Chapter Eighteen - PowerPoint PPT Presentation

1 / 40
About This Presentation
Title:

Chapter Eighteen

Description:

Chapter Eighteen. Electrochemistry. Oxidation-Reduction: Transfer Of Electrons. Wait ... Oxidation-reduction reactions involve a transfer of electrons from one ... – PowerPoint PPT presentation

Number of Views:82
Avg rating:3.0/5.0
Slides: 41
Provided by: joea152
Category:
Tags: chapter | eighteen

less

Transcript and Presenter's Notes

Title: Chapter Eighteen


1
Chapter Eighteen
  • Electrochemistry

2
Oxidation-Reduction Transfer Of Electrons
Wait
Cu metal and Ag ions
Ag metal and Cu2 ions
3
Concepts In Oxidation-Reduction
  • Oxidation-reduction reactions involve a transfer
    of electrons from one species to another.
  • Oxidation loss of e- or oxidation increases
  • Reduction gain of e- or oxidation decreases
  • The species that loses electrons is oxidized and
    is an reducing agent.
  • The species that gains electrons is reduced and
    is an oxidizing agent.
  • Review Sections 4.4 4.5 for details of
    oxidation-reduction reactions.

4
Concepts In Oxidation-Reduction
Ag e ? Ag reduction of silver silver
is the oxidizing agent Cu ? Cu2 2e
oxidation of copper copper is the reducing
agent
5
However, we never see electrons in the final
balanced chemical equation 2 Ag Cu ? 2
Ag Cu2 Can only see electrons when the
reaction is broken down into half
reactions Ag e? Ag Cu ? Cu2
2e Number of electrons produced and consumed in
half reactions must be balanced so that they
cancel out in the final chemical equation.
6
Half-Reactions
  • In any oxidation-reduction reaction, there are
    two half-reactions
  • Ag e ? Ag reduction half-reaction
  • Cu ? Cu2 2e oxidation
    half-reaction

7
Half-Reaction Method OfBalancing Redox Equations
  • Separate an oxidation-reduction equation into two
    half-equations, one oxidation and one for
    reduction.
  • Balance the atoms and the electric charge in each
    half-reaction. Electrons appear on the left in
    the reduction half-equation and on the right in
    the oxidation half-equation.
  • Adjust the coefficients in the half-equations so
    that the same number of electrons appears in each
    half-equation.
  • Add together the two adjusted half-equations to
    obtain an overall oxidation-reduction equation.

8
Redox Reactions In Acidic Solution
  • In these reactions, it will be necessary to add
    molecules of water to the right and protons (H)
    on the left in the reduction step.
  • In some of the oxidation reactions, it will be
    necessary to add molecules of water to the left
    and protons on the right.
  • After these equations have been mass balanced,
    they will need to be charge balanced by adding
    electrons
  • Simplify the overall equation, if necessary, by
    removing redundant species (species which appear
    on both sides of the equation).

9
Redox Reactions In Acidic Solution
  • Assign oxidation numbers to each atom and
    identify the species undergoing oxidation and
    reduction. Write two skeleton half-reactions.
  • oxidation increase gt oxidation oxidation
    decrease gt reduction
  • (2) Balance the numbers of atoms in each
    half-reaction.
  • (a) Balance all atoms except O and H.
  • (b) Balance O atoms by adding H2O molecules.
  • (c) Balance H atoms by adding H ions.
  • Balance electric charge by adding electrons to
    more positive side.
  • Combine two half-reactions to obtain balanced
    equation.
  • (a) Multiply each half-reaction by factors that
    make the number of
  • electrons in two half-reactions equal.
  • (b) Combine the adjusted half-equations into an
    overall equation.
  • Simplify the balanced equation if necessary.
  • Verify that the equation is balanced.

10
Redox Reactions In Acidic Solution
  • Balance the following redox equation in acidic
    solution
  • Fe2 (aq) Cr2O72- (aq) ? Fe3 (aq) Cr3 (aq)

11
Redox Reactions In Basic Solution
  • For a reaction in basic solution, OH- should
    appear instead of H in the balanced equation.
  • One method commonly used to balance such
    equations is to balance the equation as if the
    reaction occurs in acidic solution.
  • Then, to each side of the net equation, add a
    number of OH- ions equal to the number of H
    appearing in the equation.
  • As a result, one side of the equation will have
    H and OH- ions in equal number those can be
    combined into water.

