Title: The Definite Integral
1The Definite Integral
2Riemann Sums
- Sigma notation enables us to express a large sum
in compact form
3Riemann Sums
- LRAM, MRAM,and RRAM are examples of Riemann sums
- Sn
- This sum, which depends on the partition P and
the choice of the numbers ck,is a Riemann sum for
f on the interval a,b
4Definite Integral as a Limit of Riemann Sums
- Let f be a function defined on a closed interval
a,b. For any partition P of a,b, let the
numbers ck be chosen arbitrarily in the
subintervals xk-1,xk. - If there exists a number I such that
- no matter how P and the cks are chosen, then f
is integrable on a,b and I is the definite
integral of f over a,b. -
5Definite Integral of a continuous function on
a,b
- Let f be continuous on a,b, and let a,b be
partitioned into n subintervals of equal length
?x (b-a)/n. Then the definite integral of f
over a,b is given by - where each ck is chosen arbitrarily in the kth
subinterval. -
6Definite integral
- This is read as the integral from a to b of f of
x dee x or sometimes as the integral from a to
b of f of x with respect to x.
7Using Definite integral notation
The function being integrated is f(x) 3x2 2x
5 over the interval -1,3
8Definition Area under a curve
- If y f(x) is nonnegative and integrable over a
closed interval a,b, then the area under the
curve of y f(x) from a to b is the integral of
f from a to b, -
9Nonpositive regions
- If the graph is nonpositive from a to b then
10Area of any integrable function
-
-
- (area above the x-axis)
- (area below x-axis)
11Integral of a Constant
- If f(x) c, where c is a constant, on the
interval a,b, then
12Evaluating Integrals using areas
- We can use integrals to calculate areas and we
can use areas to calculate integrals. - Using areas, evaluate the integrals
- 1)
- 2)
13Evaluating Integrals using areas
- Evaluate using areas
- 3)
- 4) (altb)
14Evaluating integrals using areas
- Evaluate the discontinuous function
- Since the function is discontinuous at x 0, we
must divide the areas into two pieces and find
the sum of the areas - -1 2 1
-
15Integrals on a Calculator
- You can evaluate integrals numerically using the
calculator. The book denotes this by using NINT.
The calculator function fnInt is what you will
use. - fnInt(xsinx,x,-1,2) is
approx. 2.04
16Evaluate Integrals on calculator
- Evaluate the following integrals numerically
- approx. 3.14
- approx. .89
17Rules for Definite Integrals
18Rules for Definite Integrals
19Rules for Definite Integrals
20Rules for Definite Integrals
21Rules for Definite Integrals
22Rules for Definite Integrals
- Max-Min Inequality If max f and min f are the
maximum and minimum values of f on a,b then - min f (b a) max f
(b a)
23Rules for Definite Integrals
- Domination f(x) g(x) on a,b
- f(x) 0 on a,b 0
24Using the rules for integration
- Suppose
- Find each of the following integrals, if
possible - b) c)
- d) e) f)
25Using the rules for definite integrals
- Show that the value of
- is less than 3/2
- The Max-Min Inequality rule says the
- max f . (b a) is an upper bound.
- The maximum value of v(1cosx) on 0,1 is v2 so
the upper bound is - v2(1 0) v2 , which is less than
3/2
26Average (Mean) Value
- If f is integrable on a,b, its average (mean)
value on a,b is -
- av(f)
- Find the average value of f(x) 4 x2 on 0,3
. Does f actually take on this value at some
point in the given interval?
27Applying the Mean Value
- Av(f)
- 1/3(3) 1
- 4 x2 1 when x v3 but only v3 falls in the
interval from 0,3, so x v3 is the place where
the function assumes the average.
28Mean Value Theorem for Definite Integrals
- If f is continuous on a,b, then at some point c
in a,b, -
29The Fundamental Theorem of Calculus, Part I
- If f is continuous on a,b, then the function
- F(x)
- has a derivative at every point x in a,b, and
-
30Applications of The Fundamental Theorem of
Calculus, Part I
31Applications of The Fundamental Theorem of
Calculus, Part I
- Find dy/dx.
- y
- Since this has an x on both ends of the integral,
it must be separated.
32Applications of The Fundamental Theorem of
Calculus, Part I
33Applications of The Fundamental Theorem of
Calculus, Part I
34The Fundamental Theorem of Calculus, Part 2
- If f is continuous at every point of a,b, and
if F is any antiderivative of f on a,b, then - This part of the Fundamental Theorem is also
called the Integral Evaluation Theorem. -
35Trapezoidal Rule
- To approximate , use
- T (y0 2y1 2y2 . 2yn-1 yn)
- where a,b is partitioned into n
subintervals of equal length h (b-a)/n.
36Using the trapezoidal rule
- Use the trapezoidal rule with n 4 to estimate
- h (2-1)/4 or ¼, so
- T 1/8( 12(25/16)2(36/16)2(49/16)4)
- 75/32 or about 2.344
37Simpson Rule
- To approximate , use
- S (y0 4y1 2y2 4y3. 2yn-2 4yn-1
yn) -
- where a,b is partitioned into an even number
n subintervals of equal length h (b a)/n.
38Using Simpsons Rule
- Use Simpsons rule with n 4 to estimate
- h (2 1)/4 ¼, so
- S 1/12 (1 4(25/16) 2(36/16) 4(49/16) 4)
- 7/3