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Honors Chemistry, Chapter 14

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Title: Honors Chemistry, Chapter 14


1
Chapter 14 Ions in Aqueous Solutions and
Colligative Properties
2
Dissociation
  • When a compound that is made of ions dissolves in
    water, the ions separate from one another. This
    separation of ions that occurs when an ionic
    compound dissolves is called dissociation.
  • Examples
  • NaCl(s) water Na(aq) Cl-(aq)
  • CaCl2(s) water Ca2(aq) 2Cl-(aq)

3
Sample Problem 14-1
  • Write the equation for the dissociation of
    aluminum sulfate, Al2(SO4)3, in water. How many
    moles of aluminum ions and sulfate ions are
    produced by dissolving 1 mole of aluminum
    sulfate? What is the total number of moles of
    ions produced by dissolving 1 mole of aluminum
    sulfate?
  • Al2(SO4)3(s) water 2Al3(aq) 3SO42-(aq)

4
Sample Problem 14-1
Al2(SO4)3(s) water 2Al3(aq) 3SO42-(aq) 1
mol Al2(SO4)3? 2 mol Al3 and 3 mol SO42- 2 mol
Al33 mol SO42- 5 mol of solute ions
5
General Solubility Rules
  • Most Na, K, and NH4 compounds are soluble.
  • Most nitrates, acetates and chlorates are
    soluble.
  • Most Cl- are soluble, except for Ag, Hg(I), and
    Pb. PbCl2 is soluble in hot water.
  • Most sulfates are soluble, except Ba, Sr, and Pb.
  • Most carbonates, phosphates, and silicates are
    insoluble, except those of Na, K, and NH4.
  • Most sulfides are insoluble, except those of Ca,
    Sr, Na, K, and NH4.

6
Soluble?
  • Ca3(PO4)2?
  • What about
  • (NH4)2S(s) water 2NH4(aq) S2-(aq)
  • And
  • Cd(NO3)2(s) water Cd2(aq) 2NO3-(aq) ?
  • Double Replacement gives
  • NH4NO3 and CdS. Are either insoluble?

7
Net Ionic Equations
  • A net ionic equation includes only those
    compounds and ions that undergo a chemical change
    in a reaction in an aqueous solution.
  • Ions that do not take part in a chemical reaction
    and are found in solution both before and after
    the reaction are spectator ions.

8
Net Ionic Equations
  • Example
  • Cd2(aq) 2NO3-(aq) 2NH4(aq) S2-(aq)
  • ? CdS(s) 2NO3-(aq) 2NH4
  • Becomes
  • Cd2(aq) S2-(aq) ? CdS(s)

9
Sample Problem 14-2
  • Identify the precipitate that forms when aqueous
    solutions of zinc nitrate and ammonium sulfide
    are combined. Write the equation for the
    possible double-replacement reaction. Then writ
    the formula equation, overall ionic equation, and
    net ionic equation for the reaction.

10
Sample Problem 14-2
  • Zn(NO3)2(aq) (NH4)2S(aq) ?
  • ZnS(?)
    2NH4NO3(?)
  • Are either insoluble?
  • Zn(NO3)2(aq) (NH4)2S(aq) ?
  • ZnS(s)
    2NH4NO3(aq)

11
Sample Problem 14-2
Zn2(aq) 2NO3-(aq) 2NH4-(aq) S2-(aq) ?
ZnS(s) 2NH4 2NO3-(aq) Net
ionic equation Zn2(aq) S2-(aq) ?ZnS(s)
12
Ionization
  • Ions are formed from solute molecules by the
    action of the solvent in a process called
    ionization.
  • Ionization is different than dissociation in that
    the ions do not exist before the action of the
    solvent. In dissociation ions are already
    present and are simply separated by the action of
    the solvent.

13
Hydronium Ion
  • The H3O ion is known as the hydronium ion.
  • Example
  • H2O(l) HCl(g) ? H3O(aq) Cl-(aq)

14
Strong and Weak Electrolytes
  • A strong electrolyte is any compound whose dilute
    aqueous solutions conduct electricity well this
    is due to the presence of all or almost all of
    the dissolved compound in the form of ions.
  • Example Aqueous solution of NaCl.
  • A weak electrolyte is any compound whos dilute
    aqueous solutions conduct electricity poorly
    this is due to the presence of a small amount of
    dissolved compound in the form of ions.
  • Example Aqueous solution of HF or HC2H3OO.

