25Example Combinations(order doesnt matter)
- There are nine candidates available for
committees. How many different three-person
committees are possible? (order doesnt matter,
and selection is without replacement
NCn
9 8 7
84
3 2 1
N is 9 n is 3
26Example Permutations(order matters)
- There are nine people on the Board of Trustees.
- A president, vice president, and secretary must
be chosen. How many different possible sets of
president, VP, secretary are possible? - Order matters, selecting without replacement.
- 9 8 7
-
-
NPn
504
N is 9 n is 3
27Practice question ( 2 on p. 149)
- How many ways can three items be selected from a
group of six items? Use the letters A, B, C, D,
E, and F to identify the items, and list each of
the different combinations of the three items. - Assume without replacement.
28Answer (2 on p.149)
NCn
6 5 4 3 2 1
120/6 20
N is 6 n is 3
- ABC ABD ABE ABF ACD ACE ACF
- ADE ADF AEF BCD BCE BCF BDE
- BDF BEF CDE CDF CEF DEF
29Practice question (3 on p. 149)
- 3. How many permutations of three items can be
selected from a group of six items? Use the
letters A, B, C, D, E, and F to identify the
items, and list each permutation of items for
B,D, and F. - Assume without replacement.
30Answer (p. 149)
NPn
6 5 4
120
N is 6 n is 3
- ABC, ABD, ABE, ABF, ACB, ACD, ACE, ACF, ADB, ADC,
ADE, ADF, AEB, AEC, AED, AEF, AFB, AFC, AFD, AFE,
BAC BAD, BAE, BAF, BCA, BCD, BCE, BCF, BDE, BDF,
BEF etc. - In this case, ABC is a different sample point
than ACB.
31How many combinations are there?
- To win the Pennsylvania lottery you have to guess
six two-digit numbers and all six have to match
the winning numbers. Each number can be from 01
to 69 but no number will occur more than once in
the 6-number winning set. - As long as you select all 6 numbers correctly,
order doesnt matter.
32How many combinations are there?
- You must select all six numbers correctly but
they can be in any order and there are no
duplicate numbers in the winning set.
NCn
69 68 67 66 65 64 6 5 4 3
2
N is 69 n is 6
119,877,472
33How many permutations are there?
- Singing legend Frank Sinatra recorded 381 songs.
From a list of his top 50 songs, you must select
three that will be sung in a medley as a tribute
at the next MTV Music Awards Ceremony. The order
of songs is important so that they fit together
well. If you select three of Sinatras top 50
songs, how many different sequences are possible?
34How many permutations are there?
- You have a choice of 50 songs, you must pick 3.
You cant pick the same one twice (selecting
without replacement), and order matters.
NPn
50 49 48 117,600
N is 50 n is 3
35Assigning Probabilities to Events
36Probability
- Probability is a numerical measure of the
likelihood that an event will occur. - Probabilities are expressed as percentages that
range from 0 to 1. - A probability near 0 indicates an event is very
unlikely to occur. - A probability near 1 indicates an event is almost
certain to occur. - A probability of 0.5 indicates the occurrence of
the event is just as likely as it is unlikely. - Probabilities can be used to express the degree
of uncertainty of an event.
37Probability as a Numerical Measureof the
Likelihood of Occurrence
Increasing Likelihood of Occurrence
0
1
.5
Probability
Definitely WILL happen
Definitely WILL NOT happen
The occurrence of the event is just as likely
as it is unlikely.
38Basic requirements for assigning probabilities to
events
- A probability assigned to a particular outcome
must be between 0 and 1 inclusively - 0
- The probabilities assigned to each possible
outcome of an event must sum to 1.0 - P(E1) P(E2) P(E3).. P(En) 1
39Three methods for assigning probabilities to
events
- Classical Method
- Assigning probabilities based on the assumption
of equally likely outcomes. - Relative Frequency Method
- Assigning probabilities based on experimentation
or historical data. - Subjective Method
- Assigning probabilities based on the assignors
judgment.
40Classical method
- If an experiment has n possible outcomes, this
method would assign a probability of 1/n to each
outcome. - Example
- Experiment Rolling a die
- Sample Space S 1, 2, 3, 4, 5, 6
- Probabilities Each sample point has a 1/6
chance of occurring.
41What is the probability?
- If you flip a coin, what is the probability of
getting 5 heads? - Since there are 25 possible outcomes (in the
sample space) and HHHHH is one sample point,
there is a 1/32 probability of getting that
sample point is - 1/32 .03125 or 3.125
42What is the probability?
- If you draw a card from a deck, what is the
probability that it will be an ace? - Since there are 52 cards and 4 aces, the
probability is 4/52 or 1/13 or .0769 or 7.69.
43What is the probability?
- If there are 1,000 possible area codes, and one
area code is selected randomly, what is the
probability of getting 901? - 1 / 1000 or .001 or .1
44What is the probability?
- If you had to select any three letters from the
alphabet, what is the probability of getting ABC? - 1 / 2600 or .000385 or .0385
45What is the probability of winning the
Pennsylvania lottery?
- If you buy one ticket, it is
- 1 / 119,877,472 or .00000000832
46Relative Frequency Method
- Probabilities are based on past observance of how
often an event occurs. We assume that past
frequency will continue into the future. - Example
- P(rolling a 6) of times a 6 occurred
- of times the dice
was rolled - Example 115 / 760 ? 16.34
47Calculating probabilities using the relative
frequency method
- Last year, American Airlines booked 897,342
seats. 26,920 of those passengers (3) didnt
show up for their flight. Therefore, the
probability that a passenger wont show up for
his flight is 3. - During trial tests, 100,000 patients tried a new
cholesterol-reducing drug and 7,000 of them had
an adverse reaction. Therefore, the probability
that a person will have an adverse reaction to
the drug is 7.
48Another Example of the Relative Frequency Method
Lucas Tool Rental
- Lucas would like to assign probabilities to the
- number of floor polishers it rents per day.
Office - records show the following frequencies of daily
rentals - for the last 40 days.
- Number of Number
- Polishers Rented of Days
- 0 4
- 1 6
- 2 18
- 3 10
- 4 2
49Calculating probabilities using the relative
frequency method
- The probability that exactly one polisher will be
needed is 15. - Number of Number
- Polishers Rented of Days Probability
- 0 4 .10 4/40
- 1 6 .15 6/40
- 2 18 .45 etc.
- 3 10 .25
- 4 2 .05
- 40 1.00
The probability assignments are given by dividing
the number-of-days frequencies by the total
frequency (total number of days).
50Subjective probability method
- When economic conditions and a companys
circumstances change rapidly it might be
inappropriate to assign probabilities based
solely on historical data. - We can use any data available as well as our
experience and intuition, but ultimately a
probability value should express our degree of
belief that the experimental outcome will occur. - The best probability estimates often are obtained
by combining the estimates from the classical or
relative frequency approach with the subjective
estimates.
51Example where the subjective probability method
was used
- The weatherman says there is a 98 chance of
rain. - Scientists predict that there is a .0005 chance
that a large meteorite will hit the earth. - President Bush says there is a 65 chance that
the social security administration fund will be
bankrupt by the year 2020.
52Homework 6
- 9 on page 150
- Define sample space in terms of the of possible
outcomes - 10 on page 150
- What is the probability?
- 11 on page 150-1
- What is the probability?
- 12 on page 151
- Define sample space in terms of the of outcomes
and assign probabilities to outcomes