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Body Weight and Height, Strength and Agility

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Title: Body Weight and Height, Strength and Agility


1
Body Weight and Height, Strength and Agility
  • Section 2.5

2
Body Weight and Height
  • How much should I weigh?
  • A rule of thumb for marathon runners is 2 lb of
    body weight per inch of height.
  • Organizations, such as the Army, are concerned
    about physical conditioning and define an upper
    weight allowance acceptability.

3
Body Weight and Height
  • No other delineators such as bone density.
  • Note in a large portion of the table 5 lb per
    inch is allowed.

4
Body Weight and Height
  • In this section we examine qualitatively how
    weight and height should vary.
  • Body weight depends on a number of factors
    Height is one factor.
  • Bone density could be another. Significant
    variation or essentially constant? Bone volume?
  • Body density factor. Differences in densities of
    bone, muscle, and fat. Is body density a
    function of age and gender?

5
Body Weight and HeightProblem Identification
  • Define the problem so that bone density is
    constant (by accepting an upper limit) and
    predict weight as a function of height, gender ,
    age and body density.
  • The purpose of the weight table must also be
    specified, so we will base the table on physical
    appearance.

6
Body Weight and HeightProblem Identification
  • We identify the problem as follows
  • For various heights, genders, and age groups,
    determine upper weight limits that represent
    maximum levels of acceptability based on physical
    appearance.

7
Body Weight and HeightAssumptions
  • Assumptions about body density
  • One simplifying assumption Assume that some
    parts of the body are composed of an inner core
    of a different density.
  • Assume the inner core is composed primarily of
    bones and muscle and the outer core is primarily
    a fatty material of a different density.

8
Body Weight and HeightAssumptions
  • Assume that for adults certain parts of the body,
    such as the head, have the same volume and
    density for different people.
  • So the weight of an adult is given by
  • W k1 Win Wout, where k1 is the constant
    weight of those parts having the same volume and
    density for different individuals. Win and Wout
    are the weights of the inner and outer cores,
    respectively.

9
Body Weight and HeightAssumptions Submodel
inner core
  • We will now consider a submodel for the inner
    core.
  • People are not geometrically similar.
  • However, we are concerned with an upper weight
    limit based on physical appearance. So it would
    seem reasonable that whatever image might be
    visualized as an upper limit standard of
    acceptability for a 74-in person would be a
    scaled image of a 65-in person.
  • Thus for our problem, geometrical similarity of
    individuals is a reasonable assumption.

10
Body Weight and HeightAssumptions Submodel
inner core
  • So Vin ? h3
  • Now, what should be the average weight density of
    the inner core?
  • Assuming the inner core is composed of muscle and
    bone, each of different weight densities, what
    percentage of the total volume of the inner core
    is occupied by the bones?

11
Body Weight and HeightAssumptions Submodel
inner core
  • If the bone diameter is assumed to be
    proportional to the height, then the total volume
    occupied by the bones is proportional to the cube
    of the height. This implies that the percentage
    of the total volume of the inner core occupied by
    bones in geometrically similar individuals is
    constant.
  • And it follows that weight density ?in is
    constant (as shown in the following slide).

12
Body Weight and HeightAssumptions Submodel
inner core
  • Consider the average weight density ?avg of a
    volume V consisting of two components V1 and V2,
    each with a density ?1 and ?2.
  • Then V V1 V2 and
  • ?avgV W ?1V1 ?2V2, thus
  • ?avg ?1(V1/ V) ?2(V2/ V).
  • Thus ?avg is constant, so long as V1/ V and V2 /
    V do not change.

13
Body Weight and HeightAssumptions Submodel
inner core
  • Application of this result to the inner core
    implies that the average weight density ?in is
    constant.
  • Thus Win Vin ?in ? h3, or
  • Win k2 h3, for k2 gt 0
  • Note that the preceding submodel includes any
    case of materials with densities different than
    muscles and bone (such as tendons, ligaments, and
    organs) as long as their percentage of the total
    volume of the inner core is constant.

