Title: Body Weight and Height, Strength and Agility
1Body Weight and Height, Strength and Agility
2Body Weight and Height
- How much should I weigh?
- A rule of thumb for marathon runners is 2 lb of
body weight per inch of height. - Organizations, such as the Army, are concerned
about physical conditioning and define an upper
weight allowance acceptability.
3Body Weight and Height
- No other delineators such as bone density.
- Note in a large portion of the table 5 lb per
inch is allowed.
4Body Weight and Height
- In this section we examine qualitatively how
weight and height should vary. - Body weight depends on a number of factors
Height is one factor. - Bone density could be another. Significant
variation or essentially constant? Bone volume?
- Body density factor. Differences in densities of
bone, muscle, and fat. Is body density a
function of age and gender?
5Body Weight and HeightProblem Identification
- Define the problem so that bone density is
constant (by accepting an upper limit) and
predict weight as a function of height, gender ,
age and body density. - The purpose of the weight table must also be
specified, so we will base the table on physical
appearance.
6Body Weight and HeightProblem Identification
- We identify the problem as follows
- For various heights, genders, and age groups,
determine upper weight limits that represent
maximum levels of acceptability based on physical
appearance.
7Body Weight and HeightAssumptions
- Assumptions about body density
- One simplifying assumption Assume that some
parts of the body are composed of an inner core
of a different density. - Assume the inner core is composed primarily of
bones and muscle and the outer core is primarily
a fatty material of a different density.
8Body Weight and HeightAssumptions
- Assume that for adults certain parts of the body,
such as the head, have the same volume and
density for different people. - So the weight of an adult is given by
- W k1 Win Wout, where k1 is the constant
weight of those parts having the same volume and
density for different individuals. Win and Wout
are the weights of the inner and outer cores,
respectively.
9Body Weight and HeightAssumptions Submodel
inner core
- We will now consider a submodel for the inner
core. - People are not geometrically similar.
- However, we are concerned with an upper weight
limit based on physical appearance. So it would
seem reasonable that whatever image might be
visualized as an upper limit standard of
acceptability for a 74-in person would be a
scaled image of a 65-in person. - Thus for our problem, geometrical similarity of
individuals is a reasonable assumption.
10Body Weight and HeightAssumptions Submodel
inner core
- So Vin ? h3
- Now, what should be the average weight density of
the inner core? - Assuming the inner core is composed of muscle and
bone, each of different weight densities, what
percentage of the total volume of the inner core
is occupied by the bones?
11Body Weight and HeightAssumptions Submodel
inner core
- If the bone diameter is assumed to be
proportional to the height, then the total volume
occupied by the bones is proportional to the cube
of the height. This implies that the percentage
of the total volume of the inner core occupied by
bones in geometrically similar individuals is
constant. - And it follows that weight density ?in is
constant (as shown in the following slide).
12Body Weight and HeightAssumptions Submodel
inner core
- Consider the average weight density ?avg of a
volume V consisting of two components V1 and V2,
each with a density ?1 and ?2. - Then V V1 V2 and
- ?avgV W ?1V1 ?2V2, thus
- ?avg ?1(V1/ V) ?2(V2/ V).
- Thus ?avg is constant, so long as V1/ V and V2 /
V do not change.
13Body Weight and HeightAssumptions Submodel
inner core
- Application of this result to the inner core
implies that the average weight density ?in is
constant. - Thus Win Vin ?in ? h3, or
- Win k2 h3, for k2 gt 0
- Note that the preceding submodel includes any
case of materials with densities different than
muscles and bone (such as tendons, ligaments, and
organs) as long as their percentage of the total
volume of the inner core is constant.
14Body Weight and HeightAssumptions Submodel
outer core
- Now consider the outer core of fatty material.
- It can be argued that the thickness of the outer
core should be constant regardless of the height.
- Let ? denote the thickness.
- Then Wout ??outSout, where Sout is the surface
area of the outer core and ?out is the density of
the outer core.
15Body Weight and HeightAssumptions Submodel
outer core
- Repeating Wout ??outSout
- Again assuming the subjects are geometrically
similar Sout ? h2 - So Wout ? h2.
- It may be argued, however, that taller people can
carry a greater thickness for the fatty layer.
If it is assumed that the thickness of the outer
core is proportional to the height, then Wout ?
h3.
16Body Weight and HeightAssumptions Submodel
outer core
- Allowing both these assumptions to reside in a
single submodel gives Wout k3h2 k4h3, where
k3, k4 ? 0. - Summing the two submodels Win k2 h3, for k2 gt
0 andWout k3h2 k4h3, where k3, k4 ? 0,in W
k1 Win Wout . - We get W k1 k3h2 k5h3, for k1, k5 gt 0 and
k3 ? 0, where k5 k2 k4.
17Body Weight and HeightModel
- Model W k1 k3h2 k5h3.
- Note that the model suggests variations in weight
of a higher order than the first power of h. If
the model is valid, then taller people will
indeed have a difficult time satisfying the
linear rules given earlier. - Our judgments can only be qualitative since we
have not verified the submodels.
18Body Weight and HeightModel Interpretation
- Lets interpret the general rules given earlier,
which allowed a constant weight increase for each
additional inch of height, in terms of our
submodel. - Because the total allowable weight increase per
inch is assumed constant by the given rules, the
portion allowed for the trunk increase may also
be assumed constant.
19Body Weight and HeightModel Interpretation
- To allow a constant weight increase, the trunk
must increase in length while maintaining the
same cross-sectional area. This implies, for
example, that the waist size remains constant. - If a 30-in. waist is judged the upper limit
acceptable for the sake of personal appearance in
a male with a height of 66 in., then the 2 lb per
inch rule would allow a 30-in. waist for a male
with a height of 72 in. as well.
20Body Weight and HeightModel Interpretation
- On the other hand, the model based on geometric
similarity suggests that all distances between
corresponding points should increase by the same
ratio. Thus, the male with a height of 72 in.
should have a waist of 30(72/66) ? 32.7 in.
21Body Weight and HeightModel Interpretation
- Now we can see why tall marathoners who follow
the 2 lb per inch rule appear very thin.
22Strength and Agility
- Consider a competitive sports contest in which
men or women of various sizes compete in events
emphasizing strength (such as weight lifting) or
agility (such as an obstacle course). - How would you handicap such events?
23Strength and AgilityProblem Identification
- For various heights, weights, genders, and age
groups, determine their relationship with agility
in competitive sports.
24Strength and AgilityAssumptions
- Lets initially neglect gender and age.
- We assume agility is proportional to the ratio
strength / weight. - We further assume that strength is proportional
to the size of the muscles being used in the
event, and we measure this size in terms of the
muscles cross-sectional area.
25Strength and AgilityAssumptions
- Recall that weight is proportional to volume
(assuming constant weight density). - If we assume all participants are geometrically
similar, we have - Agility ? strength / weight ? l2 / l3 ? 1 / l
26Strength and AgilityAssumptions
- Agility ? strength / weight ? l2 / l3 ? 1 / l
- This is a nonlinear relationship between agility
and the characteristic dimension, l. - We also see that under these assumptions agility
has a nonlinear relationship with weight. - How would you collect data for this model?
- How would you test and verify your model?