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30 N

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Friction Force = ?4gcos25. 30 (4gsin25 ?4gcos25) = 4 x 2. 30 ... 41.41 88.82? = 20. 88.82? = 21.41. ? = 0.241. F= ma. 10kg. s = ut (at2) 4 = 2a. a = 2 ... – PowerPoint PPT presentation

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Title: 30 N


1
Force down the slope 4gsin25 ?4gcos25
30 N
2 ms-2
Friction Force ?4gcos25
4kg
250
4gcos25
4g
4gsin25
F ma
30 (4gsin25 ?4gcos25) 4 x 2 ? 30 -
16.57 35.52? 8 ?
35.52? 5.43 ?
? 0.153
2
Force down the slope 10gsin25
Friction Force ?10gcos25
10kg
250
10gcos25
s ut ½ (at2) 4 2a a 2
10g
10gsin25
F ma
10gsin25 ?10gcos25) 10 x 2 ? 41.41
88.82? 20 ? 88.82?
21.41 ? ?
0.241
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