12
Redox Reactions In Basic Solution
  • Steps (1) (5) same as in acidic solution.
  • Convert from acidic to basic solution.
  • (a) Add OH- to each side of the equation.
  • (b) Combine H and OH- to H2O.
  • (c) Simplify the equation if necessary.
  • Verify
  • Balance the following redox equation in basic
    solution
  • S2- (aq) I2 (aq) ? SO42- (aq) I- (aq)

13
Electrochemical Cells
  • An electrochemical cell is a system consisting of
    electrodes that dip into an electrolyte and in
    which a chemical reaction either uses or
    generates an electric current.
  • A voltaic cell is an electrochemical cell in
    which electric current is generated from a
    spontaneous redox reaction.

14
A Zinc-Copper Voltaic Cell
Zn electrode Anode (-) Oxidation Zn ? Zn2 2 e-
Cu electrode Cathode () Reduction Cu2 2 e- ?
Cu
15
Qualitative Description Of Voltaic Cells
  • A half-cell consists of an electrode immersed in
    a solution of ions.
  • The solutions in the two half-cells are joined by
    a salt bridge. This bridge keeps to the two
    half-cells in contact with one another so that
    there can be a flow of electrons.
  • Metal wires connect the electrodes to the
    terminals of an electric meter called a
    voltmeter.
  • The meter indicates that electrons flow
    continuously through the system.

16
Electrode Equilibrium
17
Important Electrochemical Terms
  • Electrode is the metal strip used in
    electrochemical experiment.
  • The anode is the electrode at which oxidation
    occurs and the cathode is the electrode at which
    reduction occurs.
  • The cell potential (Ecell) is the potential
    difference that is the driving force that propels
    electrons from the anode to the cathode.
  • Cell reaction is the redox reaction that occurs
    in a voltaic cell.

18
Cell Diagrams
  • Place the anode on the left side of the diagram.
  • Place the cathode on the right side of the
    diagram.
  • Use a single vertical line ( ) to represent the
    boundary between different phases, such as
    between an electrode and a solution.
  • Use a double vertical line ( ) to represent a
    salt bridge or porous barrier separating two
    half-cells.
  • When the half-reaction involves a gas, an inert
    material such as platinum serves as an electrode
    surface on which the half-reaction occurs.

19
Cell Diagram
(see p. 775 text)
20
(No Transcript)
21
Cell Diagrams Examples
  • Write the cell diagram for a voltaic cell with
    the
  • following redox reaction.
  • 2 Al (s) 6 H (aq) ? 2 Al3 (aq) 3 H2 (g)
  • Write cell reactions for the following voltaic
    cells.
  • Cd(s) Cd2 (aq) Ni2 (aq) Ni (s)
  • Zn (s) Zn2 (aq) Fe3 (aq), Fe2 (aq) Pt

22
Standard Electrode Potentials
  • A standard electrode potential, Eo, is based on
    the tendency for reduction to occur at the
    electrode.
  • The cell voltage, called the standard cell
    potential (Eocell), is the difference between the
    standard potential of the cathode and that of the
    anode.
  • Eocell Eo (cathode) Eo (anode)

23
Standard Hydrogen Electrode
  • In the standard hydrogen electrode, hydrogen gas
    at exactly 1 bar pressure is bubbled over an
    inert platinum electrode and into an aqueous
    solution with the concentration adjusted so that
    the activity of H3O is exactly equal to one.
  • 2 H (a1) 2 e- ?H2 (g, 1 atm)
  • E0 0 V

24
Measuring The Standard PotentialOf The Cu2 / Cu
Electrode
Pt H2(g, 1atm) H(1M) Cu2(1M)
Cu(s) anode cathode Eocell Eo(Cu2/Cu)
Eo(H/H2) Eo(Cu2/Cu) 0.000V 0.340
V Eo(Cu2/Cu) 0.340 V
Cu2 ions are more readily reduced to Cu (s) than
H ions are reduced to H2.
25
Measuring The Standard PotentialOf The Zn2 / Zn
Electrode
Pt H2(g, 1atm) H(1M) Zn2(1M)
Zn(s) anode cathode Eocell Eo(Zn2/Zn)
Eo(H/H2) Eo(Zn2/Zn) 0.000V - 0.763
V Eo(Zn2/Zn) - 0.763 V
Zn2 ions are less readily reduced to Zn (s) than
H ions are reduced to H2.
26
Standard Electrode Potentials
27
Important Points About Electrode And Cell
Potentials
  • Electrode potentials and cell voltages are
    intensive properties. Their magnitudes are fixed
    once the particular species and their
    concentrations are specified. The magnitudes do
    not depend on the total amounts of the species
    present, for example, not on the size of a
    half-cell or voltaic cell.
  • Cell voltages can be ascribed to
    oxidation-reduction reactions without regard to
    voltaic cells. Specifically, we can calculate
    Eocell from the equation for a cell reaction
    without writing a cell diagram.

