Log Transformations in Finance

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Log Transformations in Finance

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Change in NYSE, Change in Log of NYSE. CPI and Log of CPI: Same Scale. Change in CPI, ... Logs of NYSE and S&P500. NYSE, S&P500. Indices tell pretty. Much the ... – PowerPoint PPT presentation

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Title: Log Transformations in Finance


1
Log Transformations in Finance
  • International Finance
  • Dick Sweeney

2
Log Transformations in Finance
  • Reasons to use log transformations in finance
  • On levels If level has changed greatly over
    time, logs give better view of what has happened
  • Log levels slope in percentage rate of change
  • For changes Changes in log values give a better
    view than just changes in levels.
  • Changes in log levels are percentage rates of
    change
  • Changes in log levels are more likely to be
    homskedastistic than changes in levels.

3
NYSE Level, Log of NYSE LevelSame Scale
4
NYSE Value, Log of NYSE Value,Separate Scales
Aug. 29 77,962,348 Feb. 33 15,770,881 Fall
79.77
Fall 16.27
5
Change in NYSE, Change in Log of NYSE
6
CPI and Log of CPI Same Scale
7
Change in CPI, Change in Log of CPI, Separate
Scales
8
Change in Wealth from 30-day Bills,Change in Log
of Wealth
9
Logs of NYSE and SP500
NYSE, SP500 Indices tell pretty Much the same
story
10
Compounding ("The Magic of Compounding")
  • Suppose the simple interest rate is 5/year. 1
    deposited today results in 1.05 in one year 1
    (1.05) 1.05.
  • But suppose the interest is compounded 10 times
    per year and gives the same 1.05.
  • Call the rate for each of the ten sub-periods
    R10.
  • Then, (1 R10)10 1.05, or (1 R10)10/10 (1
    R10) (1.05)1/10 1.0048909 (1 R10) and
    R10 0.0048909.
  • Multiply by 10 to give 0.048909 for year and
    multiply by 100 to put in percentage terms,
    giving the compound rate 4.8909.
  • How do we find R10? Divide 4.8909 by 10 and then
    by 100. 4.89095 per year compounded ten times
    per year is "as good as" simple interest of 5
    per year.

11
Compounding (cont.)
  • Now suppose the interest is compounded 100 times
    per year and gives the same 1.05.
  • Call the rate for each of the hundred periods
    R100.
  • Then, (1 R100)100 1.05, or
  • (1 R100)100/100 (1 R100) (1.05)1/100
  • 1.00048791 (1 R100) and R100 0.00048791.
  • Multiply by 100 to give 0.048791 for the year and
    multiply by 100 to put in percentage terms,
    giving the compound rate 4.8791.

12
Compounding (cont.)
  • Call the number of times you discount per year N.
    Then, (1 RN)N (1.05), (1.05)1/N (1 RN),
  • and as N ? ?, you get the continuously compounded
    rate 0.0487902, or 4.87902.
  • You can find the continuously compounded rate by
    using (natural logs) the continuously compounded
    rate is ln(1.05) 0.0487902, or 4.87902.
  • Just so you know, 0.0487902 can be converted back
    to 1.05 by finding e0.0487902 1.05, where e is
    the "natural" number, e 2.718281828

13
Continuously Compounded Rates of Return in
Financial Markets
  • Suppose that P0 100, P1 105, div1 5. Then,
    the simple rate of return is
  • R1 ?P1 div1 / P0
  • (P1 - P0) div1 / P0
  • (P1 / P0) - 1 (div1 / P0)
  • 0.10 ? 10.00,
  • where div1 / P0 is the dividend yield.
  • In log terms, or continuously compounded terms,
  • ln(1 R1) ln(1.1) 0.0953102 ?
  • 9.53102 lt 10.00.

14
Continuously Compounded Rates of Return (cont.)
  • Suppose div1 0.00 so div1 / P0 0.00. Then,
  • R1 ?P1 / P0 (P1 - P0) / P0 (P1 / P0) - 1
    ? 5
  • In log terms, or continuously compounded terms,
  • ln(1 R1) ln(1.05) 0.0487902 ?
  • 4.87902 lt 5.00.
  • Note that ln(1 R1) ln1 (P1 / P0) - 1
  • lnP1 / P0 lnP1 - lnP0 ? lnP1.
  • ? lnP1 is the continuously compounded rate of
    change of P.
  • Note ? lnP1 lt (?P1 / P0).
  • For small (?P1 / P0), ? lnP1 ? (?P1 / P0). If
    (?P1 / P0) 0.01, then ? lnP1 ln(1.01)
    0.0099503 ? 0.01.

15
Practice 1 Figure
16
Practice 1 (same data)
Change in log levels
  • Dependent Variable PROFIT_RATE
  • Sample (adjusted) 2 100
  • Variable Coefficient Std.
    Error t-Statistic Prob
  • C -0.173938 0.110005 -1.581179
    0.1171
  • PROFIT_RATE(-1) -0.011498 0.101046 -0.113792
    0.9096
  • R-squared 0.000133     
  • Durbin-Watson stat 2.013712

Urg!
R2 ? 0.0133 (!!)
17
Practice 1 (cont.same data)
Slope approximately equal to one.
  • Dependent Variable LEVEL
  • Sample (adjusted) 2 100
  • Included observations 99 after adjustments
  • Variable Coefficient Std. Error t-Statistic
    Prob.  
  • C -0.281801 0.188601 -1.494159 0.1384
  • LEVEL(-1) 0.988304 0.016429 60.15428
    0.0000
  • R-squared 0.973893     
  • Durbin-Watson stat 2.019364     

R2 ? 97.39
Wowbut what does it mean?
18
Practice 1 (cont.)
19
Practice 1 (cont.)
20
Practice 2 Figure
21
Practice 2 (cont.)
  • Dependent Variable PROFIT_RATE
  • Sample (adjusted) 2 100
  • Variable Coefficient Std. Error t-Statistic
    Prob.  
  • C -0.038100 0.104134 -0.365876 0.7153
  • PROFIT_RATE(-1) 0.103083 0.100919 1.021445
    0.3096
  • R-squared 0.010642     
  • Durbin-Watson stat 1.943564     

22
Practice 2 (cont.)
  • Dependent Variable LEVEL
  • Sample (adjusted) 2 100
  • Variable Coefficient Std. Error t-Statistic
    Prob.  
  • C -0.575786 0.187474 -3.071280 0.0028
  • LEVEL(-1) 0.815729 0.054805 14.88426 0.0000
  • R-squared 0.695487     
  • Durbin-Watson stat 1.667700     

23
Practice 2 (cont.)
24
Practice 2 (cont.)
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