14
Body Weight and HeightAssumptions Submodel
outer core
  • Now consider the outer core of fatty material.
  • It can be argued that the thickness of the outer
    core should be constant regardless of the height.
  • Let ? denote the thickness.
  • Then Wout ??outSout, where Sout is the surface
    area of the outer core and ?out is the density of
    the outer core.

15
Body Weight and HeightAssumptions Submodel
outer core
  • Repeating Wout ??outSout
  • Again assuming the subjects are geometrically
    similar Sout ? h2
  • So Wout ? h2.
  • It may be argued, however, that taller people can
    carry a greater thickness for the fatty layer.
    If it is assumed that the thickness of the outer
    core is proportional to the height, then Wout ?
    h3.

16
Body Weight and HeightAssumptions Submodel
outer core
  • Allowing both these assumptions to reside in a
    single submodel gives Wout k3h2 k4h3, where
    k3, k4 ? 0.
  • Summing the two submodels Win k2 h3, for k2 gt
    0 andWout k3h2 k4h3, where k3, k4 ? 0,in W
    k1 Win Wout .
  • We get W k1 k3h2 k5h3, for k1, k5 gt 0 and
    k3 ? 0, where k5 k2 k4.

17
Body Weight and HeightModel
  • Model W k1 k3h2 k5h3.
  • Note that the model suggests variations in weight
    of a higher order than the first power of h. If
    the model is valid, then taller people will
    indeed have a difficult time satisfying the
    linear rules given earlier.
  • Our judgments can only be qualitative since we
    have not verified the submodels.

18
Body Weight and HeightModel Interpretation
  • Lets interpret the general rules given earlier,
    which allowed a constant weight increase for each
    additional inch of height, in terms of our
    submodel.
  • Because the total allowable weight increase per
    inch is assumed constant by the given rules, the
    portion allowed for the trunk increase may also
    be assumed constant.

19
Body Weight and HeightModel Interpretation
  • To allow a constant weight increase, the trunk
    must increase in length while maintaining the
    same cross-sectional area. This implies, for
    example, that the waist size remains constant.
  • If a 30-in. waist is judged the upper limit
    acceptable for the sake of personal appearance in
    a male with a height of 66 in., then the 2 lb per
    inch rule would allow a 30-in. waist for a male
    with a height of 72 in. as well.

20
Body Weight and HeightModel Interpretation
  • On the other hand, the model based on geometric
    similarity suggests that all distances between
    corresponding points should increase by the same
    ratio. Thus, the male with a height of 72 in.
    should have a waist of 30(72/66) ? 32.7 in.

21
Body Weight and HeightModel Interpretation
  • Now we can see why tall marathoners who follow
    the 2 lb per inch rule appear very thin.

22
Strength and Agility
  • Consider a competitive sports contest in which
    men or women of various sizes compete in events
    emphasizing strength (such as weight lifting) or
    agility (such as an obstacle course).
  • How would you handicap such events?

23
Strength and AgilityProblem Identification
  • For various heights, weights, genders, and age
    groups, determine their relationship with agility
    in competitive sports.

24
Strength and AgilityAssumptions
  • Lets initially neglect gender and age.
  • We assume agility is proportional to the ratio
    strength / weight.
  • We further assume that strength is proportional
    to the size of the muscles being used in the
    event, and we measure this size in terms of the
    muscles cross-sectional area.

25
Strength and AgilityAssumptions
  • Recall that weight is proportional to volume
    (assuming constant weight density).
  • If we assume all participants are geometrically
    similar, we have
  • Agility ? strength / weight ? l2 / l3 ? 1 / l

26
Strength and AgilityAssumptions
  • Agility ? strength / weight ? l2 / l3 ? 1 / l
  • This is a nonlinear relationship between agility
    and the characteristic dimension, l.
  • We also see that under these assumptions agility
    has a nonlinear relationship with weight.
  • How would you collect data for this model?
  • How would you test and verify your model?
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