28
An Example
Determine the E?cell for the reaction 2 Al (s)
3 Cu2 (aq) ? 2 Al3 (aq) 3 Cu (s)
29
Strengths Of Oxidizing And Reducing Agents
  • For Table 18.1
  • All of the reactions are written as reduction
    half-reactions.
  • The more positive Eo, the stronger the oxidizing
    agent.
  • The more negative Eo, the stronger the reducing
    agent.

30
Criteria For Spontaneous Change In Redox
Reactions
  • In general ?G -n F Ecell
  • At standard conditions ?Go -n F Eocell
  • If Ecell gt0, the reaction is spontaneous.
  • If Ecell lt0, the reaction is non-spontaneous.
  • If Ecell 0, the system is at equilibrium.
  • When a cell reaction is reversed, Ecell and ?G
    change signs.

31
Criteria For Spontaneous Change In Redox
Reactions An Example
  • Exercise 18.6 A
  • Should the following reaction occur
    spontaneously as written for standard-state
    conditions?
  • Cu2 (aq) 2 Fe2 (aq) ? 2 Fe3 (aq) Cu (s)

32
Equilibrium Constants For Redox Reactions
  • ?Go -RTlnKeq ?Go - nFEocell
  • RTlnKeq nFEocell
  • RT
  • or Eocell ______ lnKeq
  • nF
  • R - gas constant 8.3145 J mol-1 K-1
  • T - Kelvin temperature
  • n - the number of moles of electrons involved in
    the reaction
  • F - the faraday constant 96,485 coulombs mole-1

33
Equilibrium Constants For Redox Reactions An
Example
  • Exercise 18.8A
  • Calculate the values of ?Go and Kep at 25oC for
  • 3 Mg (g) 2 Al3 (1M) ? 3 Mg2 (aq) 2 Al (s)

34
Summarizing The Important Relationships
35
Putting Them Together
36
Corrosion Metal Loss Through Voltaic Cells
  • In moist air, iron can be oxidized to Fe2,
    particularly at scratches, nicks, or dents. These
    areas are referred to anodic areas.
  • Other regions of the iron serve as cathodic
    areas, where the electrons from the anodic areas
    reduce atmospheric oxygen to the OH- ion.
  • Iron (II) ions migrate from the anodic areas to
    the cathodic areas where they combine with the
    hydroxide ions. The iron (II) is then further
    oxidized to iron (III) by atmospheric oxygen.
    Fe2O3xH2O is common rust.

37
Corrosion Of An Iron Piling
Overall 2Fe(s) O2 (g) 2H2O (l) ? 2Fe2(aq)
4OH-(aq)
38
Protecting Iron From Corrosion
  • The simplest line of defense against the
    corrosion of iron is to paint it to exclude
    oxygen from the surface.
  • Another approach is to coat the iron with a thin
    layer of a less active metal.
  • An entirely different approach is to protect iron
    with a more active metal, as in the zinc-clad
    iron known as galvanized iron.
  • One other approach to protecting iron, similar to
    galvanization, is cathodic protection. The iron
    object to be protected is connected to a chunk of
    an active metal and the iron serves as the
    reduction half-cell.

39
Summary
  • An oxidation-reduction reaction can be separated
    into two half-reactions, one for oxidation and
    one for reduction.
  • Half-reactions can be conducted in half-cells.
  • A cell diagram for a voltaic cell is written with
    the anode on the left and the cathode on the
    right.
  • A standard hydrogen electrode has H ion at unit
    activity in equilibrium with H2 gas on an inert
    platinum electrode.
  • Standard cell potential can be calculated from
    standard potentials of cathode and anode.
  • Eocell Eo(cathode) Eo(anode)

40
Summary (Continued)
  • A redox reaction for which Ecell gt 0 occurs
    spontaneously.
  • ?Go, Eocell and Kep are related
  • ?Go -RTlnKeq - nFEocell
  • A corroding metal consists of anodic areas, at
    which dissolution of the metal occurs, and
    cathodic areas, where atmospheric oxygen is
    reduced to hydroxide ion.
  • A metal can be protected against corrosion by
    plating it with a second metal that corrodes less
    readily.
Write a Comment
User Comments (0)
About PowerShow.com