15
Colligative Properties
  • Properties that depend upon the concentration of
    solute particles but not on their identity are
    called colligative properties.

16
Vapor Pressure Lowering
  • A non-volatile substance is one that has little
    tendency to become a gas under existing
    conditions.
  • When a non-volatile substance is dissolved in a
    solvent, some solvent at the surface of the
    liquid is displaced by the solute. This reduces
    the probability that solvent molecules can escape
    from the surface thus lowers the vapor pressure.

17
Freeze-Point Depression
  • The freeze-point depression, Dtf, is the
    difference between the freezing points of the
    pure solvent and a solution of non-electrolyte in
    that solvent, and is directly proportional to the
    molal concentration of the solution.
  • The molal freezing-point constant (Kf), is the
    freezing-point depression of the solvent in a 1
    molal solution of a nonvolatile, nonelectrolyte
    solute.
  • Dtf Kf m

18
Sample Problem 14-3
  • What is the freezing-point depression of water in
    a solution of 17.1 g of sucrose, C12H22O11, and
    200 g of water? What is the actual freezing
    point of the solution?
  • Given 17.1 g sucrose
  • 200 g water
  • Kf -1.86oC/m
  • C12H22O11 342.34 g/mol

19
Sample Problem 14-3
17.1g sucrose x1 mol sucrose 0.0500 mol
342.34 g 0.0500mol sucrose
x 1000 g water 0.250 m 200 g water
1 kg water Dtf 0.250 m x (-1.86oC/m)
-0.465oC f.p. solution 0oC (-0.465oC)
-0.465oC
20
Sample Problem 14-4
  • A water solution containing an unknown quantity
    of a nonelectrolyte solute is found to have a
    freezing point of -0.23oC. What is the molal
    concentration of the solution?
  • T/P/S
  • 0.12 m

21
Boiling Point elevation
  • The boiling-point elevation, Dtb, is the
    difference between the boiling points of the pure
    solvent and a nonelectrolye solution of that
    solvent, and it is proportional to the molal
    concentration of the solution.
  • The molal boiling-point constant (Kb) is the
    boiling-point elevation of the solvent in a
    1-molal solution of a nonvolatile, nonelectrolyte
    solute.
  • Dtb Kb m

22
Sample Problem 14-5
  • What is the boiling-point elevation of a solution
    made from 20.0 g of a nonelectrolyte solute and
    400 g of water? The molar mass of the solute is
    62.0 g/mol
  • Given 20.0 g of solute
  • 400 g of water
  • 62.0 g/mol molar mass

23
Sample Problem 14-5
Dtb Kb m Dtb Kb m 20.0 g solute x 1 mol
solute 0.323 mol
62.0 g 0.323 mol solute x 1000 g water 0.808 m
400 g water 1 kg water Dtb
0.51oC/m x 8.08 m 0.41oC
24
Osmotic Pressure
  • Semipermeable membranes allow the movement of
    some particles while blocking the movement of
    others.
  • The movement of solvent through a semipermeable
    membrane from the side of lower solute
    concentration to the side of higher solute
    concentration is osmosis.
  • Osmotic pressure is the external pressure tat
    must be applied to stop osmosis.

25
Electrolytes and Colligative Properties
  • How many moles of ions are presented by a 1 molar
    solution of barium nitrate?
  • Ba(NO3)2 (s) ? Ba2(aq) 2NO3-(aq)
  • Answer 3 molar

26
Sample Problem 14-6
  • What is the expected change in the freezing point
    of water in a solution of 62.5 g of barrium
    nitrate, Ba(NO3)2, in 1.00 kg of water?
  • Given 62.5 g Ba(NO3)2
  • Ba(NO3)2 is 261.35 g/mol
  • 1.00 Kg of water
  • Dtf -1.86oC/m

27
Sample Problem 14-6
Given 62.5 g Ba(NO3)2 Ba(NO3)2 is 261.35
g/mol 1.00 Kg of water Dtf
-1.86oC/m T/P/S -1.33oC
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